"Greater than or equal to ' searches on pavement

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• 'Tools of sea for Windows' error: 'length' argument must be greater than or equal to zero. System. rope mi (System. sting. int32 int32).

  Original title: HOW to FIX THIS? 'length' argument must be greater than or equal to zero. System. Middle string (System. sting int32 int32.)

  Hi everyone in the Microsoft community,

  I am a novice at this stuff to pc, so excuse me if I ask a stupid question!

  I try to use Seatoolsforwindows, but during the research phase, this message comes on the screen...

  'length' argument must be greater than or equal to zero. System. Middle string (System. sting int32 int32.)

  I uninstalled and reinstalled Seatools, but I get the same results.
  I sought answers from Google and could not find a suggestion to install
  Microsoft Visual C ++ 2005 and Microsoft Visual C ++ 2008. I have 5 versions of this software installed.

  Details of the system
  Card mother Gigabyte X48T DQ6
  Intel Q6600 CPU
  8 GB of DDR3 RAM Corsair
  Card MSI GTX680 tiun graphic Frozr
  PSU Corsair 620W
  Operating system Windows 7 Pro
  Hard Seagate and Samsung drives

  I would appreciate if someone can help me on this one.

  Thank you

  Tim B

  Instead of using the version of win, try the bootable version

• How can I write the symbol ' greater than or equal to "in a string or a label?

  Hello

  I tried to use the "symbol" font to create the greater or equal symbol, but it does not work.

  Does anyone know how to do this?

  Thank you

  User

  The only way I know to do, is to type in the appropriate character code (Alt-0179, using the keypad), then highlighting the unique character (in most fonts, it is the exponent 3), then change the font to "symbol".  The rest of the characters in the string will be in the same font as before, only the highlighted character will change.

• Namespace 0,0 in the application descriptor file must be equal to or greater than the minimum version 3.1

  Hello everyone

  I followed the link to create app Hello world for the playbook using Flashbuilder 4.6.

  https://developer.BlackBerry.com/air/documentation/ww_air_getting_started/Create_your_first_applicat...

  and I get the following error

  Namespace 0,0 in the application descriptor file must be equal to or greater than the minimum version 3.1 required by Flex SDK. AirHelloWorld-app.xml/AirHelloWorld/srcUnknownAIR application.xml problem.

  Any ideas or suggestions?

  Thank you

  I solved this problem.

  A PC restrated it is resolved.

  Thank you

• Flex Builder error: Namespace 2.6 in the application descriptor file must be equal to or greater than the minimum version 3.1 required by Flex SDK.

  "2.6 Namespace in the application descriptor file must be equal to or greater than the minimum version 3.1 required by the Flex SDK kit."

  what it means?

  to run the application

  (1) I need lower version 3.1

  (2) I need a newer version than the 3.1

  I'm confused.

  You can change the project xml file. I solved like this.

  

• 2.6 Namespace in the application descriptor file must be equal to or greater than the minimum version

  I imported a project mobile fb fb4.6, but this error:

  2.6 Namespace in the application descriptor file must be equal to or greater than the minimum version 3.1 required by Flex SDK.

  Is there a quick fix for this?

  you need to replace http://ns.adobe.com/air/application/2.6 "> to http://ns.adobe.com/air/application/3.1" > inside *-app.xml file. ""

• give meaning to cases where minimum effective_start_date is greater than the current date

  Hi guys, I'm not a developer oracle as such, but I'm trying to get some information from oracle to send to other systems of the company, since we are dealing with oracle HRMS as the master system for employee information.

  In particular, we would like to create people in our training and the security system when they are created in oracle.

  I was told that the oracle per_all_people_f object acts as a slowly changing dimension of type 2, where a person can have several versions, which only is always the current version and the current version can be retrieved using the standard parttern of "date of current between the effective start date and actual end date. So far so good.
  
  However, I can see there are cases where the minimum 'effective_start_date' is greater than the current date. It is, indeed, equal to their start_date. I guess start_date represents "the first day of work" of the person.

  But this means then there is no "current" information known to people who have not yet really started working for the company again. This seems odd. How can I have someone for whom we have no information "currently correct? I was told that the effective_start_date of the line is automatically set to their "first day of work" date on which the information is entered into the system, IE, the user to enter information doesn't have the ability to say 'this is the current version of the data for that person, who starts at a date in the future. "

  For this reason, I cannot know these new people (who have been entered in oracle, but did not have actually to their first day of work still) training system. But we would obviously get people established in related systems so that they can use all of these systems on their first day of work.

  Have I misunderstood something here? How can there be no correct version for a person at the date and time?

