Create a trigger (pk of sequence) & JPA

Similar Questions

• Sequence creates random numbers instead of sequence numbers

  Hello
  
  I created a sequence on a column in the table and then I created a trigger before insert on this table. Here's the script:
  
  CREATE SEQUENCES SEQ_COL1
  START WITH 1
  MAXVALUE 9999999999999999999999999999
  MINVALUE 1
  NOCYCLE
  NOCACHE
  ALL;
  
  CREATE OR REPLACE TRIGGER trig_table1
  before inserting
  Table 1 for each line
  Start
  
  If: new.col1 is null then
  Select seq_col1.nextval in: double new.col1;
  end if;
  end;
  
  The problem I have is, the number generated for the col1 is random as after 1, it goes to 230 then to 340 etc... instead of being sequential.
  
  Please let me know if I'm missing something.

  Hello

  Use the ORDER parameter in your create sequence - statement.

  Heike cordially

• How can I create a trigger e-mail messages sets a phone when Gets an email from particulry?

  Hi team, support
  Customer email thunderbird whit, how can I create a trigger e-mail messages rule a phone dial when comes a word of the body particularly E-mail?

  Kind regards
  Alessandro.

  I don't think you can do this with ordinary Thunderbird. But this add-on

  https://addons.Mozilla.org/en-us/Thunderbird/addon/FiltaQuilla/

  allows you to run javascript or IIRC, launch an external program when a given filter condition is met. So this does not exactly provide an answer to your question, but allows a possible solution. '

• AE CC14 creates a composition without the sequence first inside!

  There, hell

  Since the next generation of Adobe out our hole Creative Suite is to ventilate for no rational reasons...

  However, we work with a whole group with many parallel projects and would not be updated until we have finished our real projects because of the same issue, there was last year. Open files with new version caused you were not able to open the file with an older version... (speaking of the first).

  My question:

  I'm still working with first CC 2014 and after effects CC 2014. I import my first sequence in my AE project. Now, I want to create a demo of my sequence in it. There are many ways to do it. So there are for example the icon of the model, or you can do it with the menu bar.

  It creates the composition but without the sequence in it. I do not use anything. Not all fonts and even no animation. Import of simple dynamic links (not import itself, it is imported, but it does not appear in the model. Cannot move a drop, can't do anything with it).

  

  What's wrong? He worked for more than a year.

  Now the update is online, and because of these 'new' problems in CC14 you're forcing the user to udate to CC15! It's the feeling I get when suddenly the day of the liberation of CC15 my entire deparquement Suite CC14 is crush every 20 minutes just without reason... without giving me an option for an error report.

  On my Mac:

  iMac 2012

  3.4 GHz Intel Core i7

  16 GB 1600 MHz DDR3

  NVIDIA GeForce GTX 680MX 2048 MB

  OS X 10.9.4 (13E28)

  Would be nice, if there is a rational solution for this.

  I had this problem again. And because all members of the support team supports so favorable, here's a way you can fool AE.

  Create a solid. Then right-click on the solid and select "replace images.

• Create the trigger for multiple users

  I am trying to create a trigger for a DDL event which gives an error for 2 users when they try to create a database object or a table.
  
  Here is my code. When ran it gives me the following error: "WARNING: trigger created with errors of complication."
  
  Any idea would be appreciated.
  
  Thank you!
  
  CREATE OR REPLACE TRIGGER trigger_before_create_object
  BEFORE YOU CREATE ON THE DATABASE
  
  BEGIN
  
  IF USER = USER OR "VPD_CLERK1" = "DBSEC_CLERK."
  THEN
  RAISE_APPLICATION_ERROR (' you do not have the privilege to create tables or other database objects.) Contact your administrator if you need the privilege. ") ;
  END IF;
  END;
  
  Published by: mkmety on April 20, 2013 12:10

  Welcome to the forum!

  Whenever you post provide your Oracle version 4-digit
  >
  I am trying to create a trigger for a DDL event which gives an error for 2 users when they try to create a database object or a table.

  Here is my code. When ran it gives me the following error: "WARNING: trigger created with errors of complication."

  Any idea would be appreciated.

