any analytic function or any other function of last time stamp?

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• without analytic function

  Hello experts.

  I have data similar to what follows below

  create table t1
  (
    id number(30),
    description varchar(4000)
  
  
  );
  
  insert into t1 values (1, 'zone');
  insert into t1 values (2, 'small');
  
  
  create table t2
  (
     id number(30),
     place varchar(4000),
     info varchar(4000)
  
  );
  
  insert into t2 values (1, 'USA', 'Class U');
  insert into t2 values (1, 'Mexico', 'Class M');
  insert into t2 values (2, 'Germany', 'Class G');
  

  I need help with something similar to what follows below without using any analytic function

  Description of the ID info Place

  1 box USA class U

  Mexico 1 M class

  2 small Germany class G

  Any help is appreciated. Thank you

  Hello

  user13328581 wrote:

  ... I use an older version of oracle. Oracle 7.

  Normally, your developers are older than your software.

  You should be able to do what you want with a self-join on t2; a copy (d) should be displayed, and the other copy (c) contains all related values you need for comparison.

  SELECT t2d.id

  DECODE (t2d.place

  MAX (t2c.place)

  t1.description

  ) AS description

  t2d.place

  t2d.info

  FROM t1

  , t2 t2d - display

  t2 t2c - compare

  WHERE t1.id = t2d.id

  AND t2d.id = t2c.id

  GROUP BY t1.description

  t2d.id

  t2d.place

  t2d.info

  ORDER BY t2d.id

  t2d.place DESC

  ;

  Output:

  ID DESCRIPTION PLACE INFO

  ---------- -------------------- -------------------- --------------------

  1 box USA class U

  Mexico 1 M class

  2 small Germany class G

  I've tested this in Oracle 11, but it should work in Oracle 7.

  If this isn't the case, you may need to create a view.

• analytical functions in oracle

  Hi I am new to oracle analytical functions

  I do not know how to use and where to use real-time, please send me the useful any url for it.

  I read in the Oracle Documentation , but it's not understand for me.

  Please provide me with any other useful URL, I'll read to those.if you have examples, please report it in the present.

  Thank you

  Check this box:

  ORACLE-BASE - Analytic Functions

  Analytical functions for example. Oracle FAQ

• Use of analytic functions

  Hi gurus,
  I ask someone to enlighten me on the analytical functions.
  I used the following query:

  select * from 
  (select filename,count(regexp_substr(filename,'.*era'))over(  partition by regexp_substr(filename,'.*era') ) cnt
   FROM 
  l_x12n_835_fileinfo where partitionnum=76000 and clntsysnum=76500 and radt>='01-JAN-2010')
  where cnt>1

  The sample result set is:

  FILENAME     CNT
  
  rsmedcalwa.20100105.chpwr.072.era     4
  rsmedcalwa.20100105.chpwr.072.era.1     4
  rsmedcalwa.20100105.chpwr.072.era.2     4
  rsmedcalwa.20100105.chpwr.072.era.3     4
  rsmedcalwa.20100105.chpwr.081.era     3
  rsmedcalwa.20100105.chpwr.081.era.1     3
  rsmedcalwa.20100105.chpwr.081.era.2     3
  rsmedcalwa.20100106.chpwr.088.era     3
  rsmedcalwa.20100106.chpwr.088.era.1     3
  rsmedcalwa.20100106.chpwr.088.era.2     3
  rsmedcalwa.20100108.chppr.363.era.3     4
  rsmedcalwa.20100108.chppr.363.era.1     4
  rsmedcalwa.20100108.chppr.363.era.2     4
  rsmedcalwa.20100108.chppr.363.era     4

  Now, I changed the query to:

  select * from 
  (select filename,count(regexp_substr(filename,'.*era'))over(  partition by regexp_substr(filename,'.*era') order by filename   ) cnt
   FROM 
  l_x12n_835_fileinfo where partitionnum=76000 and clntsysnum=76500 and radt>='01-JAN-2010')
  where cnt>1

  The result set has been

  FILENAME     CNT
  
  rsmedcalwa.20100105.chpwr.072.era.1     2
  rsmedcalwa.20100105.chpwr.072.era.2     3
  rsmedcalwa.20100105.chpwr.072.era.3     4
  rsmedcalwa.20100105.chpwr.081.era.1     2
  rsmedcalwa.20100105.chpwr.081.era.2     3
  rsmedcalwa.20100106.chpwr.088.era.1     2
  rsmedcalwa.20100106.chpwr.088.era.2     3
  rsmedcalwa.20100108.chppr.363.era.1     2
  rsmedcalwa.20100108.chppr.363.era.2     3
  rsmedcalwa.20100108.chppr.363.era.3     4
  rsmedcalwa.20100112.chpwr.175.era.1     2
  rsmedcalwa.20100112.chpwr.175.era.2     3

  (1) I don't understand how the addition of the order by clause changes the count. Could someone explain please?
  When I change this order by order of regexp_substr(filename,'.*era'), it gives me the correct number.
  
