Find the slot during several dates

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  Hi am gift, I can't find the window of several camera on first cc 2015

  you serve CS6 first which has the separate several camera window. First CC has multiple camera monitor in the program monitor. Click on the "key" icon and choose the multiple camera in the menu drop-down

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• To find the first Summit for data channel

  Hey guys,.

  I need a little help. I wrote a script to process some data. Basically, what the script does is calculate the linear accelerations peak, peak of the angular speeds, HIC values and IF. But there is a problem with my script that I need help. In my script, I use the ChnPeakFind command to find the pics in my chains. This command works fine to find the peak value, but what I want to do is find the FIRST Summit in the data, without worrying whether or not it is a maximum. I always encountered data that varies in which my first pic (impact analysis) may or may not be the highest point in the channel. As you can see in the Graphs.png that I have attached, the ChnPeakFind command found the 2nd Summit (red circle #2) in my chain of angular velocity (ARS resulting). But what I report is the first peak value (red circle #1). I've also attached a screenshot of the section in my code where I calculate the angular velocity. The 'i' in the calculation is just the channel group number. In this case, it is 1. Anyone know how to change the code or have another suggestion how to find the first Summit in a channel without having to stop and go to the tab analysis to manually find the pic?

  Thank you!

  Hello

  If it please see my littl below escript and let me know if this could work for you

  Dim     oChnResultant
  
  Call Data.Root.Clear)
  
  Call DataFileLoad ("E:\Customer_Examples\01_Head_Impact\Head Impact Data.tdm", "CT", "Load")
  
  Set oChnResultant = data. Root.ActiveChannelGroup.Channels.Add ("Result", DataTypeChnFloat64)
  
  Call ChnXYZAbsValue ("[1] / ARS X","[1] / ARS Y","[1] / ARS Z", oChnResultant)
  
  "Use the filter twice to get rid of the jig
  
  Call ChnSavitzkyGolayFilter (oChnResultant, oChnResultant, 1, 12)
  
  Call ChnSavitzkyGolayFilter (oChnResultant, oChnResultant, 1, 12)
  
  ' Delete few maxima to the beginninf of the signal.
  
  Calculate the call ("R = IIF (R)<>
  
  'Research for first peak.
  
  Call ChnPeakFind ("[1] / Time axis","[1]/Resultant","/PeakX","/PeakY",1,"Max.Peaks","Time")
  
  

• Why can not find the option "Transfer of data and memory" in the channel property node?

  Hi all

  I'll try to find some properties such as "data transfer and memory" in my node property 'DAQmx' Channel, as below ".

  But in my Labview 8.5, I can't. I reinstalled the NOR-DAQmx driver, but it didn't work. What I get is

  

  I missed something? Thank you.

  Kind regards

  Bo

  Hi Bo,

  Take at look at this knowledge base article.

  3ESBHEL2 Ko AE: lack of properties in the DAQmx nodes property

  Let me know if this solves your problem.

  Concerning

  John P

  Technical sales engineer

  National Instruments

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• Selection of the records of several dates but specific time

  Hello:
  I have to select records of several dates, but time should be 00:00:00 to 06:00:00 (i.e. 12 AM - 06:00)
  
  For the part of date, this can be done:
  
  WHERE
  START_TIME BETWEEN TO_DATE (APRIL 1, 2012 ',' DD-MM-YYYY ') AND TO_DATE (5 APRIL 2012 ',' DD-MM-YYYY ')
  
  But how can I fix the time above mentioed.
  
  Please let me know.
  
  Thank you/Tequila

  you mean something like this?
  If you are using timestamp you can use extract (time deposit)

  with t1 as
   (select sysdate - 3 / level as dt from dual connect by level < 101)
  select dt, to_char(dt, 'HH24') from t1 where to_number(to_char(dt, 'HH24')) < 7
  

• Can not find the file of exported data

  I have exported databases using EAS and cannot find the files.
  
  Have you tried to name the file without an extension, as well as including a .txt extension in the name of the export file. In each case, the le panneau panel message confirms that the 'export data... succeeded. "
  
  Yet, when I try to perform an import, the file I created is not anywhere in the server, directories of application or database appear in the dialog box for EAS.
  
  I'm sure I'm forgetting something obvious, but documentation did not help, either.
  
  Advice woud greatly appreciated.

  What version are you on anway file must be where essbase is installed, it will be in \app
  If you want to import then move from the to \app \app\appname\dbname

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• How to find the majority of a data set

  Dear Oracle Guru
  
  I have a data set something like for example
  
  AMT of payment which includes data like this (45,53,46,45,52,45,63,45,44,45,41,45...)
  
  I find the majority payment amt .in my given example, it's 45... IE Maximum occurrences.
  
  I couldn't get it properly. I thought AVG and MEDIAN... but not really correct
  
  Is there any other method or function that is deceiving me
  
  
  Kindly help me out of this
  
  With the best regards
  RSS

  with t
  as
  (
  select 45 payment from dual union all
  select 53 payment from dual union all
  select 46 payment from dual union all
  select 45 payment from dual union all
  select 52 payment from dual union all
  select 45 payment from dual union all
  select 63 payment from dual union all
  select 45 payment from dual union all
  select 44 payment from dual union all
  select 45 payment from dual union all
  select 41 payment from dual union all
  select 45 payment from dual
  )
  SELECT DISTINCT payment
    FROM (
       SELECT payment, DENSE_RANK() over (order by cnt desc) rnk
         FROM (
            SELECT payment, count(*) over(partition by payment order by 1) cnt
              FROM t
              )
         )
   WHERE rnk = 1
  

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  I solved it myself, DatastoreInfo is extended by the VmfsDatastoreInfo, which allows you to access HostVmfsVolume which has extensions as a field!

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

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  I'm a noob in Web development and I have this problem that is mentioned in the title. I triied to install the add-on, but it did not work. I want to read my data from my database. What can I do?

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• find the number of null data

  Hello
  
  I'm going to the table like this:
  
  NAME DESC1
  1 TEST
  1 TEST
  1 TEST
  2 REVIEW
  TEST 3
  TEST 3
  
  based on desc1 = 'TEST '.
  I need to get the result like:
  
  NAME COUNT (*)
  1 3
  2 0
  3 2
  
  Please help me how to get the result as above.

  Hello
  It will work
  SELECT NAME, SUM (DECODE (DESC1, 'TEST', 1, 0)) IN GROUP OF TEST5 BY NAME ORDER BY 1

• How to find the difference in date in years, months and days

  Hello
  I need to find the difference between 2 dates in the following way "years months days". "
  Please can help me, how can I achieve this.
  
  for example, in the scott schema emp table, I need to find the difference in date between sysdate and hiredate for an employee in the following way.
  
  12 years 7 months 4 days.

  Hello

  Please, see this post to AskTom [difference between 2 dates | http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:96012348060]. There is good information in this forum, for example you can also see this thread [calculation of years, months & days | http://forums.oracle.com/forums/thread.jspa?messageID=3115216�]

  Kind regards

  Published by: Walter Fernández on November 30, 2008 08:58 - adding another link