  Thank you!
  >
  And to alert you to the need to view the errors you got. If you did you will see this:
  >
  PLS-00306: wrong number or types of arguments in the call to "RAISE_APPLICATION_ERROR.
  >
  Oracle cannot raise your exception if you:

  1. do not define an exception to throw
  2. don't tell Oracle how exception to throw

  See the section "Defining your own Error Messages (procedure RAISE_APPLICATION_ERROR)" in the doc of the PL/SQL language
  http://docs.Oracle.com/CD/B28359_01/AppDev.111/b28370/errors.htm#i1871

  This article has examples that show how to raise your exceptions.

• Create the trigger to insert data from one user to another user in same Databas

  Dear Sir, I created a trigger as follows
  
  CREATE OR REPLACE TRIGGER TRIGGER1
  BEFORE INSERTING
  ON table1
  FOR EACH LINE
  BEGIN
  INSERT IN THE TEST. TABLE2
  VALUES (: NEW.) COLUMN1,: NEW. COLUMN2,: NEW. COLUMN3,: NEW. COLUMN4);
  END;
  /
  
  I want here to insert my user to user Test data. In this Situation when I Execute The above Trigger it shows error PL/SQL: ORA-00942: table or view does not exist
  
  Help, please

  What do you mean by run the trigger?
  Do you compile?
  Can be open as a TEST and do the following and try to compile your code of the trigger again.

  grant insert on TEST.TABLE2 to youruser;
  

  See you soon,.
  Manik.

• Create a trigger to check if the synonym already exists in the db

  Hello
  How can I create a trigger to check if the synonym already exists in the db and if exists then do not create a synonym.
  
  my work: (it's like a schematic I developed)
  
  Select * from all_synonyms;
  declare
  number of s_exists;
  Start
  -checks if the synonym
  Select 1 in s_exists to all_synonyms;
  -a mistake gets stimulus if it's not
  exception when no_data_found then
  -The DOF should be done inside
  run immediately ' create or replace synonym;
  end;
  /
  
  any help is really appreciated...
  
  Thank you
  
  Published by: Vinay Mummadi on 29 March 2013 12:51

  There are a few rules of trade more that you need to consider.

  Do not forget that there are synonyms both PUBLIC and PRIVATE.

  Just because there is a synonym of a given name does NOT mean it's the only one who tries to create a given user. If a user tries to create a synonym private, you need see if the OWNER and the NAME, the two match.

  What is a user issuing a CREATE or REPLACE for their own private synonym? Is this OK or who need help also?

• Error no valid identifier when you try to create a trigger

  Hi all
  
  I get this weird error when you try to create a trigger. Basically, it updates a table of different relationship on INSERT or UPDATE.
  
  The error I get is:
  * PL/SQL: ORA-00904: "cid": invalid identifier *.
  

  SET SERVEROUTPUT ON
  CREATE or REPLACE TRIGGER UPDATE_REL_TABLE 
       AFTER INSERT OR UPDATE ON XF_PROJECT_CODE
  FOR EACH ROW 
  DECLARE
       customer_count NUMBER;
       n_cid NUMBER;
  BEGIN 
       -- CHECK if company exist
       SELECT COUNT(*) INTO customer_count FROM XF_CLIENTS WHERE UPPER(client_name) = UPPER(:NEW.company);
       
       CASE 
       WHEN customer_count > 0 THEN
            -- GET CUSTOMER ID
            select t.cid INTO n_cid FROM XF_CLIENTS t WHERE t.CLIENT_NAME = :NEW.company;   // ERROR HERE!!
            
            -- UPDATE relationship table
            INSERT INTO XF_CLIENT_CODE_R (PROJECT_CODE_ID, cid) VALUES (:NEW.project_code_id, n_cid);
       
       ELSE
            -- customer does not exist
            n_cid := XF_CLIENTS_SEQ.NEXTVAL;
            
            -- Create client
            INSERT INTO XF_CLIENTS(cid, client_name) VALUES(n_cid, :NEW.company);
                 
            -- update relationship table
            INSERT INTO XF_CLIENT_CODE_R(project_code_id, XF_cid) VALUES (:NEW.project_code_id, n_cid);
            
       END CASE;
  END; 
  /
  SHOW ERRORS;

  The column exists and matches the data type (number). Any help appreciated. bit at loss where I'm wrong.

