What process in the database is high in the Oracle system resources

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• IOUtilities gives me an exception of the file system resources

  I wrote an application to analyze lyric, the premiere, I use IOUtilities.streamToBytes to convert the integer to a byte [] and crawled, but after reviewing some files (7-10), I got an error of 'Resource file system', I don't know why it happens, here is the code.

  private void parseFile(FileConnection LRC) throws IOException {
  
      byte[] LRC_byte = IOUtilities.streamToBytes(LRC.openInputStream());
      LRC.close();
  
      if (LRC_byte.length < 10) {
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          return;
      }
  
      String encoding = DEFAULT_ENCODING;
  
      if ((LRC_byte[0] == -2) && (LRC_byte[1] == -1)) {
          encoding = "UTF-16LE";
      } else if ((LRC_byte[0] == -1) && (LRC_byte[0] == -2)) {
          encoding = "UTF-16BE";
      } else if ((LRC_byte[0] == (byte) 0xEF) && (LRC_byte[1] == (byte) 0xBB)
              && (LRC_byte[2] == (byte) 0xBF)) {
          encoding = "UTF-8";
      }
  
      //
      // Do someting...
      //
  }
  

  But after I change the IOUtilities.streamToBytes of inputstream, below is the code

  private void parseFile(FileConnection LRC) throws IOException {
  
      InputStream input = LRC.openInputStream();
      input.mark(3);
      byte[] encode = new byte[3];
      input.read(encode);
      input.reset();
  
      String encoding = DEFAULT_ENCODE;
  
      if ((encode[0] == -2) && (encode[1] == -1)) {
          encoding = "UTF-16LE";
      } else if ((encode[0] == -1) && (encode[1] == -2)) {
          encoding = "UTF-16BE";
      } else if ((encode[0] == (byte) 0xEF) && (encode[1] == (byte) 0xBB)
              && (encode[2] == (byte) 0xBF)) {
          encoding = "UTF-8";
      }
  
      //
      // Do someting...
      //
  
      input.close();
      LRC.close();
  }
  

  Now, everything works fine, I really donnot know why version 1 do not work, but version 2 works fine.

  Why? What is the problem with the first version? It takes a day to find it.

  It seems that you do not close the input stream in the first version of the code. Maybe it's the reason.

• in the oracle system date format

  Hi expert,
  
  in our oracle date format is "mm/dd/yy", here in an application table, we got more fields:
  
  ACCOUTING_FROM_DATE ACCOUTING_TO_DATE
  
  28/1/13 1 / 01 / 00
  
  could you please tell me what date is ' 01/01/00 '?
  
  and how to change the format of oracle data without affecting the system?
  
  Thank you very much

  1001197 wrote:
  Hi expert,

  in our oracle date format is "mm/dd/yy", here in an application table, we got more fields:

  ACCOUTING_FROM_DATE ACCOUTING_TO_DATE

  28/1/13 1 / 01 / 00

  could you please tell me what date is ' 01/01/00 '?

  No.; This is one of the reasons why the 2-digit years are a bad idea.

  and how to change the format of oracle data without affecting the system?

  To change the default format for all DATEs in your session:

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  This affects only your session; It will not affect other users in other sessions.

  Regardless of which is the default format, you can display a single DATE in a format with TO_CHAR

  SELECT     TO_CHAR ( accouting_to_date
            , 'fmMM/fmDD/YYYY'
            )          AS a_to
  FROM    table_x
  ;
  

• Insufficient system resources exist to complete the API.

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  http://support.Microsoft.com/kb/909095

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• Need to find the Oracle Session with high CPU consumption and process of the BONE

  Hello
  
  I find the high use of the processor by the command "prstat. The host is running Solaris 5.10 64-bit with a database of Oracle 10.2.0.4.
  
  The grid, the high command is not available. What is the best way to find Oracle sessions using high processor and operating system processes.
  
  Thanks in advance.
  
  -Asif

  naveed27c wrote:
  Thanks, Justin.

  I have alread think SQL from Google. Now the problem is that I find the process of operating system level of Solaris.

  You can join V$ SESSION on the SID. The column PROCESS in V$ SESSION is the ID of the client operating system process.

  Justin