Why menu back to the previous screen?

Tried LLA curs OPS behavior in all applications.

What version of ATV do you have? See identify your model of Apple TV - Apple Support so uncertain. You sig says Apple TV 2, but I suspect that you have ATV 4, the current model. If so, the Menu button normally you brings to the menu bar, then you swipe left/right on the remote control to reach the other forms in the application. If you don't see the menu bar, check your TV size setting.

Tags: Apple TV

Similar Questions

  • pushed single screen several times on display battery but can not go back to the previous screen again by clicking on "back" to come to the first screen button

    Hi all

    There is a screen with meter as label, datefield and objectchoicefield in the menu drop down and add and go button, this screen is pushed repeatedly on display battery until the meter is new. But when I try to go back to the previous screen, there is problem normally by substituting the onClose() method you can pop current screen and can get the previous screen, using getActiveScreen() and then push it again if you do not override os onClose() automatically do it for you.

    But in above case when I click on the button "back" or screen previous override onclose and push, I see my first screen I wanted my current screen with the counter that is if active screen is having against label like new if I press the "back" button, it should display screen with the meter only eight and so on.

    Can someone please help me solve this problem.

    Thanks Peter for you answer, actually used function for pushscreen on stach display that was written by someone else, when I looked carefully there condtion as below,

    if (activeScreen != null) {
     Class screenClass =activeScreen.getClass();
        if (screen.getClass().equals(screenClass)) {
                        UiApplication.getUiApplication().popScreen(activeScreen);
        }
    }
    

    It's actually the previous screen of poping before push the screen from the class were same, just commented and everything works, even if you do not override onClose and press return, it will automatically displays the previous screen.

  • Cannot navigate back to the previous screen (screen cannot be closed with the ESC key)

    Hi all

    I create simple BB app with eclipse jde 4.6.1, here the code example.

    class myApplication extends UiApplication
    {
        // applicatione entry point
        public static void main(String[] args)
        {
            // create an instance of our app
            myApplication theApp = new myApplication();
            // "run" the app
            theApp.enterEventDispatcher();
        }
        // app constructor
        public myApplication()
        {
         myScreen screen = new myScreen();
            pushScreen(screen);
        }
    }
    

    where my screen is like this

    public class myScreen extends MainScreen implements ListFieldCallback {
    private Vector menu;
    private ListField menuList;
    private MenuItem menuItem = new MenuItem("Details",100,10){
    public void run(){
    int index = menuList.getSelectedIndex();
    if (index == 1){
    Dialog.alert("list  "+index+" selected");
    }
    }
    };
    public void drawListRow(ListField listField, Graphics graphics, int index,
    int y, int width) {
         ListField menulist = (ListField) listField;
         MenuRowManager rowManager = (MenuRowManager)menu.elementAt(index);
         rowManager.drawRow(graphics, 0, y, width, menulist.getRowHeight());
    }
    
    public myScreen(){
    super(DEFAULT_MENU|DEFAULT_CLOSE);
    setTitle(new LabelField("myScreen", LabelField.USE_ALL_WIDTH | DrawStyle.HCENTER));
    
    this.addMenuItem(menuItem);
    createListMenu();
    }
    
    public void createListMenu(){
    menu = new Vector();
    menuList = new ListField(){
    protected boolean keyChar(char key, int status, int time){
    if (key == Characters.ENTER){
    // open next window
    int index = getSelectedIndex();
    switch (index){
    case 0: //
    break;
    case 1: //
    break;
    case 2: //
    break;
    case 3: //
    break;
    default: // about
    break;
    }
    }
    return true;
    }
    };
    menuList.setCallback(this);
    menuList.setRowHeight(60);
    menuList.setBackground(BackgroundFactory.createSolidBackground(Color.BLACK));
    
    // first item
    BitmapField mIcon = new BitmapField(Bitmap.getBitmapResource("image1.png"));
    LabelField lblM = new LabelField ("First list item", DrawStyle.LEFT);
    lblM.setFont(Font.getDefault().derive(Font.BOLD));
    MenuRowManager menuM = new MenuRowManager();
    menuM.add(mIcon);
    menuM.add(lblM);
    menu.addElement(menuM);
    
    // 2nd item
    BitmapField tIcon = new BitmapField(Bitmap.getBitmapResource("image2.png"));
    LabelField lblT = new LabelField("Theater Near Me", DrawStyle.LEFT);
    lblT.setFont(Font.getDefault().derive(Font.BOLD));
    MenuRowManager menuT = new MenuRowManager();
    menuT.add(tIcon);
    menuT.add(lblT);
    menu.addElement(menuT);
    
    add(menuList);
    }
    
    }
    

    and the definition of menuRowManager is like that

    public class MenuRowManager extends Manager
    {
        public MenuRowManager()
        {
            super(0);
        }
    
