Windows analytical range


CREATE TABLE employee (
employee_id NUMBER,
first_name VARCHAR2(30),
last_name VARCHAR2(30),
hire_date DATE,
salary NUMBER(9,2),
manager NUMBER,
department_id NUMBER
);

CREATE TABLE department (
department_id NUMBER,
name VARCHAR2(30),
location VARCHAR2(30)
);

CREATE SEQUENCE employee_seq; 

CREATE SEQUENCE department_seq;

REM These sequences will be used eventually. For now, in order for your output to match that shown in the series articles'' examples,
REM please insert literal number values into the ID columns of the tables as shown below.

REM 8) Insert records into the employee table.

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (28, 'Emily', 'Eckhardt', to_date('07-JUL-2004', 'DD-MON-YYYY'), 100000, NULL, 10);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (37, 'Frances', 'Newton', to_date('14-SEP-2005', 'DD-MON-YYYY'), 75000, NULL, NULL);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (1234, 'Donald', 'Newton', to_date('24-SEP-2006', 'DD-MON-YYYY'), 80000, 28, 10);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (7895, 'Matthew', 'Michaels', to_date('16-MAY-2007', 'DD-MON-YYYY'), 70000, 28, 10);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6567, 'Roger', 'Friedli', to_date('16-MAY-2007', 'DD-MON-YYYY'), 60000, 28, 10);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6568, 'Betsy', 'James', to_date('16-MAY-2007', 'DD-MON-YYYY'), 60000, 28, 10);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6569, 'michael', 'peterson', to_date('03-NOV-2008', 'DD-MON-YYYY'), 90000, NULL, 20);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6570, 'mark', 'leblanc', to_date('06-MAR-2009', 'DD-MON-YYYY'), 65000, 6569, 20);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6571, 'Thomas', 'Jeffrey', to_date('27-FEB-2010', 'DD-MON-YYYY'), 300000, null, 30);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6572, 'Theresa', 'Wong', to_date('27-FEB-2010 9:02:45', 'DD-MON-YYYY HH24:MI:SS'), 70000, 6571, 30);

INSERT INTO employee (employee_id, first_name, last_name, hire_date, salary, manager, department_id)
  VALUES (6573, 'Lori', 'Dovichi', to_date('07-JUL-2011 8:31:57', 'DD-MON-YYYY HH24:MI:SS'), null, 28, 10);

REM 9) Insert records into the department table.


INSERT INTO department (department_id, name, location)
  VALUES (10, 'Accounting', 'LOS ANGELES');

INSERT INTO department (department_id, name, location)
  VALUES (20, 'Payroll', 'NEW YORK');

INSERT INTO department (department_id, name, location)
  VALUES (30, 'IT', 'WASHINGTON DC');

REM 10) Save your newly created records to the database.

Commit;

I refer the below url

SQL 101: A window on the world of analytical functions

I cannot understand the code below

{code}

Select first_name last_name, department_id, hire_date, salary,.

SUM (salary)

COURSES (PARTITION BY department_id ORDER BY hire_date

RANGE EARLIER 90) department_total

the employee

order by department_id, hire_date;

{code}

Yes, there is an explanation for 'also notes that in the Department 30, two employees'... .but miss me something here for 5-6 hours
I've read the two paragraphs next to the box of big 'next steps' several times (at least 15)

Please explain the difference between 190000 in department_id 10 which shows as expected (3 times) and this department_id = 20 that does not display the sum of wages as Department 10

Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Prod

PL/SQL Release 10.2.0.1.0 - Production

"CORE 10.2.0.1.0 Production."

