Convert an anchor in a right angle?

Hello

I would like to choose an anchor point and adjust it so that it creates a perfect right angle. How can I do?

Imagine some closed, filled with shape, composed a dozen anchor points. I would choose one of these anchor points (a corner anchor point, not a point of inflection) and adjust it (built-in? script?) while it creates a perfect right angle (90 deg.). This essentially means moving it to just the right place so that the lines connecting its two neighbouring anchor points form a right angle.

Hope that the description is clear.

Please, do not assume that the right angle that results would be necessarily oriented along an axis North-South, or any other rational compass statement.

Thanks a lot for any help or pointers...

Ariel

So here's the script I wrote. Looks like it works pretty well, but I did not too widely tested yet.

// BS"D
// Create Right Angle
// An Illustrator CS5 Script (may work in other versions too)
// Copyright (c) 2014 by Ariel (www.freelancebookdesign.com)
// This script may be used freely provided these opening comments are not removed.
// This script will adjust a point on a path (open or closed) so that it forms a 90 degree angle with its two adjacent points.
// See http://forums.adobe.com/thread/1385409?tstart=60 for more details.
// To use, select an anchor point on a path. The path must contain at least 3 anchor points.
 // The selected point should not be an end point if the path is open.
 // Run the script. The selected point will be moved the smalled distance possible such that it forms a
 // right angle with its neighbouring points.

try{
    if (app.activeDocument.selection.length == 0){
        throw("Please select an anchor point and try again.");
    }
    var mySelection = app.activeDocument.selection[0];
    if (mySelection.constructor.name != "PathItem"){
        throw ("Please select an anchor point and try again.");
    }
    var myPoints = mySelection.pathPoints;
    if (myPoints.length < 3){
        throw ("The script can only work if there are at least 3 anchor points on the path.");
    }
    var foundSelected = false;
    for (var i = 0; i < myPoints.length; i++){
        var myPoint = myPoints[i];
        if (myPoint.selected == PathPointSelection.ANCHORPOINT){
            foundSelected = true;
            break;
        }
    }
    if (foundSelected == false){
        throw ("Please select one of the anchor points.");
    }
    if (!mySelection.closed && myPoint == myPoints[myPoints.length-1]){
        throw ("The last anchor point was selected. Please select an anchor point between two others.");
    }
    if (!mySelection.closed && myPoint == myPoints[0]){
        throw("Please select an anchor point between two others.");
    }
    var prevIndex = i-1;
    var nextIndex = (i+1) % myPoints.length;
    if (mySelection.closed && prevIndex < 0){
        prevIndex = myPoints.length-1;
    }
    var adjustedPoint = adjustPoint(myPoints[prevIndex], myPoint, myPoints[nextIndex]);
    myPoint.anchor = [adjustedPoint.x, adjustedPoint.y];
    myPoint.rightDirection = [adjustedPoint.x, adjustedPoint.y];
    myPoint.leftDirection = [adjustedPoint.x, adjustedPoint.y];
}
catch(e){
    alert(e);
}
function adjustPoint(pointA, pointB, pointC){
    // A and C are static. B will be adjusted.
    var Ax = pointA.anchor[0];
    var Ay = pointA.anchor[1];
    var Bx = pointB.anchor[0];
    var By = pointB.anchor[1];
    var Cx = pointC.anchor[0];
    var Cy = pointC.anchor[1];
    // Find new point M that is midway between A and C
    var Mx = 0.5 * (Cx + Ax);
    var My = 0.5 * (Cy + Ay);
    // r = radius of circle whose diameter is AC
    var r = (Math.sqrt((Cx - Ax)*(Cx - Ax) + (Cy - Ay)*(Cy - Ay)))/2;
    // s = the distance between M and B
    var s = Math.sqrt((Bx - Mx)*(Bx - Mx) + (By - My)*(By - My));
    if (s == 0) {
        alert("The script must now disappear in a puff of infinity.");
        // pointB does not need to be moved;
        return {x: Bx, y: By};
    }
    // f is the ration between r and s
    var f = r/s;
    // D is the new point we're looking for
    var Dx = Mx + (Bx - Mx) * f;
    var Dy = My + (By - My) * f;
    return {x: Dx, y: Dy};
}

Tags: Illustrator

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