Display data with sql
Hello
create TABLE EMP ( )
Emp_id NUMBER ,
DATE of DT_FROM ,
DATE of DT_TO ,
CREATE_DATE DATE)
into EMP
(ID_EMP, DT_FROM, DT_TO, CREATE_DATE)
Values
()100 TO_DATE (March 1, 2001 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (June 30, 2001 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (1 May 2001 05:44:20 ', ' MM/DD/YYYY HH24:MI:SS '));
into EMP
()Emp_id DT_FROM DT_TO CREATE_DATE( )
Values
()100 TO_DATE (1 July 2008 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (April 30, 2012 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (May 8, 2009 14:11:21 ', ' MM/DD/YYYY HH24:MI:SS '));
into EMP
(ID_EMP, DT_FROM, DT_TO, CREATE_DATE)
Values
()100 TO_DATE (1 June 2008 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (April 30, 2012 00:00:00 ', "MM/DD/YYYY HH24:MI:SS"), TO_DATE (June 26, 2009 15:48:15 ', ' MM/DD/YYYY HH24:MI:SS '));
into EMP
(ID_EMP, DT_FROM, DT_TO, CREATE_DATE)
Values
()100 TO_DATE (September 30, 2012 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (September 30, 2012 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (September 28, 2012 17:13:52 ', ' MM/DD/YYYY HH24:MI:SS '));
into EMP
(ID_EMP, DT_FROM, DT_TO, CREATE_DATE)
Values
()100 TO_DATE (October 1, 2012 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (30 April 2013 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (December 14, 2012 11:42:15 ', ' MM/DD/YYYY HH24:MI:SS '));
into EMP
(ID_EMP, DT_FROM, DT_TO, CREATE_DATE)
Values
()100 TO_DATE (31 May 2013 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (31 May 2013 00:00:00 ', ' MM/DD/YYYY HH24:MI:SS '), TO_DATE (May 8, 2013 13:26:30 ', ' MM/DD/YYYY HH24:MI:SS '));
expected results:
DT_FROM DT_TO
03 / 01 / 2001 06/30/2001
06 / 01 / 2008 04/30/2012
09 / 30 / 2012 09/30/2012
10 / 01 / 2012 04/30/2013
05 / 31 / 2013 05/31/2013
reason for with the exception of the the 1 July 2008 ' line is there is another line with less dt_from value that was created after this line created. If there is a sub sequent row
less dt_from value and latest creation date we need to get that line and exclude the lines as over a.
Thank you
Hello
So, you need to know if there is a previous dt_from on a line more later (where 'later' is determined by create_date). This sounds like a job for the analytical MIN function:
WITH got_min_dt_from AS
(
SELECT dt_from, dt_to
, MIN (dt_from) over (PARTITION BY emp_id - just guessing
ORDER BY DESC create_date
) AS min_dt_from
WCP
)
SELECT dt_from, dt_to
OF got_min_dt_from
WHERE dt_from = min_dt_from
ORDER BY dt_from
;
Emp_id play a role in this problem? It is difficult to say when all the rows of the data sample has the same value.
