What is the limit on the query string / post / URL parameters?

Similar Questions

• Example to use the query string in the Oracle Access Manager policy.

  Hi all
  
  Can is there any one please tell me what is the value of the query string and Query String Variable OAM political?
  
  If possible, please explain with an example of the sample.
  
  Thanks in advance.
  
  Siva NAKI.

  Let's say I have an application that has logout URL as http://abc.com/app.cgi?function=logout&user=LOGGED_USER.
  In this case, logged in user will always be different, but you want the user to sign out when this URL is hit. In this scenario, you can use query string variables and specify the function = disconnect it.

  In other scenarios where you know all the query parameters and you want to protect these URLs then the query string can be used.

  Thank you
  Kiran Thakkar

• How to store the query string value in the scope of the session in webcenter spaces?

  Hello

  I want to store the query string value (which is given from URL) in the sessionScope variable. According to the value of sessionScope beacause I went some components inside my taskflow. Can someone help me how to store this value in the scope of the session. I use webcenter spaces for my application development.

  Thank you

  Ashok.

  Please see the article below

  How to pass a parameter of argument the query URL to a parameter input workflow? (Doc ID 1545808.1).

• What is the query to find the name of all applications for all EBS R12.1.3 modules?

  What is the query to find the name of all applications for all EBS R12.1.3 modules?

  With regard to:

  Mr. Shahzad Saleem

  Try:

  SELECT * FROM fnd_concurrent_programs_vl;

• You can control a URL in eloqua to add to the query string?

  If I insert a URL in an email, I can't stop eloqua to add additional query string parameters in eloqua.

  I want to make this happen because the URL doesn't seem to work if we add an extra parameter using the query string.

  I had a similar problem recently, and even turn off the tracking doesn't seem to help.  I finally decided to use a shortened URL (bit.ly) and it worked for me.

• Problems with the primary key of the query string

  Moving from asp to php, to work with David Power's book: The Essential Guide to Dreamweaver CS4 with CSS, AJAX, and PHP.  Recycling of my brain, so starting from scratch in the learning process.

  Everything was going perfectly until I tried to add the primary key of a record in a query string.  I compared my code with the example code for the book, and everything matches.  When previewing the page in my browser and hover over the link which must pass the main code on the next page, the query string does not appear correctly.  It shows user_id = but no figure shows, as it is supposed to.  www.webpage.com/update_user.php?user_id=

  Here is my code: (Please note, <>have been removed, as I was unable to find a way view the code in the correct way here (copy/paste was doesn't work do not, nor insert syntax))

  ? PHP {?}

  ? PHP echo $row_listUser ['family_name'];? PHP echo $row_listUser ["FirstName"];?

  ? PHP echo $row_listUser ['username'];?       ? PHP echo $row_listUser ["admin_priv"];?

  a href = "update_user.php? user_id =? php echo $row_listUser ['user_id'];?" "Edit / has

  a href = "delete_user.php? user_id =? php echo $row_listUser ['user_id'];?" ' Delete / has

  ? PHP} while ($row_listUser = mysql_fetch_assoc ($listUser));?

  Any ideas that could help me understand why this part does not in particular would be greatly appreciated.  Writing to the database worked perfectly, I see that there are numbers in the database as user_id, and it is defined as my primary key in the configuration database.  Such a simple process that is causing me headaches!

  Thank you

  You have the code to request a copy in your folder:

  $query_listUser = 'SELECT user_id, username, first_name, family_name, admin_priv from users ORDER BY family_name ASC';

  $listUser = mysql_query ($query_listUser, $connSCFDIR) or die (mysql_error ());

  $row_listUser = mysql_fetch_assoc ($listUser);

  $totalRows_listUser = mysql_num_rows ($listUser);

  $query_listUser = 'SELECT username, first_name, family_name, admin_priv from users ORDER BY family_name ASC';

  $listUser = mysql_query ($query_listUser, $connSCFDIR) or die (mysql_error ());

  $row_listUser = mysql_fetch_assoc ($listUser);

  The $listUser table will contain the results of the second query, which does not include the field user_id. delete the redundant code.

• PHP, handling # in a passage of the string in the query string

  I'm new to PHP the world ASP. I'm working on a shopping cart where, I'm passing the name of the item through the query string in the processcart.php file. It works fine until I have put a sign # in the name of the element. Is there a good way to manage the channels with signs # among them.
  
