Forum outings for request Insert statements

Hi all

I have a scenario that is mentioned below and need your contributions to improve performance

Sample package

Procedure a.
Insert into the array A();
End of procedure A

Procedure B
Insert into Table B();
End of procedure B

Procedure C
Insert into Table C();
C end procedure

Sample end Package


I guess when I run the package above completely, then first A procedure begins to insert 1 million followed procedure B, then C records in a sequence.

Is there any way through which everything in procedure is running, I need to run in parallel the B and c. procedure the same procedure...

Please advice on how best to achieve a performance in the above scenario... Thank you

Harinath Arasu says:
Hi blue Shasdow,

Thanks for your suggestions.

But in one procedure, if I have two update instructions as below (updated 1 million lines each), then how can I enforce instructions to update at the same time?

You can not. They are encoded to run in serial way.

Please suggest a way to update table B on the update on the table that is still ongoing. Our front end java application executes the procedure, and now two updates do not move in parallel.

Procedure a.
Update of Table;
Update of table b;
End of procedure A
/

Excuse me if my question doesn't make sense!

As a pseudo code, something like that...

Procedure A
Schedule Job to execute Procedure A_1 now;
Schedule Job to execute Procedure A_2 now;
End Procedure A;

Procedure A_1
Update Table a;
End Procedure A_1;

Procedure A_2
Update Table b;
End Procedure A_2;

Tags: Database

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    OR (bt. MEET = JT. ENCOUNTER_NO) -IF I REMOVE THESE TWO and THEN THEY BOTH PERFORM THE SAME SPEED

    )

    AND bt. ADMIT_DT < trunc (sysdate)

    AND bt. ADMIT_DT > = JT. ADMIT_DT - 1.5

    AND bt. ADMIT_DT < = JT. ADMIT_DT + 1.5

    AND bt. ADMIT_DT > = trunc(sysdate-7)

    AND bt. ADMIT_DT < trunc(sysdate-7) + 7

    AND JT. ADMIT_DT > = trunc(sysdate-7) - 1.5

    AND JT. ADMIT_DT < = trunc(sysdate-7) + 7 + 1.5

    AND 1 = 1

    );

    [/ code]

    THIS PLAN IS < 2 seconds for 5000 lines

    Hash value of plan: 1434516581

    -----------------------------------------------------------------------------------------------------------

    | ID | Operation | Name                  | Lines | Bytes | Cost (% CPU). Time |

    -----------------------------------------------------------------------------------------------------------