AMT for 32-bit Windows: Version 10.2.0.1.0 - Production

NLSRTL Version 10.2.0.1.0 - Production

Thank you

This is because of the timestamp... change your query on this subject - and you can 'see' what did Oracle:

select employee_id, last_name, first_name, department_id, hire_date, salary,
      SUM (salary)
         OVER (PARTITION BY department_id ORDER BY (hire_date)
            RANGE 90 PRECEDING) department_total,
      FIRST_VALUE(employee_id)
         OVER (PARTITION BY department_id ORDER BY (hire_date)
            RANGE 90 PRECEDING) first_emp,
      LAST_VALUE(employee_id)
         OVER (PARTITION BY department_id ORDER BY (hire_date)
            RANGE 90 PRECEDING) last_emp
from employee
order by department_id, hire_date;

Header 1
EMPLOYEE_ID, LAST_NAME FIRST_NAME DEPARTMENT_ID HIRE_DATE SALARY DEPARTMENT_TOTAL FIRST_EMP LAST_EMP ----------- ------------------------------ ------------------------------ ------------- --------- ---------- ---------------- ---------- ---------- Eckhardt Emily 10 7 July 28 04 100000 100000 28 28 Donald 10-24 - SEP - 06 80000 80000 1234 1234 1234 Newton 6567 Friedli Roger 10 May 16 07 60000 190000 6567 7895 6568 James Betsy 10 May 16 07 60000 190000 6567 7895 7895 Michaels Matthew 10 May 16 07 70000 190000 6567 7895 6573 Dovichi Lori 10 7 July 11-6573-6573 6569 peterson michael 20 3 November 08 90000 90000 6569 6569 6570 leblanc Marc 6 March 20 09 65000 65000 6570 6570 6571 Jeffrey Thomas 30 27 February 10 300000 300000 6571 6571

Header 1

EMPLOYEE_ID, LAST_NAME FIRST_NAME DEPARTMENT_ID HIRE_DATE SALARY DEPARTMENT_TOTAL FIRST_EMP LAST_EMP

----------- ------------------------------ ------------------------------ ------------- --------- ---------- ---------------- ---------- ----------

Eckhardt Emily 10 7 July 28 04 100000 100000 28 28

Donald 10-24 - SEP - 06 80000 80000 1234 1234 1234 Newton

6567 Friedli Roger 10 May 16 07 60000 190000 6567 7895

6568 James Betsy 10 May 16 07 60000 190000 6567 7895

7895 Michaels Matthew 10 May 16 07 70000 190000 6567 7895

6573 Dovichi Lori 10 7 July 11-6573-6573

6569 peterson michael 20 3 November 08 90000 90000 6569 6569

6570 leblanc Marc 6 March 20 09 65000 65000 6570 6570

6571 Jeffrey Thomas 30 27 February 10 300000 300000 6571 6571

6572 Wong Theresa 30 27 February 10 70000 370000 6571 6572

Frances Newton 37 14-SEP-05 75000 75000 37 37

11 selected lines.

trunc the timestamp off the coast... and it works as you want:

select employee_id, last_name, first_name, department_id, hire_date, salary,
      SUM (salary)
         OVER (PARTITION BY department_id ORDER BY trunc(hire_date)
            RANGE 90 PRECEDING) department_total,
      FIRST_VALUE(employee_id)
         OVER (PARTITION BY department_id ORDER BY trunc(hire_date)
            RANGE 90 PRECEDING) first_emp,
      LAST_VALUE(employee_id)
         OVER (PARTITION BY department_id ORDER BY trunc(hire_date)
            RANGE 90 PRECEDING) last_emp
from employee
order by department_id, hire_date;

Header 1
EMPLOYEE_ID, LAST_NAME FIRST_NAME DEPARTMENT_ID HIRE_DATE SALARY DEPARTMENT_TOTAL FIRST_EMP LAST_EMP ----------- ------------------------------ ------------------------------ ------------- --------- ---------- ---------------- ---------- ---------- Eckhardt Emily 10 7 July 28 04 100000 100000 28 28 Donald 10-24 - SEP - 06 80000 80000 1234 1234 1234 Newton 6567 Friedli Roger 10 May 16 07 60000 190000 6567 7895 6568 James Betsy 10 May 16 07 60000 190000 6567 7895 7895 Michaels Matthew 10 May 16 07 70000 190000 6567 7895 6573 Dovichi Lori 10 7 July 11-6573-6573 6569 peterson michael 20 3 November 08 90000 90000 6569 6569 6570 leblanc Marc 6 March 20 09 65000 65000 6570 6570 6571 Jeffrey Thomas 30 27 February 10 300000 300000 6571 6571 6572 Wong Theresa 30 27 February 10 70000 370000 6571 6572 Frances Newton 37 14-SEP-05 75000 75000 37 37 11 selected lines.

