Imaginary number

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• Solve this linear system HP50g

  Hi guys,.
  I am an engineer in electrical engineering and have to solve systems of linear equations on a regular basis, so that the functionality is very important for me. Everything works very well, 95% of the time but sometimes I meet systems that the HP50g doesn't seem to like. For example one below.
  
  I want to solve for x, y, z and one in terms of V
  
  V- 100000 x +is-100000 100000x= 0
  -250000is-V+ 100000x100000z= 0
  -250000z+ 100000one+ 100000y= 0
  a+ 100000-250000z= 0
  
  After these 4 equations is on the stack, I'm them in a vector by pushing {4} in the stack and then by pressing -> ARRY. Then I push the variables I want to solve for the battery, x, y, z and a and a vector of them. Then, I use LINSOLV to solve the system. However, when I do it this way, the calculator gives me an equation for x, an equation for y and 2 equations for z and no equation for s. I'm not sure what I'm doing wrong. Is there another way to do that would give me 4 equations, one for each variable I want to solve for in terms of V?
  
  If my method to solve linear equations is somehow confusing, I basically followed this video
  http://www.YouTube.com/watch?v=z802L29JyQE
  
  Thanks in advance.

  Hello

  Do not know exactly how you typed, so I'm being explicit just for some b:

  Notes:

  (1) as an equation is entered, use ' '

  (2) it is preferable to use a comma to separate the real and imaginary parts

  (3) explicit use multiply

  If the entry will look like this:

  '(4,3*X) = (4.7)'

  For this simple equation and assuming that X is defined as an independent variable (reproduced by 'X' in the top middle of the screen), you can use SOLVEVX for this one: (No. 5 in S.SLV menu or F5 if you use soft-keys)

  with "_Approx" uncontrolled, the answer is:

  X = 7/3

  with "vabout" checked the answer is:

  X = (2.333333333,0) (although X is part of the imaginary number, it is himself a real number).

  Kind regards.

• Calculate the imaginary part of the complex number

  I recently got a s 35 HP. I would like to know how to enter a complex number with an imaginary part calculated, like 2 + sqrt (3) I. I tried several strategies by using parentheses, even put the sqrt (3) in a stored variable and recalling it, but everything I tried of gives me an answer "Syntax error". It is hard to believe that something so simple can be done easily. I hope someone out there has an easy solution!

  Hi, Make,

  The link you cite is the same document that I have referred to in my rating of 17/08/2015 at 4:15, mention the kind of number that I want to, but don't say don't not how to enter in the calculator. However, moving to RPN, one CAN easily enter these numbers. Two examples:

  3 + 2i [sqrt] 2 [sqrt] ix3 + which reads: 3i1.4142 (in format xiy)

  5. [sqrt] 3i 3 [sqrt] [+/-] ix5 + which reads: 5i - 1.7321 (once again, in the format xiy)

  or, put the real part first, 5 [ENTER] 3 [Sqrt] [+/-] ix +.

  So, as I suspected, I need to use RPN for this sort of thing.

  Thank you for your support.

  John

• HP - 50g written problem complex number. How to write (3 + i * 3 * sqr (3)) to RPN? (3, i3sqr (3))

  Hello everyone, I don't know how to write (i 3, * (3 * sqr (3))) RPN mode.

  Can someone help me please? I already searched the gug pdf guide help, without result.

  Thank you.

  Hello

  A few notes in the representation of a complex number as a vector:

  (1) the i is omitted, the second number is supposed to be the imaginary part.

  (2) the 50 g accepts only decimal numbers for vector representation

  Thus, at the entrance there. I guess you have the calculator in complex mode and exact mode (about not checked in "MODE"-> "SAE"), i.e. "C =" displayed at the top of the screen.

  RPN mode:

  Press 3 then ENTRY (3 is at level 1)

  Press ENTER again (3 is now duplicated and on both levels 1 and 2 - one advantage of RPN)

  Press ENTER again (3 is now duplicated and on levels 1, 2 and 3)

  Press the button of sqrt (x). Level 1 shows a 3 with a sign of the square root.