    |   0 | INSERT STATEMENT.                       |     3.   378.    42 (3) | 00:00:01 |

    |   1.  LOAD SELECT ACE | LINKER_SEC_BETACH_IP |       |       |            |          |

    |   2.   VIEW                            |                       |     3.   378.    42 (3) | 00:00:01 |

    |   3.    CONCATENATION.                       |       |       |            |          |

    |*  4 |     FILTER                        |                       |       |       |            |          |

    |*  5 |      TABLE ACCESS BY INDEX ROWID | SEC_ENCOUNTERS_DELME |     1.    74.     3 (0) | 00:00:01 |

    |   6.       NESTED LOOPS |                       |     1.   137.    13 (0) | 00:00:01 |

    |   8 S        TABLE ACCESS BY INDEX ROWID | BETACH_VISITS |     1.    63.    10 (0) | 00:00:01 |

    |*  8 |         INDEX RANGE SCAN | IDX_BETACH_VISITS_006 |     1.       |     9 (0) | 00:00:01 |

    |*  9 |        INDEX RANGE SCAN | NDX_SEC_ENC_05 |     1.       |     2 (0) | 00:00:01 |

    | * 10 |     FILTER                        |                       |       |       |            |          |

    | * 11 |      TABLE ACCESS BY INDEX ROWID | SEC_ENCOUNTERS_DELME |     1.    74.     4 (0) | 00:00:01 |

    |  12.       NESTED LOOPS |                       |     1.   137.    14 (0) | 00:00:01 |

    |  13.        TABLE ACCESS BY INDEX ROWID | BETACH_VISITS |     1.    63.    10 (0) | 00:00:01 |

    | * 14 |         INDEX RANGE SCAN | IDX_BETACH_VISITS_006 |     1.       |     9 (0) | 00:00:01 |

    | * 15 |        INDEX RANGE SCAN | NDX_SEC_ENC_06 |     3.       |     2 (0) | 00:00:01 |

    | * 16.     FILTER                        |                       |       |       |            |          |

    | * 17.      TABLE ACCESS BY INDEX ROWID | SEC_ENCOUNTERS_DELME |     1.    74.     4 (0) | 00:00:01 |

    |  18.       NESTED LOOPS |                       |     1.   137.    14 (0) | 00:00:01 |

    | * 19.        TABLE ACCESS BY INDEX ROWID | BETACH_VISITS |     1.    63.    10 (0) | 00:00:01 |

    | * 20.         INDEX RANGE SCAN | IDX_BETACH_VISITS_006 |     1.       |     9 (0) | 00:00:01 |

    | * 21.        INDEX RANGE SCAN | NDX_SEC_ENC_03 |     3.       |     2 (0) | 00:00:01 |

    -----------------------------------------------------------------------------------------------------------

    Information of predicates (identified by the operation identity card):

    ---------------------------------------------------

    4 filter (TRUNC (SYSDATE@!-7) - 1.5 < = TRUNC (SYSDATE@!-7) + 7 + 1.5 AND)

    TRUNC (sysdate@!-7) < TRUNC (SYSDATE@!-7) + 7 AND TRUNC(SYSDATE@!) > TRUNC (SYSDATE@!-7))

    5 - filter("BT".") ADMIT_DT' > = TRUNC (SYSDATE@!-7) AND "BT". "" ADMIT_DT "< TRUNC(SYSDATE@!) AND

    'BT '. "" ADMIT_DT "< TRUNC (SYSDATE@!-7) + 7 AND"BT ". "" ADMIT_DT "> = INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 "

    (AND "BT". "" ADMIT_DT "< = INTERNAL_FUNCTION ("JT". "ADMIT_DT") + (1.5) "

    8 - access("JT".") ADMIT_DT' > = TRUNC (SYSDATE@!-7) - 1.5 AND

    "JT". ("' ADMIT_DT" < = TRUNC (SYSDATE@!-7) + 7 + 1.5)

    filter (INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TRUNC(SYSDATE@!) " AND

    INTERNAL_FUNCTION ("JT". "ADMIT_DT") + 1.5 > = TRUNC (SYSDATE@!-7) AND "

    INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TRUNC (SYSDATE@!-7)(+7) "

    9 - access("BT".") MEET JT '=' '. ("' ENCOUNTER_NO")

    10 filter (TRUNC (SYSDATE@!-7) - 1.5 < = TRUNC (SYSDATE@!-7) + 7 + 1.5 AND)

    TRUNC (sysdate@!-7) < TRUNC (SYSDATE@!-7) + 7 AND TRUNC(SYSDATE@!) > TRUNC (SYSDATE@!-7))

    11 - filter("BT".") ADMIT_DT' > = TRUNC (SYSDATE@!-7) AND "BT". "" ADMIT_DT "< TRUNC(SYSDATE@!) AND

    'BT '. "" ADMIT_DT "< TRUNC (SYSDATE@!-7) + 7 AND"BT ". "" ADMIT_DT "> = INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 "

    (AND "BT". "" ADMIT_DT "< = INTERNAL_FUNCTION ("JT". "ADMIT_DT") + 1.5 AND "

    LNNVL ("BT". "JT"="MEETING" "." " ENCOUNTER_NO'))

    14 - access("JT".") ADMIT_DT' > = TRUNC (SYSDATE@!-7) - 1.5 AND

    "JT". ("' ADMIT_DT" < = TRUNC (SYSDATE@!-7) + 7 + 1.5)

    filter (INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TRUNC(SYSDATE@!) " AND

    INTERNAL_FUNCTION ("JT". "ADMIT_DT") + 1.5 > = TRUNC (SYSDATE@!-7) AND "

    INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TRUNC (SYSDATE@!-7)(+7) "

    15 - access("BT".") PTN_CHART «= TO_NUMBER ("JT".» RHRN'))

    16 filter (TRUNC (SYSDATE@!-7) - 1.5 < = TRUNC (SYSDATE@!-7) + 7 + 1.5 AND)

    TRUNC (sysdate@!-7) < TRUNC (SYSDATE@!-7) + 7 AND TRUNC(SYSDATE@!) > TRUNC (SYSDATE@!-7))