Header 1

EMPLOYEE_ID, LAST_NAME FIRST_NAME DEPARTMENT_ID HIRE_DATE SALARY DEPARTMENT_TOTAL FIRST_EMP LAST_EMP

----------- ------------------------------ ------------------------------ ------------- --------- ---------- ---------------- ---------- ----------

Eckhardt Emily 10 7 July 28 04 100000 100000 28 28

Donald 10-24 - SEP - 06 80000 80000 1234 1234 1234 Newton

6567 Friedli Roger 10 May 16 07 60000 190000 6567 7895

6568 James Betsy 10 May 16 07 60000 190000 6567 7895

7895 Michaels Matthew 10 May 16 07 70000 190000 6567 7895

6573 Dovichi Lori 10 7 July 11-6573-6573

6569 peterson michael 20 3 November 08 90000 90000 6569 6569

6570 leblanc Marc 6 March 20 09 65000 65000 6570 6570

6571 Jeffrey Thomas 30 27 February 10 300000 300000 6571 6571

6572 Wong Theresa 30 27 February 10 70000 370000 6571 6572

Frances Newton 37 14-SEP-05 75000 75000 37 37

11 selected lines.

Tags: Database

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Range and lines
Hi people,

I never used beach or front lines in analytical functions. I took the time to learn a little about them, but can't understand why would you need to use it? Most of the things that I needed I got in advance or delay functions. So what is the problem with window functions? Where are they useful?

Best regards
Igor
Hi, Igor,.

Igor S. wrote:
Hi people,

I never used beach or front lines in analytical functions. I took the time to learn a little about them, but can't understand why would you need to use it? Most of the things that I needed I got in advance or delay functions. So what is the problem with window functions? Where are they useful?

What do you mean by "window function"?
That commonly means the functions that allow you to specify a window of consecutive rows in your data set and the function will operate on the lines within this window. In this sense, the more analytical functions are functions of the window.

The default window's RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW. You only need to specify a window clause (in other words, the BEACH or the LINES) If you want to replace.

For example, the following query shows the weighted average of the table scott.emp and the number of treatments that contribute to this average, two different ways. The cnt_sal and avg_sal columns use the windowing by default, so the numbers on each line to include this line itself and all the previous lines (where hiredate determines what is earlier). The cnt_60 and avg_60 columns include only 60 days, not including the line itself. Note that sometimes there are 0 rows in this window.
```
SELECT       ename
,       hiredate
,       sal
,       COUNT (sal) OVER ( ORDER BY  hiredate )     AS cnt_sal
,       AVG (sal)   OVER ( ORDER BY  hiredate     )     AS avg_sal
,       COUNT (sal) OVER ( ORDER BY  hiredate
                            RANGE BETWEEN  61 PRECEDING
                            AND          1 PRECEDING
                     )                    AS cnt_sal_60
,       AVG (sal)   OVER ( ORDER BY  hiredate
                            RANGE BETWEEN  61 PRECEDING
                            AND          1 PRECEDING
                     )                    AS avg_sal_60
FROM      scott.emp
ORDER BY  hiredate
;
```
Note that the formula of cnt_sal is exactly the same as the cnt_sal formula, except that cnt_sal_60 specifies a RANGE. It goes the same for avg_sal and avg_sal_60.
Output:
```
ENAME      HIREDATE         SAL    CNT_SAL    AVG_SAL CNT_SAL_60 AVG_SAL_60
---------- --------- ---------- ---------- ---------- ---------- ----------
SMITH      17-DEC-80        800          1        800          0
ALLEN      20-FEB-81       1600          2       1200          0
WARD       22-FEB-81       1250          3 1216.66667          1       1600
JONES      02-APR-81       2975          4    1656.25          2       1425
BLAKE      01-MAY-81       2850          5       1895          1       2975
CLARK      09-JUN-81       2450          6     1987.5          1       2850
TURNER     08-SEP-81       1500          7 1917.85714          0
MARTIN     28-SEP-81       1250          8   1834.375          1       1500
KING       17-NOV-81       5000          9 2186.11111          1       1250
JAMES      03-DEC-81        950         11 2147.72727          1       5000
FORD       03-DEC-81       3000         11 2147.72727          1       5000
MILLER     23-JAN-82       1300         12 2077.08333          2       1975
SCOTT      19-APR-87       3000         13 2148.07692          0
ADAMS      23-MAY-87       1100         14 2073.21429          1       3000
```
Published by: Frank Kulash on April 3, 2013 09:16
Example added scott.emp

