Count the points...

Similar Questions

• Count the edges of the 2 signals TTL (Heidenhain linear scale)

  Hi all

  This is my first post here. :-)

  Currently, I'm doing a VI to be used with a linear scale. The linear scale gives 2 TTL signals that have an offset of 90 °. The change in distance of the linear scale is given by counting the fronts and edges of the two signals. See the following image: Ua1 is signal 1 and signal 2 Ua2. You can ignore the other signals.

  

  Now, I want to count the 4 edges in order to translate the 2 signals in the distance. This means that I need advanced two counters for Rising-rising, Rising-Falling Falling Falling, falling on the rise for 2 signals. I tried to do 4 points two counters in LabVIEW but that of course does not work, because an acquisition of data can access the card TTL or I did it wrong.

  Once I have to handle this, I also want to understand the meaning.

  My card TTL: NI 9402

  My electronic Heidenhain interface: 100 IBV (http://www.heidenhain.com/fileadmin/pdb/media/img/598_160-23.pdf - also at the origin of the image)

  Hardware configuration: linear scale-> IBV (Elektronic Interface)-> NI 9402-> LabVIEW

  Signals: Analog 3-> 3 TTL-> OR 9402

  I hope I do not double post. Any help would be greatly appreciated.

  I used Heidenhain linear scales in many applications.

  As stated in the previous post, the output of your balance is as a quadrature encoder. Therefore, you must use an entry of the DAQ card counter to measure the position of the scale.

  The desired X 4 mode is done by the meter itself (not possible with some old maps of OR).

  As starting point, see measure angular Position.vi that comes with examples of LabVIEW. On your linear scale, change the type of the polymorphic DAQmx create channel VI CI linear encoder and etiquette of pulses per revolution at a Distance by pulse.

  Feel free to post back if you need further assistance.

• count the numbers peaks

  Hello, I am new user of labview. I want to count the numebr of spikes which will be detected in the pic detetctor.

  now u can suggest me some realted to counts example that appears in the chart or table

  thanq

  2249kumar wrote:

  If the particle has energy (radon) 5 MeV it takes 1. If it was again 5 MeV it takes 2 altogether, it must be with the total counts.

  I assume you mean if the energy of radon will less than 5 more than 5 (threshold), add - it to the count (+ 1).

  Don't count that peaks after having dropped below 5 and then go back on it 5 (rising edge)? hysteresis?

  Also, I assume that you will work on a simple radon energy reading (or point) at a time. Stamps to collect 100 readings in a waveform and then by peak count after collecting your data.

• How to count the number of clicks: a user makes? + Penalized if too many

  Hi all

  I have a video where the user needs to search for objects. It should click when an object is in the video. I created click boxes during the opportune times.

  What I do:

  I count the number of clicks and display it below the video. So, for example when a user clicks on an icon at the bottom of the video. If he clicks 5 times more, there are 6 icons in a row. Too much pressure, I can say that the user is cheating and give him a score of 0.

  Anyway to do this?

  The first decision is to increment the counter by 1, sorry, typed too fast should be:

  Increment of 1 V_counter

  You should see that the syntax when you created the first decision. This means that each click will add 1 to v_counter, the reason why it must be the first decision. Only indicator related to the value of v_counter must be added, given that the previous indicators are already should have been disclosed with the previous clicks. This conditional action must be triggered by the success of the click box. Because it takes several clicks, is expected to try it myself, was little crowded today. Apology.

  You add new information now: what do you mean by "conditional login?

  If you need to partition must be reported to an LMS (still do not know which), you should know that all quiz system variables are read-only. This means that the maximum score is set at the beginning of the tutorial. You can attach a note to each interactive object. Probably the best way would be to add a button next (with a break point after the click box), who will get a score. Since you want a penalty when v_counter is greater than 5, you will need to use the following two buttons: one with a score = 0 and the other with a score = X (points you want to give). If you put the beginning of the chronology of these buttons just after the timeline of the click box, you can add a final decision to the advanced conditional action that will check which button to display. If I label the value 0 has marked button "Bt_Next_0" and the version marked "Bt_Next_points" that last decision is:

  IF v_counter is greater than 5

  Disable Bt_Next_points

  Hide Bt_Next_points

  See the Bt_Next_0
  Select Bt_Next_0

  ON THE OTHER

  Disable Next_0

  Hide Bt_Next_0

  See the Bt_Next_points
  Select Bt_Next_points

• Scripting: Count the number of selected pixels (non-quadrangle) or alternative approach

  Is it possible to count the number of pixels in a selection that is not a quadrilateral? For example, if I have cntl - click on the thumbnail of a text layer, I would like to know how many pixels is selected.