  Good fishing! Who'd do all right.

• ORA-00928: lack of keyword SELECT when you create a trigger

  Hello
  
  I am trying to create a trigger that is simple for the purpose of verification as below:
  

  CREATE OR REPLACE TRIGGER customer_audit
  before insert or update or delete on CUSTOMER for each row
  BEGIN
     if :old.cname is null and :new.cname is not null or :old.cname is not null and :new.cname is null  or :old.cname != :new.cname  THEN
        INSERT INTO audit_table (:old.cname,  :new.cname, null, 'cname');
        COMMIT;
     ENDIF;
  end;

  This compiles with warning. When I check the warning, he said:
  

  TRIGGER customer_audit compiled
  Warning: execution completed with warning
  3/32           PL/SQL: ORA-00928: missing SELECT keyword
  3/7            PL/SQL: SQL Statement ignored

  Do not know how to SELECT is part of what I'm trying to do here, or miss me something of totally. Help, please. Thank you very much.

  Change ENDIF; in END IF; and try again...

• Create a trigger and a procedure

  Hello
  
  I need to create a TRIGGER to insert or update a value in a field in a table.
  "That is: insert or update my table (SUP_ACCOUNT) setting the field ACCOUNT ' 10.1.1.1".
  Fields on the table SUP_ACCOUNT (COMPANY, BILL, COD_SUPPLIER, ACCOUNT, VALUE, TEXT, DATE_ACCOUNT)
  
  And create a PROCEDURE that every 90 minutes check the item (ITEM table) which was inserted today and update another table (table ITEM_ACCOUNTS) with a value, i.e. 10.2.2.2
  The fields are equal are:
  ELEMENT (COMPANY, CODE_ITEM)
  ITEM_ACCOUNTS (COMPANY, CODE_ITEM) in this table, I need change the field ACCOUNT of to 10.2.2.2
  
  Could I make myself understood?
  
  ---
  Oracle Database 11 g Release 11.2.0.1.0 - 64 bit

  something like that;

  create or replace procedure my_procedure as
    begin
     update t1 set t1.a = '10.1';
     commit;
  
  end my_procedure;
  /
  
  begin
    -- Job defined entirely by the CREATE JOB procedure.
    dbms_scheduler.create_job (
      job_name        => 'update_job',
      job_type        => 'PLSQL_BLOCK',
      job_action      => 'begin my_procedure; end;',
      start_date      => systimestamp,
      repeat_interval => 'freq=minutely; interval=90',
      end_date        => null,
      enabled         => true,
      comments        => 'Job defined to run every 90 minutes.');
  end;
  /
  

  See this for more details:

  http://download.Oracle.com/docs/CD/B28359_01/server.111/b28310/schedadmin006.htm

• Help me in creating a trigger Insert and Update Options

  Hello
  
  Please help me in creating a trigger.
  
  My requirement is that, after insert or update on a Table, I want to launch an event.
  
  I have started this way, but does not know how to fully implement it.
  
  I have a dept table
  
  
  CREATE TRIGGER DepartmentTrigger
  INSERT AFTER on Dept
  BEGIN
  INSERT INTO mytable VALUES("123","Kiran");
  END DepartmentTrigger;
  
  
  Please tell me how I can put the update option also.
  
  Thanks in advance.

  Please tell me how I can put the update option also.

  Add "or update". ;-)

  Here are a few suggestions, but you definitely need to refer to the manual page that suggested the previous poster.

  CREATE OR REPLACE the TRIGGER DepartmentTrigger
  AFTER INSERT or Update ON Dept
  BEGIN
  INSERT INTO mytable VALUES(:new.) Dept 'DEPT ADDED OR CHANGED');
  END DepartmentTrigger;

  The "or replace" means that you can replace the shutter button as you develop without having to type in a drop statement each time. Just change and reissue your script over and over again until you get it right.

  The addition of "update or" or "Or remove" fact the trigger too much fire for these events. Note, you peut want separate triggers in different scripts and with different names for each event. You must decide whether your design is really the same thing either an insert or an update.

  : new. Dept, this is how you should refer to the vale has changed the Dept column (: old.) Dept is the previous value). I changed the double quotes in the string in the clause VALUES of apostrophes.