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Hello

You are looking for an application that will process and return only the many lines that add up to a special value on a column value.

for example

ID name date_joined allocated salary

-- ------ --------------- ------- ------------

1 Tom January 1, 2010 1000 5000

Dave 2 3000 5000 February 1, 2010

3 Cindy 1000 5000 01-apr-2010

4 Ian 01-mar-2010 1000 5000

5 Matt 10 -jan-2010 1000-5000

Return the lines where wages adding upto or beyond the value allocated to 5000, order by date_joined or more former employee first.

The query should return:

ID name date_joined allocated salary

-- ------ --------------- ------- ------------

1 Tom January 1, 2010 1000 5000

2 Matt 10 -jan-2010 1000-5000

3 Ian 01-mar-2010 1000 5000

Dave 4 3000 5000 February 1, 2010

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Thank you.

Thanks for the input guys.

Here, the ask is:

1. how to treat only as lines that satisfy the "allocated" value, without treatment of all lines.

> Thanks to Jarkko year John for the right direction.

> RanitB thank you for your approach to the application of the model, I am not well versed with model query that I'll get to. But for the moment its not useful for me.

2. to get only as much lines that are either less than or equal to 'assigned' value or satisfy "allocated", from less than "attributed" just beyond "allocated".

(Sorry for the language, if its not very clear, I do not know how this fits better, following example should help demonstrate).

I came up with the following code, although there could be best way to do it, I hope to see someone.

{code: sql}

create table t:

Select object_name, join_dt, the salary of 1000 last_ddl_time, allocated 5500

of object;

Select

/ * gather_plan_statistics * / *.

(select

object_name, join_dt, salary, allocated, sofar, lag (sofar, 1, 0) over (order by join_dt) lag_sofar

(select

object_name, join_dt, salary, allocated,

Salary on sofar (order by no_lig)

(select object_name, join_dt, salary, allocated, row_number() on no_lig (order of join_dt) t) t - must do it has several join_dt even inputs (objects have same time ddl)

)

where

allocated > lag_sofar;

OBJECT_NAME	JOIN_DT	SALARY	ALLOCATED	SOFAR	LAG_SOFAR
SDO_TOPO_GEOMETRY	17 JULY 02	1000	5500	1000	0
SI_AVERAGECOLOR	18 JULY 02	1000	5500	2000	1000
SI_COLORHISTOGRAM	18 JULY 02	1000	5500	3000	2000
SI_POSITIONALCOLOR	18 JULY 02	1000	5500	4000	3000
SI_FEATURELIST	18 JULY 02	1000	5500	5000	4000
SI_STILLIMAGE	18 JULY 02	1000	5500	6000	5000

{code}

Sorry for the bad formatting, I tried couple of code integration/formatting of tags, but could not get formatting just as many of you have done above.

Can someone point me on the document where the tags for this type of formatting is present?

For now I am marking my question as answered with my own response and that of the other answers as useful.

If I get a better approach/solution I would mark it as correct.

Why I said no e-mail program when you try to send a scanned document

Just bought the new laptop HP Pavilion and new HP printer all in one.

First of all, I'm stuck with Windows 8 (horror! after XL)

In addition, never used a scanner before.

Configure printer OK. Not sure where the scanned document should go in 'Library', but managed to find a picture I had scanned.

When you want to send the picture, I get a message that basically said...

No e-mail program to perform the requested action. Install an e-mail program or, if you have already installed, create an association in the default programs control panel...

as far as I can see, in the default programs control panel, when I click on the EMAIL he just said Microsoft windows. Cannot change, delete, replace... cannot do anything.

