flooding in switch operation

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  I'm pretty green when I just went and routing configurations please bear with me.  I'm available what I want to achieve and what I could do until now (although it may be completely wrong).

  I have an office where we run low on IP addresses for our local network, the obvious answer is to get VOIP phones on their own subnet.  So, I have a switch PC6224 I want to use to create the second subnet.

  Existing Workstation LAN = 172.22.144.0 (255.255.255.0)

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  I would like to create an IPPhone = 172.22.145.0 (255.255.255.0) subnet

  Here's what I have "Achieved" so far:

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  Here is my config of 6224 switch operation:

  Console execution #show
  ! Current configuration:
  ! Description of the system "PowerConnect 6224, 3.3.6.4, VxWorks 6.5.
  ! 3.3.6.4 system software version
  ! Passage mode is configured as disabled
  !
  Configure
  database of VLAN
  VLAN 2-3
  VLAN 2 1 routing
  VLAN 3 2 routing
  subnet of VLAN association 172.22.144.0 255.255.255.0 3
  subnet of VLAN association 172.22.145.0 255.255.255.0 2
  output
  battery
  1 1 member
  output
  IP address no
  IP routing
  IP route 0.0.0.0 0.0.0.0 172.22.144.1
  interface vlan 2
  name "IPPhone.
  Routing
  IP 172.22.145.1 255.255.255.0
  output
  interface vlan 3
  name "TWLAN".
  Routing
  IP 172.22.144.12 255.255.255.0
  output
  level of 746f7a78621059d80fdc538acc40cbf2 user name 'admin' password encrypted 15
  !
  interface ethernet 1/g3
  switchport access vlan 3
  output
  !
  interface ethernet 1/g4
  switchport access vlan 3
  output
  !
  interface ethernet 1/g5
  switchport access vlan 2
  output

  !
  interface ethernet 1/g6
  switchport access vlan 2
  output
  !
  interface ethernet 1/g7
  switchport access vlan 2
  output
  !
  interface ethernet 1/g8
  switchport access vlan 2
  output
  !
  interface ethernet 1/g9
  switchport access vlan 2
  output
  !
  interface ethernet 1/g10
  switchport access vlan 2
  output
  !

  interface ethernet 1/g11
  switchport access vlan 2
  output
  !
  interface ethernet 1/g12
  switchport access vlan 2
  output
  !
  interface ethernet 1/g13
  switchport access vlan 2
  output
  !
  interface ethernet 1/g14
  switchport access vlan 2
  output
  !
  interface ethernet 1/g15
  switchport access vlan 2
  output
  !
  interface ethernet 1/g16

  switchport access vlan 2
  output
  !
  interface ethernet 1/g17
  switchport access vlan 2
  output
  !
  interface ethernet 1/g18
  switchport access vlan 2
  output
  !
  interface ethernet 1/g19
  switchport access vlan 2
  output
  !
  interface ethernet 1/g20
  switchport access vlan 2
  output
  !
  interface ethernet 1/g21
  switchport access vlan 2

  output
  !
  interface ethernet 1/g22
  switchport access vlan 2
  output
  !
  interface ethernet 1/g23
  switchport access vlan 2
  output
  !
  interface ethernet 1/g24
  switchport access vlan 2
  output
  output

  Console #.

  Any help would be greatly appreciated.

  Thanks, Grant

  What port connects to 172.22.144.1 the jump according to the internet?

  What should happen is we need a VLAN 'remote' separate just for the connection between the 6224 and your 172.22.144.1 jump following the internet device.

  If 172.22.144.1 remains the same, then you must create another local network VIRTUAL to "TWLAN".  Eventually, VLAN 4 with a range of ip addresses of 172.22.146.1 - 254 255.255.255.0.  Where the VLAN 4 interface has an IP address defined as 172.22.146.1.  Once that all connected devices again VLAN 4 that were in the VLAN 3 need to change there IPs and gateway 172.22.146.1

  So the only port that has configuration of VLAN 3 is the connection to 172.22.144.1 port next to the internet break.  The IP address defined on the interface VLAN 3 should be in the same subnet as 172.22.144.1 range.

  Here is a diagram that can help you to see the whole upward.  VLAN 100 in the diagram represent VLAN 3 in your case.  Switch 2 would represent your device from the internet of next hop.

  

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  >
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  Drop tablespace undotbs1 including content and data files

  Is there a problem if I... I ask because my current undo tablespace size is 8.5 GB?
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  Hello, I have problem on my code on the timer.

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  package
  {
  Add in your import here instructions
  import flash.display. *;
  import flash.events. *;
  import flash.utils.Timer;
  import flash.events.TimerEvent;

  //...

  
  SerializableAttribute public class MathsQuiz extends MovieClip
  {
  Add to your variables of class here
  private var score: Number;
  private var operand1:Number;
  private var operand2:Number;
  private var startNewGame:Boolean;
  private var Oper: int;
  private var Question: int = 1;
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  {

  }

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  {
  var userInput:int;
  var correctAns:int;
  

  switch (Oper)
  {
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  If (evt.keyCode is 13)
  {
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  {
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  }
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  {
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  myTimer.currentCount += 10;
  
  }
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  }
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  If (evt.keyCode is 13)
  {
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  If ((userInput is correctAns))
  {
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  }
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  }
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  }
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  }
  on the other
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  }
  on the other
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  score = 5;
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  }
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  }
  break;
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  {
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  Operand1 = 0;
  Operand2 = 0;
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  myTimer.start ();
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  Get the game loop to run
  
  addEventListener (Event.ENTER_FRAME, update);
  stage.addEventListener (KeyboardEvent.KEY_DOWN, checkAnswer);
  }

  public void update(evt:Event)
  {
  This is the game loop

  Manage the user input
  advanced feature addon:
  How to manage the entry of undetermined

  Manage the game logic
  Math.Random () =
  real number is between 0.0 1
  or MATH.floor (Math.random () * 13)
  If (Question 30 > | myTimer.currentCount > 60)
  {
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  }
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  {

  Operand1 = int (Math.random () * 13);
  Operand2 = int (Math.random () * 13);
  Oper = Math.floor (Math.random () * 4);
  startNewGame = false;

  }
  
  switch (Oper)
  {
  case 0:
  txtOper.text = ' + ';.
  break;
  case 1:
  txtOper.text = ' - ';.
  break;
  case 2:
  txtOper.text = ' * ';
  break;
  case 3:
  txtOper.text = ' / ';.
  break;
  }

  Manage the display
  txtOperand1.text = String (operand1);
  txtOperand2.text = String (operand2);

  txtScore.text = String (score);

  }
  } //end class
  } //end package
  [/ ACE]

  Use a separate variable to take into account rather than using the currentCount the timer.  Whenever the timer cycles add 1.  Whenever a wrong answer is given add 10.

  For the problem with your conditional that does not work, use the trace() function to see what the value of the Question and County are to see if they reach the values as you would expect they should.