Function group & order by function

Hi all; »

When we use function group & sort function. Always I get the error message.

SQL > select sum(bytes/1024/1024), NAME of v$ datafile including the group by name.

where the group by name

* ERROR on line 2:

ORA-00936: lack of expression

SQL > select sum(bytes/1024/1024), NAME, FILE number of v$ datafile where order by case number;

where to order by case number

*

ERROR on line 2:

ORA-00936: lack of expression

SQL > select name, sum (bytes/1024/1024), the status of v$ datafile where ts #= '4' group of FILE #;

Select name, sum (bytes/1024/1024), status from v$ datafile

*

ERROR on line 1:

ORA-00979: not a GROUP BY expression

SQL > select name, sum (bytes/1024/1024), the status of v$ datafile where TS #= '4';

Select name, sum (bytes/1024/1024), status from v$ datafile

*

ERROR on line 1:

ORA-00937: not a single group group function

Thanks in advance...

Hello

GTS (DBA) wrote:

...

I need output only for ts #= '4' only... I mean

Select sum(bytes/1024/1024), NAME from v$ datafile {only for ts #= 4}

...

This looks like a job of a WHERE clause:

SELECT SUM (bytes / 1024 / 1024) AS megabytes

name

folder #.

V $ datafile

WHERE the ts # = 4-* NEW *.

GROUP BY name

folder #.

ORDER BY line #.

;

Tags: Database

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    PWD

    -------------------------------------------------------------------------------------------------------------------

    12412913141313139139130121

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CORE     11.2.0.3.0     Production
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  3  /
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ERROR at line 2:
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  3  /

RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
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1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30
,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,5
7,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,
84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100,101,102,103,104,105,106,107,
108,109,110,111,112,113,114,115,116,117,118,119,120,121,122,123,124,125,126,127,
128,129,130,131,132,133,134,135,136,137,138,139,140,141,142,143,144,145,146,147,
148,149,150,151,152,153,154,155,156,157,158,159,160,161,162,163,164,165,166,167,
168,169,170,171,172,173,174,175,176,177,178,179,180,181,182,183,184,185,186,187,
188,189,190,191,192,193,194,195,196,197,198,199,200,201,202,203,204,205,206,207,
208,209,210,211,212,213,214,215,216,217,218,219,220,221,222,223,224,225,226,227,
228,229,230,231,232,233,234,235,236,237,238,239,240,241,242,243,244,245,246,247,

RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
--------------------------------------------------------------------------------
248,249,250,251,252,253,254,255,256,257,258,259,260,261,262,263,264,265,266,267,
268,269,270,271,272,273,274,275,276,277,278,279,280,281,282,283,284,285,286,287,
288,289,290,291,292,293,294,295,296,297,298,299,300,301,302,303,304,305,306,307,
308,309,310,311,312,313,314,315,316,317,318,319,320,321,322,323,324,325,326,327,
328,329,330,331,332,333,334,335,336,337,338,339,340,341,342,343,344,345,346,347,
348,349,350,351,352,353,354,355,356,357,358,359,360,361,362,363,364,365,366,367,
368,369,370,371,372,373,374,375,376,377,378,379,380,381,382,383,384,385,386,387,
388,389,390,391,392,393,394,395,396,397,398,399,400,401,402,403,404,405,406,407,
408,409,410,411,412,413,414,415,416,417,418,419,420,421,422,423,424,425,426,427,
428,429,430,431,432,433,434,435,436,437,438,439,440,441,442,443,444,445,446,447,
448,449,450,451,452,453,454,455,456,457,458,459,460,461,462,463,464,465,466,467,

RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
--------------------------------------------------------------------------------
468,469,470,471,472,473,474,475,476,477,478,479,480,481,482,483,484,485,486,487,
488,489,490,491,492,493,494,495,496,497,498,499,500,501,502,503,504,505,506,507,
508,509,510,511,512,513,514,515,516,517,518,519,520,521,522,523,524,525,526,527,
528,529,530,531,532,533,534,535,536,537,538,539,540,541,542,543,544,545,546,547,
548,549,550,551,552,553,554,555,556,557,558,559,560,561,562,563,564,565,566,567,
568,569,570,571,572,573,574,575,576,577,578,579,580,581,582,583,584,585,586,587,
588,589,590,591,592,593,594,595,596,597,598,599,600,601,602,603,604,605,606,607,
608,609,610,611,612,613,614,615,616,617,618,619,620,621,622,623,624,625,626,627,
628,629,630,631,632,633,634,635,636,637,638,639,640,641,642,643,644,645,646,647,
648,649,650,651,652,653,654,655,656,657,658,659,660,661,662,663,664,665,666,667,
668,669,670,671,672,673,674,675,676,677,678,679,680,681,682,683,684,685,686,687,

RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
--------------------------------------------------------------------------------
688,689,690,691,692,693,694,695,696,697,698,699,700,701,702,703,704,705,706,707,
708,709,710,711,712,713,714,715,716,717,718,719,720,721,722,723,724,725,726,727,
728,729,730,731,732,733,734,735,736,737,738,739,740,741,742,743,744,745,746,747,
748,749,750,751,752,753,754,755,756,757,758,759,760,761,762,763,764,765,766,767,
768,769,770,771,772,773,774,775,776,777,778,779,780,781,782,783,784,785,786,787,
788,789,790,791,792,793,794,795,796,797,798,799,800,801,802,803,804,805,806,807,
808,809,810,811,812,813,814,815,816,817,818,819,820,821,822,823,824,825,826,827,
828,829,830,831,832,833,834,835,836,837,838,839,840,841,842,843,844,845,846,847,
848,849,850,851,852,853,854,855,856,857,858,859,860,861,862,863,864,865,866,867,
868,869,870,871,872,873,874,875,876,877,878,879,880,881,882,883,884,885,886,887,
888,889,890,891,892,893,894,895,896,897,898,899,900,901,902,903,904,905,906,907,

RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
--------------------------------------------------------------------------------
908,909,910,911,912,913,914,915,916,917,918,919,920,921,922,923,924,925,926,927,
928,929,930,931,932,933,934,935,936,937,938,939,940,941,942,943,944,945,946,947,
948,949,950,951,952,953,954,955,956,957,958,959,960,961,962,963,964,965,966,967,
968,969,970,971,972,973,974,975,976,977,978,979,980,981,982,983,984,985,986,987,
988,989,990,991,992,993,994,995,996,997,998,999,1000,1001,1002,1003,1004,1005,10
06,1007,1008,1009,1010,1011,1012,1013,1014,1015,1016,1017,1018,1019,1020,1021,10
22,1023,1024,1025,1026,1027,1028,1029,1030,1031,1032,1033,1034,1035,1036,1037,10
38,1039,1040,1041,1042,1043,1044,1045,1046,1047,1048,1049

SQL>

    SY.

  • limit the number of values in the listagg function and create several games

    Hi all

    I have a requirement where I would like to group one of the fields in a field based on the number of records. Lets say if we have an employee with multiple CODEZONE. Please see the example below. I want concatenation of each 10 EMPNO records into one. If she has more than 10 records for a given EMPNO, it should show in the form of another record.
    For example:
    EMPNO CODEZONE
    A111 AL
    A111 AK
    A111 AZ
    A111 AR
    A111 CA
    A111 CO
    A111 CT
    TO A111
    A111 DC
    A111 FL
    A111 GA
    A111 HI
    B222 AL
    B222 AK
    B222 AZ
    B222 AI
    B222 KS
    B222 KY
    THE B222
    B222 ME
    B222 MD
    MY B222
    B222 MI
    B222 CA
    B222 CO
    B222 CT
    B222 OF

    Result set:
    EMPNO CODEZONE
    A111 AL | AK | AZ | AR | CA | CO | CT | OF | DC | FL
    A111 GA | HI
    B222 AL | AK | AZ | AI | KS |     KY | THE | ME | MD | MY
    B222 MI | CA | CO | CT | OF

    The above example can have any number of area CODE for a given EMPNO, the end result should show only a maximum of 10 codes for an EMPNO in each record. If she has more than 10 CODEZONE, it should show as another record. Please provide me with a generic statement to solve this problem. I was not able to control by setting the limit on records for an EMPNO gave to the LISTAGG function. Any ideas are much appreciated.

