Count the number of times a letter appears in a string and the number of real-time display?

Similar Questions

• Count the number of times you click on hot spots.

  The specific problem I'm having right now counts the number of times where an is clicked a hotspot. I have four hot spots and need to track the number of times where is clicked on each hotspot. The variable "tent" gives me the total for the whole interaction. Since they are not considered, I can't use correct or wrong. You have any ideas? I would use the "tries@title" icon, but all the hotspots are contained in the icon interaction so that no longer works.

  Thanks for any help you can provide,

  I often structured interactions so that I can enjoy the variable 'ChoiceNumber. If your access points are all consecutive and they are the first things to the right of the interaction, you can use a variable from the list.

  [ClickList: =]

  Then at the top of each of your answers, you can use

  ClickList [ChoiceNumber]: = ClickList [ChoiceNumber] + 1

  Each task in ClickList is taken into account the time that spot has been used and you can use the sum to get the total of all tasks. If they can not be the first thing then you can always use an offset value... ClickList [ChoiceNumber-4]: = ClickList [ChoiceNumber-4] + 1

  HTH,

  Mike

• Count the number of times that that a field is filled

  Help!

  I am building a form with fields of number 10 named task1, task2, task3, etc.. Different users may or may not use all of these fields. For example, a user can only fill 7 of these fields of number 10, while another user can use only 5. I need the form to count the number of the task fields were filled and put that number into a numeric field named TotalTasks.

  Any help is appreciated!

  Gene-O

  OK, here is a corrected version. The code on each of the fields for tasks thise was

  Whereas there is a subform Page2. I renmaed subform Page2 and which caused problems on a couple of

  fields on page 1. Then I updated the code of responsibility and disciplinary fields as well. Everything seems to b working now.

  Paul

• How to count the time exactly?

  I tried to count the time using a VI like the one attached.

  It's that's not couting correctly. There is a possible reason, I have observed.

  The computer isn't able to handle the VI as soon as necessary.

  I thought about this because, when in edit mode the time count was very bad, and, when I created an application and installed, it ran okay, how 'light '. But today, when I tried to use this application with an old computer it did not work. The clock is slow.

  Is it possible to count the time correctly?

  I use a DAQ6009 to make my works, my VI is big enough and I need one iteration to each 1 ms (milliseconds) as I am with digital inputs from 5 events of coders (I know that's not the right way to count the encoders, but it's the only way I can do it, and it works).

  Thank you in advace! I hope you can help me!

  Hugs!

  Ok.  I will try to help you understand certain things.

  The number of cycles and wait (and wait until the next ms Multiple) functions all use a 1 kHz derived from the clock of the processor clock. The accuracy of these clocks is not large, although they are probably similar to the precision of the stopwatch.  Any time generated by these functions will show some differences in the time of the clock as it is derived from a different oscillator.

  Updates from the front panel are time by LabVIEW and the operating system. Most of the screens are updated with 60 to 80 times per second, maximum. What made the operating system, an update of the screen might be delayed by 10s of milliseconds or more.  It is certain that not all of the values at the end of the Add function will be displayed.

  Wait for him until the next ms many will wait more than 1 ms if the other code in the loop takes longer than 1 ms.  I don't know, but I think that the indicator is buffered so that any delay by the operating system to update the display should not slow down the loop. I tried to remove the flag, and it doesn't seem to make a big difference.

  I modified your VI to provide several indications of the performance. First of all, I added to the sequence of three-frame structure to allow synchronization of the loop. Second, I changed to a loop which runs a specified number of iterations. Thirdly, I hooked up the output of the timer until the next ms Multiple to a tunnel of autoindexing allowing a record of the time of each iteration appears in the table of ticks. I calculated the differences between successive instants and poster on a chart, so that you can see the performance.

  I didn't want to sound criticism of your use of English.  You write in English, much better than I could in your language!  What I was trying to make is that such general descriptions that ' Besides correctly ' without quantitative results or evidence in support of the application do not have enough information to help us help you.

  Lynn

• Count the total number of specific words on each page

  I have a script that counts the number of times where the word 'Manager' is displayed on each page of a report.

