Add void partition on another column in oracle

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• Necessary to valuate the sequence in another column in oracle

  Hi all

  I have the sql like query below

  Select header_id, order_number of oe_order_headers_all.

  and that's how the display of the data

  heder_id order_number

  111 500001

  121 500400

  I need to display a different field with values of sequence like as below

  ID heder_id order_number

  1 111 500001

  2 121 500400

  so, how to get the sequence value in another column help me please on this.

  Thnaks

  You can use virtual ROWNUM

  Select rownum, header_id, order_number of oe_order_headers_all id

• Oracle 11.2 - perform parallel DML on a table that is not partitioned with LOB column

  Hello

  Since I wanted to demonstrate the new enhancements of Oracle 12 c on SECUREFICHIERS, I tried to use PDML declarations on a table that is not partitioned with LOB column, in Oracle 11 g and Oracle 12 c releases. The Oracle 11.2 SECUREFICHIERS and large objects Developer Guide January 2013 said clearly:

  Parallel execution of the following DML operations on tables with LOB columns is supported. These operations performed in parallel run only mode when it is run on a partitioned table. The DML statements on tables not partitioned with LOB columns continue to run in serial execution mode.

  • INSERT SELECT AS
  • CREATE TABLE AS SELECT
  • DELETE
  • UPDATE
  • MERGE (conditionally UPDATE and INSERT)
  • Multi-table INSERT

  So, I created and filled a simple table with a BLOB column:

  SQL> CREATE TABLE T1 (A BLOB);
  Table created.
  

  Then, I tried to see the execution of a parallel ABOLITION plan:

  SQL> EXPLAIN PLAN FOR
    2  delete /*+parallel (t1,8) */ from t1;
  
  Explained.
  

  SQL> select * from table(dbms_xplan.display);
  
  PLAN_TABLE_OUTPUT
  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
  Plan hash value: 3718066193
  
  -------------------------------------------------------------------------------------------------------
  | Id  | Operation             | Name     | Rows  | Cost (%CPU)| Time     |    TQ  |IN-OUT| PQ Distrib |
  -------------------------------------------------------------------------------------------------------
  |   0 | DELETE STATEMENT      |          |  2048 |     2   (0)| 00:00:01 |        |      |            |
  |   1 |  DELETE               | T1       |       |            |          |        |      |            |
  |   2 |   PX COORDINATOR      |          |       |            |          |        |      |            |
  |   3 |    PX SEND QC (RANDOM)| :TQ10000 |  2048 |     2   (0)| 00:00:01 |  Q1,00 | P->S | QC (RAND)  |
  |   4 |     PX BLOCK ITERATOR |          |  2048 |     2   (0)| 00:00:01 |  Q1,00 | PCWC |            |
  |   5 |      TABLE ACCESS FULL| T1       |  2048 |     2   (0)| 00:00:01 |  Q1,00 | PCWP |            |
  
  PLAN_TABLE_OUTPUT
  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
  -------------------------------------------------------------------------------------------------------
  
  Note
  -----
     - dynamic sampling used for this statement (level=2)
  

  And I ended up executing the statement.

  SQL> commit;
  Commit complete.
  
  SQL> alter session enable parallel dml;
  Session altered.
  
  SQL> delete /*+parallel (t1,8) */ from t1;
  2048 rows deleted.
  

  As we can see, the statement was executed in parallel:

  SQL> select * from v$pq_sesstat;
  
  STATISTIC                      LAST_QUERY SESSION_TOTAL
  ------------------------------ ---------- -------------
  Queries Parallelized                    1             1
  DML Parallelized                        0             0
  DDL Parallelized                        0             0
  DFO Trees                               1             1
  Server Threads                          5             0
  Allocation Height                       5             0
  Allocation Width                        1             0
  Local Msgs Sent                        55            55
  Distr Msgs Sent                         0             0
  Local Msgs Recv'd                      55            55
  Distr Msgs Recv'd                       0             0
  
  11 rows selected.
  

  Is this normal? It is not supposed to be supported on Oracle 11 g with no partitioned table containing the LOB column...

  Thank you for your help.