  My requirement is to check how many similar file names I.
  
  (2) if there are any other better elsewhere, please let me know.

  Hello

  Analytical functions still carried on in a window of the the result set, which can be smaller than the result set.
  If you have a PARTITION BY clause, the window for each row includes rows with the same values from all the PARTITION BY expressions.
  If you have an ORDER BY clause, the window includes that of a section of consecutive lines in the score, as defined by a windowing clause (in other words, LINES or KEEP them). The default value is "RANGE BETWEEN UNBOUNDED PRECEDING AND LINE CURRENT.

  In your case, if the analytical clause is:

  over(  partition by regexp_substr(filename,'.*era') )
  

  and the line you are looking at a filename = 'rsmedcalwa.20100105.chpwr.072.era.2', the window takes up the entire partition, in other words, all lines whose name includes "rsmedcalwa.20100105.chpwr.072.era". In other words, the window is identical to the partition, because theree is no ORDER BY clause.

  But if you add an ORDER BY clause:

  over(  partition by regexp_substr(filename,'.*era') order by filename   )
  

  then the window (potentially) decreases. Since there is no clause window, the default value 'RANGE BETWEEN UNBOUNDED PRECDING AND a CURRENT LINE' is used, which means that only the lines with a lower or equal to "rsmedcalwa.20100105.chpwr.072.era.2" file name (using the normal string comparison) will affect the results.

  The analytical ORDER BY clause is required for certain features (such as ROW_NUMBER) significance only in regard to certain commands. For the most part fucntions (including COUNTY), the ORDER BY clause is optional, and you do not have to use a. In this case, it seems that you do not want the effect of a smaller than the partition window, just so, do not use an ORDER byclause of Analytics for this function.

  Remember, the analytical ORDER byclause is completely independent the ORDER BY query clause. If you want the result presented in a certain order, use an ORDER BY clause at the end of the query. It will not change the results of the analytical functions.

• Analytic function can support this requirement?

  As a result of some Qry, I get the following result set.
  
  Column1 Column2 
  A       100    
  A       200
  A       200
  A       100
  B       200
  B       200
  B       200 
  C       100
  C       200
  D       200
  D       200
  E       200
  
  With this as input i had to take some decision like, For a particular Column1 value, if all the avaiable value of column2 is 200 (B, D & E in this case), i need to do one set of operations, if atleast one of the value for Column2 is non 200 (A & C in this case), i need to do another set of operation. How to frame the If clause or any other approach?
  
  
  By using Analytical count(*) function, is it possible to generate something like
  
  Column1 Column2   Column3(200_count)
  A       100       2
  A       200       2
  A       200       2
  A       100       2
  B       200       3
  B       200       3
  B       200       3
  C       100       1
  C       200       1
  D       200       3
  D       200       3
  E       200       3

  Jin
  Something lilke this?

  with data as (
  select 'A' column1,       100     column2 from dual union all
  select 'A' column1,       200 from dual union all
  select 'A' column1,       200 from dual union all
  select 'A' column1,       100 from dual union all
  select 'B' column1,       200 from dual union all
  select 'B' column1,       200 from dual union all
  select 'B' column1,       200  from dual union all
  select 'C' column1,       100 from dual union all
  select 'C' column1,       200 from dual union all
  select 'D' column1,       200 from dual union all
  select 'D' column1,       200 from dual union all
  select 'E' column1,       200 from dual
  )
  select
  column1,column2,count(0) over (partition by column1,column2) cnt
  
   from data
   order by column1
  

  The query above is considered the occuerence for each Column1 Column2.
  If you want to count only 200 something like can help you.

  with data as (
  select 'A' column1,       100     column2 from dual union all
  select 'A' column1,       200 from dual union all
  select 'A' column1,       200 from dual union all
  select 'A' column1,       100 from dual union all
  select 'B' column1,       200 from dual union all
  select 'B' column1,       200 from dual union all
  select 'B' column1,       200  from dual union all
  select 'C' column1,       100 from dual union all
  select 'C' column1,       200 from dual union all
  select 'D' column1,       200 from dual union all
  select 'D' column1,       200 from dual union all
  select 'E' column1,       200 from dual
  )
  select
  column1,column2,sum(
  case when column2=200 then
  1
  else
  0
  end
  
