inverse tangent broadband (2 entries) inaccurate

Similar Questions

• Problems of the inverse tangent function

  Hello

  I try to use the function trigonometric "arctangent", but it does not work because I think that it should. I want to change a gradient at an angle, normally on a calculator, I use height divided by the length and press the tan ^-1 (inverse tan) function and get the angle. For example, the inverse tangent of 1. 45 (degrees) If I use the inverse tangent function in Labview 2010, I get a completely different = 0.7853 result... I use it wrong or the function does not work correctly.

  I've attached an example so that you can reproduce the result. I also had a similar problem with sin and cos in the formula of node structures.

  Thanks for any help you can give,

  James

  Hi James

  I have not seen your VI. I know, given out by the trigonometric functions in Labview is expressed in radians. You need to radian to degree conversion for the response under 45.

  Concerning

  Javed

• Inverse trigonometric functions

  Is it possible to calculate the inverse tangent, cosine and sine? The Math class has 'tan', 'cos' and 'Sin' but not 'atan', 'acos' or 'asin '. Is it possible to do it on the Blackberry?

  Hello

  Take a look at this

  class net.rim.device.api.util.MathUtilities

• Effectiveness of the Cartesian to spherical coordinate of the conversion

  I use a VI in the LV 2014 distribution called ".vi NI_AALPro.lvlib:3D Conversion of coordinates (scalar)". It uses DBL inputs and outputs and has several functions of table build in it as a library function call. I need to make a massive number of Cartesian to spherical conversions with SGL values, and so I would like to re - write this VI using LV primitives most efficiant manner.

  The calculation seems to be pretty simple, and I've attached a VI that does this. However, there is a problem with the calculation of the polar angle. From what I've read online, this is just arctan (y / x), but I get incorrect values when x is negative (but not when there is negative).

  From what I've read on the site of Wolfram, "the inverse tangent must be properly set to the right quadrant of (x / y) into account." I searched online for more details on the calculation, but I'm lost. Any trig works there who can help me?

  Definitions are extremely important in the definition of coordinate systems.  You include with your VI Cart_to_Sph documents of many errors and inconsistencies.

  This is a convention that I use and which seems to be acceptance quite wide (I'm not sure that's the convention of Wolfram, however).

  Let X, Y and Z is a right coordinate system.  That P is a point whose X, Y, Z coordinates we know.  Define a system of spherical polar coordinates (SSC) as follows:

  • Project of a line from the origin to P.
  • RADIUS (rho) - length of the line from the origin to P.
  • The line of the project on the X - Y plane.
  • Azimuth (theta) - measured Angle to the left of the x-axis for this proposed line.  By convention, theta varies less pi (radians), pi.
  • Polar angle (phi) - the angle between the axis Z (or 'pole') and the line from the origin to P.  By convention, including phi between 0 and pi.

  Under this system of coordinates, the following code (very similar to Altenbach, which uses a slightly different coordinate system) cards X, Y, Z in Rho, Theta, Phi:

  

  We will check certain quantities of 'known '.  Start with the x-axis of the unit, [1, 0, 0].  This clearly has length, Rho = 1.    The X axis lies in the XY, so the angle between the latter and the Z axis is 90 °, Phi should be pi/2.  Finally, the projection of the X axis in the XY plane is located along the X axis, so the angle between the two axes of X is 0, so Theta should be 0.  The first Re / Im polar will give 1, Theta Yes 0 = 0.  The second will give 1, pi/2, and Yes 1 = Rho and Phi = pi/2.

  How about unit Z, [0, 0, 1]?  Again, the length, Rho, is 1.  Technically, since the z plans on the origin, the Azimuthal angle cannot be properly defined (the X coordinates and are 0), so we'll do a loophole 'math' and just say that it is zero.  The polar angle is easy - the angle between the Z axis and the pole, the Z axis is 0, so Phi = 0.  Now "do the math".  Put [0, 0] in the first Re / Im polar gives [0, 0], so theta = 0.  The second d / Im to polar takes [1, 0] [1, 0], Rho Yes = 1 and Phi = 0.

  It is easy to show (in particular by the coding of this place and put in test of numbers) that negative quantities are working properly.  Rho is always non-negative, Phi is always in the range 0... PI and theta of pi-pi, with the sign depends on the sign of Y (as it should).