I don't know that I'm being stupid. I have no one to ask. I am nearly 70, do not understand half of what is all about. Can anyone help - in understandable English, please.

Thank you

Just bought the new laptop HP Pavilion and new HP printer all in one.

First of all, I'm stuck with Windows 8 (horror! after XL)

In addition, never used a scanner before.

Configure printer OK. Not sure where the scanned document should go in 'Library', but managed to find a picture I had scanned.

When you want to send the picture, I get a message that basically said...

No e-mail program to perform the requested action. Install an e-mail program or, if you have already installed, create an association in the default programs control panel...

as far as I can see, in the default programs control panel, when I click on the EMAIL he just said Microsoft windows. Cannot change, delete, replace... cannot do anything.

I don't know that I'm being stupid. I have no one to ask. I am nearly 70, do not understand half of what is all about. Can anyone help - in understandable English, please.

Thank you

Hello

If you are simply trying to select an image file, right click and select send to/recipient of the message, it will not work if you are using the default Windows 8 App Mail.

You must have a Desktop Email program is installed to do this, such as Windows Live Mail, which is part of the Windows Essentials range.

Windows Live Mail - free

http://Windows.Microsoft.com/en-us/Windows-Live/Essentials-other-programs

To attach the image using Windows 8 Mail App, open the Mail application and select new email message.

Click on the paper clip icon in top/right (attachments).

Navigate to the folder where the image is stored and Select the file.

Click the button to join at the bottom of the screen.

This will attach the file to the new email.

Let us know if you have any other questions.

Concerning

CQL join with 2-channel time-stamped application
Hello

I am trying to join the two channels that are time-stamped application, both are total-ordered. Each of these 2 channels retrieve data in a table source.

The EPN is something like this:

Table A-> processor A-> A channels->
JoinProcessor-> channel C
Table B-> processor B-> B-> channel

My question is, how are "simulated" in the processor events? The first event that happens in any channel and the Treaty as the timestamp, starting point get it? Or fact block treatment until all channels have published its first event?

Channel A
--------------
timestamp
1000
6000

Channel B
-------------
timestamp
4000
12000

Channel B arrived both of system a little later due to the performance of the db,

I would like to know if the following query won't work, whereas I would like to match the elements of channel A and B which are 10 sec window and out matches once in a stream.

The following query is correct?

Select a.*
A [here], B [slide 10 seconds of range 10 seconds]
WHERE a.property = b.property

I'm having a hard time to produce results of the join well I checked the time stamp of application on each stream and they are correct.
What could possibly cause this?

Thank you!

Published by: Jarell March 17, 2011 03:19

Published by: Jarell March 17, 2011 03:19
Hi Jarrell,

I went through your project that had sent you to Andy.

In my opinion, the following query should meet your needs-

ISTREAM (select t.aparty, TrafficaSender [range 15 seconds] t.bparty t, CatSender [range 15 seconds] c where t.aparty = c.party AND t.bparty = c.bparty)

I used the test of CatSender and TrafficaSender data (I show only the part bparty fields and here and that too as the last 4 characters of each)

TrafficaSender (, bparty)
At t = 3 seconds, (9201, 9900)
At t = 14 seconds (9200, 9909)
To t = 28 seconds (9202, 9901)

CatSender (, bparty)
At t = 16 seconds, (9200, 9909)
At t = 29 seconds (9202, 9901)

For query q1 ISTREAM = (select t.aparty, TrafficaSender [range 15 seconds] t.bparty t, CatSender [range 15 seconds] c where t.aparty = c.party AND t.bparty = c.bparty)

the results were-
At t = 16 seconds, (9200, 9909)
At t = 29 seconds (9202, 9901)

and it seems OK for me

Please note the following-

(1) in the query above I do NOT require a "abs1(t.ELEMENT_TIME-c.ELEMENT_TIME)".<= 15000"="" in="" the="" where="" clause.="" this="" is="" because="" of="" the="" way="" the="" cql="" model="" correlates="" 2="" (or="" more)="" relations="" (in="" a="" join).="" time="" is="" implicit="" in="" this="" correlation="" --="" here="" is="" a="" more="" detailed="">

In the above query, either W1 that designating the window TrafficaSender [range 15] and W2 means the CatSender [range 15] window.