  Michael

  Hello

  The explain plan shows that only the query is run in parallel but not delete it.

  Concerning

  Maurice

• Add new partition

  Hello
  
  Oracle 11.2.0.1
  Windows
  
  I'll have a partitioned IOT, something like this:
  
  create table my_table)
  col1 number (10) not null,
  col2 varchar2 (7) not null,
  COL3 varchar2 (20) not null,
  COL4 varchar2 (20) not null,
  col5 varchar2 (20) not null,
  col6 date not null,
  col7 number 4 not null,.
  COL8 varchar2 (1) not null,
  VARCHAR2 (1) col9 not null,.
  primary key (col1, col2, col3, col4, col5, col6, col7, col8, col9)
  )
  index of the Organization
  partition by range (col3, col4 col5)
  (partition p1 values less than ('%', '%', '%'),)
  P2 partition of values less than ('b %', 'B %', 'B %'),
  P3 partition values less than ('%c', '%c', '%c'),
  PARTITION VALUES LESS THAN (MAXVALUE, MAXVALUE, MAXVALUE) p27)
  
  Now, I want to add new range partition on column col7. There is an index exists on col7 too, but given that the table is carrying about 200 million lines, only fixed whose index is not good, so I thought to add the same type of partition on col7. In col7 there is value of beach between 2000 and 2010 only.
  
  Well want to tell me how should I proceed to add the new partition on another column of ITO existing partitioned please.
  
  Thank you.

  It seems that you must start generic character. Given that, the table partitioning, or using regular index will help. Your only option if this is the case is to use Oracle Text.

  It seems strange that you really want to understand the generic nature of beginning. I know that when I'm looking for a person, usually at least the first part of the name or the name. It's pretty rare that someone looking for "Justin Cave" would be looking for 'stin' rather than 'Justin' or 'cellar '. If you actually store the name in a single column rather than having separate columns for first name, last name, etc., maybe you just need to review the model data to break the names, remove the wildcard queries early and then use an appropriate normal index.

  Justin

• Add column if the value in another column

  How can I add a column as column name 'YES_OR_NO.
  
  SELECT VALUE_ID IN THE TABLE TABLE_NAME
  
  VALUE_ID
  ---
  1
  2
  3
  4
  5
  
  Now, I want to create another column in the sql query called YES_OR_NO and that if there is a value in VALUE_ID then column YES_OR_NO must say 'YES' if there is no value in the column VALUE_ID of this line YES_OR_NO must say 'NO '.
  
  or just a way for her also to work would be to show this new column or not if a value in another column of table_name_2 (this would be ideal)
  If new column yes_or_no and fill by a Yes or a no if a value is found in another table

  Assuming that you are on a version that supports the CASE expression:

  SELECT VALUE_ID
        , case when VALUE_ID is null then 'NO' else 'YES' end as YES_NO
  FROM TABLE_NAME
  

• I have a column with two values, separated by a space, in each line. How to create 2 new columns with the first value in a column, and the second value in another column?

  I have a column with two values, separated by a space, in each line. How do I create 2 new columns with the first value in one column and the second value in another column?

  Add two new columns after than the original with space separated values column.

  

  Select cell B1 and type (or copy and paste it here) the formula:

  = IF (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')

  shortcut for this is:

  B1 = if (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')

  C1 = if (Len (a1) > 0, Member SUBSTITUTE (A1, B1 & "", ""), "")

  or

  the formula of the C1 could also be:

  = IF (Len (a1) > 0, RIGHT (A1, LEN (A1) −FIND ("", A1)), "")

  Select cells B1 and C1, copy

  Select cells B1 at the end of the C column, paste

• Cannot add a partition on my external hard drive

  When you try to add a partition to my 'Seagate Expansion Drive' HD post, I get "Partition failed with the error: change the requested target disk size or a related disk is too small." Please, try another drive or partition, or make a bigger change. "OS 10.9.5

  

  Here is the result of diskutil list:

  / dev/disk1

  #: NAME SIZE TYPE IDENTIFIER

  0: GUID_partition_scheme * TB 5.0 disk1

  1: EFI EFI 314,6 MB disk1s1

  2: Apple_HFS CHS MacBook Pro 809,4 GB disk1s2

  3: disk1s3 Apple_Boot Recovery 650.0 MB HD

  4: Apple_HFS TB Seagate Expansion Drive 4.1 disk1s4

  5: given Microsoft Basic W 61.4 GB disk1s5

  Again, try to divide up to disk1s4 into two partitions. Various attempts to size of the new partition does not work. Thanks for your help!