    Thank you

    1008754 wrote:
    Hi all

    I have a requirement where I would like to group one of the fields in a field based on the number of records. Lets say if we have an employee with multiple CODEZONE. Please see the example below. I want concatenation of each 10 EMPNO records into one. If she has more than 10 records for a given EMPNO, it should show in the form of another record.
    For example:
    EMPNO CODEZONE
    A111 AL
    A111 AK
    A111 AZ
    A111 AR
    A111 CA
    A111 CO
    A111 CT
    TO A111
    A111 DC
    A111 FL
    A111 GA
    A111 HI
    B222 AL
    B222 AK
    B222 AZ
    B222 AI
    B222 KS
    B222 KY
    THE B222
    B222 ME
    B222 MD
    MY B222
    B222 MI
    B222 CA
    B222 CO
    B222 CT
    B222 OF

    Result set:
    EMPNO CODEZONE
    A111 AL | AK | AZ | AR | CA | CO | CT | OF | DC | FL
    A111 GA | HI
    B222 AL | AK | AZ | AI | KS |     KY | THE | ME | MD | MY
    B222 MI | CA | CO | CT | OF

    The above example can have any number of area CODE for a given EMPNO, the end result should show only a maximum of 10 codes for an EMPNO in each record. If she has more than 10 CODEZONE, it should show as another record. Please provide me with a generic statement to solve this problem. I was not able to control by setting the limit on records for an EMPNO gave to the LISTAGG function. Any ideas are much appreciated.

    Thank you

    ME_XE?with data (empno, areacode) as
  2  (
  3     select 'A111', 'AL' from dual union all
  4     select 'A111', 'AK' from dual union all
  5     select 'A111', 'AZ' from dual union all
  6     select 'A111', 'AR' from dual union all
  7     select 'A111', 'CA' from dual union all
  8     select 'A111', 'CO' from dual union all
  9     select 'A111', 'CT' from dual union all
 10     select 'A111', 'DE' from dual union all
 11     select 'A111', 'DC' from dual union all
 12     select 'A111', 'FL' from dual union all
 13     select 'A111', 'GA' from dual union all
 14     select 'A111', 'HI' from dual union all
 15     select 'B222', 'AL' from dual union all
 16     select 'B222', 'AK' from dual union all
 17     select 'B222', 'AZ' from dual union all
 18     select 'B222', 'IA' from dual union all
 19     select 'B222', 'KS' from dual union all
 20     select 'B222', 'KY' from dual union all
 21     select 'B222', 'LA' from dual union all
 22     select 'B222', 'ME' from dual union all
 23     select 'B222', 'MD' from dual union all
 24     select 'B222', 'MA' from dual union all
 25     select 'B222', 'MI' from dual union all
 26     select 'B222', 'CA' from dual union all
 27     select 'B222', 'CO' from dual union all
 28     select 'B222', 'CT' from dual union all
 29     select 'B222', 'DE' from dual
 30  )
 31  select
 32     empno, listagg(areacode, ',') within group (order by emp_grp)   as emp_list
 33  from
 34  (
 35     select
 36             ceil(row_number() over (partition by empno order by areacode) / 10) as emp_grp,
 37             empno,
 38             areacode
 39     from data
 40  )
 41  group by empno, emp_grp;

EMPNO                          EMP_LIST
------------------------------ ------------------------------
A111                           AK,AL,AR,AZ,CA,CO,CT,DC,DE,FL
A111                           GA,HI
B222                           AK,AL,AZ,CA,CO,CT,DE,IA,KS,KY
B222                           LA,MA,MD,ME,MI

4 rows selected.

Elapsed: 00:00:00.05
ME_XE?

    In the future, it would be nice if you could provide baseline data.

    See you soon,.

  • LISTAGG function: "result of concatenating string is too long."

    Hello

    I use Oracle SQL developer 3.0.04 version. I tried using the LISTAGG function to group the data.
    CREATE TABLE FINAL_LOG AS
SELECT SESSION_DT, C_IP, CS_USER_AGENT,
listagg(WEB_LINK, ' ')
     WITHIN GROUP(ORDER BY C_IP, CS_USER_AGENT) "WEB_LINKS"
     FROM webviews
     GROUP BY C_IP, CS_USER_AGENT, SESSION_DT
     ORDER BY SESSION_DT
    However, I get the error message,

    SQL error: ORA-01489: result of concatenating string is too long

    Is it possible to go around it, or are there other alternatives?