  Hello

  How normally "inform you" the training system on a new person record? If it's a kind of report or an interface, it may be useful changed to examine a number of days in the future, for example + 7

  It is important to understand when you look at an Oracle HRMS instance through enforcement (i.e. the ' front end'), you look at the data on a date date (of the session) - by default, the date is the system date, but it is possible for a user to change this date to be in the future or the past as they see fit. The ability to implement the records in person in the future is a great feature to have, of course, but it must be understood that in this situation, at the date of the day the person's file logically does not exist yet from the point of view of the MFC features. Behind the scenes, however, in the per_all_people_f of the table, the line exist. Similarly, future update of changes to a person (e.g. marital status from Single to married) could be implemented, and the change in status would be visible if the session has been scheduled on a date or after the date of the marriage. As correctly observe you, behind the scenes, the table will hold all historic entries for this person_id with contiguous effective_start_date and effective_end_date beaches.

  Either way, date_start value is not related to as such hiring date; It is actually the value of effective_start_date earlier for the person_id. All changes, regardless of how many or what the effective_start_date is in each case, will always carry this same start_date value. It * may * be identical to the hiring date (certainly the fact that you configure their hire date person records would cause that), but if the person has been created as a postulant effective from 1 September and was then hired has effect from 21 September, column start_date value would be still 1 September. The record of the person would be visible when the current date is on or after this date - the only difference is that they show that an employee until the 21st.

  I hope this helps, but it is possible, that I just confused you more!

  Clive

• Increment Dt start with day greater than the Dt at the end of the year Prev in Pro * C

  Morning people and greetings from Toronto.
  
  I'm trying to change a Pro * C program. Since ages I touched a Pro * C program but I have made an attempt for her. I would probably need some help andhopefully is the right forum I could nto seem to find any section decicated Pro * C programs.
  
  Here's what its supposed to do. I'm supposed to check if a Start Date of overlap between the start dates and dates from the end of the previous year, and if so, I'm supposed to assign one day Start Date greater than the Date of the end of the previous year.
  
  I have a control panel that stores records for start date and end Date for each year. Here's what I have for 2010.
  
  Start date = 8 May 2010 '; End date = may 12, 2011 'year =' 2010 From now the previous record in the table 1 (where the new record is supposed to be inserted) has a record that looks like this:
  

  DOC_ID     NAME               YEAR         START_DATE     END_DATE
  ------------------------------------------------------------------------------------------------
  999999     Mary Poppins      2009         03-May-2009      08-May-2010

  Now, based on the control table, the Start Date for 2010 coincides with the Date of the end of 2009. In this case, I would need to move the start date = may 9, 2010 "(Date of end + 1)
  
  Here is my ProC program in hand
  

  /* Include Headers */
  #include <stdio.h>
  #include <stdlib.h>
  #include <string.h>
  #include <ctype.h>
  #include <math.h>
  ---------------------------
  /* Define constants */
  ---------------------------
  #define  nullterm(string) string.arr[string.len] = '\0';
  /* SQL Host Variables */
  exec sql begin declare section;
  exec sql include sqlca;
  
   varchar   ctrl_start_date[11];
   short     ctrl_start_date_ind;
   varchar   ctrl_end_date[11];
   short     ctrl_end_date_ind;
  
   varchar   end_date[11];
   short     end_date_ind;
  
   int       exist_end_date_flag;
   short     exist_end_date_flag_ind;
  
  exec sql end declare section;
  
  
  /* Function Prototypes */
  
  void check_date_overlap();
  
  
  void main(int argc, char *argv[])
  {
  /* Coding starts here */
  
  void get_ctrl_dates()
  {
   exec sql
    select  to_char(trunc(ctrl_start_date),'YYYY/MM/DD'),
            to_char(trunc(ctrl_end_date),'YYYY/MM/DD')
    into    :ctrl_start_date :ctrl_start_date_ind,
            :ctrl_end_date  :ctrl_end_date_ind
    from    control_tb
    where   current_yyyy = :year_number;
  }
  
     check_date_overlap();
  
     if (strcmp( (char *)run_mode.arr,"N")==0)
     {
      check_date_overlap();
      create_person_rec(); /* This will insert record into person_tb table */
     }
  }
  
  /***********************/
  /* CHECK_DATE_OVERLAP  */ 
  /***********************/
  void check_date_overlap()
  {
  
   exist_end_date_flag = 0; /* assume he does not have a record */
  
   exec sql
    select count(*), end_date + 1
    into   :exist_end_date_flag exist_end_date_flag_ind,
           :end_date :end_date_ind
    from   person_tb
    where  doc_id = :doc_id
    and (( :ctrl_start_date between start_date  and end_date ) or
         ( :ctrl_end_date   between start_date  and end_date ) or
         ( start_date between :ctrl_start_date  and :ctrl_end_date ) or
         ( end_date   between :ctrl_start_date  and :ctrl_end_date ))
    and    year_number = (:year_number - 1)
    group by end_date
    having count(*) = 1;
  
    /*** Error Check Routine goes in here ***/
  
    /* Overlapping of dates; Set the Start Date equal End Date + 1 to avoid overlap */
    if (exist_end_date_flag == 1)
    {
     print_to_err_file("The Start Date is overlapping with a previous period.",0);
    }
  
     nullterm(end_date);
  
  } /* check_date_overlap */

  Here would be my question:
  
  My question is, should the SQL above be written like this instead?