  David

  DEPearson wrote:
  > I'm new to PHP the world ASP. I'm working on a shopping cart where I
  > pass the option through the query string name in the processcart.php file. It works
  > great until I have put a sign # in the name of the element. Is there a good way to manage
  > strings containing signs # among them.

  PHP can handle # in a string without problems. The error that you are
  manufacturing must pass # by a query string. In a URL, # indicates a
  element named inside the page. To use # as a character who is preserved
  as a literal value, you need to urlencode. You can either do
  with the urlencoded function. It is probably easier to use the
  URL directly: %23 represents #.

  --
  Adobe Community Expert David Powers
  Author, "The Essential Guide to Dreamweaver CS3" (friends of ED)
  Author, "PHP Solutions" (friends of ED)
  http://foundationphp.com/

• How to get the query of the region "PL/SQL function body returns the query string"?

  Hello
  
  is it possible to get the query string from the region of type "PL/SQL function body returns the query string"?
  
  I can get the definition of the region as a PL/SQL procedure, but I am interested in the returned query. I tried to write something like
  
  < pre > v_return_query: = «...» » ;
  : P49_QUERY: = v_return_query;
  Return v_return_query; < / pre >
  
  to save the return on hidden item P49_QUERY string, but it does not work. I get the error message: ERR-1002 cannot find the item for the "P49_QUERY" element ID in the application '4000 '.
  
  Kind regards
  Przemek

  If you need to make reference to a page element in the block then you can use this type of control to avoid having to use generic column names:

  if apex_application.get_current_flow_sgid(:APP_ID) = apex_application.get_sgid then-- runtime  :P9_SQL := vSQL;else-- design time  null;end if;
  

  But if all you want to do is capture the SQL debugging you can take all the references element in the block and use the insert statement (in a debug table) as I showed earlier.

  Scott

• What is the problem with this URL

  Can someone tell me what is the problem with this url

  owa_util.redirect_url(apex_util.prepare_url('f?p='||:APP_ID||':25:'||:APP_SESSION||'::'||:DEBUG||':25,28'||':P25_JOBID,P25_PG:&P3_JOBID.,3, null,||:APP_SESSION'));

  It gives me a value for P25_PG, that is to say 3 but always sets P25_JOBID to 0
  
  Gus

  Hello Gus,

  It looks like point P3_JOBID has no value for the rendering of the page.
  If the value is set subsequently, you can try the following change

  owa_util.redirect_url(apex_util.prepare_url('f?p='||:APP_ID||':25:'||:APP_SESSION||'::'||:DEBUG||':25,28'||':P25_JOBID,P25_PG:'||:P3_JOBID||',3, null,||:APP_SESSION'));
  

  But the part at the end

  ||',3, null,||:APP_SESSION'
  

  Wil do nothing because you give only 2 items in the list separated by commas of the page elements you want to submit. Everything after the second comma in the comma separated value list is of no use for the url of the apex.

  As additional info, the URL of the Apex is built like this:
  >
  1 - application ID or alias
  2 - page ID or Alias
  3 - session & SESSION. : APP_SESSION
  4. application (for example, PRINT_REPORT = REPORT_1) & ASK. : REQUEST
  5 - debug (YES or NO) & DEBUG. : DEBUG
  6 - cache framework

  APP - clear the cache for the entire application
  SESSION - clear the current user session cache
  PR - Reset pagination
  x - clear the page cache x
  -empty the cache for the element y

  7 - separated by a comma list of items on the page
  8 - the list of values separated by commas
  9 - mode printer friendly (YES or blank)

  f? p = & APP_ID.: 1010: & APP_SESSION. : & DEBUG. : RP, 1010:P1010_ITEM1, P1010_ITEM2, P1010_ITEM3:A, B, C
  >

  Kind regards
  Kees Vlek
  -----
  Company: http://www.orcado.nl
  Blog: http://www.orcado.nl/blog/blogger/listings/69-kvlek
  Twitter: http://www.twitter.com/skier66
  If the answer to question please change replied and mark the appropriate post as correct / helpful.

• Extract the subset of data in the query string

  Hi all

  I am using query strings in Eloqua for some time and found the implementation of them quite simple. I recently ran well across a scenario where it is not set up as a standard string.

  The URL ends up looking like this:

  http://Sub.domain.com/LP=123/?var=AB-business-_-AB-BusinessAB-_-TRK1AB23_hm_comp2-e_abcdefg_s

  The 'TRK1AB23' is the component I want to extract and place in a field.

