Similar Questions

• Error when selecting all the columns in the table

  Hi all

  When I write a query by selecting all the columns of the table fromo using * function as well as another new column, I get the error,

  Select *, to_char (hiredate, 'fmday') day

  WCP

  where to_char (hiredate, 'fmday') ('Monday');

  ERROR on line 1:

  ORA-00923: THE KEYWORD not found where expected

  I need all the columns in the table with the column user-defined 'day '. Is there a way I can get the result like this?

  Hello

  padders wrote:

  Alias table to use...

  Or the name of the table, for example

  Select emp.*, to_char (hiredate, "fmday") as day

  WCP

  where to_char (hiredate, 'fmday') ('Monday');

  The bottom line is that * must be qualified (with a table name or alias) when the SELECT clause includes anything else besides *.

• How to find a value in any column of the table - essentially a search

  Hi guys,.

  Thanks in advance for your help.

  I'll try to find a value in any column of the table? How can I do?

  An example of value would be "FEDERAL."

  Using Oracle 11 g and SQL Developer.

  Thank you

  It's a question that is asked in the past several times (but not recently from what I remember).

  Michaels has provided in the past, solutions which are quite clever, just using SQL...

  10g of solution

  Michaels > var val varchar2 (5)

  Michaels > exec: val: = "Sub".
  PL/SQL procedure successfully completed.

  Michaels > select distinct substr (: val, 1, 11) "keyword."
  substr (table_name, 1, 14) "table."
  substr (t.column_value.getstringval (), 1, 50) ' / value of the column.
  CLO.
  Table
  (xmlsequence
  (dbms_xmlgen.getxmltype ("select" | column_name))
  || 'from ' | table-name
  || ' where upper (')
  || column_name
  || ') as superior (' %' |: val)
  || '%'')'
  ) .extract (' LINES/rowset / * "")
  )
  ) t
  -where table_name in ('EMPLOYEES', 'JOB_HISTORY', 'SERVICES')
  order of the "Table".

  11g upwards

  SQL > select table_name,.
  column_name,
  : search_string search_string.
  result
  from (select column_name,
  table_name,
  "ora: view("' ||) " table_name | "") / LINE /' | " column_name | "[ora:contains (text ()," %' |: search_string | ")]. (%») > 0]' str
  CLO
  where table_name in ('EMP', 'Department')),
  XMLTable (columns str result varchar2 (10) path '.')
  /

  TABLE_NAME COLUMN_NAME SEARCH_STRING RESULT
  ------------------------------ ------------------------------ -------------------------------- ----------
  DEPT                           DNAME                          es                               RESEARCH
  EMP                            ENAME                          es                               JAMES
  EMP                            JOB                            es                               SALESMAN
  EMP                            JOB                            es                               SALESMAN

  4 selected lines.

• grant to specifice column of the table

  How I can give grants to specifice column of the table

  Hello

  Use this

  grant (empno, ename) update on emp to scott;

  better compliance
  skyniazi

• How to remove columns from the table on the master 1-0?

  I have an array of 96 columns with strings. I also have the array of int 96-elemets (mask) with 1 and 0.

  What I want to do is to is to remove (or hide - but I read that it is not possible) all the columns with index corresponding to 0 in the mask table.

  example:

  columns in the table

  1 2 3 4 5

  mask

  0 1 0 0 1

  I want to remove the columns 1, 3 and 4 and leave only 2 and 5 in my table.

  How can I do?

  If I create loop for with i as the index of the column, when I do DeleteTableColumns() columns number decreases, and I get an error of range out of

  Or do I have an option to hide the unnecessary columns (not set their width to 1, it's very ugly-looking)?

  Please help me (())

  Hello rovnyart!

  1. removal of columns in the table:

  I suspect that the reason why you get the out-of-range error is due to fact that in your loop, you delete the columns in the table, you'll eventually end up by referring to a column that no longer exists, because the other columns before it have been deleted. While you remove each column of your table in the loop for example, the column index number will move, because you deleted the other columns in front of her.