  This is what is returned in the console after running the script:

  Count the number of managers 1 Page number 1

  Count the number of managers 2 Page number 1

  Count the number of managers 3 Page number 1

  Count the number of managers 4 Page number 1

  Count the number of managers 5 Page number 1

  Count the number of managers 1 Page number 2

  Count the number of managers 2 Page number 2

  Count the number of managers 3 Page number 2

  I need the console to report with only the total number of times that the word Manager appears on each page (once) and not iterate over each of them.

  Can someone please advise how this can be achieved?

  Script as follows:

  var this.numPages = NUMPAGES;

  for (var k = 0; k < numpages; k ++)
  {
  {
  numWords var = this.getPageNumWords (k);

  var number = 0;

  for (var i = 0; i < numWords; i ++)
  {
  var ckWord = this.getPageNthWord (k, i, true);
  var q = this.getPageNthWordQuads (k, i);
  Convert quads in the rotation by default user space
  Userspace used by links.
  m = (new Matrix2D).fromRotated(this,0);
  mInv = m.invert)
  r = mInv.transform (q)
  r = r.ToString)
  r = r.split(",");
  If (ckWord = "Manager")
  {
  Count ++;
  Console.println ("Count none managers" + count + "Number of Page" + (k + 1));
  }
  }
  }
  }

  Just move the statement outside the inner loop:

  var this.numPages = NUMPAGES;

  for (var k = 0; k)< numpages;="" k++)="">

  numWords var = this.getPageNumWords (k);

  var number = 0;

  for (var i = 0; i)< numwords;="" i++)="">

  var ckWord = this.getPageNthWord (k, i, true);

  var q = this.getPageNthWordQuads (k, i);

  If (ckWord = 'Manager') {}

  Count ++;

  }

  }

  Console.println ("Count none managers" + count + "Number of Page" + (k + 1));

  }

• How to count the number of conditionally highlight cells in a column or row

  I'm working on a table to identify problems with my credit rating. So, I have a column that indicates the due date on the invoice and G that contains the date to which I made the payment.

  I'm trying to follow how many times I'm late with payments. I want to improve.

  So if the G column is later than column D, both with the Date formatting. So, now I've highlighted cells and I want to summarize for the year, how many times I was late payments.

  I thought a column G to count the number of days before or after that back I was with payments. But if the sum, it only gives me no useful information. I guess I could count the number of cells with values less than 0.

  I prefer to be able to put in the summary column for G something that said 0-12 years ago has highlighted cells in the column.

  Thank you

  You can not count based on sharing or formatting.  You can, however, be based on the same conditions.

  There are functions:

  COUNTIF() counties based on a condition is true

  and

  COUNTIFS() based on several conditions being true

  = NB. If

  Here is a way.  IT will take an additional column that calculates the "delay" in the days of a payment

  

  the first two lines are the lines of header

  H3 = IF (COUNTA (D3, G3) > 1, MAX ((G3−D3) DUR2DAYS, 0), "")

  It's shorthand dethrone select cell H3, and type (or copy and paste it here) the formula:

  = IF (COUNTA (D3, G3) > 1, MAX ((G3−D3) DUR2DAYS, 0), "")

  Now select cell H3, copy

  Select the H3 cells at the end of column H, dough

  H1 = "payments late =" & COUNTIF(H,">0")

• Count the number of 1 is present in digital waveforms obtained by converting the pulse signals.

  Hello

  I use Analogtodigital.Vi to convert the pulse of the sequences in digital.signals.I am able to get the representation of digital waveforms of impulses.

  But how to count the number of 1 is present in the converted digital waveform. I want to count the number of 1 is present in the digital waveform converted.

  Thanks in advance.

  Have you tried the block scheme of similar to the Digital.vi of opening?

  It creates an array 2D uncompressed 1 and 0, which is the binary 16 bits A/D conversion of each element in the array Y of the input waveform. You can use the DWDT digital Array.vi Boolean to convert a 2D Boolean table. Then convert Boolean values to 1.0 and summarize the array of integers. The sum must be the number of 1 bits in the digital waveforms.