  Andy

• Need to create a trigger that generates multiple rows in another table

  {size: 12} Hello
  
  I use Oracle9i (9.2.0.4.0)
  
  My problem is:
  I need to create a trigger that create different in the other table lines when someone will introduce a new line in the first table.
  
  For this, I use the table 4:
  
  1. first one where you want the trigger.
  2. a second just to take information.
  3. a third to make a trip meter.
  4. the fourth is the table where I want to create new lines. {size}
  
  Here is a summary of these 4 tables:
  
  {color: blue} Table 1
  STOJOU
  Number ¿Nulo? Tipo
  STOFCY_0 NOT NULL VARCHAR2 (9)
  ITMREF_0 NOT NULL VARCHAR2 (60)
  LOT_0 NOT NULL VARCHAR2 (45)
  VCRTYP_0 NOT NULL NUMBER (3)
  VCRNUM_0 NOT NULL VARCHAR2 (45)
  VCRLIN_0 NOT NULL NUMBER (10)
  QTYSTU_0 NOT NULL NUMBER
  NUMVCR_0 NOT NULL VARCHAR2 (45) {color}
  
  {color: blue} Table 2
  ITMMASTER
  Number ¿Nulo? Tipo
  ITMREF_0 NOT NULL VARCHAR2 (60)
  ZCOEFI_0 NOT NULL NUMBER {color}
  
  {color: blue} Table 3
  ZCTUART;
  Number ¿Nulo? Tipo
  CTUART_0 NOT NULL NUMBER (10)
  CTUDATE_0 NON NULL DATE {color}
  
  {color: blue} Table 4
  ZUART
  Number ¿Nulo? Tipo
  ZUARTDM_0 NOT NULL VARCHAR2 (102)
  STOFCY_0 NOT NULL VARCHAR2 (9)
  STOCOU_0 NOT NULL NUMBER
  ITMREF_0 NOT NULL VARCHAR2 (60)
  LOT_0 NOT NULL VARCHAR2 (45)
  CREDAT_0 NOT NULL DATE
  QTYSTU_0 NOT NULL NUMBER
  STA_0 NOT NULL VARCHAR2 (3)
  VCRLIN_0 NOT NULL NUMBER (10)
  VCRNUM_0 NOT NULL VARCHAR2 (45)
  VCRTYP_0 NOT NULL NUMBER (3) {color}
  
  I do this trigger:
  

  CREATE OR REPLACE TRIGGER CREA_REGISTROS_TRAZA
  AFTER INSERT ON STOJOU
  FOR EACH ROW
  DECLARE
     n INTEGER;
     ct NUMBER;
     fecha_actual VARCHAR2;
     fecha_old VARCHAR2;
     codigo_dm VARCHAR2;
  BEGIN
     fecha_actual := TO_CHAR(SYSDATE, 'DD/MM/YYYY');
     -- SELECT TO_CHAR(sysdate, 'DD/MM/YYYY') INTO fecha_actual FROM DUAL;
     SELECT TRUNC((STOJOU.QTYSTU_0/ITMMASTER.ZCOEFI_0),0) INTO n FROM STOJOU INNER JOIN ITMMASTER ON STOJOU.ITMREF = ITMMASTER.ITMREF;
        FOR i IN 1 .. n
     LOOP
        SELECT CTUART_0,TO_CHAR(CTUDAT_0, 'DD/MM/YYYY') INTO ct,fecha_old FROM ZCTUART;
        IF fecha_old <> fecha_actual THEN
          ct := 0;
        END IF;
        ct := ct + 1;
        INSERT INTO ZCTUART
          (CTUART_0,CTUDAT_0)
        VALUES
          (ct,SYSDATE);
        codigo_dm := SUBSTR('000000000000000000000',1,20 - LENGHT(NEW.ITMREF_0)) || NEW.ITMREF_0 || SUBSTR('0000000000',1,10 - LENGHT(NEW.LOT)) || NEW.LOT || SUBSTR('0000',1,4 - LENGHT(ct)) || ct;
        INSERT INTO ZUART
          (ZUARTDM_0,ITMREF_0,CREDAT_0,STA_0,QTYSTU_0,LOT_0,STOFCY_0,VCRLIN_0,VCRNUM_0,VCRTYP_0)
        VALUES
          (codigo_dm,NEW.ITMREF_0,SYSDATE,0,NEW.QTYSTU_0,NEW.LOT_0,NEW.STOFCY_0,NEW.VCRLIN_0,NEW.VCRNUM_0,NEW.VCRTYP_0);
     END LOOP;
  END CREA_REGISTROS_TRAZA;
  /

  {size: 12} And the error message I get States is just:
  "The trigger was created with compilation errors."
  Thanks for the help {size}

  You must prefix your NEW "columns" with a colon, as in: NEW.