  In addition, the Windows partition will not rise. Any change in the partition scheme Gets the same error. I tried to delete the Windows partition to see if that was the issue.

• I need an html link tag in answers + concatenate with another column, so that the link may open the site with the countries

  Please share me your ideas for this problem

  in the responses, I need to add a link to HTML and parallel to concatenate it with another column

  example of think this link as https:\\google.com + another column (column for the google link concatenation)

  https:\\google.com + column country so that it can turn directly to page-> https:\\google.com\India

  so that helps me to access a particular site of my organization and opening of a given page

  Hi 3051369,

  Glad it worked.

  Could you please mark this question as answered?

  Thank you

  JeromeFr

• Copy data from one column to another column in the form of customization

  Hi all

  I need, it's that I need to copy the value of a column to another column.

  But the two columns are different from the TAB

  Who be used, please send me the code.

  Thank you

  And can you describe your condition more clearly?

  My question was... you try to copy the incident followed summary on behalf of the task? In this case, you will need to find the event that triggers ONCE you have entered your resume. Enter in the preview, select display custom events and see what events are triggered. These are the 'moments' that you can use to add additional programming.

• Column sum based on a single value of another column

  Hi all

  I've searched and searched, but just can't find if this is even possible, let alone how to do it.  What I'm trying to do, it's the sum of a column.  However, only summarize the results of this column if a specific value of another column is present.  So, for example, the following is a sample database entry:

  Rate of pay hours

  2.3                                  $14.00

  1.2                                  $14.00

  2.4                                  $12.50

  0.75                                $12.50

  So for that, I want the sum of hours worked column but only the sum of hours worked if the wage rate is $14.00 and $ 12.50.  Because these numbers are generated in a database (with the various people who enter multiple rates of pay), I won't be able to set the where statement to have a specific amount (since I don't know the specific amount each registrant), the amount must be a variable in the where the statement.  With MySQLI, I know not how to make the sum of hours worked, but I do not know how the sum of hours worked if and only if the line corresponds to the unique value in the rate column.

  Then have it automatically loop through and total hours worked for other unique values in the column salary rate.  Finally, out all unique values in the column rate in variables so that I can do the following for each game:

  $total1 = $total_hours1 * $wage_rate1
  $total2 = $total_hours2 * $wage_rate2
  $overall_total = $total1 + $total2
  

  where $wage_rate1 = $14.00 and $total_hours1 = 2.3 + 1.2: etc.

  Is it still possible?  If so, how?  If possible, can someone please let me know a good reference so I can learn how to be the best way to implement?

  Thank you

  So with that, I get the correct $final_total printed, but I still get the error, 'notice: Undefined variable: final_total. Why is it not defined, but prints the total exact? How to remove the error?

  You get this notice is because you use the assignment combined, operator that is normally used to add a value to a variable and assign the new value to it.

  $final_total += $total;

  is a shortcut for this:

  $final_total = $final_total + $total;

  The undefined $final_total is on the right side of the assignment operator. The first time through the loop, you add $total to a non-existent value. Because of the type of PHP juggling, this becomes:

  $final_total = 0 + $total;

  The next time the loop runs, $final_total has a value, so that you get the view variable not defined only once.

  To avoid advice, initialize $final_total to zero before the start of the loop.

  $final_total = 0;

  While ($row = {$sql-> fetch_array())}

• How add us partition on an existing table?

  Hi gurus,

  What would be the best way to add a partition to an existing table?

  Is there a simple documentation for example?

  Thank you

  What would be the best way to add a partition to an existing table?

  Is there a simple documentation for example?

  Was it something you were ask in an interview?