  This application, if anyone has another approach to try...

  

  My goal is the place the text at some point where it covers do not all lines (or, Alternatively, the place where it covers the smallest number of pixels line). My approach is to insert a text in red to the desired location, apply a BlendMode.Multiply to the text. The number of Red pixels always on the screen will show how many pixels line I'm concealing. Then I move the text into a region and check the histogram in 76 index (which is 255,0,0), find the point with the highest number of red (meaning concealing pixels less line) and finally move the text at that location. See the code snippet below:

  var bestCX = cX;

  var bestCY = cY;

  var bestPixelDensity = - 1;

  var pixelDensity = 0;

  var searchRegionWidth = 3000;

  var searchRegionHeight = 2000;

  loop through an area 3000 x 2000 around where you want

  for (var x = cX - searchRegionWidth/2; x < cX + searchRegionWidth/2; x ++)

  {

  for (var y = cY - searchRegionHeight/2; y < cY + (searchRegionHeight/2); y ++)

  {

  textItemRef.position = new Array (x, y);

  pixelDensity = myDocument.histogram [76]; index of 255,0,0 (red)

  If this point is greater than the previous highest density, use it instead.

  if(pixelDensity > bestPixelDensity)

  {

  bestCX = x;

  bestCY = y;

  bestPixelDensity = pixelDensity;

  }

  }

  }

  move text in the best location found

  textItemRef.position = new Array (bestCX, bestCY);

  The problem is that the images I use are very large ((7000x7000px) for each histogram control takes a few seconds and I really need to move in a fairly large region (3000 x 2000) to find the best place.) I think that it is perhaps faster if I'm not using the histogram at all, and instead each time that I move the text, I select the text and see how many points is in the selection. Any help or alternative approaches would be great!

  I don't know the answer, the only thing I can think is the whole of the histogram to the selection and treatment of the histogram of the selected area.

• Count the number of records between two values of keys (BTREE)

  How can I count the number of keys between two values?

  I use python driver and BTREE access method.

  = >

  Ideally, what I want is a set of whole time series data (intervals may change) to a given number of points on average. The keys are timestamps and the values are the data that it takes on average. I need to count the number of records between two timestamps so that I can divide this figure by the number of points I need and data on average. What is the best way to do it?  Or should I keep the timestamp constant intervals and use the RECNO access method?

  Thank you
  (first post btw... and why is there not a lot of people at stackoverflow that answering the questions of Berkeley DB?)

  BDB is an integrated db and there no internal counters or statistics you might grap to use for this.    You will have to do it manually.

  You can create a cursor, grap the records you want, whenever you get the next card that you bump a counter.

  If you are using RECNO, you can use a slider to obtain the number of registration (DB_GET_RECNO), and if all that you data is in

  sequentail records with no missing documents, you can find the total number of take the last rec #-original rec # + 1 to get a count.

  If you pass the SQL API, you can issue a SQL query to give you a count.  Select count (*) where...

  As you enter the data anyway, so better perhaps to count records as you go along.

  Thank you

  Mike

• Question newbie Oracle SQL adding columns to count the contents of the other columns

  Greetings,

  I do not understand how to integrate charges to my current SQL code that would consist of food and then the elements of the car for each person. Once I understood this concept I want to apply to my real data base (Oracle) where I count medication and problems for each patient.

  Using my data of test below, for example the My goal would be to have the number of columns show that Cathy had County 3 foods and an element 1 cars (the County would need to ignore the values zero in these columns). I really don't like if the counter value is repeated in every row for that person.

  Select data1. Name, data1. Category, Data1.Results,

  Box When data1. IN category ("food") then end FOOD data1.results,

  Box When data1. IN category ('Cars') then data1. Results end of CARS

  Of

  (

  Select T1.name name, category null, null results in a_Main T1, a_Food T2 where T1.cpi_seq = T2. CPI_SEQ

  UNION

  Select T1.name, 'food', T2. Food a_Main T1, a_Food T2 where T1.cpi_seq = T2. CPI_SEQ

  UNION

  Select T1.name, 'cars', T3. Cars a_Main T1, a_Cars T3 where T1.cpi_seq = T3. CPI_SEQ