  To resolve this, even if you delete a column in your loop, make sure that you take also into account that the index of the column is moved because of the removed columns.

  2 hide columns in table:

  You can use the ATTR_COLUMN_VISIBLE attribute to hide columns in the table:

  http://forums.NI.com/T5/LabWindows-CVI-idea-exchange/add-attr-column-visible-attribute-for-table-Col...

  http://zone.NI.com/reference/en-XX/help/370051Y-01/CVI/uiref/cviattrcolumnvisible_column/

  3 alternatives:

  Note that another alternative would also use a tree instead, control as the tree control also supports the hidable columns:

  http://forums.NI.com/T5/LabWindows-CVI/table-hide-column/TD-p/569773

  Best regards!

  -Johannes

• How to create a status column in the table

  Hello everyone

  I am trying to create a column of the table status in frontview Panel. I enclose a picture with her to say clearly what I say.plz tell me how to create the active status column in the table.

  I want to show green for safety stock and red for safety stock below.

  
  

• How to find the primary key columns in the tables in MS Access using SQL queries

  How to find the primary key columns in the tables in MS Access using SQL queries

  Hello

  This is the forum for Windows Vista programs related issues.

  For better assistance, please try instead the Forums in SQL Server .

  Thank you! Vincenzo Di Russo - Microsoft MVP Windows Internet Explorer, Windows Desktop Experience & security - since 2003. ~ ~ ~ My MVP profile: https://mvp.support.microsoft.com/profile/Vincenzo

• Query took too much time when adding new column to the table and the index set on this

  I added a new column to the table that contains thousands of records. and created the composite index with three columns (those newly added + two existing column)

  for the specifics. TBL table there are two columns col1, col2

  I added the new column col3 to TBL and created composit index (col1, col2, col3).

  Now for all the records in col3 is NULL. When I choose on this table, it takes too long...

  Any idea what my I do bad., I have check the query plan, it is using the index

  It is solved using collection of statistics using the

  DBMS_STATS. GATHER_TABLE_STATS

  @Top.Gun thanks for your review...

• Get columns from the table shown in the iterator

  Hello...

  I have the table in a collection of standard panel.  So, I can show/hide certain columns in the table using the columns in the view menu.

  Then I'm trying to do is export to excel (using apache poi) by looping through the table iterator.  What I can't do is search if the column is not displayed.  I don't want all the columns that are exported without worrying.  How can I achieve this?

  My bean is similar to the following for loop through the iterator:

  BindingContext bindingContext = BindingContext.getCurrent ();

  BindingContainer bindingContainer = bindingContext.getCurrentBindingsEntry ();

  DCIteratorBinding dcIteratorBinding = (DCIteratorBinding) bindingContainer.get ("EmployeesIterator");

  lines [] oracle.jbo.Row = dcIteratorBinding.getAllRowsInRange ();

  for (oracle.jbo.Row line: lines) {}

  {for (String colName: {row.getAttributeNames ())}

  output to excel cell here using row.getAttribute (colName) m:System.NET.SocketAddress.ToString)

  }

  }

  Thank you.

  Hello

  It's like ask the engine in your car to what colors the seats have. The iterator doesn't know anything about the visible state of a column. If the displayed columns must be determined from the table instance (richeTableau)

  The following article solves exactly the requirement that you have: Oracle ADF: Build Your Own it comes with a sample that you can download here: http://www.oracle.com/technetwork/issue-archive/2013/13-jul/o43adf-1940728.zip

  Have a look at CustomPanelCollectionBean.java:

  The method and code that you want to look for is:

  private String getRowHtml (row rw) {}

  StringBuffer rowHtmlBuf = new StringBuffer();

