What is the 'Live' page and need help with the data merge
Hello
Im very new to indesign naked with me. Im trying to merge data (need to create a fusion template?) and what I understand is that I need to be on the page 'Live '. Someone on the forum suggested this...
There are two ways to set up the model of fusion. You can put your placholders on the master page or on the live page. If the placehlders are on the master page, only the frame (s) with placeholders, as well as other grouped objects, will be duplicated. On the live page, ID will try to duplictate EVERYTHING on the page, so you must be very careful about installation and sizing of objects.
I want to be on the LIVE page... How can I do this? Got any other sort but can't get several records for the life of me to come.
Thank you for your help adavance
It is the opposite of multiple records per page. Make x copies of a single record on a page, put x sets of organized placeholders as you want on the page. A good way to do it is with Edit > step and repeat after you set up the left superior set. Now merge as one record per page.
Tags: InDesign
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Making the ear of corn and need help with the ball.
I do some corn on the COB for an illustration and I need help with the texture of the ball. I've been slowly making progress with gradient for kernels mesh, but I can't seem to recreate the look of the ball at all. I tried to recreate it in a rectangle by using the option in the menu object (1 row, 50 columns) gradient mesh and I'm trying with the fusion in object mode, but not lucky yet. Can someone help to put me on the right track to make the texture:
I've been slowly making progress with gradient for kernels mesh, but I can't seem to recreate the look of the ball at all.
Tank,
You have published three images stylistically very different. The first is photographic and call probably (but not necessarily) for graduates of mesh. The other two are graphical treatments (and frankly, they're both rather flat; lack of depth).
Illustration style extends the range of cartoonish in sketchy photo-realism and all the rest. The problem is you didn't show your own attempt so that anyone can have an idea of what you're trying to achieve the stylistic point of view.
I just need to put in place so that the final step does not appear the whole box. The problem now is trying to make the style of the good brush to reproduce the effect...
You seem to think you have to build a kind of linear construction and then find a way to reshape the shape of each part of the leaf. Yes, you pouvez approach it this way, but Illustrator users has often tend to be what aunt Molly would call "too clever by half."
Not everything must be something semi intelligent auto or complex and tedious consruct involving brushes, envelopes, masks, etc, etc. Much can be accomplished by thinking that he just thanks to measure you draw directly economic paths and constructions, which take no more time (often less) and result in very tidy, simple files. Again, a lot depends on what you are trying to achieve the stylistic point of view. But here's an example that only took a few minutes to draw:
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JET
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Updated software and need help with what to buy
I am a professional wedding/portrait photographer who uses photoshop cs3 with some additional photography actions in Photoshop. I have lightroom also but that you not him have not used in years. I think it's lightroom 1. I shoot both first and JPEG. I'm interested in some other photoshop actions that require me to use Lightroom 4 or later or Adobe csmera gross. I also know my photoshop is very old, but it's not my priority to replace. My question is that if I get Lightroom which should buy Lightroom 4 and a higher? And can I edit raw files in Lightroom 4 or higher, or do I also Adobe camera raw? In addition, what are the links to purchase programs and are is only a compensation per month thing? Thank you!!
Adobe Camera Raw is a plug-in for Photoshop and Photoshop Elements. All the technology that is in the plug in Camera Raw is integrated in the Lightroom program. Lightroom does not use plug in Camera Raw, because he didn't need it. But the technology is precisely the same thing. So I do not know you can say that Camera Raw is better or worse than Lightroom because they use the same technology.
For buying Lightroom 4 or 5 of Lightroom, you will need to find a dealer that has the version that is available. Adobe sells only Lightroom 6, the last standalone and Lightroom CC 2015, which is the version of the subscription. Programs are basically the same, although Lightroom CC has received some updates of features that are not available in Lightroom 6. The subscription creative cloud is really a good because not only that you get all the features of Lightroom and updates frequently, but you also have the latest version of Photoshop with all the features it offers. Photoshop and Lightroom together make a powerful combination, especially for the professional photographer. And if you're still using Photoshop CS3, I think you would find that there are huge advantages to have the latest version of Photoshop.
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The chain is be ignored and need help with why?
Hi all.
I hope again with help from the community.
There is a chain created (code below) and it runs with success - at least she built MOST of the tables.