  You cannot add a partition to a table unless this table is a partitioned table.

  The table is already partitioned? If so, after the DDL.

  The Oracle documentation has examples of adding partitions to a table that is already partitioned

  Partition management

  Adding Partitions

  This section explains how to manually add partitions of a partitioned table and explains why partitions can be added specifically for partitioned more indexes.

  Adding a Partition to a partitioned Table range

  Use of the ALTER TABLE ... ADD PARTITION statement to add a new partition at the end 'high' (the point after the last existing partition). To add a partition at the beginning or in the middle of a table, use the SPLIT PARTITION clause.

• cannot add a partition

  Enterprise Linux Enterprise Linux Server 5.4 version (Carthage)
  2.6.18 - 164.el5PAE kernel on an i686
  
  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Production
  With partitioning, OLAP and Data Mining options
  
  When I tried to add a partition of a table of partitoned already
  He throws because of errors
  
  
  SQL > ALTER TABLE PR_PAYSLIP_T ADD PARTITION PAR_2012PAY the VALUES LESS THAN (TO_DATE('31-DEC-2012','DD-MON-YYYY')) TABLESPACE payer3;
  ALTER TABLE PR_PAYSLIP_T ADD PAR_2012PAY PARTITION VALUES LESS THAN (TO_DATE('31-DEC-2012','DD-MON-YYYY')) TABLESPACE PAYER3
  *
  ERROR on line 1:
  ORA-00604: an error has occurred at the SQL level 1 recursive
  ORA-20120: NO PERMISSION TO EDIT THIS TABLE
  ORA-06512: at line 9 level
  
  
  Please offer your suggestions.
  
  Sandra.

  ORA-20120 isn't a standard Oracle database error message: it is probably used by application code. Maybe you have a trigger on ALTER TABLE DDL?

• Delete based on another column dublicate records

  How can I remove duplicate records, based on another column.
  
  the table structure
  CREATE TABLE IA_EXPORT_LEVEL
  (
  A_NO VARCHAR2 (22 BYTE),
  IM VARCHAR2 (18 BYTE),
  ctn_level NUMBER (2)
  )
  
  reviews
  A_NO IM ctn_level
  
  S1 S1 1
  S1 M1 2
  S1 h1 3
  H2 S2 1
  S2 h2 2
  S3 h1 2
  S3 h1 3
  S4 h6 4
  S4 h6 5
  
  I want to delete all records other than the minimum value of the ctn_level
  
  output should like below
  S1 S1 1
  H2 S2 1
  S3 h1 2
  S4 h6 4
  
  Published by: OraFighter on December 16, 2011 13:44

  DELETE FROM IA_EXPORT_LEVEL where rowid IN
  (select rid from
  (select rowid rid, row_number() over (partition by A_NO,IM order by ctn_level) rn from IA_EXPORT_LEVEL )
  where rn > 1 )
  /
  

  Hope your question.

• Add a large number of columns to a shape

  Is there an easier way to add a large number of columns to a form of how I do it?
  What happens in general I find that a bunch of columns must be added to the table, what I do in the database. So I need to get these
  columns added to an existing form. As I do that is to create a new block in the form of referencing the same table, just like the old block.
  Delete all the columns in the new block that were in the old block.
  Move all the triggers of old block of the old block to the new block. Move old items to the old block of the newblock.
  Search for old block properties where clauses or whatever and who recreate in the new block...
  and then delete the old block and rename the new block to the old name of block.
  Phew! A lot of potential for error here.
  I need to possibly adjust the canvas for items and of course to reorganize things.
  
  Is there a better way?
  
  (BTW it's forms 11.1.1.4)
  
  Published by: Lake on May 5, 2011 10:15
  
  Published by: Lake on May 5, 2011 10:20

  Maybe create a routine of jdapi to compare the elements of a block known based on a table with the data dictionary ( user_tab_cols )? As each piece of information is given in the database (data type, the column name,...) should not be too difficult to implement.

  http://www.Oracle.com/technetwork/Developer-Tools/Forms/documentation/jdapi904019-131445.zip

  see you soon

• How do rotate on a date and see the sum of the value of another column

  Hello
  
  I searched through the forum and cannot find a query similar to my question feels so post this new thread.
  