  /***********************/
  /* CHECK_DATE_OVERLAP  */ 
  /***********************/
  void check_date_overlap()
  {
  
   exist_end_date_flag = 0; /* assume he does not have a record */
  
   exec sql
    select count(*), end_date
    into   :exist_end_date_flag exist_end_date_flag_ind,
           :end_date :end_date_ind
    from   person_tb
    where  doc_id = :doc_id
    and (( :ctrl_start_date between start_date  and end_date ) or
         ( :ctrl_end_date   between start_date  and end_date ) or
         ( start_date between :ctrl_start_date  and :ctrl_end_date ) or
         ( end_date   between :ctrl_start_date  and :ctrl_end_date ))
    and    year_number = (:year_number - 1)
    group by end_date;
  
    /*** Error Check Routine goes in here ***/
  
    /* Overlapping of dates; Set the Start Date equal End Date + 1 to avoid overlap */
    if (exist_end_date_flag == 1)
    {
      /* Is this even correct or would I have to do a strcpy?.
          Also note that I am overwriting ctrl_start_date which
          was fetched earlier in get_ctrl_dates() */
     ctrl_start_date = end_date + 1;
     print_to_err_file("The Start Date is overlapping with a previous period.",0);
    }
  
     nullterm(end_date);
  
  } /* check_date_overlap */

  Published by: Raj404261 on June 10, 2009 11:21

  You can put your code between the {code}

  As
  {code}
  your code...
  ...
  {code}

  SS

• How to create a default profile for all users of a computer under Windows 7/Vista for Firefox versions greater than 8? I would that all new users on a computer to get the same values by default, homepage, bookmarks, etc...

  I found some help on older versions of Firefox, but I can't seem to find anything for the latest versions greater than 8. There must be a way to do this for imaging large scale.

  Have you created a defaults\profile in the folder of the program Firefox (C:\Program Files\Mozilla Firefox\)?

  All files in this folder will be moved into each newly created profile folder.

  To give the prefs a default, it is best to do this via a mozilla.cfg file.

  Use a mozilla.cfg file in the Firefox program folder to lock the prefs or specify default values.
  
  Place a local file - settings.js in the defaults\pref folder where you will also find the channel - prefs.js to specify using mozilla.cfg file.

  pref("general.config.filename", "mozilla.cfg");
  pref("general.config.obscure_value", 0); // use this to disable the byte-shift
  

  See:

  • http://KB.mozillazine.org/Locking_preferences

  You can use these functions in mozilla.cfg:

  defaultPref();  // set new default value
  pref();         // set pref, but allow changes in current session
  lockPref();     // lock pref, disallow changes
  

• relaxation led when the value is greater than

  Hey everybody! I have to do a project and im stuck because I'm a noobler with regard to labview. I'm using labview 6 and got to watch the pressure and temperature of a reactor in time. I need to create a system in which if a value is greater than it triggers an alarm (perhaps led can show it) or is less than a certain limit. I mean it should trigger an alarm when the temperature or pressure is beyond 100 and less than 10. And after that to generate a text document in which it is specified the time and date at which these values were exceeded. I also use randomly generated values. Can I get help please? I'm not manage it by myself)

  Line and force. as Norbert said.

  You won't get much sympathy on overloaded around here.  Three things occurred to me that I read your messages:

  1. You will be in trouble when you get a job if you think that you will be not always charged.
  2. If I help you, you'll probably end up working for me and I still have to do your homework.
  3. You'll be fine.  Engineers outsource their work all the time.

  

• IMAQ_USB - 1074396024 (coverage Minimum value must be greater than zero)

  Hello

  I have problems to use a USB WebCam when I try to run an executable file in a PC that not have installed LabVIEW. The error code that is displayed is 1074396024 (coverage Minimum value must be greater than zero).

  When I run it on a PC that installed, LabVIEW everythings works great!

  Someone has an idea to help me? The sample program is attached.