Tags: Database
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drop table ta purge; create table ta as SELECT 'A' AS A FROM dual union all select 'B' from dual; drop table tb purge; create table tb as SELECT 'A' AS A, 'B1' AS B FROM dual UNION ALL SELECT 'A', 'B2' FROM dual ; drop table tc purge; create table tc as SELECT 'A' AS A, 'C1' AS C FROM dual UNION ALL SELECT 'A', 'C2' FROM dual UNION ALL SELECT 'A', 'C3' FROM dual UNION ALL SELECT 'A', 'C4' FROM dual ; drop table td purge; create table td as SELECT 'A' AS A, 'D1' AS D FROM dual UNION ALL SELECT 'A', 'D2' FROM dual UNION ALL SELECT 'A', 'D3' FROM dual;
Now 3 solutions: full join, group by and pivot:
with b as ( select a, b, row_number() over(partition by a order by b) rn from tb ) , c as ( select a, c, row_number() over(partition by a order by c) rn from tc ) , d as ( select a, d, row_number() over(partition by a order by d) rn from td ) select a, b, c, d from ta left join b using(a) full join c using(a, rn) full join d using(a, rn) order by a, rn; select a, max(b) b, max(c) c, max(d) d from ( select a, null b, null c, null d, 1 rn from ta union all select a, b, null, null, row_number() over(partition by a order by b) rn from tb union all select a, null, c, null, row_number() over(partition by a order by c) rn from tc union all select a, null, null, d, row_number() over(partition by a order by d) rn from td ) group by a, rn order by a, rn; select A,B,C,D from ( select 'A' tab, a, null val, 1 rn from ta union all select 'B' tab, a, b, row_number() over(partition by a order by b) rn from tb union all select 'C' tab, a, c, row_number() over(partition by a order by c) rn from tc union all select 'D' tab, a, d, row_number() over(partition by a order by d) rn from td ) pivot(max(val) for tab in('B' B, 'C' C, 'D' D)) order by a, rn;A B C D A B1 C1 D1 A B2 C2 D2 A C3 D3 A C4 B Personally, I would prefer to view the data by using a 'join the union', in order to avoid the impression that the different detail records are related somehow.
select ta.a, b, c, d from tb full join tc on 1=0 full join td on 1=0 right join ta on ta.a in (tb.a, tc.a, td.a);
A B C D A B1 A B2 A C1 A C2 A C3 A C4 A D1 A D2 A D3 B -
How always display the date with taskbar buttons activated in widows 8?
It's got to be average, just to be there. Even using the buttons small taskbar, it is actually enough space to have always the date and stacked. I would be well with them, next to each other also. I don't really understand why the date masks even as it would fit really well. I'm fine with the help of a third party program if necessary. I already have the classic interface installed because microsoft somehow forgot to add the menu start Windows 8.
There are several strange suggestions and wonderful here for you to play with. Make sure that you first create a system restore point.
Windows 7 - display date using small icons
http://superuser.com/questions/89628/Windows-7-display-date-using-small-icons -
Encapsulate data problems when loading with sql loader
Hi all
I use sql loader to load data into a flat file HP UNIX.
I find the fi the NUMBER data type or date type get wraped to the new line, the control file triggered errors.
The data looks like to (field dilimiter is |, record dilimter is ~):
1 A87CCH | 1 A87CCH | PLAN_ACCOUNT_PROMOTION | HIR6A-1 | 20100706 06:06:24 | 1 DNE1 | DC?
2010.7 FY1011 Promoiton | 1 A87AW0 | 1 HJEZE | Private | 20100730 00:00:00 | 00 20100710
: 00:00 | 0 | Completed | 20100730 00:00:00 | 20100710 00:00:00 | 0 | 1 4A6PKP | TFMAAI | N
| 0 | 0 | 0 | 0 | 0 | 0 | 1 4A6PKP | Approved | 1 8U4E-163 | 00:00:20110630 00 |
20100708 01:45:35 | 20100707 00:00:00 | -1||| 0 | 9000 | 0 | 0 ||| 100. N | 0 | 0 | 0 | 0
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | N | 20110426 04:01:34 | 1 8U4E-163 | 0|||||||||
||||| ~
The control file looks like:
OPTIONS (ERRORS = 1000, DIRECT = TRUE, PARALLEL = TRUE, DATE_CACHE = 5000, discardmax = 50)
UNRECOVERABLE
load data
INFILE ' / home/bs7822/leon/leon.dat' "str" ~ "»
BADFILE ' / home/bs7822/leon/leon.bad'
DISCARDFILE ' / home/bs7822/leon/leon.discard'
ADD THE LEON_123456 TABLE
FIELDS TERMINATED BY ' | '. SURROUNDED OF POSSIBLY "" "
TRAILING NULLCOLS
(
X_INTERFACED_DT EXPRESSION "to_date (replace (replace (: X_INTERFACED_DT_BF, chr (10),"), Chr (13), "), 'YYYYMMDD hh24:mi:ss')", "
X_INTERFACED_DT_BF boundfiller,
EXTERNAL DECIMAL X_ACCRUAL_AMT,
X_PLAN_SHIPMENT_PATTERN_ID TANK (90)
)
I think that replace it can treat the wrapped date. But I want to know if we can find a faster or easier way to conquer this topic since the beginning.