  Lynn

  Note: The VI attached is saved in version 8.6. When I have it saved for the previous Version a warning was generated about the possible differences in the versions. Let me know if it doesn't work, and you are using which version of LV.

• Boolean switch until the released counter + the number of cycles

  Hi, I want to use a Boolean command button (switch release) to rely on a specific value and when obtaining this value (while pressing continuously the button) to turn on an led. If I release this Boolean button, I want to count the time until a value and then to turn off the light, like a hand for a hand detection dry.

  I was thinking of using the number of cycles in a sequence of plate with a delay for the time being I want to split on a matter of true or false, but the problem is that the count of the number of cycles is continuous and not slaughter not on the specific value I want for the power button truning the seeing.

  Any help?

  TNX

  Guy

  
  

• How to count the number of clicks: a user makes? + Penalized if too many

  Hi all

  I have a video where the user needs to search for objects. It should click when an object is in the video. I created click boxes during the opportune times.

  What I do:

  I count the number of clicks and display it below the video. So, for example when a user clicks on an icon at the bottom of the video. If he clicks 5 times more, there are 6 icons in a row. Too much pressure, I can say that the user is cheating and give him a score of 0.

  Anyway to do this?

  The first decision is to increment the counter by 1, sorry, typed too fast should be:

  Increment of 1 V_counter

  You should see that the syntax when you created the first decision. This means that each click will add 1 to v_counter, the reason why it must be the first decision. Only indicator related to the value of v_counter must be added, given that the previous indicators are already should have been disclosed with the previous clicks. This conditional action must be triggered by the success of the click box. Because it takes several clicks, is expected to try it myself, was little crowded today. Apology.

  You add new information now: what do you mean by "conditional login?

  If you need to partition must be reported to an LMS (still do not know which), you should know that all quiz system variables are read-only. This means that the maximum score is set at the beginning of the tutorial. You can attach a note to each interactive object. Probably the best way would be to add a button next (with a break point after the click box), who will get a score. Since you want a penalty when v_counter is greater than 5, you will need to use the following two buttons: one with a score = 0 and the other with a score = X (points you want to give). If you put the beginning of the chronology of these buttons just after the timeline of the click box, you can add a final decision to the advanced conditional action that will check which button to display. If I label the value 0 has marked button "Bt_Next_0" and the version marked "Bt_Next_points" that last decision is:

  IF v_counter is greater than 5

  Disable Bt_Next_points

  Hide Bt_Next_points

  See the Bt_Next_0
  Select Bt_Next_0

  ON THE OTHER

  Disable Next_0

  Hide Bt_Next_0

  See the Bt_Next_points
  Select Bt_Next_points

• Scripting: Count the number of selected pixels (non-quadrangle) or alternative approach

  Is it possible to count the number of pixels in a selection that is not a quadrilateral? For example, if I have cntl - click on the thumbnail of a text layer, I would like to know how many pixels is selected.

  This application, if anyone has another approach to try...

  

  My goal is the place the text at some point where it covers do not all lines (or, Alternatively, the place where it covers the smallest number of pixels line). My approach is to insert a text in red to the desired location, apply a BlendMode.Multiply to the text. The number of Red pixels always on the screen will show how many pixels line I'm concealing. Then I move the text into a region and check the histogram in 76 index (which is 255,0,0), find the point with the highest number of red (meaning concealing pixels less line) and finally move the text at that location. See the code snippet below:

  var bestCX = cX;

  var bestCY = cY;

  var bestPixelDensity = - 1;

  var pixelDensity = 0;

  var searchRegionWidth = 3000;

  var searchRegionHeight = 2000;

  loop through an area 3000 x 2000 around where you want

  for (var x = cX - searchRegionWidth/2; x < cX + searchRegionWidth/2; x ++)

  {

  for (var y = cY - searchRegionHeight/2; y < cY + (searchRegionHeight/2); y ++)

  {

  textItemRef.position = new Array (x, y);

  pixelDensity = myDocument.histogram [76]; index of 255,0,0 (red)