  Read visible columns in the table of the table instance. This way the

  PanelCollection can be used to show/hide columns and exclude

  printing to HTML

  Table richeTableau = this.getRichTable ();

  the list of columns determine the print attributes

  The list of columns in = table.getChildren ();

  int attrCount = columns.size ();

  rowHtmlBuf.append (this.addRowStart ());

  for (int i = 0; i)< attrcount;="" i++)="">

  for all visible columns, add columns to print

  If (((RichColumn) columns.get (i)) .isVisible ()) {}

  If (rw.getAttribute (i) instanceof ViewRowSetImpl) {}

  ignore the collections of detail used for master/detail example

  constraints in British Colombia ADF

  } ElseIf (rw.getAttribute (i) instanceof oracle.jbo.domain.Timestamp) {}

  shorten date to exclude the infromation times

  SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");

  String dateFormatString = sdf.format (((Timestamp) rw.getAttribute (i)) .getData ());

  rowHtmlBuf.append (this.addDataCell (dateFormatString));

  } else {}

  Prnt attribute values and if sure that null values don't raise a NPE. Add a white character to NULL

  attribute values

  rowHtmlBuf.append (this.addDataCell (rw.getAttribute (i)! = null? rw.getAttribute (i) m:System.NET.SocketAddress.ToString ():))

  " "));

  }

  }

  }

  rowHtmlBuf.append (this.addRowEnd ());

  Return rowHtmlBuf.toString ();

  }

  You need to access the Rich Table instance (for example using the JSF component binding) to then compare the attribute in the iterator with the visibility of the column

  Frank

• Impossible to extract the data of an additional column in the table advance

  Hello

  We have an obligation to add an extra column to the table of advanced search. In addition, we need sort the table using this additional column.

  Now, we have achieved the following:

  1. the required VO was already extended previously and the additional column (LAST_UPDATE_DATE) is already present in the definition of the EO. So, we just added the tag for LAST_UPDATE_DATE in YOUR XML in the form:

  < ViewAttribute

  Name = "LAST_UPDATE_DATE".

  IsPersistent = "false".

  Type = "Oracle.jbo.domain.date"

  ColumnType = "DATE".

  AliasName = 'LAST_UPDATE_DATE. '

  Expression = "LAST_UPDATE_DATE."

  SQLType = 'DATE' >

  < / ViewAttribute >

  2 added a new MessageStyledText column, and updated the following property:

  Prompt = LastUpdateDate. Discover the Instance = TaskPerzSumVO. Display attribute = LAST_UPDATE_DATE. Sort Allowed = true

  The field is now visible in table advance and whenever we seek, attaches the value as ' 1901-01-01'. While I checked manually in the respective table, we have the appropriate data. But in the front end we do not get the data in our additional column of table in advance. In addition, if we try to sort the table by clicking the column LAST_UPDATE_DATE, we get the NPE error. Spec of NullPointerException is as follows:

  # # 0 in detail

  1. java.lang.NullPointerException

  at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:989)

  Kindly help us to obtain the appropriate data in the additional column. Thank you!

  Kind regards

  Zahid

  Hi Zahid,

  This is the error:

  29000: unexpected exception caught: oracle.jbo.NoObjException, msg = Houston-25003: TaskEO.LAST_UPDATE_DATE object of type entity activity not found

  Tag entity by its use should have only name of EO and not the name of the attribute.

  Use instead under the tag:

  EntityUsage = "TaskEO".

  Also, I mentioned that rather tags manually, add it please try Wizard VO to add this attribute in EO attributes available list.

• ADF: Columns of the Table filtering problem

  Hello
  
  My Version of JDeveloper is 11.1.1.5
  
  I am facing a problem with the filter of the table...
  
  Is it possible to implement the feature of research on filtering only on af:table with panelCollection?
  
  Could someone help me please in this?
  
  I need Research* not only the filtering of the data inside the table with the facet of the columns of the table filter...
  
  Can someone help me with this application?
  
  Many thanks in advance,
  
  Kind regards
  Anil
  
  Published by: 977652 on February 17, 2013 19:28
  
  Published by: 977652 on February 17, 2013 19:38

  You can just type in the filter like '% EBS' field and you will find your file.