    17 - filter("BT".") ADMIT_DT' > = TRUNC (SYSDATE@!-7) AND "BT". "" ADMIT_DT "< TRUNC(SYSDATE@!) AND

    'BT '. "" ADMIT_DT "< TRUNC (SYSDATE@!-7) + 7 AND"BT ". "" ADMIT_DT "> = INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 "

    (AND "BT". "" ADMIT_DT "< = INTERNAL_FUNCTION ("JT". "ADMIT_DT") + 1.5 AND "

    LNNVL ("BT". "PTN_CHART '= TO_NUMBER ("JT".' RHRN')) AND LNNVL ("BT". "JT"="MEETING" "." " ENCOUNTER_NO'))

    19 - filter("JT".") PHNS' IS NOT NULL)

    20 - access("JT".") ADMIT_DT' > = TRUNC (SYSDATE@!-7) - 1.5 AND

    "JT". ("' ADMIT_DT" < = TRUNC (SYSDATE@!-7) + 7 + 1.5)

    filter (INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TRUNC(SYSDATE@!) " AND

    INTERNAL_FUNCTION ("JT". "ADMIT_DT") + 1.5 > = TRUNC (SYSDATE@!-7) AND "

    INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TRUNC (SYSDATE@!-7)(+7) "

    21 - access("BT".") PHN '=' JT '. ("' PHN ')


    When I placed this SQL in PL/SQL (AND place it in an immediate execution) it slows down.

    THIS PLAN GOES ~ 5minutes to 5000 lines

    Hash value of plan: 60405780

    ----------------------------------------------------------------------------------------------------------

    | ID | Operation | Name                  | Lines | Bytes | Cost (% CPU). Time |

    ----------------------------------------------------------------------------------------------------------

    |   0 | INSERT STATEMENT.                       |     1.   126.     2 (0) | 00:00:01 |

    |   1.  LOAD SELECT ACE | LINKER_SEC_BETACH_IP |       |       |            |          |

    |   2.   VIEW                           |                       |     1.   126.     2 (0) | 00:00:01 |

    |*  3 |    FILTER                        |                       |       |       |            |          |

    |*  4 |     TABLE ACCESS BY INDEX ROWID | SEC_ENCOUNTERS_DELME |     1.    74.     1 (0) | 00:00:01 |

    |   5.      NESTED LOOPS |                       |     1.   137.     2 (0) | 00:00:01 |

    |   4 >       TABLE ACCESS BY INDEX ROWID | BETACH_VISITS |     1.    63.     1 (0) | 00:00:01 |

    |*  7 |        INDEX RANGE SCAN | IDX_BETACH_VISITS_006 |     1.       |     1 (0) | 00:00:01 |

    |*  8 |       INDEX RANGE SCAN | NDX_SEC_ENC_07 |     2.       |     1 (0) | 00:00:01 |

    ----------------------------------------------------------------------------------------------------------

    Information of predicates (identified by the operation identity card):

    ---------------------------------------------------

    3 filter (TO_NUMBER(:4) - 1.5 < = TO_NUMBER(:5) + 7 + AND 1.5: 2 < TO_NUMBER(:3) + 7 AND)

    To_date(:1) > TO_DATE (:2))

    4 - filter("BT".") PHN '=' JT '. "' PHN ' AND 'JT '. "' PHN ' IS NOT NULL OR

    'BT '. «PTN_CHART «= TO_NUMBER ("JT".» ("' RHRN") OR "BT". «"JT MEETING «=»» ("' ENCOUNTER_NO")

    7 - access("JT".") ADMIT_DT' > = TO_NUMBER(:4) - 1.5 AND "JT". ("' ADMIT_DT" < = TO_NUMBER(:5) + 7 + 1.5)

    filter (INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 < TO_NUMBER(:3) + 7 AND "

    INTERNAL_FUNCTION ("JT". "ADMIT_DT")-1.5 <: 1 AND INTERNAL_FUNCTION ("JT" ".") " (ADMIT_DT') + 1.5 > =: 2)

    8 - access("BT".") ADMIT_DT' > = INTERNAL_FUNCTION ("JT". "ADMIT_DT") - 1.5 AND "BT". ("' ADMIT_DT" <: 1).

    filter ("BT". "ADMIT_DT" < TO_NUMBER(:3) + 7 AND "BT" "." " ADMIT_DT' > =: 2 AND

    'BT '. "" ADMIT_DT "< = INTERNAL_FUNCTION ("JT". "ADMIT_DT") + (1.5) "

    I have it!