The problem is: the last three tables all rely on the same condition and only two of them pass.
The code below, step 4, steps 5 and 6 are all dependent on the success of step 3.
When work for this string is executed, all stages of execution fails with the exception of step 5.
The interesting thing (to me at least), is that regardless of the generation of the table is step 5 fails. For example, in the code below prog_Y is attributed to step 5 and it fails. If I swap prog_Y to step_4 and prog_X to step_5, step_5 still does not work. Same result if prog_Z is listed as step 5. While steps 4 and 6 to run correctly.
Further info in job run lists of details: table or view does not exist. However, I confirmed the procs behind programs every summer executed successfully and the tables exist.
I tried several things to get more information: change the numbers.dropping/redefining step leaving down the chain and redefine, retype the steps and rules.
Help, please. Suggestions of why this step 5 may be at fault or where to find more information is super useful.
Thank you very much
Fritz
When the string is executed partially
/* 1. Create the string * /.
BEGIN
() dbms_scheduler.create_chain
CHAIN_NAME = > 'dgr_cmpl_chain ',.
RULE_SET_NAME = > null,
EVALUATION_INTERVAL = > null,
Comments = > 'Chain that loads tables of degree completion.');
END;
/* 2. Define the steps of the string * /.
BEGIN
DBMS_SCHEDULER. () DEFINE_CHAIN_STEP
chain_name = > 'dgr_cmpl_chain ',.
step_name = > "step_1".
program name = > 'prog_intrmdt_1');
DBMS_SCHEDULER. () DEFINE_CHAIN_STEP
chain_name = > 'dgr_cmpl_chain ',.
step_name = > "step_2"
program name = > 'prog_intrmdt_2');
DBMS_SCHEDULER. () DEFINE_CHAIN_STEP
chain_name = > 'dgr_cmpl_chain ',.
step_name = > "step_3"
program name = > 'prog_base');
DBMS_SCHEDULER. () DEFINE_CHAIN_STEP
chain_name = > 'dgr_cmpl_chain ',.
step_name = > "step_4"
program name = > 'prog_X');
DBMS_SCHEDULER. () DEFINE_CHAIN_STEP
chain_name = > 'dgr_cmpl_chain ',.
step_name = > "step_5"
program name = > 'prog_Y');
DBMS_SCHEDULER. () DEFINE_CHAIN_STEP
chain_name = > 'dgr_cmpl_chain ',.
step_name = > "step_6"
program name = > 'prog_Z');
END;
/* 3. Add rules * /.
BEGIN
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > 'TRUE ',.
action = > 'START step_1. "
nom_regle = > 'rule_1. "
Comments = > 'String degree start.');
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > "step_1 succeeded."
action = > 'START step_2. "
nom_regle = > "rule_2");
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > "step_2 succeeded."
action = > 'START step_3 ',.
nom_regle = > 'rule_3');
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > "step_3 succeeded."
action = > 'START step_4 ',.
nom_regle = > 'rule_4');
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > "step_3 succeeded."
action = > 'START step_5 ',.
nom_regle = > 'rule_5');
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > "step_3 succeeded."
action = > 'START step_6 ',.
nom_regle = > 'rule_6');
DBMS_SCHEDULER. () DEFINE_CHAIN_RULE
chain_name = > 'dgr_cmpl_chain ',.
State = > ' completed and full of step_5 step_4 and end step_6 "
action = > "END."
nom_regle = > 'rule_7');
END;
/*
*/
/* 4. Select the string * /.
BEGIN
DBMS_SCHEDULER. SELECT ("dgr_cmpl_chain");
END;
/* 5. Create a job that points to the string. */
/ * Wizard of work used to create jobs * /.
Thanks a lot for your suggestions. Very grateful.
Looks like this may have been a self-inflicted error.
There were a few other errors which confuse this explanation. But today, this seems to be the most likely case.
The END condition was initially step completed 6. Turns, then step 3 successful, all the steps 4, 5 and 6 began at the same time. Well, step 6 was shorter than the 5 step execution time. So step 6 would end, and the end to trigger the end of the string before step 5.
This worked constantly since the END condition has been updated in order to assess the steps, 4, 5 and 6.
Fritz
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Need help with Oracle SQL merge records according to date and term dates
Hi all
I need help to find this little challenge.