• I need help to create a trigger

  Hi, first off I want to just say that I am a complete newbie when it comes to creating triggers so please bear with me.
  
  I want to create a trigger that checks a condition prior to an update. Specifically, I have a two tables RENTAL and VEHICLE respectively, where the RENTAL table follows deployed vehicle rentals and the CAR table contains details about each vehicle. The main foreign key linking two tables is the identification number of the vehicle (VEH_VIN). The table of VEHICLE also contains an attribute called COND_CODE, as in the condition of the vehicle, which can contain the values TANK 'n', 'E', of the ', or 'P' (which means new, Excellent, satisfactory or poor).
  
  Here's what I want the trigger to do. When a new entry is made to the RENTAL table, I want the trigger to check the status of the new entry vehicle (COND_CODE) in the VEHICLE dashboard. If the condition of the vehicle is poor, so I want the trigger to stop the new entry deployed to the location table and an error message to be printed. If the condition of the vehicle is not poor, the new entry is added successfully.
  
  I created a preliminary trigger, (detailed below), but I'm sure that this is not correct:
  
  CREATE OR REPLACE TRIGGER no_poorcond
  Before you INSERT or update OF rental WE of veh_vin
  FOR EACH LINE
  BEGIN
  IF cond_code = "P" THEN
  RAISE_APPLICATION_ERROR (-20001, ' cannot register a vehicle in bad state')
  ON THE OTHER
  veh_vin =: new.veh_vin
  DBMS_OUTPUT. Put_line ('new location has been added');
  END IF;
  END;
  
  Can anyone tell me please what changes I should make to the trigger in order to perform the actions that I have described above? Thanks in advance.

  Opps

  I missed ';' at the end of the select query. I not had your table structure, so I found difficulties in my database running of your relaxation.
  Still, you can try this

  CREATE OR REPLACE TRIGGER no_poorcond
  BEFORE INSERT OR UPDATE OF veh_vin ON rental
  FOR EACH ROW
  declare
  v_cond_code char(1);
  BEGIN
  select cond_code into v_cond_code from VEHICLE where veh_vin = :new.veh_vin;
  IF v_cond_code = 'P' THEN
  RAISE_APPLICATION_ERROR(-20001, 'Cannot register a vehicle in poor condition');
  END IF;
  END;
  

• Create the trigger after insert

  Hello
  
  I would like to ask how to create a trigger after insert on a table. Basically, what I wanted to do are when an insert to table1 it will insert the records to table2. But the problem is that folders that will be inserted in the new tables are entries/fields, who lived in NEW York City (on table of ld)
  
  after insertion, I wanted to add another field in table2 as status
  
  
  create table table1)
  
  Name varchar2 (55),
  City varchar2 (55)
  
  );
  
  create (table2)
  
  Name varchar2 (55)
  status int (1)
  )
  
  Hope you could help me.
  
  Thank you
  
  Best regards

  antok1015 wrote:
  Hello

  I would like to ask how to create a trigger after insert on a table. Basically, what I wanted to do are when an insert to table1 it will insert the records to table2.

  It's easy...

  SQL> create table table1(
    2    Name varchar2(55),
    3    City varchar2(55)
    4  );
  
  Table created.
  
  SQL>
  SQL> create table table2 (
    2    Name varchar2(55),
    3    status number(1)
    4  );
  
  Table created.
  
  SQL>
  SQL> create or replace trigger trg_tbl1 after insert on table1
    2  for each row
    3  begin
    4    insert into table2 values (:new.name, 1);
    5  end;
    6  /
  
  Trigger created.
  
  SQL> insert into table1 values ('Fred','Bob');
  
  1 row created.
  
