How concatinate values of column in a single column

Similar Questions

• Select the records from the first n distinct values of column

  I need to write a query in plsql to select records for the first 3 values distinct from a single column (example below, ID) and all lines for the next 3 distinct values of column and so on until the end of the number of distinct values in a column.
  for example:
  Age of name ID
  1 abc 10
  1 def 20
  2 IA 10
  2 20 JKL
  2 mno 60
  3 10 pqr
  4 the RST 10
  4 10 TÜV
  5 vwx 10
  6 10 XYZ
  hij 6 10
  7 lmn 10
  .
  .
  .
  so now... (up to a few County)
  Result must be
  1 the application should result->
  Age of name ID
  1 abc 10
  1 def 20
  2 IA 10
  2 20 JKL
  2 mno 60
  3 10 pqr
  
  Query 2 should lead to->
  4 the RST 10
  4 10 TÜV
  5 vwx 10
  6 10 XYZ
  hij 6 10
  
  Query 3 should lead to->
  7 lmn 10
  .
  .
  9... ..
  so now...
  How to write a query for this inside a loop.

  Hello

  Thus, a panel will consist of the lowest id value, the 2nd lowest and the 3rd lower, reggardless of how many lines is involved. The next group will include the 4th lowest id, the 5th lowest and the 6th lowest. To do that, you must assign the numbers 1, 2, 3, 4, 5, 6,... for the rows in order by id, with all lines with the same id, getting the same number and without jumping all the numbers.
  This sounds like a job for the analytical DENSE_RANK function:

  WITH     got_grp_id     AS
  (
       SELECT     id, name, age
       ,     CEIL ( DENSE_RANK () OVER (ORDER BY id)
                 / 3
                 )          AS grp_id
       FROM     table_x
  )
  SELECT     id, name, age
  FROM     got_grp_id
  WHERE     id     = 1     -- or whatever number you want
  ;
  

  If you would care to post CREATE TABLE and INSERT statements for your sample data, then I could test it.
  See the FAQ forum {message identifier: = 9360002}

• Retrieve two values of column in a table

  Hi I want to retrieve two values of column in a table and store the values as a single column value in another table... How to do with it?

  Use in this way:
  Insert in tab2 (col1) select col1 | col2 from tab1;

• How to fill a column with numbers and maintain when adding or deleting lines?

  So far, I've discovered two ways to fill a column with the number:

  1. Enter '1' in a single cell, '2' in the one below, select both, and then use the yellow dot to drag down - it will do the rest.

  2 create a formula such as 'A2 + 1' and drag also.

  However, in both cases it will work if I manually this continues to do for each newly added line at the bottom. Now, that alone would not be that big of a problem if it wasn't for the fact that I'm working with a table where the lines can be added among other rows in the future.

  Having said that, could someone please tell me how to create a column with a number that will increase automatically? I mean - if I add a new line between line 56 and 57, I want the new line to have a '57"in it, and the" old 57 "would now be"58"and so on." " I don't want to drag the whole column, which can be hundreds if not more than a thousand lines.

  Try to put this in the cells in the column:

  = ROW()

  In the formula, you can add or subtract a number if necessary to get the starting number that you need.

  SG

• How to take a column of duplicate names and fill a different column with the same names, excluding duplicates?

  How to take a column of duplicate names and fill a different column with the same names, excluding duplicates?

  I find easier to use this copy separate Automator Service (download Dropbox).

  To install in your numbers > Services, double-click menu just the package downloaded .workflow and if necessary give permissions in system preferences > security & privacy.

  To use, just:

  1. Select the cells in the column with duplicate names.
  2. Choose separate copy in numbers > Services menu.
  3. Click once in the upper cell where you want the deduplicated values appear.
  4. Command-v to paste.

  SG

• How do delet several columns in the 2D table 0

  Dear Sir.

  Please tell me how delet 0 multiple column besuace zero of one by a column of delet take too much time. Here, I have attached the program with this message and the main file.

  

  Julian_prince wrote:

  Please tell me how delet 0 multiple column besuace zero of one by a column of delet take too much time. Here, I have attached the program with this message and the main file.

  How big are your real matrices? How do you measure the speed? How fast is now and how fast should it be?

  In all cases, you can do it with a single loop, for example as an attachment.

• How to dynamically generate columns in conventional reports

  Hi all

  How to create dynamic columns in classic reports.

  I need to create these columns that depends on the difference of the date column start date and end date.

  for example: 4 November 2015 start_date and end_date is November 7, 2015

  I show the columns Day1, day 2, day 3 and day 4.

  and the values of these columns are checkboxes.

  Kind regards

  Arianne.

  Hi ujwala1234,

  ujwala1234 wrote:

  How to create dynamic columns in classic reports.

  I need to create these columns that depends on the difference of the date column start date and end date.

  for example: 4 November 2015 start_date and end_date is November 7, 2015

  I show the columns Day1, day 2, day 3 and day 4.

  and the values of these columns are checkboxes.

  The old packed timesheet application has the tip for how to display the day of the week selected by the user in the form of columns in the tabular presentation.