    Tim Hall has a page on the various techniques of aggregation of chain that guides you through an example of creating and using a user-defined aggregate.

    On AskTom referenced by Tim page, there is an implementation of an aggregation function of string that returns a CLOB that you can use.

    If you want to understand what makes the user-defined aggregate function, it may look a bit complex, especially if you have never looked at object types in PL/SQL. You don't need to understand all the details of the implementation if you use just the code, however, you can simply create the function and use it as you would with any other aggregate function.

    Justin

  • Relacing functions

    I have a few sql querries who call many functions. The reason for function calls is that there are many records of children that can be returned by the function and it's actually concatonting all together in 1 channel and back. Because I called a bunch of functions in the query, in my opinion, his achievement of my performance. Is it possible to eliminate the service and into sql or a better way to do this right?

    IE select emp_name, emp_id, get_med_visit_outcomes1 (emp_id), get_med_visit_outcomes2 (emp_id), get_med_visit_outcomes3 (emp_id),.
    WCP

    FUNCTION get_med_visit_outcomes (l_pk_id in varchar2) return VARCHAR2 IS

    l_outcomes varchar2 (32000);
    l_cnt number: = 0;

    CURSOR get_med_visit_outcomes IS
    Select B.med_visit_outcome
    of med_visit_outcome B, stu_med_visit_outcome A
    where A.fk_stu_med_visit = l_pk_id
    and B.pk_id = A.fk_med_visit_outcome
    order by 1;
    BEGIN
    FOR x in get_med_visit_outcomes LOOP
    l_cnt: = l_cnt + 1;
    If l_cnt = 1 then null;
    l_outcomes: = x.med_visit_outcome;
    on the other
    l_outcomes: = l_outcomes | ', ' || x.med_visit_outcome;
    end if;
    END LOOP;

    RETURN (nvl(l_outcomes,'-'));
    END;

    If you are on version 11.2, LISTAGG is good for these problems:

    select
emp_name,
emp_id,
nvl((
  select listagg(B.med_visit_outcome,',') within group (order by B.med_visit_outcome)
  from med_visit_outcome B, stu_med_visit_outcome A
  where A.fk_stu_med_visit = emp.emp_id
  and B.pk_id = A.fk_med_visit_outcome
),'-') outcomes1
from emp

    If you are on older than 11.2 versions, you can see here the various other techniques [url http://www.oracle-base.com/articles/misc/StringAggregationTechniques.php].

  • Listagg function displays the keyword not found error message

    is version of Oracle 11 g
    create or replace
function fn_months_attended
return number is
v_array varchar2(1000);
begin
  select LISTAGG(c.act_id,',') within group (order by c.act_id desc) INTO V_ARRAY from 
          programmes a,campaigns b,activities c
        where  a.pro_id=b.cam_pro_id 
        and    b.cam_id=c.act_act_id 
        order by act_id DESC ;
return v_array;
end;

Error i received 
Error(6,3): PL/SQL: SQL Statement ignored
Error(6,39): PL/SQL: ORA-00923: FROM keyword not found where expected
    can you please suggest me to find exactly the problem

    Hello

    In the LIST of 11 GR 1 tot material. function does not work. It works in only 11 GR 2.

    Kind regards
    Champion.

  • Oracle LISTAGG function

    Hi all

    I'm still reviewing the analytical functions and I was wondering if someone can help me with the LISTAGG function. If this has nothing to do with some school or as homework. It's just me discover Oracle.

    So, here is some code to insert data of base. It's just a person table and an array of phone number.
    -- to avoid name conflicts ;-)
DROP TABLE PERSONNES CASCADE CONSTRAINTS purge;
DROP TABLE TELEPHONES CASCADE CONSTRAINTS purge;

-- create a person table with an id and a name.
CREATE TABLE PERSONNES (
    ID_PERSONNE NUMBER(10)
  , NOM         VARCHAR2(100)
  , CONSTRAINT PK_PERSONNES PRIMARY KEY(ID_PERSONNE)
);