  If this point is greater than the previous highest density, use it instead.

  if(pixelDensity > bestPixelDensity)

  {

  bestCX = x;

  bestCY = y;

  bestPixelDensity = pixelDensity;

  }

  }

  }

  move text in the best location found

  textItemRef.position = new Array (bestCX, bestCY);

  The problem is that the images I use are very large ((7000x7000px) for each histogram control takes a few seconds and I really need to move in a fairly large region (3000 x 2000) to find the best place.) I think that it is perhaps faster if I'm not using the histogram at all, and instead each time that I move the text, I select the text and see how many points is in the selection. Any help or alternative approaches would be great!

  I don't know the answer, the only thing I can think is the whole of the histogram to the selection and treatment of the histogram of the selected area.

• Count the number of records between two values of keys (BTREE)

  How can I count the number of keys between two values?

  I use python driver and BTREE access method.

  = >

  Ideally, what I want is a set of whole time series data (intervals may change) to a given number of points on average. The keys are timestamps and the values are the data that it takes on average. I need to count the number of records between two timestamps so that I can divide this figure by the number of points I need and data on average. What is the best way to do it?  Or should I keep the timestamp constant intervals and use the RECNO access method?

  Thank you
  (first post btw... and why is there not a lot of people at stackoverflow that answering the questions of Berkeley DB?)

  BDB is an integrated db and there no internal counters or statistics you might grap to use for this.    You will have to do it manually.

  You can create a cursor, grap the records you want, whenever you get the next card that you bump a counter.

  If you are using RECNO, you can use a slider to obtain the number of registration (DB_GET_RECNO), and if all that you data is in

  sequentail records with no missing documents, you can find the total number of take the last rec #-original rec # + 1 to get a count.

  If you pass the SQL API, you can issue a SQL query to give you a count.  Select count (*) where...

  As you enter the data anyway, so better perhaps to count records as you go along.

  Thank you

  Mike

• Try to count the number of records where some columns are met

  Using SQL in Toad against an Oracle table, I'm trying to count the number of records in a table where some columns are filled. For
  example, I need to know the total number of records from a table where
  
  ln_stop_cd is not null - 65000 records
  ln_process_cd is <>- 25000 0 records
  ln_opt_cd is not null - 7500 records
  
  and the record_type = "A".
  
  I know that the total individual records as described above. However, I do not know how
  the SQL to show for record_type = 'A' the total count is 97500 records. Any help would be
  appreciated.

  Hello

  It seems that the problem is that the indictment may overlap; You can count the same rank 0, 1, 2 or 3 times, depending on whether 0, 1, 2 or 3 of these 3 independent conditions are met.

  Try something like this:

  SELECT     COUNT (in_stop_cd)
        + COUNT (CASE WHEN in_process_cd  != 0        THEN 1 END)     -- this site doesn't like the other inequality operator
        + COUNT (in_opt_cd)        AS grand_total
  FROM    table1
  WHERE     dt          >= TO_DATE ('01-JUN-2011', 'DD-MON-YYYY')
  AND     dt          <  TO_DATE ('02-JUN-2011', 'DD-MON-YYYY')
  AND     record_type       = 'A'
  ;
  

  You want to make charges without making 3 assists separated through the table. The problem is the 3 original requests had slightly different WHERE clauses.
  Put these conditions in the WHERE clause and make other conditions apply only to the individual counties, either with a column instead of *, or using a CASE statement that contains the condition that applies only to the column.

  Also, the date is not a column name good. Do not compare the DATEs to strings. If your column is really a DATE and you want to ignore the hours, the minutes and seconds, then the best way is to compare the column with 2 other DATES, as shown above. It's more coding, but it is more efficient and more reliable.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  You don't have to display a large amount of data. You can probably give an excellent example of this problem with only 5 or 10 rows of sample data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  Published by: Frank Kulash, August 4, 2011 11:27

• REGEXP: Count the number of commas before a given tank

  Hi guys,.
  
  I was wondering if this is possible? I want to count the number of commas ',' before a given string.
  