  First of all, it is probably useful indicating that I am using Oracle 10 g.
  
  I have a table that is used to store the details of the booking (essentially a booking system) and I would use this data to display the details of the customers stay on one line.
  
  The table has the following columns:

  BOOKING_ID
  CUSTOMER_ID
  DATE_OF_ARRIVAL
  NUMBER_OF_NIGHTS
  NUMBER_OF_PEOPLE

  Some example records could be:
  
  

  BOOKING_ID    CUSTOMER_ID     DATE_OF_ARRIVAL    NUMBER_OF_NIGHTS   NUMBER_OF_PEOPLE
  --------------------------------------------------------------------------------------------
  1                    201      13-JAN-2010        5                   1
  2                    202      13-JAN-2010        3                   2  
  3                    202      13-JAN-2010        4                   1
  4                    203      15-JAN-2010        2                   3

  On this basis I would like to display the output so that I can show a sum of the NUMBER_OF_PEOPLE reserved to per customer per day, as such:

  CUSTOMER_ID     13-JAN   14-JAN   15-JAN   16-JAN   17-JAN   18-JAN   19-JAN 
  -----------------------------------------------------------------------------------------
  201                   1       1        1        1        1        0        0
  202                   3       3        3        1        0        0        0
  203                   0       0        3        3        0        0        0

  I watched analytical functions in the documentation and several books of Oracle that I have, but have so far struggled to find how to make the performance desired. Even using the excellent response to the previous post on the forum, I got Re: how to count the occurrence of a date in a range I was not able to get a feasible request.
  
  Any help or advice would be much appreciated.
  
  Kind regards
  Stu
  
  Published by: macmanxie on January 10, 2011 21:16

  Hello

  macmanxie wrote:
  ... The suggested approach goes only to return a number if the DATE_OF_ARRIVAL corresponds to the date in the CASE statement, however I have the added complexity of wanting to show a count of all the days that the customer is booked, for, by making use of the NUMBER_OF_NIGHTS. I tried to use some of the examples provided on morganslibrary.org, for example:

  sum( CASE WHEN  TRUNC (arrival_date) between '01/13/2011' and TRUNC (arrival_date+no_of_nights) THEN nvl(no_of_people,0) ELSE 0 END) AS jan_13
  

  but this does not produce the desired result.

  You check if arrival_date is between January 13 and arrival_date + no_of_nights (as if the arrival date could all be posterior to the arrival_date + no_of_nights).
  Are not really interested in whether or not January 13 ib between arrival_date and arrival_date + no_of_nights?

  NVL ( SUM ( CASE
                  WHEN  TO_DATE ( '01/13/2011'
                         , 'MM/DD/YYYY'
                       )          BETWEEN  TRUNC (arrival_date)
                           AND       TRUNC (arrival_date) + no_of_nights
               THEN  no_of_people
           END
         )
      , 0
      )          AS jan_13
  

  Always format your code. It is important to format your code if you are the only who who will ever read but it is even more important if you are posting on a forum like this and ask other people to read.
  Not to compare the DATEs in the strings; explicitly use a conversion function, like TO_DATE, above, where necessary.
  Both
  SUM (NVL (x, 0)) and
  NVL (SUM (x), 0) get the same results, but the latter is more effective. If you have 1000 lines, the first way is calling NVL 1000 times, but the second way is calling only once.

  If your previous thread
  Re: How to count the occurrence of a date in a range
  Gets you the right data, but it has one row for each distinct combination of customer_id and date, then you can switch it to a form that contains a line by the customer and another column for each date.

  If you need help, post CREATE TABLE and INSERT statements for some examples of data and outcomes from these data. The post you are trying better to a request, including a subquery that gets no cross-the raw table dynamic results.
  There will be a fixed number of columns in the output swing? If this is not the case, how do you deal with that? Which of these options in the thread I posted above)
  Re: County report and the sum of the number of rows by multiple columns
  ) is best for your needs? Than others is acceptable?