        // Causes the fields within this row manager to be layed out then
        // painted.
        public void drawRow(Graphics g, int x, int y, int width, int height)
        {
            // Arrange the cell fields within this row manager.
            layout(width, height);
    
            // Place this row manager within its enclosing list.
            setPosition(x, y);
    
            // Apply a translating/clipping transformation to the graphics
            // context so that this row paints in the right area.
            g.pushRegion(getExtent());
    
            // Paint this manager's controlled fields.
            subpaint(g);
    
            g.setColor(0x00CACACA);
            g.drawLine(0, 0, getPreferredWidth(), 0);
            //g.drawLine(10, 0, 10, getPreferredHeight());
    
            // Restore the graphics context.
            g.popContext();
        }
    
        // Arranges this manager's controlled fields from left to right within
        // the enclosing table's columns.
        protected void sublayout(int width, int height)
        {
            // set the size and position of each field.
            int fontHeight = Font.getDefault().getHeight();
            int preferredWidth = getPreferredWidth();
    
            // start with the Bitmap Field of menu icon
            Field field = getField(0);
            layoutChild(field, 48, 48);
            setPositionChild(field, 0, 6);
    
            // set the menu title label field
            field = getField(1);
            layoutChild(field, preferredWidth - 16, fontHeight+1);
            setPositionChild(field, 55, 30-fontHeight/2);
    
            setExtent(preferredWidth, getPreferredHeight());
        }
    
        // The preferred width of a row is defined by the list renderer.
        public int getPreferredWidth()
        {
            return Graphics.getScreenWidth();
        }
    
        // The preferred height of a row is the "row height" as defined in the
        // enclosing list.
        public int getPreferredHeight()
        {
            return 60;
        }
    }
    

    the problem is, when the first screen showed (pushed), I cannot "navigate back (close) the screen with ESC, won't my code?" Am I missing something here?

    Thanks in advance

    You want to substitute keyChar() into your custom domain.

    Don't forget that you must re - delegate all keystrokes that you do not consume.

  • How to navigate to the previous screen (as opposed to the previous page)?

    Hello

    I looked in the manual online where the back to the previous screen"" button. I can't find that, but I saw that "previous screen" is listed in the list of keyboard shortcuts. The keystrokes for this command are separate from those to go to the previous page. If I navigate to a page via a hyperlink, I want a sequence of button or the button to return to the page containing the link hypertext, not the previous page.

    Here are the shortcuts:

    Previous screen: PG. Prev or shift + enter

    Previous page: arrow left or Ctrl + PG. Prev

    So on page 41 in my document, I have a list of hyperlinks to the pages in the section. I click on one of the links and it takes me on page 77. Now, I want to go back to the list of topics, so I tried all four of the keyboard shortcuts, and they all were doing exactly the same thing: they all went to page 76. How can I navigate directly to the list on page 41?

    Application: Acrobat DC STD, bought in 2015.

    OS: Windows 10

    Thank you

    Joyce

    It's the "previous view":

  • The back button often responds with a drop down menu of the story rather than simply go back to the previous page. There used to be a small arrow for that, why did you do that?

    The back button often responds with a drop down menu of the story rather than simply go back to the previous page. There used to be a small arrow for that, why did you do that?

    When I left click on the back instead of the browser navigation back button, I go almost every time to get the list of previous browsing history or it will just doing nothing until I click on the new button. The history of combination of button "return" rather than a separate between the historical click of the buttons box is the problem. Combined with my arthritic fingers of aging that is. If I was as fast as I used to be I guess it wouldn't be a problem. I liked the separate history area. This action combination navigation / buttons story scenario is problematic. I'm fairly certain that if I find it quite disturbing to bring to your attention that there are others (old beards) in the same boat I am.

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    D

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    You must not yet be aware of the gesture «back» It goes like this, the straight shot, left on the gesture area (the area below the screen, left and right of the Center button). You enter only at half way, and you can start on the right edge, or just left of the Center button.

    Become very familiar with this gesture he used all the time.

    There is also an option that you can activate by allowing a complete sweep in any direction will take you to the adjacent open card. I think that this gesture is set to off by default.

    Good luck.

    PS - In the application of Navigation of Sprint, I can't seem to leave the navigation once it starts. In other words, you must close the application and open again to define a new topic. I know two ways to issue the command to stop the navigation, but none of them work effectively.

    Message edited by Mrolesen on 21/06/2009 20:17
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