    I added / * + USE_CONCAT * / forces subquery and not it the PL/SQL plan of union the subqueries.

    Hoek thanks for the link to the use of the tracing utility.

    Jason

  • Need help with the insert statement

    Hello

    I have a question on how to write a SQL statement.

    This is the table of "base":
    CREATE TABLE TEMP_TBL
(
id_nr NUMBER,
DATE_DOK DATE,
DATE_DUE DATE,
DATE_DOK_PAY DATE,
DEB NUMBER,
KRD NUMBER
);

insert into temp_tbl (ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('1',TO_DATE('11.01.2011','DD.MM.YYYY'),TO_DATE('25.02.2011','DD.MM.YYYY'),NULL,'423,24','0');
insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('2',TO_DATE('16.12.2011','DD.MM.YYYY'),TO_DATE('13.06.2011','DD.MM.YYYY'),NULL,'91270,15','0');
insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('3',TO_DATE('27.09.2011','DD.MM.YYYY'),TO_DATE('27.09.2011','DD.MM.YYYY'),NULL,'0','2000');
    and it comes to resoult in the target table. SQL statement must take care of the insert in a base of the target table table (example below is already provided with test data).
    create table table_sod
(

      id_nr number
     ,date_from date
     ,date_to date
     ,deb_krd number

);

One thing to note here :  values in column deb_krd under insert 1 and 4 must be summarized in insert 4.

insert into table_sod (id_nr,date_from,date_to,deb_krd) values('1',null,to_date('25.02.2011','dd.mm.yyyy'),'423,24');
insert into table_sod(id_nr,date_from,date_to,deb_krd) values('2',to_date('26.02.2011','dd.mm.yyyy'),to_date('13.06.2011','dd.mm.yyyy'),'423,24');
insert into table_sod(id_nr,date_from,date_to,deb_krd)values('3',null,to_date('13.06.2011','dd.mm.yyyy'),'91270,15');
insert into table_sod(id_nr,date_from,date_to,deb_krd)values('4',to_date('14.06.2011','dd.mm.yyyy')to_date('27.09.2011','dd.mm.yyyy'),'91693,39');
insert into table_sod(id_nr,date_from,date_to,deb_krd)values('5',null,to_date('27.09.2011','dd.mm.yyyy'),'2000');
    If someone could give me a helping hand how write correct insert statement I would be really gratefull.

    Thank you for your time!

    I came here with my own assumptions with this

    SQL> select rownum id_nr
  2       , date_from
  3       , date_to
  4       , case when date_from is null then deb
  5              else sum(case when date_from is not null then deb else 0end) over(order by id_nr, no)
  6         end deb_krd
  7    from (
  8            select id_nr
  9                 , case when lg_dt is null or ld_dt = date_due then  null else lg_dt+1 end date_from
 10                 , ld_dt date_to
 11                 , case when deb = 0 then krd else deb end deb
 12                 , no
 13              from (
 14                      select t1.*
 15                           , lead(t1.date_due) over(order by t1.id_nr, t2.no) ld_dt
 16                           , lag(t1.date_due) over(order by t1.id_nr, t2.no) lg_dt
 17                           , t2.no
 18                        from temp_tbl t1
 19                       cross
 20                       join (select 1 no from dual union all select 2 no from dual) t2
 21                       order by id_nr, no
 22                   )
 23             where ld_dt is not null
 24         )
 25  /

     ID_NR DATE_FROM DATE_TO      DEB_KRD
---------- --------- --------- ----------
         1           25-FEB-11      42324
         2 26-FEB-11 13-JUN-11      42324
         3           13-JUN-11    9127015
         4 14-JUN-11 27-SEP-11    9169339
         5           27-SEP-11       2000

  • exception in two places to insert statement

    Hi all

    I want to insert an exception to two places in pl sql. I get the error. Is it possible to apply the exception to two places in the insert statement.