  ) over (partition by column1) cnt
  
   from data
   order by column1
  

  Kind regards
  Bobin

  Published by: Buga added second query

• Analytical function in Oracle

  I have a situation where I partitioned a Recordset. If in one partition on this recordset, the value of a field (field name registered) is '45' I need to order the result of this partition by - "outdate" desc "this provision" desc and order the other partition of desc 'key',' sequence ' desc, desc "outdate."
  
  If the query looks like to.
  
  Select row_number() over (partition by the order of the keys in sequence) RowNo, key, seq, status, outdate, receivedate from table1 where...
  order by?
  
  
  RowNo status outdate Seq key provision
  1 200 0 24 9/13 / 2009 12/9/2009
  2 200 1 23 9/10 / 2009 9/09/2009
  3 200 2 24 9/09 / 2009 9/08/2009
  
  1 210 0 24 9/13 / 2009 12/9/2009
  2 210 1 * 45 * 9/09/2009-9/08/2009
  3 210 2 24 9/10 / 2009 9/09/2009
  
  So I need to get the query that will order the first series of partition by desc 'key',' order ' desc, desc "outdate" and the second set of partition (because the status of '45' exists in the second partition) by "outdate" desc "this provision" desc.
  
  The output of the query should look like
  
  RowNo status outdate Seq key provision
  1 200 0 24 9/13 / 2009 12/9/2009
  2 200 1 23 9/10 / 2009 9/09/2009
  3 200 2 24 9/09 / 2009 9/08/2009
  
  1 210 0 24 9/13 / 2009 12/9/2009
  2 210 2 24 9/10 / 2009 9/09/2009
  3 210 1 * 45 * 9/09/2009-9/08/2009
  
  I don't know if this is possible using the analytical function.
  
  I would appreciate if any can help me with that.
  
  Thanks in advance

  Hello

  Welcome to the forum!

  You can use analytical functions in the ORDER BY clause.

  I do not have your tables, so I'll use scott.emp to illustrate.

  The following query sorts first by deptno. After this, the sort order for the departments that contain at least one seller is:
  b job
  (b) ename
  DEPTNO = 30 is be the only Department with a seller, so it's the only sorting as shown above.
  Other departments will be sorted by
  (a) sal
  (b) job

  SELECT       deptno
  ,       ename
  ,       job
  ,       sal
  FROM       scott.emp
  ORDER BY  deptno
  ,            CASE
            WHEN  COUNT ( CASE
                                 WHEN  job = 'SALESMAN'
                        THEN  1
                       END
                     ) OVER (PARTITION BY deptno) > 0
            THEN  ROW_NUMBER () OVER ( PARTITION BY  deptno
                                        ORDER BY        job
                              ,            ename
                            )
            ELSE  ROW_NUMBER () OVER ( PARTITION BY  deptno
                                        ORDER BY        sal
                              ,            job
                            )
         END
  ;
  

  Output:

  .   DEPTNO ENAME      JOB              SAL
  ---------- ---------- --------- ----------
          10 MILLER     CLERK           1300
          10 CLARK      MANAGER         2450
          10 KING       PRESIDENT       5000
          20 SMITH      CLERK            800
          20 ADAMS      CLERK           1100
          20 JONES      MANAGER         2975
          20 SCOTT      ANALYST         3000
          20 FORD       ANALYST         3000
          30 JAMES      CLERK            950
          30 BLAKE      MANAGER         2850
          30 ALLEN      SALESMAN        1600
          30 MARTIN     SALESMAN        1250
          30 TURNER     SALESMAN        1500
          30 WARD       SALESMAN        1250
  

  The small set of sample data you posted, the results you want can be achieved simply through

  ORDER BY  key
  ,         outdate     DESC
  

  I guess it's just a coincidence.

  If you need help, post some examples of data that requires really looking at the status column to get good results. Display the data in executable form, such as CREATE TABLE and the instructions INSERT, olr, as Salim, a WITH clause. (Maybe you can simply add or change a couple of lines in the example Salim already posted data).

• Analytic function to summarize

  Hi, I have a question regarding the analytical functions.
  
