Get the last disc based on the date

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  Hi TimRsandiego,

  SignalExpress is programmed to display graphs with default scales based on the type of action, it's reading. These scales and settings can be changed by right-clicking on the graph, and then select Properties.

  If you are interested to learn more about how to use SignalExpress, I would recommend checking out some demonstrations/tutorials on NI.com. You can find some of these demos at the following location:

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• < dateformat: create, get the date in en_GB, es_ES instance

  Hello

  I don't know if it's a bug or normal behavior:

  I get the date in en_GB, but I ask the date to es_ES, the snippet of code below:

  < ics:if condition =' < % = ics. GetList ("FechaBlog")! = null & & ics. GetList("FechaBlog").hasData () % > ' >

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  22-may-2015

  I expect to get: 22 -mayo- 2015; But if change the 'average' datestyle to "long", I am getting:

  
  

  2015 22 Mayo

  
  

  as expected, in es_ES.

  This is the normal behavior? WCS 11.1.1.8

  Kind regards

  Hello Jorgitoito,

  This is how Java has shaped the date in Spanish. It is not specific to the WebCenter Sites.

  You can give it a try with this simple Java code:

  java.util.Locale locale = new java.util.Locale("es", "ES");
   java.text.DateFormat mediumFormat   = java.text.DateFormat.getDateInstance(java.text.DateFormat.MEDIUM, locale);
  System.out.println(mediumFormat.format(new java.util.Date()));
  java.text.DateFormat longFormat   = java.text.DateFormat.getDateInstance(java.text.DateFormat.LONG, locale);
  System.out.println(longFormat.format(new java.util.Date()));
  

  The results I got:

  27-May-2015

  2015 27 Mayo

  I suspect that 27-May-2015 here is not in English; It is simply the first three letters of mayo.

  Kind regards

  Stephan.

• Is there a way to get the data for submission of form of eloqua using the REST API?

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• Compare and get the data in the tables (see post for details)

  I have two tables TableA and TableB. I struggle to write a query to get the dates of TableB (instead of TableA dates) where TableA dates don't coincide with the tableB (beginning and end).

  Example 1: For account A1234,.

  TableA got 2 rows 1/31/2014-3/3/2014 (which corresponds to TableB row), but TableA got another rank 31/01/2014 - 31/01/2014 that corresponds with the date of TableB Begin. In this case, I'm looking for output as below,

  Use TableB start and end date and combine number two rows from TableA for this account

  ACCOUNT	TableB_BEGIN	TableB_END	AMOUNT
  A1234	31/01/2014	03/03/2014	100.0000000000

  Example 2: For the B7777 account.

  TableA end date aligns with the end dates of TableB for this account, in this case I want out put as,.

  Use TableB start and end date and get the amount of TableA

  ACCOUNT	TableB_BEGIN	TableB_END	AMOUNT
  B7777	05/04/2013	06/05/2013	200.0000000000

  Example 3: On behalf of D5555,.

  Even a TableA line corresponds with TableA, there are two other rows in TableA matching start date with TableA and correspondence with the end date with TableA, in this case, that I put as,.

  Use TableB start and end date and combine number three rows from TableA for this account.

  ACCOUNT	TableB_BEGIN	TableB_END	AMOUNT
  D5555	08/08/2014	10/09/2014	1100.0000000000

  Example 4: To account E6666.

  Table corresponds to a row with TableB and no additional lines in TableA, just display the data in A table

  Tables and data:

  create table TableA
  (
    Account varchar2(10) not null,
    Begin   date not null,
    End     date not null,
    Amount  number(19,10) not null
  )
  ;
  
  
  create table TableB
  (
    Account varchar2(10) not null,
    Begin   date not null,
    End     date not null,
    Amount  number(19,10) not null
  )
  ;
  