  When I use the following code, I find myself everything of value, I want to pull all the way to the end of the string. What should I do to this code to retrieve only the characters that I need?

  function getQueryStringParamValue (strQStrParam) {}

  strURL var = document.location.href;

  var strQStrParamValue = "";

  If (strURL.indexOf('?')! = - 1) {}

  strQStrParamValue = strURL.substr (strURL.indexOf('?') + 1);

  If (strQStrParamValue.indexOf (strQStrParam)! = - 1) {}

  strQStrParamValue = strQStrParamValue.substr (strQStrParamValue.indexOf (strQStrParam));

  strQStrParamValue = strQStrParamValue.substr (strQStrParamValue.indexOf ('TRK') + 1);

  If (strQStrParamValue.indexOf('&')! = - 1) strQStrParamValue = strQStrParamValue.substr (0, strQStrParamValue.indexOf ('&'));

  Return strQStrParamValue;

  } else {}

  strQStrParamValue = defaultHiddenFieldNameValue;

  Return strQStrParamValue;

  }

  } else {}

  strQStrParamValue = defaultHiddenFieldNameValue;

  Return strQStrParamValue;

  }

  }

  Insert here the name of the form

  var form = 'generic ';

  function setCampaign() {}

  var elqForm = return [form];

  Repeat for each field to be completed

  elqForm.elements ['singleLineText'] .value = getQueryStringParamValue ('var');

  }

  Window.OnLoad = setCampaign;

  < /script >

  Egan,

  Your answer actually has helped me tremendously. I learned to look closer the code and found that it was an option of substring. I changed the substring to look at the first three characters of the code (which are always consistent) and then adjusted to shoot only the eight characters containing the code.

  It is not the prettiest or most appropriate code but it does exactly what I need to!

• Bug: APEX_COLLECTION. CREATE_COLLECTION_FROM_QUERY_B change the query string

  Hi APEX Dev Team.
  
  I found a bug (or I don't know how to get around unexpected behavior) in APEX_COLLECTION. CREATE_COLLECTION_FROM_QUERY_B. I think that it also applies to the CREATE_COLLECTION_FROM_QUERY.
  
  What's happening: some strings are replaced in the query, I pass into the function. for example '22% ' is replaced by a white. It is not good if I have a query like this:

  SELECT MYCOLA, MYCOLB, MYCOLC FROM MYTABLEA WHERE MYPHONE LIKE '%22306%';

  This returns no rows in the collection. If I run this query in SQL Developer she returns 5 rows.
  
  When I change the declaration subsequently, it returns 5 rows in the collection.

  SELECT MYCOLA, MYCOLB, MYCOLC FROM MYTABLEA WHERE MYPHONE LIKE '%2306%';

  Trace shows me, the first SELECT statement is replaced by

  SELECT MYCOLA, MYCOLB, MYCOLC FROM MYTABLEA WHERE MYPHONE LIKE ' 306%';

  Which is obviously false :-)
  
  The changes seem to be limited to 22%, I found no other characters encoding URLS that are replaced in the query.
  
  Please fix, as I can't find any workaround.
  
  Thank you
  Peter
  
  -----
  Blog: http://www.oracle-and-apex.com
  ApexLib: http://apexlib.oracleapex.info
  BuilderPlugin: http://builderplugin.oracleapex.info
  Work: http://www.click-click.at

  Hi Peter,.

  Thanks for reporting this. This seems to be a legacy logic which is no longer necessary (the logic to replace the string '22% '). I corrected it to Application Express 4.1.

  To work around the problem, you can concatenate this string in your application, allowing you to avoid this logic. For example,.

  SELECT MYCOLA, MYCOLB, MYCOLC FROM MYTABLEA WHERE MYPHONE LIKE '%2 '. 2306 ' %';

  Thanks again.

  Joel

• Need help with the query string manipulation

  Hello
  
  With the help of 10.1.0.4.2
  
  Given a table called PREFIX_CODES that contains a column called PREFIX_CODE
  with the following data:
  
  PREFIX_CODE - VARCHAR2 (20)
  -------------------
  AAA
  BENAMER
  CARTER
  
  and another table called SUBSCRIBERS with a column called SUBSCRIBER_ID
  with the following data:
  
  SUBSCRIBER_ID - VARCHAR2 (30)
  ---------------------
  BBBB-123456
  AAA-444444
  DD-2222222
  EEEE-888888
  
  Is there a query that will pull all the SUBSCRIBER_ID that begin with
  each of the PREFIX_CODES? The following query is not valid, but it
  This will give you an idea of what I'm trying to do:
  
  SELECT SUBSCRIBER_ID
  SUBSCRIBERS
  WHERE AS SUBSCRIBER_ID (SELECT PREFIX_CODE |) » %'
  OF PREFIX_CODES)
  
  Using the data from above, I would like that the query to return:
  
  BBBB-123456
  AAA-444444
  
  Thanks for your help!