-- table with phone number for persons. 
CREATE TABLE TELEPHONES (
    ID_TELEPHONE NUMBER(10)
  , ID_PERSONNE  NUMBER(10)
  , NUMERO       VARCHAR2(100)
  , ACTIF        CHAR(1) DEFAULT '0' -- is the number active or not.
  , CONSTRAINT PK_TELEPHONES PRIMARY KEY(ID_TELEPHONE)
  , CONSTRAINT UK_NUMERO     UNIQUE(ID_TELEPHONE, NUMERO)
  , CONSTRAINT C_ACTIF_BOOLEAN CHECK(ACTIF IN ('0', '1'))
  , CONSTRAINT FK_PERSONNE   FOREIGN KEY(ID_PERSONNE) REFERENCES PERSONNES
);

-- insert some data.
BEGIN
  -- create a person with a random name.
  FOR i in 1 .. 10 LOOP
    INSERT INTO PERSONNES(ID_PERSONNE, NOM)
      VALUES (i, InitCap(DBMS_RANDOM.STRING('l', 5)));
    
     -- for each newly inserted person, insert 5 different phone numbers.
    FOR j in 1 .. 5 LOOP
      INSERT INTO TELEPHONES(ID_TELEPHONE, ID_PERSONNE, NUMERO, ACTIF) 
        VALUES(((i-1)*10) + j, i,  
            '+32.' ||
              TRUNC(DBMS_RANDOM.VALUE(1, 9)) || '.' ||
              TO_CHAR(DBMS_RANDOM.VALUE(1, 999), 'fm099') || '.' ||
              TO_CHAR(DBMS_RANDOM.VALUE(1, 99), 'fm09') || '.' ||
              TO_CHAR(DBMS_RANDOM.VALUE(1, 99), 'fm09'), 
            CASE MOD(j, 2) WHEN 0 THEN '0' ELSE '1' END
        );
    END LOOP;
  END LOOP;
  
  -- now insert two different person without any phone number.
  INSERT INTO PERSONNES(ID_PERSONNE, NOM)
    VALUES (100, InitCap(DBMS_RANDOM.STRING('l', 5)));

  INSERT INTO PERSONNES(ID_PERSONNE, NOM)
    VALUES (101, InitCap(DBMS_RANDOM.STRING('l', 5)));

END;
    The following query returns all the person with their different phone numbers into a single line.
    SELECT NOM, LISTAGG(NUMERO, ', ') WITHIN GROUP (ORDER BY NULL)
  FROM PERSONNES A
 LEFT JOIN TELEPHONES B ON A.ID_PERSONNE = B.ID_PERSONNE
 GROUP BY NOM 
 ORDER BY 2 NULLS LAST;
    But what I would like is to have numbers grouped by the flag of the ASSET.
    Name1   Actif=0  +32... , +3200000000
Name1   Actif=1  +32... , +...........
Name2   Actif=0  +32... , +3200000000
Name2   Actif=1  +32... , +...........
    I thought that maybe using the PARTITION CLAUSE but I couldn't understand it. So maybe one of you has a better idea? I want to do in a single query (without using the inline views or with clause). But all the tips are welcome. I just discover Oracle ;-)

    Thank you

    Hello

    user13117585 wrote:
    ... But what I would like is to have numbers grouped by the flag of the ASSET.

    This is the solution! You want to have results grouped by asset, so add assets to the GROUP BY clause:

    SELECT NOM
,      ACTIF          -- New
,      LISTAGG(NUMERO, ', ') WITHIN GROUP (ORDER BY NULL)
  FROM PERSONNES A
 LEFT JOIN TELEPHONES B ON A.ID_PERSONNE = B.ID_PERSONNE
 GROUP BY NOM
 ,        ACTIF     -- New
 ORDER BY 3 NULLS LAST     -- Changed
;

    If you want to display ACTIVE, you will need to add it to the SELECT clause.
    Don't forget to change the ORDER BY clause, which changes what is in the column #2, as stated above (assuming that it is how you want the output sorted). However, a better way is to give this column alias, which can be used in the ORDER BY clause:

    SELECT NOM
,      ACTIF
,      LISTAGG(NUMERO, ', ') WITHIN GROUP (ORDER BY NULL)     AS NUMEROS     -- Alias defined
  FROM PERSONNES A
 LEFT JOIN TELEPHONES B ON A.ID_PERSONNE = B.ID_PERSONNE
 GROUP BY NOM
 ,        ACTIF
 ORDER BY NUMEROS NULLS LAST     -- Alias used
;

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