  SQL> select * from table2;
  
  NAME                                                        STATUS
  ------------------------------------------------------- ----------
  Fred                                                             1
  
  SQL>
  

  But the problem is that folders that will be inserted in the new tables are entries/fields, who lived in NEW York City (on table of ld)

  after insertion, I wanted to add another field in table2 as status

  This is not sensible. Please explain what you mean.

• What is this error when creating a trigger

  Hello
  
  I have create a trigger and get the following error. What is - c
  
  1 CREATE OR REPLACE TRIGGER TRG_AUDIT_LOGON AFTER
  2 LOG ON TO THE DATABASE
  3 Declare
  4 v_sid v$session.sid%type;
  type of v_serial 5 v$ session.serial # %;
  v_username 6 v$session.username%type;
  v_osuserid 7 v$session.osuser%type;
  8 v_machinename v$session.machine%type.
  v_PROGRAM 9 v$session.program%type;
  v_TERMINAL 10 v$session.terminal%type;
  11 v_hostname v$instance.host_name%type;
  v_instance_name 12 v$instance.instance_name%type;
  13 v_application_id v$database.dbid%type;
  date of v_logon_time 14;
  15 v_Audit_tab_check varchar2 (30);
  16 v_system_users_tab_check varchar2 (30);
  17 v_sql_Audit_upload varchar2 (1000): = "INSERT INTO dbaoper. T_AUDIT (HOST_NAME, APPLICATION_ID, INSTANCE_NAME, SID, SERIAL #, username, OSUSERID, MACHINENAME, PROGRAM, TERMINAL, LOGON_TIME) VALUES (: v_hostname,: v_application_id,: v_instance_name,: v_sid,: v_serial,: v_username,: v_osuserid,: v_machinename,: v_program,: v_TERMINAL,: v_logon_time) ';
  18 type c_audit_cur_typ is ref cursor;
  19 C_Audit c_audit_cur_typ;
  20 V_system_users_tab: = "T_SYSTEM_USERS";
  21 No_Audit_records Exception;
  Begin 22
  23 select table_name in v_Audit_tab_check from dba_tables where owner = 'DBAOPER' and table_name = "T_AUDIT";
  24 select table_name in v_system_users_tab_check from dba_tables where owner = 'DBAOPER' and table_name = "T_SYSTEM_USERS";
  25 c_Audit open for ' SELECT sid, serial # username, osuser, machine, terminal program v $ session WHERE audsid = userenv ("' sessionid" ') and program not as "'oracle@%J0%"' and no user name (select * from dbaoper.' |) V_system_users_tab |') and type! = "' BACKGROUND"' ';
  26 c_Audit of fetch in v_sid, v_serial, v_username, v_osuserid, v_machinename, v_program, v_TERMINAL;
  27 if c_Audit % Notfound then
  28 lift No_Audit_records;
  Else 29
  30 select host_name, instance_name in v_hostname, v_instance_name from v$ instance;
  31 select dbid from v_application_id from v$ database;
  32 select sysdate in double v_logon_time;
  33 execute immediate v_sql_Audit_upload using v_hostname, v_application_id, v_instance_name, v_sid, v_serial, v_username, v_osuserid, v_machinename, v_program, v_TERMINAL, v_logon_time;
  34 end if;
  35 close C_Audit;
  exception of 36
  37 when no_data_found then
  38 dbms_system.ksdwrt (2, 'ORA-20001 Audit T_AUDIT or T_SYSTEM_USERS not found Audit information tables are not entered'
  (39);
  40 what then No_Audit_records
  41 dbms_output.put_line ('Audit number to insert records");
  42 * end;
  SQL > /.
  
  WARNING: Trigger created with compilation errors.
  
  SQL > sho err
  Errors for TRG_AUDIT_LOGON TRIGGER:
  
  LINE/COL ERROR
  -------- -----------------------------------------------------------------
  18/20 PLS-00103: encountered the symbol "=" when expecting one of the
  Next:
  constant exception < an ID >
  < a between double quote delimited identifiers > double Ref table Fedya
  char time timestamp interval date binary national character
  NCHAR
  The '< an identifier >' replaced with '=' to
  continue.
  
  
  Thank you
  Pramod

  replace * "' * with *" *. For example userenv ("' sessionid" ') to userenv ("sessionid")