I have groups and flags and effective dashboards and dates of term against these indicators according to the following example:
GroupName Flag_A Flag_B Eff_date Term_date Group_A THERE THERE 20110101 99991231 Group_A N N 20100101 20101231 Group_A N N 20090101 20091231 Group_A N N 20060101 20081231 Group_A N THERE 20040101 20051231 Group_A THERE THERE 20030101 20031231 Group_B N THERE 20040101 99991231 Group_B N THERE 20030101 20031231 As you can see, group_A had the same combination of (N, N) flag for three successive periods. I want to merge all the time periods with the same indicators in one. Where entry into force will be the most early (underlined) time period and end date will be later (underlined)
So the final result should look like this:
GroupName Flag_A Flag_B Eff_date Term_date Group_A THERE THERE 20110101 99991231 Group_A N N 20060101 20101231 Group_A N THERE 20040101 20051231 Group_A THERE THERE 20030101 20031231 Group_B N THERE 20030101 99991231 Thanks for your help
Here's the DDL script
drop table TMP_group_test;
create table TMP_group_test (groupname varchar2 (8))
, flag_a varchar2 (1)
, flag_b varchar2 (1)
, eff_date varchar2 (8)
, term_date varchar2 (8)
);
insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20110101 ', ' 99991231');
insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20100101 ', ' 20101231');
insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20090101 ', ' 20091231');
insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20060101 ', ' 20081231');
insert into TMP_group_test values ('Group_A', 'n', 'Y', ' 20040101 ', ' 20051231');
insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20030101 ', ' 20031231');
insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20040101 ', ' 99991231');
insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20030101 ', ' 20031231');
commit;
Post edited by: user13040446
It is the closest, I went to the solution
I create two rows;
Rnk1: partition by group name, order of eff_date / / desc: this grade will sort the records of the most recent and handed to zero for each group\
Rnk2: (dense) partition by group name, flag_A, flagb: this grade for each combination of group\flag gives a number so that they are classified as "families".
Then I use the function analytic min
Min (eff_date) more (partition of GroupName, rnk2): the idea is that, for each Member of the same family, the new date is the min of the family (and the max for the date of the term), at the end I just need separate so that the duplicates are gone
Now the problem. As you can see from the query below, records of 1 and 6 (as identified by rownum) are identified in the same family, because they have the same combination of flag, but they are not successive, so everyone must keep its own date of entry into force.
If only I can make the distinction between these two that would solve my problem
Query:
Select rowNum,GroupName, flag_a, flag_b, eff_date, term_date, rnk1, rnk2
, min (eff_date) more than (partition by GroupName rnk2( ) min_eff
Of
(
Select rowNum,
GroupName , flag_a , flag_b , eff_date , term_date
rank() more than (partition by GroupName stopped by eff_date desc) rnk1
DENSE_RANK() more than (partition by GroupName order by flag_A flag_B ( ) rnk2
de dsreports . tmp_group_test
) order by rowNum
Hello
user13040446 wrote:
Hi KSI.
Thanks for your comments, you were able to distinguish between these lines highlight, but lost lines 2,3,4 which are supposed to have the same date min = 20060101.
Please see the table wanted to see the final result I want to reach
Thanks again
This first answer is basically correct, but in the main query, you want to use the function MIN, not the analytical function aggregation and GROUP BY columns with common values, like this:
WITH got_output_group AS
(
SELECT GroupName, flag_a, flag_b, eff_date, term_date
ROW_NUMBER () OVER (PARTITION BY GroupName
ORDER BY eff_date
)
-ROW_NUMBER () OVER (PARTITION BY GroupName, flag_a, flag_b)
ORDER BY eff_date
) AS output_group
OF tmp_group_test
)
SELECT GroupName, flag_a, flag_b
MIN (eff_date) AS eff_date
MAX (term_date) AS term_date
OF got_output_group
GROUP BY GroupName, flag_a, flag_b
output_group
ORDER BY GroupName
eff_date DESC
;
The result I get is
GROUP_NA F F EFF_DATE TERM_DAT
-------- - - -------- --------
Group_A Y 20110101 99991231 Y
N Group_A 20101231 20060101 N
Group_A N 20051231 20040101 Y
Group_A Y Y 20031231-20030101
Group_B N Y 99991231 20030101
which is what you asked for.