  
  TableA Data:
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('31-01-2014', 'dd-mm-yyyy'), 0.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('03-03-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('B7777', to_date('18-04-2013', 'dd-mm-yyyy'), to_date('06-05-2013', 'dd-mm-yyyy'), 120.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('C6666', to_date('25-06-2014', 'dd-mm-yyyy'), to_date('08-07-2014', 'dd-mm-yyyy'), 10.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('16-08-2014', 'dd-mm-yyyy'), 1000.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 0.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('16-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('E6666', to_date('01-01-2014', 'dd-mm-yyyy'), to_date('01-02-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  TableB Data:
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('03-03-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('B7777', to_date('05-04-2013', 'dd-mm-yyyy'), to_date('06-05-2013', 'dd-mm-yyyy'), 200.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('C6666', to_date('06-06-2014', 'dd-mm-yyyy'), to_date('08-07-2014', 'dd-mm-yyyy'), 10.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 1100.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('E6666', to_date('01-01-2014', 'dd-mm-yyyy'), to_date('01-02-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  
  
  SELECT A.ACCOUNT,
         A.BEGIN,
         A.END,
         A.AMOUNT,
         B.ACCOUNT,
         B.BEGIN,
         B.END,
         B.AMOUNT
    FROM TABLEA A
    LEFT JOIN TABLEB B
      ON A.ACCOUNT = B.ACCOUNT
  

  Hello

  SeshuGiri wrote:

  Hi Frank,.

  Your query/solution works very well, but I forgot to mention something in the first post...

  Please insert these additional lines and try the request again.

  TableA Additional lines:

  1. Insert into TABLEA (ACCOUNT, BEGIN, END, QUANTITY)
  2. values ('F9999', to_date (January 2, 2014 ',' dd-mm-yyyy ""), to_date (3 January 2014 ', 'dd-mm-yyyy'), 999.0000000000);
  3. Insert into TABLEA (ACCOUNT, BEGIN, END, QUANTITY)
  4. values ('A1234', to_date (March 3, 2014 ',' dd-mm-yyyy ""), to_date (4 March 2014 ', 'dd-mm-yyyy'), 999.0000000000);

  TableB Additional lines:

  1. Insert into TABLEb (ACCOUNT, BEGIN, END, QUANTITY)
  2. values ('A1234', to_date (March 3, 2014 ',' dd-mm-yyyy ""), to_date (4 March 2014 ', 'dd-mm-yyyy'), 999.0000000000);

  Question 1:

  The table has a rows for A1234 account (i.e. the time period different than the ranks for the same account)

  one is A1234 31/01/2014-03/03/2014, A1234 03/03/2014-03/04/2014

  Your query that returns two rows for A1234 account (which is what I want), but the amount is messed up.

  	ACCOUNT	BEGIN	END	TOTAL_AMOUNT
  1	A1234	31/01/2014	03/03/2014	1100
  2	A1234	03/03/2014	03/04/2014	1100

  Except:

  	ACCOUNT	BEGIN	END	TOTAL_AMOUNT
  1	A1234	31/01/2014	03/03/2014	101
  2	A1234	03/03/2014	03/04/2014	999

  Question 2:

  In some cases TableA will have an account (F9999), but the TableB don't. I can just this line by making the Left Join right join?

  I don't get the results with additional data. I get 1099 for two lines where account = 'A1234 '.  I get 1100 as the amount on the line with the account = "D5555.  You did it other changes to data?

  Except:

  	ACCOUNT	BEGIN	END	TOTAL_AMOUNT
  1	A1234	31/01/2014	03/03/2014	101
  2	A1234	03/03/2014	03/04/2014	999

  Still, I don't see why you want to 101 for the amount of the first row.  Why not 100?

  How can you know which rows from tablea should get attached to what rows from tableb, when the account is not unique?

  Maybe you want something like this:

  SELECT a.account

  b.begin

  b.end

  SUM (a.amount) AS total_amount

  FROM tablea a

  ON a.account = b.account JOIN tableb B

  AND a.begin BETWEEN b.begin

  AND b.end

  AND a.end BETWEEN b.begin

  AND b.end

  GROUP OF a.account, b.begin, b.end

  ORDER BY a.account

  ;

  but I guess just to your needs, and guessing is not a very good or reliable way to solve problems.

  Question 2:

  In some cases TableA will have an account (F9999), but the TableB don't. I can just this line by making the Left Join right join?

  Yes, it looks that you want an outer join.  What happened when you tried?  As always, post your code, the exact results you want from the given sample data, as well as an explanation of how you get these results from these data.