  Reference: old packages of timesheet Application

  That's how I'd do:

  • Select the range of dates populate the days between the date columns range in a collection of the APEX.
  • Display the columns as editable using the APEX_ITEM API.

  NOTE: Application of time sheets there was select list for weeks, so always the number of dynamic columns would be 7 + column code time.

  Also, the maximum number of modifiable columns, you can use on your page APEX is 50.

  Kind regards

  Kiran

• change the color of line based on the value of column 5 Apex in the classic report

  Version of the apex 5.0.0.00.31

  Standard universal theme

  Page theme default template

  Classic report

  Foldable report template

  Hello

  I know this question has been asked several times here, but I'm working on 5 Apex and need to know the correct way to do it in this version.

  I need to change the color of the text of the entire line (no background color) based on the value in one of the columns of the classic report. I have just two conditions, if the value of column = Yes, color should be red, otherwise it must be green.

  I am new to jscript and css, so appreciate if someone can tell me the solution with steps.

  I have already checked this link that changes the value of the column, need to do something similar to the whole line.

  https://tylermuth.WordPress.com/2007/12/01/conditional-column-formatting-in-apex/

  Hi coolmaddy007-Oracle,.

  Here's an example set up on the apex.oracle.com according to the specifications you gave: https://apex.oracle.com/pls/apex/f?p=35467:1

  Version of the apex 5.0.0.00.31

  Standard universal theme

  Page theme default template

  Classic report

  Foldable report template

  Here is how it is done:

  Create a dynamic action with the following specifications:

  Name: Give the appropriate name

  Event: After refresh

  Selection type: region

  Region: select your region classic report

  Condition: No strings attached

  Action: Run the JavaScript Code

  Fire on loading the Page: Yes

  Code:

  $('td[headers="JOB"]').each(function() {
    if ( $(this).text() === 'MANAGER' ) {
      $(this).closest('tr').find('td').css({"color":"red"});
    }
    if ( $(this).text() === 'SALESMAN' ) {
      $(this).closest('tr').find('td').css({"color":"green"});
    }
    if ( $(this).text() === 'CLERK' ) {
      $(this).closest('tr').find('td').css({"color":"blue"});
    }
  });
  

  NOTE: Download the selector appropriate for your knowledge $('td[headers="JOB"]') case using firebug/browser development tools.

  Items concerned: leave blank.

  PS: Changed the example to change the color of text instead of the background color.

  I hope this helps!

  Kind regards

  Kiran

• How to remove a column from a table in a dell identtiymananger 7.0

  How to remove a column from a table in a dell identtiymananger 7.0

  Hello

  In Version 7 of the removal of a single custom column can be accomplished by a stored procedure, available in the database called: QBM_PColumnDrop

  Hope that helps.

  Cordially Fatih

• Dictionary of data values in column view (s)

  The following query is the list of the most fragmented tables.

  My question is that I do not understand why the value of the blocks is multiplied by 8. Is because the value of column of blocks show a kilo byte? so convert us kilo bits?

  My second question is, what is the value of these columns represent in general? In other words, when I look at the data of avg_row_len how can I understand the which type of data it represent?

  For example: avg_row_len, the number in this column represents byte? or kilobye?

  select table_name,round((blocks*8),2) "size (kb)" ,
                  round((num_rows*avg_row_len/1024),2) "actual_data (kb)",
                 (round((blocks*8),2) - round((num_rows*avg_row_len/1024),2)) "wasted_space (kb)"
from dba_tables
where (round((blocks*8),2) > round((num_rows*avg_row_len/1024),2))
order by 4 desc

  Thanks in advance.

  So what you don't understand? Num_Rows * avg_row_len gives "average you" number of bytes occupied by the data in the table. Num_Rows * avg_row_len/1024 is same in KB. And round ((num_rows*avg_row_len/1024), 2) round it to two decimal places. blocks * 8 (as I said, code you posted assume table block size is 8K) is the space allocated to the table in KB. And I have no idea why code is rounded, something that is whole number to start.

  SY.

• How to add two columns in the criteria (OBIEE 11 g)

  Hello
  
  I try to add two columns in a criterion of obiee
  
  * "Done - OLB processed invoices. "" Invoice amount - currency "__" made - OLB processed invoices "." " The amount of taxes AR - billing currency"
  
  but the problem is:-
  The first column have 500000000 and the second column contains some NULL values from the table. I think that this could be the problem when I try to add that it gives no output.
  just an empty box.
  
  Can someone tell me how we can add columns in this State.
  
  Thank you to each and every one.

  Try IFNULL (expr, value)
  for the other columns

  "Done - OLB processed invoices". " Charge the amount - currency "+ IFNULL (" made - OLB processed invoices "". ")" AR tax - currency billing", 0)

  Published by: Srini VIEREN on March 20, 2013 10:02

• Oracle how to multiply two columns of different tables and results

  Oracle how to multiply two columns of different tables and get the result in the third column?
  