  ) data1

  where data1. Category is not null

  by name, category

  Name	Category	Results	FOOD	CARS
  Cathy	cars	Fiero	NULL VALUE	Fiero
  Cathy	food	Soaking of the points	Soaking of the points	NULL VALUE
  Cathy	food	Scoop	Scoop	NULL VALUE
  Cathy	food	SoftServe	SoftServe	NULL VALUE
  Dave	cars	Firebird	NULL VALUE	Firebird
  Dave	cars	Gremlin	NULL VALUE	Gremlin
  Dave	cars	Transport	NULL VALUE	Transport
  Dave	cars	Vega	NULL VALUE	Vega
  Dave	food	Count Chocula	Count Chocula	NULL VALUE
  Dave	food	Donuts	Donuts	NULL VALUE
  Dave	food	Little retarded	Little retarded	NULL VALUE
  Dave	food	Pizza	Pizza	NULL VALUE
  Mary	cars	Taurus	NULL VALUE	Taurus
  Mary	food	Bird seed	Bird seed	NULL VALUE
  Mike	cars	Honda	NULL VALUE	Honda
  Mike	cars	Jeep	NULL VALUE	Jeep
  Mike	food	Burger	Burger	NULL VALUE
  Mike	food	Fries	Fries	NULL VALUE
  Mike	food	Foam	Foam	NULL VALUE
  Sue	cars	Pinto	NULL VALUE	Pinto
  Sue	cars	Taurus	NULL VALUE	Taurus
  Sue	food	Humus	Humus	NULL VALUE
  Sue	food	Kabooli	Kabooli	NULL VALUE

  Select data1. Name, data1. Category, Data1.Results,

  Box When data1. IN category ("food") then end FOOD data1.results,

  Box When data1. IN category ('Cars') then data1. Results end of CARS,

  Count (*) over (partition t1.name, data1. NTC category),

  Of

  (

  Another way would be

  Select

  ..

  de)

  all

  )

  Group

  name

  Category

  order by

  name

  Category

  Depends on your needs (for example, the final projection).

• What is the significance of the points/status in the forum

  I've worked with oracle since 1992, and yet I still have no idea how the thing of points in for a job. (Obviously it has not seemed to be of great importance or I would have asked this question early :-)  But ok, for what reason if points are awarded? I noticed that the forum now has a list of "participants" in the order of 'status' which seems to be random and not in the order of points or how much bling they have on their icon. The champion of the oppressed, said "good". So where people cash in their points? Just curious.

  From there:

  https://wikis.Oracle.com/display/Forums/Forums+FAQ

  What are the "reward points"?

  It is possible for you to reward an answering machine for a 'helpful' answer 5 points or 10 points for 'proper' (or not at all). Users who accumulate in certain amounts of points reached different levels of recognition (see legend). In this way, users who are always useful or appropriate answers raise their position in the community. (Note: in order to assign the points, you must identify your message as a "question" first, which is defined as the default value.)

  So where people cash in their points? Just curious.

  I'm also not sure right now. I threw myself by the last bar where I tried to pay with some of my points, and the coffee dispenser also constantly of my offer still ignores all my points for a small cup.

  Seriously, they are more valuable. With X points you get an another badge right display to your handle, and also if you are in the top X of a forum you are displayed in the list of participants top of page (very similar as with the message previously counter) forum. Others so that they do not have a lot of value.

  see you soon

• Count the number of values selected in a form

  Hello

  I need to count the number of values in a form.

  Here's my dump of the form:

  

  I want to count the values encircled in red.

  The number I want to, so in this case is 5.

  Any suggestions?

  Aegis,

  Yes, good point.  Here's a minor tweak:

  Total: #total #.

  -Carl V.

• count the entity instances

  Hello
  I want to count the entity instances. OPA provides the same InstanceCount() function. However, only works if the entity instance screen is submitted. I want to make it work any any point. Any idea?

  To control a flow on a summary screen, simply create a Boolean visibility attribute:

  the flow is enabled if
     InstanceCount(the thingamies) > 0
  

  Then, set the attribute for visibility on the flow on the summary screen "the flow is activated" with a default state of persons with disabilities (or hidden). Then, it will be hidden when the number of instances is unknown.

• script function IDOC to count the string

  Hello
  
  Does anyone know if there is any build-up in idoc script function to count the number of string.
  
  For example:
  A, B, C, D, E
  
  I want to count how many comma is using script idoc. If there is no generation in function, what would be the best way to achieve this.
  
  Thank you very much.

  There is no built-in function, but I would simply do this:

  <$rsMakeFromString("MyStringRS", "a,="" b,="" c,="" d,="" e")$="">
  <$numCommas =="" mystringrs.#numrows="" -="" 1$="">

  Good luck and please award points as you wish.

• Count the unused paragraph styles

  I want to check InDesign documents my students to see if they have been neatly with their style sheets. I have a script that works partially (I think this would work in CS4, if you replace CS4 CS5).