  Timo

• delete extra spaces in the column of the table

  How can Hi I remove extra spaces in the column of the table for example if the table column is store as "ÄAAAAA" how to remove this extra space
  
  This is the column I have what it takes to remove extra spaces
  

  select SUBTYPES  from tablesubtype;

  am in
  Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
  PL/SQL Release 11.2.0.3.0 - Production
  CORE Production 11.2.0.3.0
  AMT for Solaris: 11.2.0.3.0 - Production Version
  NLSRTL Version 11.2.0.3.0 - Production
  
  Published by: adf0994 on 03/12/2012 11:30
  
  Published by: adf0994 on 03/12/2012 11:42

  UPDATE tablesubtype
     SET SUBTYPES  = TRIM (SUBTYPES);
  

  RTRIM do it alone will not be enough coz it takes away only right spaces and NOT left those.
  I guess in your case do a PLATE will be more advantageous to be safe and avoid left spaces in the future.

  For the intermediate spaces... try this.

  UPDATE tablesubtype
     SET SUBTYPES  = REGEXP_REPLACE (SUBTYPES, ' ', '');
  

  Hope this helps,
  Vanessa B.

  Published by: Vanessa B December 3, 2012 14:33
  -added regexp

• How to insert sequence numbers in a column in the table:

  I'm going to the emp table:
  
  
  EmpNo enmae job
  1111 ramu Sager
  S.S.E COMER 7658
  8280 GETA INTERN
  
  
  modify the table emp Add number of sno
  
  sno for I must generate 1,2,3...
  
  How can I do this

  What is

  update emp set sno = somesequence.nextval where sno is null;
  

• How to check the index, on the number of columns in the table is created

  How to check on the number of columns in the table the index has been created. ??
  
  OR
  
  How check index, on the number of columns in the table that it is been created?

  890306 wrote:
  How to check on the number of columns in the table the index has been created. ??

  >

  OR

  How check index, on the number of columns in the table that it is been created?

  query USER_IND_COLUMNS

  SQL> desc user_ind_columns
   Name                            Null?    Type
   ----------------------------------------- -------- ----------------------------
   INDEX_NAME                             VARCHAR2(30)
   TABLE_NAME                             VARCHAR2(30)
   COLUMN_NAME                             VARCHAR2(4000)
   COLUMN_POSITION                        NUMBER
   COLUMN_LENGTH                             NUMBER
   CHAR_LENGTH                             NUMBER
   DESCEND                             VARCHAR2(4)
  

  Handle: 890306
  Status level: Beginner
  Join date: October 8, 2011
  Messages total: 13
  Total Questions: 5 (5 open)

  Why all the question still pending?

  Published by: sb92075 on December 3, 2011 17:21

• Unable to add a new column to the table of the LCD? Option, just usually add it.

  I have a form of LCD with a table in it. Im trying to simply add a new column to the table. The option is there, but the column appear just after clicking Add the column to the left. I selected a column, right click the space > insert > column to the left. But the habit intsert. The object table properties tab shows lines and colum numbers, but they are grey.
  
  See screenshots:
  
  http://www.emermed.NET/staging/forums...
  
  http://www.emermed.NET/staging/forums...
  
  It is a dynamic array, where a new line can be inserted using a button. Is that the dynamic nature of the question? ID hate to cancel all the flow dynamics and programming just to add a column, and then reapply them all.
  
  Thank you!

  Hello

  You do not add the columns in the object > palette (screenshot 2) of the Table. I suspect that the problem is that it is not enough on the page (in the content area) to add the column. In the screenshot 1, if you look at the width of the column highlighted from the space to the right of the table, you will see that a column can be added due to restrictions of space.

  Reduce the width of the column highlighted (temporarily), and then add a column. Once added, you can resize the columns to match the width of the page.

  Hope that helps,

  Niall