• Get the data in table of javafx

  Bat I can get the data in table as:

  [code]

  for (int i = 0; i < dtm.getRowCount (); i ++)

  {

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  [/ code]

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  You can browse the data simply by practice

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    // ...
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    for (TableColumn col : table.getColumns()) {
      Callback, ObservableValue> cellValueFactory = col.getCellValueFactory();
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    }
  }
  

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• Is it possible to see/get the data from the table to a dump file

  I have files dmp generated using expdp on oracle 11 g...

  expdp_schemas_18MAY2013_1.dmp

  expdp_schemas_18MAY2013_2.dmp

  expdp_schemas_18MAY2013_3.dmp

  Can I use a settings file given below to get the data from the table in the file sql or impdp the only option to load the data of table in database.

  VI test1.par

  USERID = "/ as sysdba".

  DIRECTORY = DATA

  dumpfile=expdp_schemas_18MAY2013%S.dmp

  SCHEMAS = USER1, USER2

  LOGFILE = user_dump_data.log

  SQLFILE = user_dump_data. SQL

  and impdp parfile = test1.par.

  No,

  DataPump cannot retrieve a dumpfile data in a flat file.

  Dean

• How to get the dates of discontinuity

  If there is discontinuity in dates how we write the query...
  I need to get the dates and the dates of discontinuity.
  I / p:
  
  item_no first_date second_date
  1 January 1, 10 Aug 1, 10
  
  1-01 - 7.-10 1er January 11
  
  1 February 1, 11 1 July 11
  "
  "
  "
  o/p:
  
  1 1 January 10 01 - aug - 10
  
  1 02-aug-10 (first_date + 1) 31-aug-10(second_date-1) - dates of discontinuity
  
  1-01 - sep - 10 (second_date) 1st January 11
  
  1 January 2, 11 January 31, 11
  
  1 February 1, 11 1 July 11
  
  '
  '
  '
  Please let me know is possible

  SQL> select  *
    2    from  tbl
    3  /
  
          ID FIRST_DAT SECOND_DA
  ---------- --------- ---------
           1 01-JAN-10 01-AUG-10
           1 01-SEP-10 01-JAN-11
           1 01-FEB-11 01-JUL-11
  
  SQL> with t1 as (
    2              select  tbl.*,
    3                      lag(second_date) over(partition by id order by first_date) prev_second_date
    4                from  tbl
    5             ),
    6       t2 as (
    7               select  *
    8                 from  tbl
    9              union all
   10               select  id,
   11                       prev_second_date + 1,
   12                       first_date - 1
   13                 from  t1
   14                 where prev_second_date + 1 < first_date
   15             )
   16  select  *
   17    from  t2
   18    order by id,
   19             first_date
   20  /
  
          ID FIRST_DAT SECOND_DA
  ---------- --------- ---------
           1 01-JAN-10 01-AUG-10
           1 02-AUG-10 31-AUG-10
           1 01-SEP-10 01-JAN-11
           1 02-JAN-11 31-JAN-11
           1 01-FEB-11 01-JUL-11
  
  SQL>  
  

  SY.

• How to get the date for the first Monday of each month

  Dear members,
  
  How to get the date for the first Monday of each month.
  
  I wrote the following code
  
  SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL
  
  But he looks at complex bith.
  
  Abhishek
  
  Published by: 9999999 on 8 March 2013 04:30

  Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

  select  sysdate current_date,
          trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
    from  dual
  /
  
  CURRENT_D FIRST_MON
  --------- ---------
  08-MAR-13 04-MAR-13
  
  SQL> 
  

  Here is the list of the first Monday of the month of this year:

  with t as(
            select  add_months(date '2013-1-1',level-1) dt
              from  dual
              connect by level <= 12
           )
  select  dt first_of_the_month,
          trunc(dt + 6,'iw') first_monday_the_month
    from  t
  /
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-JAN-13 07-JAN-13
  01-FEB-13 04-FEB-13
  01-MAR-13 04-MAR-13
  01-APR-13 01-APR-13
  01-MAY-13 06-MAY-13
  01-JUN-13 03-JUN-13
  01-JUL-13 01-JUL-13
  01-AUG-13 05-AUG-13
  01-SEP-13 02-SEP-13
  01-OCT-13 07-OCT-13
  01-NOV-13 04-NOV-13
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-DEC-13 02-DEC-13
  
  12 rows selected.
  
  SQL> 
  

  SY.