  Press on multiply key, level 1 shows 3· SQRT (3)

  Press LeftShift (white), then I (above the TOOL key), level 1 indicates an i

  Press on multiply key, level 1 shows 3· SQRT (3)· I have

  Press + key, level 1 shows 3 + 3· SQRT (3)· I have (or 3· SQRT (3)· i + 3 according to the parameter Flag - 27)

  If you want to keep the symbolic result (with the symbol of the 'SQUARE root'), leave it in this form, if you want to convert to vector format press (red) RightShift, then -> NUM (above the ENTER key).

  The result will be a decimal vector shape (3, 5.19615242271).

  Kind regards

  BartdB

• Adobe is really sitting very high on their horse (imaginary?): their software system and phone MAZE makes it (almost)?) Impossible to disable a CS6 on a computer crashed, so I can re - install my product PAID again! Any help in sight?

  Adobe is really sitting very high on their horse (imaginary?): their software system and phone MAZE makes it (almost)?) Impossible to disable a CS6 on a computer crashed, so I can re - install my product PAID again! Any help in sight? @

  Serial number and activation support (no-Cloud) https://forums.adobe.com/thread/2041990 to adjust the number of activations

• How to add an imaginary line in the result of the value of a SELECT statement.

  Hello all-
  
  I have requirment to add an imaginary line in the result set of a SELECT statement.
  
  For example lets say it is a pay table having the following columns:
  
  Number of Payment_id
  status varchar2 (10)
  number amount
  date of payment_date
  
  so here's the data: -.
  
  Payment_id status amount payment_date
  applied 1 100 12/07/2008
  2 Reversed 200 01 / 06/2009
  Applied 3 300 01 / 07/2009
  
  
  Here is my SQL
  
  Select * form payment where payment_date > = 01/01/2009
  
  The output will be
  
  2 Reversed 200 01 / 06/2009
  Applied 3 300 01 / 07/2009
  
  My desired output is less than
  
  2 Reversed 200 01 / 06/2009
  Applied 3 300 01 / 07/2009
  reversed-200 2, 01 / 06/2009-(Dummy Row)
  
  Third line here is the imaginary line that I add when the status is "reversed".
  
  I would be very grateful for any help on this...
  
  Thank you
  Gerard

  Cartesion join against a shadow table is a useful method to create a fictitious line:

  with my_tab as (select 1 cust_id, 1 Payment_id, 'Applied' Status, 100 Amount, to_date('12/07/2008', 'mm/dd/yyyy') payment_date from dual union all
                  select 1 cust_id, 2 Payment_id, 'Reversed' Status, 200 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 1 cust_id, 3 Payment_id, 'Applied' Status, 300 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 1 Payment_id, 'Applied' Status, 100 Amount, to_date('12/07/2008', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 2 Payment_id, 'Reversed' Status, 200 Amount, to_date('01/05/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 3 Payment_id, 'Applied' Status, 300 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 4 Payment_id, 'Reversed' Status, -400 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 5 Payment_id, 'Applied' Status, 500 Amount, to_date('01/07/2009', 'mm/dd/yyyy') payment_date from dual),
                  --- end of mimicking your table
        dummy as (select 'Reversed' col1, 1 rn from dual union all
                  select 'Reversed' col1, 2 rn from dual)
  select mt.cust_id,
         mt.payment_id,
         mt.status,
         decode(dummy.rn, 2, -1*mt.amount, mt.amount) amount,
         mt.payment_date
  from   my_tab mt,
         dummy
  where  mt.status = dummy.col1 (+)
  order by mt.cust_id, mt.payment_id, dummy.rn nulls first;
  
  CUST_ID     PAYMENT_ID     STATUS     AMOUNT     PAYMENT_DATE
  1     1     Applied     100     07/12/2008
  1     2     Reversed     200     06/01/2009
  1     2     Reversed     -200     06/01/2009
  1     3     Applied     300     06/01/2009
  2     1     Applied     100     07/12/2008
  2     2     Reversed     200     05/01/2009
  2     2     Reversed     -200     05/01/2009
  2     3     Applied     300     06/01/2009
  2     4     Reversed     -400     06/01/2009
  2     4     Reversed     400     06/01/2009
  2     5     Applied     500     07/01/2009
  

  Published by: Boneist on January 7, 2009 23:10
  NB. You may need to mess around with the order if that is not in the order you want. You did not mention what the rules were for all orders expected, so I composed my own * {;-)

  Also, I added a (cust_id) identifier to differentiate different types of payments, as is usually the case. Remove unless it is not applicable to your case.

