any case when and the sql clause

Hello:
What follows is my sql clause:
SELECT T.*, b.name
OF dbtest1 t
LEFT OUTER JOIN dbtest b ON t.NO = b.empno
WHERE t.ChineseName like '% "| : ChineseName | ' %' AND b.name like "%" | : name | » %'
ORDER BY t.ChineseName

The main problem is that I want to check the b.name if it is null, it can be passed as function NVL, so I try using case when, but it does not work.
When there are the b.name in where clause, the columns of result will not include data without b.name (or implies the b.name is NULL); And that
the result data are not entirely accurate.
is it possible to use the case when it is implemented in the following code snippet:

-case when b.name is not NULL then b.name like "%" | : name | » %'
Else b.name = NULL (b.name = b.name does not seem to work on the analysis of data zero)
end

Thank you very much.

962769 wrote:
The main problem is the table is the form of the cross, and the like clause will filter the
data without a name. Basically, it should show the empty columns, however, it won't.
so, when I test the sql code, I fhound Like "%" | b.Name | ' %' will not get the data when the original dbtest1 table data
has no id corresponding to the BD test. It seems pointless to go the LEFT OUTER JOIN.

Thank you

WHERE t.ChineseName like '%'||:ChineseName||'%'
AND  (
        b.name like '%'||:name||'%'
       or b.empno is null
    )

Tags: Database

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