Now both W1 and W2 are evaluated to CQL Relations since in the CQL model WINDOW operation over a Creek gives a relationship.

Let us look at the States of these two relationships over time

W1 (0) = W2 (0) = {} / * empty * /.
... the same empty up to t = 2
W1 (3) = {(9201, 9900)}, W2 (3) = {}
same content for W1 and W2 until t = 13
W1 (14) = {9201 (9900) (9200, 9909)}, W2 (14) = {}
same content at t = 15
W1 (16) = {9201 (9900) (9200, 9909)}, W2 (16) = {(9200, 9909)}
same content at t = 17
W1 (18) = {(9200, 9909)}, W2 (18) = {(9200, 9909)}
same content at up to t = 27
W1 (28) = {(9200, 9909), (9202, 9901)}, W2 (28) = {(9200, 9909)}
W1 (29) = {(9202, 9901)}, W2 (29) = {(9200, 9909), (9202, 9901)}

Now, the result.
Let R = select t.aparty, TrafficaSender [range 15 seconds] t.bparty t, CatSender [range 15 seconds] c where t.aparty = c.party AND t.bparty = c.bparty

It is the part of the application without the ISTREAM. R corresponds to a relationship since JOINING the 2 relationships (W1 and W2 in this case) that takes a relationship according to the CQL model.

Now, here's the most important point about the correlation in the JOINTS and the implicit time role. R (t) is obtained by joining the (t) W1 and W2 (t). So using this, we must work the content of R over time

R (0) = JOIN of W1 (0), W2 (0) = {}
the same content up to t = 15, since the W2 is empty until W2 (15)
R (16) = JOIN of W1 (16), W2 (16) = {(9200, 9909)}
same content up to t = 28, even if at t = 18 and t = 28 W1 changes, these changes do not influence the result of the JOIN
R (29) = JOIN of W1 (29), W2 (29) = {(9202, 9901)}

Now the actual query is ISTREAM (R). As Alex has explained in the previous post, ISTREAM leads a stream where each Member in the difference r (t) - R (t-1) is associated with the t. timestamp applying this to R above, we get

R (t) - R (t-1) is empty until t = 15
(16) R - R (16 seconds - 1 nanosecond) = (9200, 9909) associated with timestamp = 16 seconds
R (t) - R (t-1) is again empty until t = 29
(29) R - R (29 seconds - 1 nanosecond) = (9202, 9901) associated with timestamp = 29 seconds

This explains the output

Problem with the RANGE Windows in the analytical functions
Hello
I have a table what abc described as

SQL > desc abc;
Name Null? Type
----------------------------------------- -------- ----------------------------
ID VARCHAR2 (10)
NAME VARCHAR2 (20)
NUMBER VALUE (10)

I'm a little confused by the behavior of writing SQl query below.

Select ID, NAME, VALUE, SUM (VALUE) MORE (sorting BY ID of PARTITION INTERVAL value BETWEEN 2 PREVIOUS and 2 that follows) one of ABC;

The result is
NAME ID VALUE HAS
---------- -------------------- ---------- ----------
BEN 1 4 a1
BEN 3 13 c3
BEN 4 12 d4
BEN 12 5 e5
BEN 17 17 b2
TAB 11 11 a1
TAB c3 20 20
B2 100 100 TAB

I correctly get the values for the first partition of "BEN". But could you please explain the values that are to come in the field has for the second partition of the "LEG"?
It isn't give the sum of the beach, instead its just give the filed value.

Thanks in advance.

Kind regards
Abdoulaye

HP 1200dtwn printer range: HP 1200 printer compatibility with Windows 7 and 10

A range of printers HP 1200dtwn manufactured in 2004 is compatible with my operating system to Windows 7 64 bit? What happens if I switch to Windows 10?

HP Laser printer 1200 series has drivers for WIN 7 through 10 WIN.

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