• Phone number not an option for iMessage on iPad mini

  Hello

  So my ID Apple was recently hacked and had to change my password on all my devices (iPhone 6 and mini iPad). But now that I changed, my iMessage works well for my iPhone, but on my iPad, I have no option to choose my phone number. I tried to reset iMessage, reset my iPad, everything. Now I'm curious to know why, that's happened what else I can do for an option again.

  Thanks in advance for helping me!

  To go through all these steps?

  Use continuity to connect to your Mac, iPhone, iPad, iPod touch and Apple Watch - Apple Support

  Use this feature with any Mac, iPhone, iPad, or iPod touch that satisfies the requirements of continuity system. Make sure that your devices are configured as follows:

  • Each device is connected to iCloud with the same Apple ID.
  • On iPhone, go to settings > Messages > Send and receive. Make sure the Apple ID at the top of the screen is the same Apple ID you use for iMessage on other devices. Add a check to your address, phone number, so that you can be reached by both iMessage. Do the same on your iPad or iPod touch.
  • On iPhone, go to settings > Messages > transfer, text messages, then choose which devices to send and receive text messages from the iPhone. A verification code and then on each device. Enter this code on your iPhone.
  • On Mac, open Messages, and then choose message > Preferences. Click accounts, and then select your account from iMessage. Make sure the Apple ID shown here is the same Apple ID you use on other devices. Add a control to your phone number and email address.

  Use the SMS and MMS messaging

  

  To use this feature, simply start conversations as usual in the Messages application on any of your devices. Alternatively, you can start a conversation by clicking a phone number in Safari, Contacts, calendar, or other applications detecting phone numbers. All your incoming and outgoing messages on all your devices.

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  Column1	Column2
  5	5
  5	2
  5	5
  4	3
  4	4

  Football match
  3

  I basically you want to compare two columns and count matches in the corresponding lines. I tried using the following formula:

  SUMPRODUCT (--($column1=$column2))

  ... but it doesn't work! Any suggestion?

  Tiago,

  It seems you are trying to use array formulas (maybe since excel?) who do not work in number.

  Here's how I would solve this problem:

  

  Make sure that the table where data is named 'Data' (as shown, or change the table name references to match your table name)

  Add a new column (C)

  C2 = AND (A2 = B2, A2≠ "")

  It's shorthand dethrone select cell C2, then type (or copy and paste it here) the formula:

  = AND(A2=B2, A2≠"")

  Select cell C2, copy

  Select cells C2 at the end of the C column, paste

  the formula say to check to see if the cell in column A is NOT empty, and is equal to the cel in column B

  Now in the summary table (single cell table):

  A1 = COUNTIF (Data::C, TRUE)

• My phone transferred to my husbands phone number

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  Remove the SIM card as well. The sim card has your number.

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  This is the sort order...  I think you would need to change the names of the artists so that they start with something that gets sorted at the top of the list in alphanumeric order.  For example, replace 10,000 Maniacs a_10, 000 Maniacs.

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  Problem solved:

  When you start the new phone he kept stuck on my iCloud password so I jumped this option. When the phone started, my iCloud showed I was connected and all my contacts were correct. I disconnected icloud, removed from the contacts to the new phone and re-connected to iCloud. Problem solved.

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  vrmcw wrote:

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  account settings - sync mails - 'Exchange' on my phone - spam day-

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  See this - change or remove your Apple ID - Apple Support payment informationand if it does not help, scroll to the bottom of the article where you will find a contact for iTunes link which can help in this matter.

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  Thanks for your wisdom shared, Oh wise Ones.

  I'm not aware of do what you want.  You can post your comments directly to Apple using the menu item "numbers > provide Feedback numbers.

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  You disconnect from the iMessage and FaceTime on his device and connect you then return with his new Apple ID? If she checked in settings > Messages, send / receive, is his number and Apple ID the only checkmark beside it? Have you checked your device in settings > Messages > Send and receive, and make sure that your number and Apple ID are the only ones to be audited?