  SCENARIO OF
  I have two fields: TICKET_ID and TASK_TIME
  
  For each TICKET_ID, I have a task_time calculated as in the example:
  

   
  
  TICKET_ID                            TASK_TIME 
  
  112293                                 25                                    
  
  112294                                 1200                                  
  
  112294                                 40                                    
  
  112295                                 40                                    
  
  112296                                 60                                    
  
  112297                                 120                                   
  
  112298                                 60                                    
  
  112299                                 60                                    
  
  112300                                 180                                   
  
  112301                                 1440                                  
  
  112302                                 4320                                  
  
  112303                                 120                                   
  
  112304                                 306                                   

  TASK_TIME calculation is the following: IPTV_COUNT_TASKS_TIME (JTF_TASKS_B.Task Id: CREATION_DATE_UL)
  
  where:
  
  IPTV_COUNT_TASKS_TIME is a function of DB
  JTF_TASKS_B.Task Id is an area from runtime
  : CREATION_DATE_UL is a parameter after PERIOD
  
  
  As you can see the 112294 ticket I have 2 rows.
  What I want to achieve is the following: I would like to have average task_time (taking into account all tickets), but I don't want to count 2 times the ticket 112294
  
  So... What have I done?
  I create another calculated field named SUM (Task_time) where the calculation is: SUM (TASK_TIME) OVER (PARTITION OF TICKET_ID)
  and I got:
  

   
  
  TICKET_ID                            TASK_TIME 
  
  112293                                 25                                    
  
  112294                                 1240   
  
  112294                                 1240                                
  
  112295                                 40                                    
  
  112296                                 60                                    
  
  112297                                 120                                   
  
  112298                                 60                                    
  
  112299                                 60                                    
  
  112300                                 180                                   
  
  112301                                 1440                                  
  
  112302                                 4320                                  
  
  112303                                 120                                   
  
  112304                                 306                                   

  .. .and it isn't good, because, in order to calculate the AVG (TASK_TIME) I want to have only one ticket 112294 (and see only once the value of 1240)
  In other words, I need to summarize the task_time for each ticket and show the result only once for each ticket.
  
  Where is the error? How I do change the SUM (Task_time) calculation?
  
  Thanks in advance for any suggestion
  
  Alex

  Hello

  You can create the package in a schema, although usually an APPS environment I would create the package in the APPS schema because then you need not to grant privileges.

  Rod West

• Report Builder 6i do not recognize the analytical functions

  Hi all, in an attempt to speed up a slow query, I applied the analytical function to it. I can save the query in the generator without any problem, however, I can't create data between this request and other links. After I have comment on the analytical function, data bindings can be made. My colleague says Report Builder 6i is too old so he can recognize only the ANSI SQL syntax. Since our server DB uses Oracle 10 g 2, is there a way for the generator of reports to identify and compile syntax of Oracle 10 g?
  
  Thank you very much.

  Hello

  Your colleague is right. Even if the SQL query is executed by the DB server, reports must analyze the SQL query.

  The SQL parser included in reports 6i-based 8.0.6

  You can see this version using the report designer:

  Menu: Help-> on Report Builder...

  ORACLE Server Release 8.0.6.0.0

  Concerning

• Not able to install any other OS on Satellite M70

  I have a Toshiba M70-181 and my friend has a series of satellite Toshiba M70-189.

  (a) we both are not able to install any other OS outside one (Windows XP Home edition (German)) provided with the product. Is it not possible to install any other OS? Toshiba does not support any other OS?

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  (d) if it is not possible to install any other OS is so their a workaround so that we can install another OS?

  [Edited by: admin on 12 February 06 15:33]

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  Good bye

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  I reinstalled the air combat Simulator 3 but he can't play. He gets at the beginning and then freezes. I've got shield deluxe antivirus 2009. He has not done this with the 2008 deluxe version of shield. Yet, I can play any other game.

  Hi gullo56,

  Welcome to Microsoft Answers Community Forums.

  To help you better I would ask,

  a. If it functioned very well under Windows 7 before?

  ·         I suggest you to disable your firewall security software and check if you are able to play the game.

  From the link below, what I discovered is Microsoft Flight Simulator 3 is not completely compatible with Windows 7, but I would suggest that you follow the steps below to help troubleshoot your problem.

  http://www.Microsoft.com/Windows/compatibility/Windows-7/en-us/search.aspx?type=software&s=combat%20flight%20simulator%203

  1. as Microsoft Combat Flight Simulator 3 is supported by Microsoft Windows Vista to function normally, I suggest you run this program in Vista compatibility mode in Microsoft Windows 7.