  I want to multiply all the lines of the quantinty column in the table of quantity with the relevant lines of the table of prices price column and get the result of multiplying in the third column. What should I use procedure trigerr? OR IS IT POSSIBLE HOW TO DO IT PLEASE HELP :D
  
  Edited by: 994229 2013-03-15 12:44

  /* Formatted on 3/15/2013 3:51:08 PM (QP5 v5.185.11230.41888) */
  CREATE TABLE mytable1
  AS
     (SELECT 1 id, 5 VALUE FROM DUAL
      UNION ALL
      SELECT 2, 7 FROM DUAL
      UNION ALL
      SELECT 3, 8 FROM DUAL);
  
  CREATE TABLE mytable2
  AS
     (SELECT 1 id, 4 VALUE FROM DUAL
      UNION ALL
      SELECT 2, 12 FROM DUAL
      UNION ALL
      SELECT 10, 12 FROM DUAL);
  
    SELECT id,
           mytable1.VALUE,
           mytable2.VALUE,
           mytable1.VALUE * mytable2.VALUE product
      FROM mytable1 FULL OUTER JOIN mytable2 USING (id)
  ORDER BY id;
  

  ID     VALUE     VALUE_1     PRODUCT
  1     5     4     20
  2     7     12     84
  3     8
  10          12     
  

• How to hide a column in the report when there are only zeros.

  Hi Experts.,.
  
  Is it possible to hide a column in the report when there are only zeros.
  
  Thanks in advance
  Vincent

  Vincent Krishna wrote:
  Hi Experts.,.

  Is it possible to hide a column in the report when there are only zeros.

  Thanks in advance
  Vincent

  No out-of-the-box, but there are several workaround solutions if you want to continue an any of them:

  (1) use a view selector. A single report will be a pivot table with the column, the other will have the same report less column. Users can switch reports.

  (2) use a column selector. The two choices would be this column or an empty space. If white is chosen (because the user has no values), the column "will disappear" according to the report.

  (3) guided use NAV. This method involves the intervention of the user. Build a small report using the single column and put a filter "is not equal to" 0. Because there is only a single column, so all lines are 0, the report returns no rows.

  Use this report in the properties of guided navigation from one section of the dashboard. Assign to this "If the report returns lines" and put the report that contains the column in this section. Now add another article on your table edge and in the properties of guided navigation of this section, set on "If the report will return no rows" and it points to the small report as well. In this section, put a second version of your report without the column in it.

  When the column contains all zeros, the second section with column will not display in it; the first section is not displayed. When at least a line contains a value not zero, the first section is displayed with the column, and the second part will not be.

• How to add the column to the compressed table

  Hi gurus,
  
  Can someone help me how to add a column to compressed tables
  
  
  Thanks in advance

  The only difference is if added column has a default value. In this case:

  SQL> create table tbl(id number,val varchar2(10))
    2  /
  
  Table created.
  
  SQL> insert into tbl
    2  select level,lpad('X',10,'X')
    3  from dual
    4  connect by level <= 100000
    5  /
  
  100000 rows created.
  
  SQL> select bytes
    2  from user_segments
    3  where segment_name = 'TBL'
    4  /
  
       BYTES
  ----------
     3145728
  
  SQL> alter table tbl move compress
    2  /
  
  Table altered.
  
  SQL> select bytes
    2  from user_segments
    3  where segment_name = 'TBL'
    4  /
  
       BYTES
  ----------
     2097152
  
  SQL> alter table tbl add name varchar2(5) default 'NONE'
    2  /
  alter table tbl add name varchar2(5) default 'NONE'
                      *
  ERROR at line 1:
  ORA-39726: unsupported add/drop column operation on compressed tables
  
  SQL> alter table tbl add name varchar2(5)
    2  /
  
  Table altered.
  
  SQL> update tbl set name = 'NONE'
    2  /
  
  100000 rows updated.
  
  SQL> commit
    2  /
  
  Commit complete.
  
  SQL> select bytes
    2  from user_segments
    3  where segment_name = 'TBL'
    4  /
  
       BYTES
  ----------
     7340032
  
  SQL> select compression from user_tables where table_name = 'TBL'
    2  /
  
  COMPRESS
  --------
  ENABLED
  
  SQL> alter table tbl move compress
    2  /
  
  Table altered.
  
  SQL> select bytes
    2  from user_segments
    3  where segment_name = 'TBL'
    4  /
  
       BYTES
  ----------
     2097152
  
  SQL> 
  

  SY.

• How the values to insert into the table with the command insertion

  Dear all
  can someone tell me how the values to insert into the table with the command insert, I want to say I always use command insert behind my forms on what shutter release button press the button of my save, but today I had a form of 6i, where controls (textbox, combo, etc.) are delineated with directly the table with I guess than the Properties Windows , I created 3 columns in tand 3 text on forms fields, now kindly tell me how to do this fields to fill and do not insert command, I mean directly defined with table column
  
  
  
  Please help me its urgent

  Hello

  If the block is based on your database table, just committed the shape, then changes will be applied to the database.

  François