-
Having problems reading CLOB data > 32000 and thought that maybe I can load the data into 3 separate columns less than 32000 k each.
I tried to substring of a part of it first to see if it worked.
DDL
CREATE TABLE 'E406702 '. "" DSR3 ".
(
"RECORDNO' CHAR (8 BYTES),
'DOCUMENTUNIVERSALID' CHAR (32 BYTES),
"CREATIONDATE" TANK (30 BYTES),
VARCHAR2 (250 BYTE) "ETL_STATUS."
VARCHAR2 (4000 BYTE) "DSRDESCRIPTION."
VARCHAR2 (4000 BYTE) "FORM."
'REQUESTID' VARCHAR2 (4000 BYTE)
)
CONTROL FILE
DOWNLOAD THE DATA
INFILE 'DSR2DATA.txt' ' str "\r '"
ADD
IN THE DSR3 TABLE
FIELDS TERMINATED BY ' <: s: >.
(RecordNo CHAR (8),
DocumentUniversalID TANK (32),
CreationDate CHAR (30),
CHAR ETL_STATUS (250).
DSRDescription TANK (32700) "substr(:DSRDescription,1,32)."
SHAPE TANK (4000).
RequestId TANK (4000))
Doing this, that I was able to load half of my files.
Check the newspaper and saw
SQL * Loader: release 11.2.0.1.0 - Production on sea Feb 19 09:40:40 2014Copyright (c) 1982, 2009, Oracle and/or its affiliates. All rights reserved.
Control file: c:\mytest7\DSR3CONTROL.txt
Data file: DSR2DATA.txt
Chain of the treatment of the files option: ' str "\r '"
Bad leadership: c:\mytest7\DSR3CONTROL.bad
Discard File: none is specified
(Allow all releases)Number of loading: ALL
Number of jump: 0
Authorized errors: 50
Link table: 64 lines, maximum of 256000 bytes
Continuation of the debate: none is specified
Path used: classicsTable DSR3, loaded from every logical record.
Insert the option in effect for this table: APPENDColumn Position Len term Encl. Datatype name
------------------------------ ---------- ----- ---- ---- ---------------------
RECORDNO FIRST 8 CHARACTERS
String endpoint of: "<: s: > '"
DOCUMENTUNIVERSALID THEN 32 CHARACTERS
String endpoint of: "<: s: > '"
CREATIONDATE THEN 30 CHARACTERS
String endpoint of: "<: s: > '"
ETL_STATUS THEN 250 CHARACTERS
String endpoint of: "<: s: > '"
DSRDESCRIPTION CHARACTER THEN 32700
String endpoint of: "<: s: > '"
The SQL string for the column: 'substr(:DSRDescription,1,32) '.
TRAIN THEN 4000 CHARACTERS
String endpoint of: "<: s: > '"
REQUESTID THEN 4000 CHARACTERS
String endpoint of: "<: s: > '"value used for the parameter LINES increased from 64 to 6
Record 79: Rejected - error on the DSR3 table.
ORA-01461: can bind to a LONG value only for insert into a LONG columnRecord 82: Rejected - error on the DSR3 table.
ORA-01461: can bind to a LONG value only for insert into a LONG columnRecord 94: Rejected - error on the DSR3 table.
ORA-01461: can bind to a LONG value only for insert into a LONG columnRecording 160: Rejected - error on the DSR3 table.
What is the problem that. My goal was to make it work and then try to perform the following operations:
Change the ddl to
'DSRDESCRIPTION' CLOB,
'DSRDESCRIPTION1' CLOB,
'DSRDESCRIPTION2' CLOB,
Change the control for this file.
DSRDescription TANK (32700) "substr(:DSRDescription,1,32700)."
DSRDescription2 TANK (32700) "substr(:DSRDescription,32701,65401)."
DSRDescription3 TANK (15000) "substr(:DSRDescription,65402,80000)."
Is - this bad way to go on this subject?