  For example:
  Let's say I have this string:
  

  SELECT 'Hello', 
         dump('Hello {The ')
    FROM dual;

  Which returns:
  

  'HELLO'        DUMP('HELLO{THE')                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                
  ------------------ -----------------------------------
  Hello                            Typ=96 Len=11: 72,101,108,108,111,32,123,84,104,101,32

  I was wondering if it is possible to count all commas before the 123 tank? In this example, it should return 6
  Can anyone help?
  
  Thank you

  Something more in this sense then...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select dump('Hello {The ') as dmp from dual)
    2  --
    3  select length(regexp_replace(regexp_substr(dmp,'[^ ]+,123',1,1),'[^,]')) as str
    4* from t
  SQL> /
  
         STR
  ----------
           6
  
  SQL>
  

• How to count the number of data records?

  Hey guys, how to count the number of records, I had on a data object variable?

  Im having a result of sql query in a variable like this:

  oDB.resolveNode("#command").query.select.value = "SELECT * FROM Customers WHERE CliNombre LIKE ' % ' + input1 +" %' ";

  oDB.open ();

  oDB.first ();

  So I need to count the number of records retrieved by this SQL query at the moment. Help please

  Then move the cursor back to the first record after you have your account.

  There is a keyword count in SQL that will allow you to get the account of your request. You can run that first - get your account, and then run the actual query to get the Recordset. This would require a separate data connection. Some examples of code.

  var xfa.event.newText = inName;
  If (inName == "") {}
  App.Alert ("you must enter a name--try again!")
  }
  var nIndex = 0;
  While (xfa.sourceSet.nodes.item (nIndex) .name! = "DataConnection2")
  {
  nIndex ++;
  }

  oDB = xfa.sourceSet.nodes.item (nIndex) .racing var (1); pertaining to the specified data connection node
  App.Alert (ODB.saveXML ("Pretty"));

  var nIndex = 0;
  While (xfa.sourceSet.nodes.item (nIndex) .name! = "DataConnection3")
  {
  nIndex ++;
  }
  var oDBCount = xfa.sourceSet.nodes.item (nIndex) .racing (1); pertaining to the specified data connection node
  Configure sql call DB to get the number of records that match the criteria

  oDBCount.nodes.item (1).query.setAttribute ("text", "commandType");
  oDBCount.nodes.item (1).query.select.nodes.item (0) .value = "Select count (*) from table1 where AcctNumber = '" + inName + "'";
  oDBCount.open)
  oDBCount.close)

  Configure sql call DB to get the specified employee number

  oDB.nodes.item (1).query.setAttribute ("text", "commandType");
  oDB.nodes.item (1).query.select.nodes.item (0) .value = "Select * from table1 where AcctNumber = '" + inName + "'";
  App.Alert (ODB. Nodes.Item (1) .saveXML ("Pretty"));

  now connect to the DB and get a recording
  oDB.open)
  oDB.close ();

  Note the SQL command use the keyword count (take a look at the oDBCount section). This will return a number of return to the cllaer. When I set up the data connection, a node count (*) that appeared there. I dragged to the form and it has created a field called count that the onus at this node. When the query is executed, the number of resulting records returns to this field. You can have hidden it so that your users can not see it and also to change the binding votes to zero, so it is not included in the data file that is submitted when the form is complete.

  Paul

• Count the number of zero terms between non zero terms

  Hello.  I have a table of data of zero and nonzero (example: {1 2 56 2 3 0 0 0 0 0 2 3 5 2 3 5 2 0 0 0 0 32 43}) I need to count the number of zeros of each string of zeros and mark that number against the first zero no term following the string of zeros (NOTE (: string is used here as a description of a series of zeros, not a string variable).  So the plot which coordinates since my example would be (5.2) and (4.32).

  I'm clear on the way to the path, but I am unable to store only each final count of consecutive zeros without having unnecessary data in my plot.

  Thanks in advance to all those who have advice!

  -Mike

  Do something like that?

  EDIT: Minor Correction because of the additional function of decrement.