    Thank you

    Uday


    Begin
    Declare
    Number of V_Code;
    V_Errm Varchar2 (64);
    Number of V_Code1;
    V_Errm1 Varchar2 (64);



    INSERT INTO recovery
    Select Employee_Id, salary * 1.1 employees
    Where Commission_Pct >. 2;
    EXCEPTION
    While others then
    V_Code: = Sqlcode;
    V_Errm: = Substr (Sqlerrm, 1, 64);
    Dbms_Output.put_line ("Error Code" |) V_Code | ': ' || V_Errm);

    Insert Into Scap_Fact_Loading_Errors Values (V_Code, V_Errm, Systimestamp);


    INSERT INTO recovery
    Select Employee_Id, salary * 1.1 employees
    Where Commission_Pct >. 1;
    EXCEPTION
    While other then V_Code1: = Sqlcode;
    V_Errm1: = Substr (Sqlerrm, 1, 64);
    Dbms_Output.put_line ("Error Code" |) V_Code1 | ': ' || V_Errm1);
    INSERT INTO Scap_Fact_Loading_Errors VALUES (v_code1, v_errm1, SYSTIMESTAMP);

    END;

    Published by: 929521 on January 7, 2013 10:15

    for example.

    Declare
  V_Code Number;
  V_Errm Varchar2(64);
  V_Code1 Number;
  V_Errm1 Varchar2(64);

begin

  -- 1st begin .. end block
  begin
    INSERT INTO Raise
    Select Employee_Id, Salary*1.1 From Employees
     Where Commission_Pct > .2;
  EXCEPTION
    When Others Then
      V_Code := Sqlcode;
      V_Errm := Substr(Sqlerrm, 1, 64);
      Dbms_Output.Put_Line ('Error code ' || V_Code || ': ' || V_Errm);
      Insert Into Scap_Fact_Loading_Errors Values (V_Code, V_Errm, Systimestamp);
  end;

  -- 2nd begin .. end block
  begin
    INSERT INTO Raise
    Select Employee_Id, Salary*1.1 From Employees
     Where Commission_Pct > .1;
  EXCEPTION
    When Others Then V_Code1 := Sqlcode;
      V_Errm1 := Substr(Sqlerrm, 1, 64);
      Dbms_Output.Put_Line ('Error code ' || V_Code1 || ': ' || V_Errm1);
      INSERT INTO Scap_Fact_Loading_Errors VALUES (v_code1, v_errm1, SYSTIMESTAMP);
  end;

end;

  • Help with the insert statement

    Hello

    I was wondering if someone could help write me a sql statement.

    Here is my table:
    CREATE TABLE "TEMP_INVOICE" 
   ("INVOICE" VARCHAR2(100 BYTE),
     "DATE_OF_DOCUMENT" DATE, 
     "DATE_OF_PAY_DAY" DATE, 
     "D" NUMBER, 
     "K" NUMBER
   );
    Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.
    insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.02.2012','dd.mm.yyyy'),to_date('01.03.2012','dd.mm.yyyy'),5000,0);
 
insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.04.2012','dd.mm.yyyy'),'','',1000);
 
insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.05.2012','dd.mm.yyyy'),'','',3000);
 
insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.06.2012','dd.mm.yyyy'),'','',1000);

insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.07.2012','dd.mm.yyyy'),to_date('01.09.2012','dd.mm.yyyy'),8000,0);
 
insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.10.2012','dd.mm.yyyy'),'','',5000);
 
insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.11.2012','dd.mm.yyyy'),'','',2000);
 
insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.12.2012','dd.mm.yyyy'),'','',1000);
    I want to do is make an insert allows you to table another call is MADE:
    CREATE TABLE "INVOICE" 
   ("INVOICE" VARCHAR2(100 BYTE),
    "DATE_OF_DOCUMENT" DATE, 
     "DATE_OF_PAY_DAY" DATE,
     "DATE_OF_PAYMENT_REC" DATE,
     "VALUE" NUMBER,
     "VALUE_DEDUCT" NUMBER,
    "DATE_FROM" DATE,     
     "DATE_TO" DATE
     );
    Statements in the INVOICE table should be like this:


    ........ The Bill... date_of_document... date_of_pay_day... date_of_payment_rec... value... value_deduct... Date_from... Date_to
    1......     1000...............1.1.2012.................1.3.2012................NULL............................ 5000... NULL... 1.3.2012...1.4.2012
    2......     1000...............1.4.2012.................NULL..................... 1.4.2012...1000... 4000... 2.4.2012... 1.5.2012
    3......     1000...............1.5.2012.................NULL..................... 1.5.2012...3000... 1000... 2.5.2012... 1.6.2012
    4......     1000...............1.6.2012.................NULL..................... 1.6.2012...1000


    Can someone help me with the sql statement that would insert data from table to table Bill temp_invoice as in the example?