  Thks

  Hey neat,

  To run your executable file in a free LabVIEW PC, you must install LAbVIEW Run-Time Engine and Vision Run-Time Engine.

  http://digital.NI.com/public.nsf/allkb/3EB8C8AFC1593B4A8625712E0002869B

  Engine performance vision application for permit.

  Best regards

  Abel Souza

  Engineering applications

  National Instruments Brazil

• Read byte with a value up to 127 lire byte with an ASCII value greater than 7F (127 dec)

  Hello

  I have to read a byte with a value greater than 127, Labview turn 27.

  In help I saw that Labview provides a description of ASCII that pour values ranging up to ' 127.

  What do I need to do?

  LabVIEW 6.1

  Windows XP

  Hello

  I want to read a byte with a maximum value of 127, but Labiew reurn arround 27 value

  How do I do?

  

  Rigid wrote:

  Thanks for your help. I'm not changing lyke I understand (my English is poor quiet...)

  I have another program that communicate with the instrument. I know byte (6) must be greater than 18 (greater than 7F actually).

  But with Labview, I'm only 18.

  While it might be higher than 18 x, an I8 is signed, and therefore it cannot be greater than x7F - it has a range of-128 to 127. A U8 is not signed, and it's why he has a range from 0 to xFF. However, x 18 is the same if you treat as signed or not signed. I don't see how LabVIEW can read a wrong value on the serial port. Are you sure you're looking at the correct byte? Your code shows that you split the chain twice. Are you sure that you do this properly?

  Given that you use on Windows you can recheck the chain received using PortMon. Allows you to see what is actually received by the driver for the serial port on Windows.

  P.S. I actually meant the whole byte function.

• Read/write file binary change greater than 128 bytes.

  Hi all, maybe a strange question, but I'm scratching my head on this one. There is undocumented behavior in the function of read/write binary file, where U8 a value greater than 128/0 x 80 get automatically converted to 0x3F value?

  I try to use LabVIEW to generate a binary file custom that we'll load in an EEPROM, so all data in the binary file is stored as values of U8. I have a "template" file, and eventually I'll take the logic implemented to replace the fields with the data from the true value. However, I am struck by the anomaly that when I just read the file in LabVIEW and then réécrirait, all the values 0x80 and more are truncated to 0x3F value. Has anyone seen this before, and is there a solution?

  I noticed writing the value 0 x 80 directly to one generates a binary file (such as a U8) 0 x 90, 0 x 70 being written in the binary file. It is also rather undesirable, as it adds additional bytes in the bytestream, and the bytes of EEPROM must be in exact locations.

  

  

  Join your data file.

  This program is to give the images below?  Are you sure that LabVIEW is to write the bytes differently?  I really doubt that.

• Drivers not less than or equal error when computer starts.

  Original title: error.

  Hello. Today, after loging on my desktop, rebooted pc. When the computer reboots. same problem again. I tried to reinstall windows xp, but after copying files and restarting. either it gets stuck before loading windows or give me the blue screen with the drivers not less than or equal, and other warnings on blue screen restart when... tried to replace the drive hard but same problem. P4: 2.60 ghz (it was a celeron 2.0 but it changed on 2 months) 512 MB of ram (that's 256) vga added by me.and the drive restarts several times or turn off... help please

  Hi marilym,.

  Please write us with the following details so that we can better help you.

  (1) what is the exact full error message?

  (2) what is the brand and model of your computer?

  The issue you described could be because corrupt drivers installed on your computer. Follow the steps in the link given below. The link given below is for DRIVER_IRQL_NOT_LESS_OR_EQUAL errors as well.

   

  Stop error message on a Windows XP-based computer: "STOP 0x000000D1".

   

  http://support.Microsoft.com/kb/916595

  I suggest you to provide us with the minidump files so that we can understand the root cause of the problem and help you at best. Follow the instructions in the link below.

  Use SkyDrive download collected files and post screen shot/image

  http://social.technet.Microsoft.com/forums/en-us/w7itproui/thread/4fc10639-02dB-4665-993a-08d865088d65

  Follow the steps in the link, find the question and if the problem persists we write with the minidump files. We will help you to come.

• Outlook 2007 backup file is greater than the source file. Why?

  My Outlook pst data source personal folders file using 2.4 GB.  The backup file (by using the backup tool) uses 5.4 GB.  Why the difference?  I back up all my data on a hard drive to FAT 32 format, which will not accept a file greater than 4 GB, so I'm not able to save Outlook backup file given its current size.

  Hello GaryCalgary,

  Thanks for visiting the site of the community of Microsoft Windows XP. The question you have posted is related to Outlook and would be better suited to the community of Office Discussion groups. Please visit the link below to find a community that will provide the support you want.
  Outlook General Questions Discussion Group

  Steven
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think