Solve this linear system HP50g

Hi guys,.
I am an engineer in electrical engineering and have to solve systems of linear equations on a regular basis, so that the functionality is very important for me. Everything works very well, 95% of the time but sometimes I meet systems that the HP50g doesn't seem to like. For example one below.

I want to solve for x, y, z and one in terms of V

V- 100000 x +is-100000 100000x= 0
-250000is-V+ 100000x100000z= 0
-250000z+ 100000one+ 100000y= 0
a+ 100000-250000z= 0

After these 4 equations is on the stack, I'm them in a vector by pushing {4} in the stack and then by pressing -> ARRY. Then I push the variables I want to solve for the battery, x, y, z and a and a vector of them. Then, I use LINSOLV to solve the system. However, when I do it this way, the calculator gives me an equation for x, an equation for y and 2 equations for z and no equation for s. I'm not sure what I'm doing wrong. Is there another way to do that would give me 4 equations, one for each variable I want to solve for in terms of V?

If my method to solve linear equations is somehow confusing, I basically followed this video
http://www.YouTube.com/watch?v=z802L29JyQE

Thanks in advance.

Hello

Do not know exactly how you typed, so I'm being explicit just for some b:

Notes:

(1) as an equation is entered, use ' '

(2) it is preferable to use a comma to separate the real and imaginary parts

(3) explicit use multiply

If the entry will look like this:

'(4,3*X) = (4.7)'

For this simple equation and assuming that X is defined as an independent variable (reproduced by 'X' in the top middle of the screen), you can use SOLVEVX for this one: (No. 5 in S.SLV menu or F5 if you use soft-keys)

with "_Approx" uncontrolled, the answer is:

X = 7/3

with "vabout" checked the answer is:

X = (2.333333333,0) (although X is part of the imaginary number, it is himself a real number).

Kind regards.

Tags: HP Tablets

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