  The bit that does not try to save the styles within groups. I commented in the script to display the error section. I get the error:

  "Invalid value for the set property" applied paragraph style". "Planned to string, the style section or anything, but will put \"body text (body). " "number 30477

  I tried to put the name of the style and the group, because that's how it works if you do it manually, IE body text (body). But it does not work.

  Any help would be appreciated.

  property myTypeReport: ' " - makes available anywhere.
  " game of myTypeReport to '" - prevents report becomes cumulative when running several times.
  Tell application "Adobe InDesign CS5"
  the value myDocument to rating 1
  game of unusedStyles to "'
  game of myFoundItems to "'
  
  game myDescription to "unused paragraph styles"
  the value myParagraphStyleGroups for each paragraph style group of myDocument
  the value myParagraphStyles for each paragraph style of myDocument
  
  Repeat with I have a 3 in (County of myParagraphStyles)
  define myStyle to the the point i of myParagraphStyles name
  the value find text preferences for Nothing
  the value text preferences to change anything
  the value applied paragraph style to find text preferences to myStyle
  tell myDocument
  the value myFoundItems to find text
  if (account myFoundItems) = 0 then the value unusedStyles to (unusedStyles + 1).
  end say
  end Repeat
  
  -This is the section of the error
  Repeat with x 1 to the number of myParagraphStyleGroups
  set myGroup to the of the point x of myParagraphStyleGroups name
  the value myParagraphStyles for this entire paragraph styles to paragraph style group myGroup of myDocument
  Repeat with I have from 1 to (count of myParagraphStyles)

  
  game of myStyle to (name of point i of myParagraphStyles) & "(" & myGroup & "") " string "
  -Returns the myStyle
  the value find text preferences for Nothing
  the value text preferences to change anything
  the value applied paragraph style to find text preferences to myStyle
  tell myDocument
  the value myFoundItems to find text
  if (account myFoundItems) = 0 then the value unusedStyles to (unusedStyles + 1).
  end say
  end Repeat
  end Repeat
  -finish the section error
  
  "myReport game to "(" & unusedStyles & "")" " & "\t\t" & myDescription
  if (County unusedStyles) > 0 then the value myTypeReport to myTypeReport & myReport and return
  return myTypeReport
  end say

  Can you make best use of all styles of paragraph in your document instead of styles of paragraph of the document, which should access the independent styles of groups? You would have to give on the name using as reference (probably a good thing anyway) and use the style itself (in your find/replace).

• Count the number of times you click on hot spots.

  The specific problem I'm having right now counts the number of times where an is clicked a hotspot. I have four hot spots and need to track the number of times where is clicked on each hotspot. The variable "tent" gives me the total for the whole interaction. Since they are not considered, I can't use correct or wrong. You have any ideas? I would use the "tries@title" icon, but all the hotspots are contained in the icon interaction so that no longer works.

  Thanks for any help you can provide,

  I often structured interactions so that I can enjoy the variable 'ChoiceNumber. If your access points are all consecutive and they are the first things to the right of the interaction, you can use a variable from the list.

  [ClickList: =]

  Then at the top of each of your answers, you can use

  ClickList [ChoiceNumber]: = ClickList [ChoiceNumber] + 1

  Each task in ClickList is taken into account the time that spot has been used and you can use the sum to get the total of all tasks. If they can not be the first thing then you can always use an offset value... ClickList [ChoiceNumber-4]: = ClickList [ChoiceNumber-4] + 1

  HTH,

  Mike

• How adobe does not count the activations?

  How adobe does not count the activations of computer for this product.  I activated 2 computers, disabled 2 computers and then tried to activate another, only to be told that I got too many activations.  I tried to use my new Sony reader and was told by Sony that it was a question of adobe.  I talked to adobe to be told that it was a computer problem.  I have a new Christmas gift which is totally unusable!  We should be able to understand it!

  Please give me some help here!  It was a very expensive gift to have just sitting around.  I should have gotten the KINDLE!

  You should only withdraw the authorization if:

  -You give the computer

  or

  -You must decidied use a different AdobeID (and give up books associated with the old AdobeID).

  This is the last that can cause you a problem as Sony software

  I guess at this point you have submtted a case of taking in charge of web ( http://www.adobe.com/support/digitaleditions click on 'Submit a web case')

  Reset the number of activations is a relatively simple application, that our support team can support, and who should get so that you can re-enable the computers.

• variable with two digits after the point

  Hi all

  How can I specify variable to work with two numbers (one, three) after the point?

  e.q.

  Set one to 3.14159265358 like (lack of knowledge here)

  return a

  3.14 returned must

  It is a two-step process:

  Set A to 3.14159265358

  Set A (round (A * 100)) / 100

  The 100 can be changed as needed.

  (144176)