If you can load data without any problem and read-only is a problem then you can use SUBSTR and concate (|) to read the entire string. Something like this:
Select substr (DSRDescription, 1, 32000) | substr (DSRDescription, 32001, 64000) | dsr3 substr(DSRDescription,64001);
or
with the data as
(
Select substr (DSRDescription, 1, 32000) in the DSRDescription of dsr3
Union of all the
Select substr (DSRDescription, 32001, 64000) in the DSRDescription1 of dsr3
Union of all the
Select substr(DSRDescription,64001) in the DSRDescription2 of dsr3
)
Select * from data;
Onkar
-
Hello
I have a date format that is varchar2 and value is as on 2009-03 - 31.i need to convert to date and it must be as on 31 March 09
I get as error 0RA-01981... Please help me in thisSQL> select to_date('2009-03-31','yyyy-mm-dd') xc from dual ; XC ------------------------------ 31-MAR-09
For your http://ora-01981.ora-code.com/ error
SS
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Need help with vSphere data script, packaging and sending it to the data warehouse
Greetings PowerCLI gurus.
Everyone can offer suggestions on a script which can query vSphere and pull on the following fields of the virtual computer:Name State Status Host Space in use Space used Format in a file in the CSV format and send the file to an FTP server?
Much respect to all, thanks a lot in advance.
Hello-
Happy to help you.
OK, well, if this database is accessible through a UNC path, you might make a copy directly using Copy-Item. If you use different credentials, you can encrypt and store in an XML file. HAL Rottenberg wrote to do http://halr9000.com/article/531.
Or, if this pension data is something that supports the secure copy (scp) or secure FTP (SFTP), those who would be good options. Again, you can store the alternative credentials in an encrypted in an XML file format and use them as needed.
Certainly, there is a balance to be struck between security and ease of use. It may be such that the transmitted data are not considered sensitive to all, and clear data transfers are acceptable. Probably still a good idea to take measures to protect the credentials at least.
-
new to pl/sql and need help with the procedure
Hello, I got two personnel and BONUS tables which are not bound by constraints
STAFF
ID_NUMBER HIREDATE SALARY BONUS
---------------------- ------------------------- ---------------------- ----------------------
100020 12 MAY 03 13600
100021 4 NOVEMBER 01 30000
100022 8 APRIL 02 28000
100023 8 APRIL 02 24000
BONUS
PERCENTAGE MORE_THAN_YEARS
---------------------- ----------------------
0.1-3
5 0.15
0.3 7
9 0.45
0.5-12
I am trying to create a procedure that would calculate bonus based on years of employment according to the bonus table.
If employees sysdate-hiredate is greater than 5, it is salary*0.15%...
I created this procedure, but I am stuck here.
I calculated the duration of employment for each soldier using the slider in a loop, but I don't know how to get the bonus Board values and connect with each other.
Please help me!
create or replace
procedure bonus_staff
as
cursor c1 is select * personnel;
good true;
Start
FOR ITEM IN C1
LOOP
good: = FLOOR (months_BETWEEN(SYSDATE,ITEM.hiredate)/12) *.
personal update
set bonus = good
where id_number = ITEM.id_number;
When exit c1% notfound;
end loop;
end;
/
Thanks in advance...personal update
set bonus = (select percentage
bonus of
where more_than_years = (select max (more_than_years)
bonus of
where more_than_years<=>=>
)
/You can do this in pure SQL, which operates on a game, so no PL/SQL is necessary.
----------
Sybrand Bakker
Senior Oracle DBA -
new and need help with the value $ in a sale
I have just come across this product and h
Ave fall in love with. question: how to format
from field pays $ 0.00 in
the number field instead of only 18
all free used is appreciated
Define the display pattern for the numeric field to num {($z9.99)} to display as $18.00 18...
Thank you
Srini
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I have HP Deskjet 3050 a all-in-One Printer - J611g and need help with printing, please?
I just bought the HP Deskjet 3050 all-in-one printer-J611g a. The manual has shown to do the printer double-sided printing odd pages then only print even pages only, and it works very well for one page on one side of the sheet. However, when I want to print two pages on one side of the paper and another of two pages on another aspect of the sheet, print the odd pages or even pages only just does not work! Ditto to print more than one PowerPoint presentation on one side of the page, if I click on print the odd pages only, then the printer will display the odd number of powerpoint slide instead of print odd number. I used to have another printer HP Officejet and never had any problems with two-sided printing. This printer comes with the function double-sided printeing at all? If so, how can I do duplex printing?
Thank you very much!