    Thank you!

    PS

    I would try to explain.
    (1) the first statement that is to be inserted is original imply that at which is different DATE_OF_PAY_DAY to NULL.
    To this inserted negative of the original imply, we must add date_from that is exatly the same date_of_pay_day and date_to which is exactly the same as the date of the first payment. Payment which came first!
    (2) we have now in the second insert statement. It will be the first payment of lease with date_of_document and date_pf_payment_rec, which is the same as date_fo_document. Value field will be populated with the amount of payment received and value_deduct field will be the value of the original imply - value of the first payment. Date is date_of_document + 1 and date_to is the date of the next payment.
    (3) Insert us the next installment. Date_od_payment_rec is the same as date_of_document... value is the amount of the second payment and value_deduct's previous value_deduct which was of 4000 - value of this second payment. date_from date_of_payment_rec + 1 and date_to is the date of the next payment

    So we continue this same pattern until we reached the final payment when we finish insert with the statement:
    Date of the document (date of the last payment received) and even for date_of_payment_rec and field value with the amount of the payment receieved. The rest (value_deduct, date_from, date_to) is null.

    I really hope you understand what I'm trying to do here.

    If you have any other questions please.

    Published by: user13071990 on November 22, 2012 04:16

    Published by: user13071990 on November 22, 2012 04:16

    Hello

    user13071990 wrote:
    ... Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.

    Ok!
    Be sure to post the results you want new data.

    You probably need to add "PARTITION BY the Bill" to all analytical clauses in my solution:

    INSERT INTO invoice
( invoice, date_of_document, date_of_pay_day, date_of_payment_rec
, value,   value_deduct,     date_from,           date_to
)
SELECT       invoice
,       date_of_document
,       date_of_pay_day
,       CASE
           WHEN  k > 0
           THEN  date_of_document
       END          AS date_of_payment_rec
,       NVL (d, k)     AS value
,       NVL2 ( date_of_pay_day
            , NULL
            , SUM (d) OVER ( PARTITION BY  invoice
                                      ORDER BY      date_of_document
                     )
            - SUM (k) OVER ( PARTITION BY  invoice
                                      ORDER BY      date_of_document
                     )
            )     AS value_deduct
,       NVL ( date_of_pay_day
           , date_of_document + 1
           )          AS date_from
,       LEAD (date_of_document) OVER ( PARTITION BY  invoice
                                        ORDER BY      date_of_document
                           )
                      AS date_to
FROM       temp_invoice
;

    Because I'm not an English speaker nativ, that I just posted what it should look like after the insert is successful.

    OK, so you can't explain as you want, but you still need to explain.

    ... @Frank Kulash: you are very close, but still not quite what I'm looking for.

    Point out where my solution is the production of incorrect results, and explain (as you can) how to get good results in these places.

  • On the insert statement

    Hi all

    I need to insert rows into a table, all the columns are have same value except a column that is to say


    insert into table values ('a', 'b', 'b', 'b');

    insert into table values ('b', 'b', 'b', 'b');

    Insert in the table values ('b', 'b', 'c', 'b');

    y at - there no shortcut for insert because there are thousands of records to insert

    Help, please

    Thank you

    If data are available in another table, you can use a select statement inside your insert statement.

    Incomplete example

    NSERT INTO TABLE (
  COL1,
  COL2,
  COL3,
  COL4

)
SELECT FROM OTHERTABLE WHERE...,
'b'
'b'
'b'
...

    The doc show this as an example:

    INSERT INTO AIRPORTS (AIRPORT, CITY, COUNTRY)
  SELECT AIRPORT, CITY_NAME, COUNTRY FROM CITIES
  ORDER BY AIRPORT;

    SELECT yourvalue, 'b', 'b', 'b' of...

    Best regards

    mseberg

    Published by: mseberg on October 6, 2012 08:31

  • Question related to the INSERT statement

    Imagine this scenario:

    -table_a has 5 000 000 records at time t1

    -table_b is empty at time t1

    -At time t1, I execute the following statement:
              insert into table_b
            select * from table_a;
   
    -L' insert statement ends in time t2

    -Between t1 and t2, say 3 000 new records have been added to the table_a (by OLTP processes).
    Thus, at time t2, table_a has 5 003 000 records.

    My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
    5 003 000 or somewhere between these two counts?