  For information about how to run a program in an earlier version of Windows, visit the link below,

  http://Windows.Microsoft.com/en-us/Windows7/make-older-programs-run-in-this-version-of-Windows

  2. you can also try to reduce the hardware acceleration and check if it solves your problem,

  1. Click Start-> Control Panel-> appearance and personalization.

  2. under customization, click on adjust the screen resolution.

  3. in the display settings dialog box, click the Advanced Settings button.

  4. in the monitor Properties dialog box, click the Troubleshooting tab.

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  7 move the hardware acceleration slider to none to reduce or turn off video hardware acceleration.

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  9. restart Windows.

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  Kind regards

  Arona - Microsoft technical support engineer

  --------------------------------------------------------------------------------------

  Visit our Microsoft answers feedback Forum and let us know what you think.

• Which analytical function to use?

  
  Hi gurus,

  DB - Oracle 11 g 2

  I followed the examples of data in the table test_a.

  col1 col2 col3

  -----            -------            --------

  x                 y                   y

  p                 q                  y

  a                b                   y

  p                q                   y

  t                 r                    y

  p                q                   y

  The col3 column is always 'y '. But here's the data p, q, there is repeated 3 times (duplicate) and if this is the case I want to update only the first recordings like "n" col3 it is to say p, q, n. rest will be as it is.

  I am able to get the row_number() for it but not able to do this.

  Select col1, clo2, clo3 row_number() over (partition by col2) arrested by col1 as test_a r_num

  Would it be possible directly by any analytic function?

  Thank you

  SID

  COL4 is logical...

  Something like that?

  with x as)

  Select col1, col2 ' x' 'y', 'y' col3 col4 1 Union double all the

  Select 'p' col1, col2 'q', 'y' col3 col4 2 Union double all the

  Select 'a' col1, col2 'b', 'y' col3 col4 3 of all the double union

  Select 'p' col1, col2 'q', 'y' col3 col4 4 Union double all the

  Select 't' col1, col2 'r', 'y' col3, col4 5 Union double all the

  Select 'p' col1, col2 'q', 'y' col3 col4 6 double

  )

  ---

  Select * from)

  Select x.*,

  ROW_NUMBER() on rn1 (score of col1, col2, col3 col4 sort),

  ROW_NUMBER() on rn2 (partition by col1, col2, col3 col4 desc sorting)

  x

  )

  where rn1 = 1 and rn2 <> 1;

  Understand the logic and simply change SELECT a query to UPDATE...

• Truncate output of analytical function?

  For example this query:

  Select month, sum (tot_sales) monthly_sales,.

  AVG (Sum (tot_sales)) (any order by month

  between 1 above and 1 below) rolling_avg

  orders

  where year = 2001 and region_id = 6

  Group by month;

  gives me an output which includes several decimal places for the rolling_avg column.

  Is there a way to truncate this? I tried to use the rounded outside the analytical function and surely enough, it didn't work. I can't think otherwise.

  You can use an external selection on the result of this query

  select trunc(rolling_avg) from
  ( rolling_avg query);
  

• event.localX of a MovieClip regardless of any other DisplayObject over/under/inside

  Here is an example:

  var table:Table = new Table();
  stage.addChild(table);
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    book.y = Math.random() * stage.stageHeight;
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  var tablePt:Point = table.globalToLocal (globalPt);

  trace (tablePt.x, tablePt.y);

  }

  SOLVED

• Drive the analytic function

  
  Hello

  I have a doubt about this analytical function to lead,

  I have this table,

  create table test3 (no number, name varchar2 (30));

  
  Insert into TEST3 (NO, NAME) values (1, 'fen');
  Insert into TEST3 (NO, NAME) Values (3, 'DEN');
  Insert into TEST3 (NO, NAME) values (2, 'Sun');
  Insert into TEST3 (NO, NAME) values (2, 'sen');
  Insert into TEST3 (NO, NAME) values (1, 'end');
  COMMIT;

  I put like that with this request.

  
  Select lead don't (don't) over (partition by any order of name), name of test3.

  NO NAME

  1 fen
  end
  2 Sun
  Sen
  DEN

  But I need as below output, I am unable to get the third 'NO' that has a value, I get null for that, even if I partitioned
  by the 'NO '.

  NO NAME

  1 fen
  end
  2 Sun
  Sen
  3 DEN

  Please clear my doubt.

  Thanks in advance.

  Like this

  Select decode (NWR, 1, no, null) no

  name

  de)

  Select row_number() over (partition by any order by name) rno

  None

  name

  of test3

  )