This is a limitation of the software that you use and how the HP printers recognize the incoming files. When compress you multiple pages on a single "page" this page is actually two pages, with even and odd numbers. It is therefore difficult for the software to determine the page numbers 'odd' and 'even' when printing, because it is no longer applicable to the relevant pages, but the format in which they are being printed.
I hope this information is useful!
-
I'm new construction sites and need help with boxes of zoom
I'm currently building a website with a shopping cart, before getting to the basket I'd like to see an option for expansion of each element. They see the regular image and then if I could add a button they can click to view a larger image. Unfortunately I do not have the Web site on a server at this time. Any help you can give me would be appreciated. Thanks in advance.
Try this:
http://ALT-Web.com/demos/jQuery-disjointed-image-gallery.shtml
Nancy O.
ALT-Web Design & Publishing
Web | Graphics | Print | Media specialists
http://ALT-Web.com/
http://Twitter.com/ALTWEB -
IM GOING CRAZY AND NEED HELP WITH ADOBE 9.3
I tried to uninstall adobe 9.3, but when I do I get this message: the component you are trying to use is on a network resourse which is not available. Click OK to try again. or enter and replacing the path to the folder containing the installation package 'AcroRead.msi' in the box below.
I have
I tried to reinstall, uninstall, find the folder... nothing. I'm a pc at home, and I'm not addicted to any network... Please help me! I'm about to start online courses and have a pdf program that works lmao
You can try the Microsoft install Cleanup Utilitiy: http://majorgeeks.com/download.php?det=4459
-
Hi all
need your spiritual help once more!
I have a table 'product' as below:
create table product)
product_id number (2),
product_info varchar (4000));
Select * from product:
product_id product_info
1 < ticketing > < product = 'TV' > < productservice = "shipping" > < / productservice > < / product = 'TV' > < / ticket >
I need to get the column product_info information in a new table with 2 columns product and productservice product_details. as in: -.
Select * from product_details:
product_id product productservice
1 expedition TV
any suggestions on how to do it.
PS-> for a product it can be several services and there may be several products for a ticket.Your XML file is not well formed at all (so many errors in there).
However, if you had a valid XML code, you could do something like that...
SQL> ed Wrote file afiedt.buf 1 with t as (select 1 as product_id, '
' as product_info from dual union all 2 select 2, ' ' from dual) 3 -- 4 -- end of test data 5 -- 6 select t.product_id, x.* 7 from t 8 ,xmltable('/ticketing/product' 9 passing xmltype(t.product_info) 10 columns product varchar2(10) path '/product/@name' 11 ,service varchar2(15) path '/product/productservice/@name' 12* ) x SQL> / PRODUCT_ID PRODUCT SERVICE ---------- ---------- --------------- 1 TV shipping 2 VCR delivered -
Need help with the port forwarding for a XBox remote Streaming
I have a router R6200v2 and need help with port forwarding.
I came across this set of instructions for setting up stream port forwarding XBox remotely from anywhere
http://kinkeadtech.com/2015/07/how-to-stream-Xbox-one-to-Windows-10-from-anywhere-with-Internet/
I have no idea when it comes to such things and I want to make sure I do it correctly without messing up my existing home network.
Port Forwarding and triggering Port pages setup look very different from what the guy uses. Can someone walk me through what I do to set up please?
Hi @varxtis,
You must enter them in the field for a start external Port and external completion Port. You will need to send individually except for the range of 49000-65000. The steps are as follows.
1. create a Service name (it could be something else that you cannot use the same service name twice. Ex. XBOX1, XBOX2 and so forth.)
2. Select the type of service (TCP, UDP or both)
3 entry 5050 times a start external Port and external endpoints.
4. Select the IP address of your XBOX.
5. Select apply.
6 do the same for other port numbers. To the beach, use 49000 for the external departure Port and for the external completion Port 65000.
Kind regards
Dexter
The community team
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get rid of the shadow of the legend in the tab control
Hello I use LV7.0 on W2K and have encountered a difficulty. Often when I need a text face before being modified programmatically, I'll put a control or the off indicator on the side (out of sight) and serve its legend of the label. It keeps me from
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Recently, I buy a scandisk 4 GB USB key. It came with secure access software. I failed and eventually remove the software. Then I downloaded the software to access secure on my USB key. I got the arch in place. Then I closed it down. Now, whene