Best regards
Leonuser12064076 wrote:
Thank you for your response. But how to ensure that a record is in a single line? For example, to unload data with coil?The table has more than 100 columns.
Best regards
LeonUH... which guarantee is implemented by anyone or anything that generates the data in the first place.
for example if I am extracting data to CSV for a customer or another application, making sure that it is 1 card per line with delimiters known etc.What is your own code that produces the data in the first place? If so, how are you to produce? With large amounts of data I wouldn't do it with SQL * Plus spool command, but I do with UTL_FILE within PL/SQL, or generating data in a file CLOB and spell the CLOB in a go using one of the CLOB methods available writing files.
-
Excerpt from SQL data with specific format.
All,
I have the oracle database version 10.2.0.4 in which I need to extract data from a table using the format below.
1.1 st 3 positions of the postal code, followed by
2.1 st letter of the name, followed by
3.1 st 2 consonants in the name of the street, followed
4 2 (for companies)
I can use the function substr to 1 and 2 above.
For 3, I tried regexp_substr. but the output includes vowels too. I don't know how to proceed. Is there another function or is there another way to do it?
I am concatenating 3 columns and display data as below.
for example
Help, please.Col1 Col2 Col3 FLOOR INC 24540 67 FRANKLIN TPKE STE 114 Displayed as 245FFR2 234AAS2-- testdata: with yourtable as ( select 'abcdefg' name from dual union all select '1aBexea' name from dual ) -- query for first two consonants: select substr(regexp_replace(regexp_replace(name,'[^a-zA-Z]',''),'[aeiouAEIOU]',''),1,2) from yourtable;Explanation:
-Internal Regexp removes everything except the letters.
-Outer Regexp removes vowals and keep the consonants.
-substr selects the first two consonants. -
Display different data with CSV
Hello
How can I build a query to separate the data with csv, but show me only the distinct records
SQL> SELECT t1.cd_usuario||','||t1.cd_usuario_cc usuarios
I woudld like show only, each record in each line
2 FROM sibtb_usuario_email t1;
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
upisergi,udoaldir,ubaemers
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
ukagisle,udoaldir
usisheil,ureanacl,usomaris
ureanacl,
usisheil,udoaldir,ujuhelio,ujujulio,ufinilo
ukagisle
Is it possible to do so, by using ORACLE 9.2.02
udoaldir
upisergi
ukagisle
usisheil
ureanacl
usomaris
ujuhelio
ujujulio
ufinilo
TIALike this?
With T as( SELECT distinct t1.cd_usuario||','||t1.cd_usuario_cc||',' usuarios FROM sibtb_usuario_email t1 ) select distinct usuarios from ( select case when no=1 then substr(usuarios, 1,instr(usuarios,',')-1) else substr(usuarios,instr(usuarios,',',1,no-1)+1,(instr(usuarios,',',1,no)-instr(usuarios,',',1,no-1))-1) end usuarios from t cross join ( select level no from (select max((length(usuarios)-length(replace(usuarios,',')))+1) len from t) connect by level <= len ) ) where trim(usuarios) is not null / USUARIOS --------------------------------------------- usisheil ujujulio upisergi udoaldir ureanacl ukagisle ubaemers usomaris ujuhelio ufinilo 10 rows selected. Elapsed: 00:00:00.07HTH,
PrazyPublished by: Prazy on April 28, 2010 18:33
In SQL format... Looked clumsy *.<> -
Display data in the report to pl/sql
I need to display data in a report using pl/sql.
The structure of the table would be fixed, but the data it would come from a pl/sql.
Is this possible in Apex 3.2.1 for that? If so, how can we do this?Hi Hozy,
As much as I know APEX report cannot manipulate the slider.
If the options are:
1)
Try the PIPE...
http://www.databasejournal.com/features/Oracle/article.php/2222781/returning-rows-through-a-table-function-in-Oracle.htm(2) as has said Roel, complete apex collection using your ps/sql and use it in the report.
Kind regards
Shijesh
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