    I guess it will be 5,000,000 because that is the number when the insert statement
    has started to run.

    Any comment is appreciated.

    Syed Ullah says:
    Imagine this scenario:

    -table_a has 5 000 000 records at time t1

    -table_b is empty at time t1

    -At time t1, I execute the following statement:

    insert into table_b
select * from table_a;

    -L' insert statement ends in time t2

    -Between t1 and t2, say 3 000 new records have been added to the table_a (by OLTP processes).
    Thus, at time t2, table_a has 5 003 000 records.

    My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
    5 003 000 or somewhere between these two counts?

    I guess it will be 5,000,000 because that is the number when the insert statement
    has started to run.

    Any comment is appreciated.

    At time t2, it is possible that the answer is 0. Once the insert operation finishes (can be any time after t1 in your example, possibly before t2, possibly after) and assuming you checked in the same session where you run the insert, you would see 5 000 000. In other sessions you would continue to see 0 up to what the session who made the done insert one COMMIT.

    http://docs.Oracle.com/CD/E11882_01/server.112/e25789/consist.htm#CNCPT121

    Is something that you should read. He described these concepts much better than what you'll probably find in a few posts on the forum.

  • LogMiner does not list INSERT statements

    Hello

    does anyone know why logminer does not INSERT statements? I have this problem on a 10.2.0.4 database. On a 11.2.0.1 database are, no problem.

    Unit test:
    SQL> select * from v$version;

BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Prod
PL/SQL Release 10.2.0.4.0 - Production
CORE    10.2.0.4.0      Production
TNS for 32-bit Windows: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production

SQL> select supplemental_log_data_min from v$database;

SUPPLEME
--------
NO

SQL> select sequence# from v$log where status = 'CURRENT';

 SEQUENCE#
----------
       180

SQL> create table scott.test_load (id number);

Table created.

SQL> insert into scott.test_load select rownum r from user_objects where rownum <= 10;

10 rows created.

SQL> commit;

Commit complete.

SQL> select sequence# from v$log where status = 'CURRENT';

 SEQUENCE#
----------
       180

SQL> alter system archive log current;

System altered.

SQL> select sequence# from v$log where status = 'CURRENT';

 SEQUENCE#
----------
       181

SQL> select name from v$archived_log where sequence#=180;

NAME
--------------------------------------------------------------------------------------------------------
C:\ORACLE10G\PRODUCT\10.2.0\FLASH_RECOVERY_AREA\TEST10G\ARCHIVELOG\2010_09_08\O1_MF_1_180_68H49WQS_.ARC

SQL> exec sys.dbms_logmnr.add_logfile('C:\ORACLE10G\PRODUCT\10.2.0\FLASH_RECOVERY_AREA\TEST10G\ARCHIVELOG\2010_09_08\O1_MF_1_180_68H49WQS_.ARC');

PL/SQL procedure successfully completed.

SQL> exec sys.dbms_logmnr.start_logmnr(options=>sys.dbms_logmnr.dict_from_online_catalog);

PL/SQL procedure successfully completed.

SQL> select seg_owner, seg_name, to_char(timestamp,'mm/dd/yy hh24:mi:ss') timestamp, sql_redo
  2      from v$logmnr_contents
  3      where table_name = 'TEST_LOAD';

SEG_OWNER  SEG_NAME             TIMESTAMP         SQL_REDO
---------- -------------------- ----------------- ---------------------------------------------
SCOTT      TEST_LOAD            09/08/10 15:35:29 create table scott.test_load (id number);

SQL>
    While the DDL part is present. If the minimum additional logging is enabled, INSERT statements are visible also in 10.2.0.4 (in 11.2.0.1, they are also visible if additional logging is disabled). Anyone know the reason of such behaviour in 10.2.0.4?

    I ask because I have a 10.2.0.4 database production that has not allowed an additional minimum logging. It seems there were a few 'ad hoc' changes in some tables, and because we have not enabled the audit, I tried to see if something can be found in the recovery logs archived. I searched on them and I have not found anything. Anyway, as the unit test above shows, I can't be sure if there was in fact no change to the data or only logminer recount not the...


    Thank you very much in advance and greetings.
    Swear

    Hello

    By default, the Oracle 10.2.0.4 database - does not provide any additional registration, which means that default LogMiner is not usable. Because of which you might not see the results.

    -Pavan Kumar N

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