  Hello

  Welcome to the forum!

  You were on the right track. To find if a given subscriber corresponds to any prefix_code, you can do an EXISTS subquery:

  SELECT     subscriber_id
  FROM     subsribers     s
  WHERE     EXISTS ( SELECT  NULL
                    FROM      prefix_codes
             WHERE      s.subscriber_id     LIKE prefix_code || '%'
              )
  ;
  

  This will tell you if at least a prefix code. It won't tell you exactly how many, or what they were.
  Your message, I'm guessing that there may be more than one, and you can deduct the subscriber_id itself, then the above query should work for you.

• What is the query block?

  Hi guys,.
  
  I searched a lot on the "query block" on google, but dosent find any satisfactory article that will explain basic concept to me.
  
  I would like to know about the parameter query block that we specified when using indicators of query optimization in oracle.
  
  
  How can they be used? where we can find them?
  
  
  any suggestions?
  
  
  Thanks and greetings
  VD

  Vkrant,
  You did exactly the same thing that is asked of me all the time. What is the purpose of this indication in a simple query that I have to show you all the time. The answer is nothing, makes complex things however. But but but, in a very complex query, where there is a cross reference of the sections of different query is required, this trick will be useful to give a name to the underlying query.
  >
  Select / * + dept_id full (@qb d) QB_NAME (qb)
  of db.dept d;

  can we say its just alias?
  >
  Yes, any. Give an official name to the query. In this query, Department table will be available with FTS.
  HTH
  Aman...

• Report with the query with union and parameters

  Hello
  
  We have an obligation to create a report with the request, which is the union and parameters.
  
  I intend to create a database for the report based on a query. But the problem here is that the way to pass parameters in the query.
  
  Request is something like that
  
  Select x.a, x.b, x.c
  x
  where x.year =: para1
  and x.status = 'A '.
  Union of all the
  Select x.a, x.b, x.c
  x
  where x.year =: para1 - 1
  and (x.status = 'c' and x.date =: para2 or x.status = 'I' and x.date < =: para2)
  
  Here x.year in the first select statement must be equal to: para1 and second select statement, it should be: para - 1.
  
  How this requirement can be achieved?
  
  Client don't want to separate worksheet, a parameter and another for the actual data that I tried with sys_context and it worked. But the client wants the result in a single sheet only... So I need to change their approach.
  
  Help, please.
  
  Thank you

  Hello
  Another option is to convert the request so that you will have the items from the selection
  for example on the query you provided that you can use:

  Select 'Curr' rec_type, x.a, x.b, x.c, x.year, x.date, x.status
  x
  where x.status = "A".
  Union of all the
  Select 'Prev' rec_type, x.a, x.b, x.c, x.year, x.date, x.status
  x
  where x.status in ('c', 'I')

  then, in the workbook, you will be able to create conditions such as:
  rec_type = 'Curr' and year =: para1

  rec_type = 'Prev' and year =: para1-1
  rec_type = 'Prev' and (status = 'c' and date =: para2 or status = 'I' and date)<=>

  Tamir

• What is the empty string, the value null in the column, or...?

  I use Oracle 11.2, a table tb_class as follows:
  
  TB_CLASS (number (3) id, varchar2 (32) nm, seqNum number (3));
  
  1, 212
  2, "under", 12
  3, 'qq', 12
  
  Select * from TB_CLASS where id = 1 and n = null;... .no selected line
  Select nvl (nm) in the TB_CLASS where id = 1; ... 1 selected line
  
  Any know what's in the column of row id = 1 nm? I thought that it is an empty string, but why it returns no rows in the first query?
  
  Thank you!

  (1) in Oracle there is no difference between NULL and an empty string.

  (2) NULL is never equal to what whatsoever (including another NULL). NULL is never spotty what whatsoever (including another NULL). You must use the IS NULL and IS NOT NULL operators to search for NULL values

  SELECT *
    FROM tb_class
   WHERE nm IS NULL
  

  or

  SELECT *
    FROM tb_class
   WHERE nm IS NOT NULL
  

  Of course, it is also possible that you declare that the NM column contains one or more spaces or it contains one or more non-printable characters and not a NULL value. That's why we asked you what dump (nm) returns

  Justin