  Bob 'just do the math' Schor

  PS - If you think this is fun, just try 3D rotation matrices...

• Explanation of function Math.atan2

  Hello guys
  It is a piece of code AS3 things do move
  I tried to understand what atan2 actually does?
  
  Please explain
  
  If all goes well, I'll get help here :)
  
  Thanks in advance

  It's pretty accurate.

  If you remember the trigonometry, the tangent of an angle (theta) formed by the x-axis, and a line from (0,0) to (x, y) is y / x. that is to say, tan (theta) = y / x.

  and the arctan is just the opposite: given the number y / x, what's the angle? That is to say, y = theta.

  MOS ' (dx, dy) code can be considered as a point on a Cartesian coordinate system. If you draw a line connecting the point (0,0) to (dx, dy) that line crosses the x axis and an angle with the x-axis. This angle is the inverse tangent (arctan) dy divided by dx (dy/dx).

  Flash, in addition to having a function of Math.atan (y/x) also has a Math.atan2(y,x) atan2 function that accepts two parameters, so no division is necessary.

• System clock is constantly inaccurate - Satellite Pro U400

  Salaam :-)

  My laptop computer system clock is constantly inaccurate. I have windows 7 on h-Satellite Pro U400 - 13. Whenever I have look at the clock on the taskbar left I see it well before the correct time. I have this laptop for about 18 months, it points to a dead battery, leading to a CMOS failure?

  Selam aleykum,

  Your laptop is still new and the cmos battery should not be dead. I recommend:

  1 leave the laptop charge 48 hours the full cmos battery.
  2. If your system has an always on broadband connection, you can automate the process by changing the interval between updates.
  Open the registry editor by choosing Start-> Run-> Regedit
  Find the key to register HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\
  Services\W32Time\TimeProviders\NtpClient
  Select the entry for SpecialPollInterval, and change the decimal value to a time you want to use. The data value is in seconds, so, for example, 172800 value will change the synchronization for 2 days interval, a value of 86400 to happen in 1 day or a value of 3600 will change in an hour.
  Exit the registry editor and make sure sync automatically checked for your system clock settings. (Make sure you use Apply when you ve times your changes to the area to set the system clock time, so the change is permanent.)

  http://img821.imageshack.us/img821/8924/registrytwaek.jpg

  I placed my printscreen registry where enter 3600 (this means that each time your system clock will synchronize with the time server, but you always connected to the Internet)

• Inverse Laplace first HP

  I have the HP FIRST and trying to get the ilaplace (9 s ^ 2 + 18 s-216) /(s^3+s^2+21s+153), s, t

  When I submit that he kick back the problem again. If I don't put the variables at the end it gives me the same problem with

  Dirac (x).

  I tried other examples here and can't get the same answers from other missions. The dirac (x) keep appearing.

  Thanks for any help anyone can give me.

  Looking at it, it seems that will be the ridiculously high suite is probably way beyond what can handle the CASE. What result do you expect here?

  [edit]

  http://www.WolframAlpha.com/input/?i=inverse+Laplace+transform+%289s ^ 2 2B18s 216% 29% 2F % 28 s ^ 3% 2Bs ^ 2% 2B21s % B 2, 153% 29

  This entry correctly?

• Tecra R10 - 10J - 3 G Broadband F3507G does not

  I have a new toshiba Tecra R10 - 10J
  I went down to windows XP

  Even though the documentation says nothing, I found the thin slot; (it's behind the battery) I put my sim card inside (this sim card works in a usb key with my 3G provider).

  In Device Manager, the toshiba F3507G broadband shows 3 times:
  in network cards
  in the com ports
  in modem

  But when I run the wireless toshiba (version 5) Manager, nothing is known.
  He doesn't seem to see the slot and the device (the shortcut key is also well-positioned to plug brodband)

  I've updated the drivers and firmware from the toshiba website: still the same problem.
  I looked in the Bios: nothing is displayed regarding the brodband modem.

  I don't know what else to do?

  Thanks for your help

  > But when I run the wireless toshiba (version 5) Manager, nothing is known.
  Please post the error here.
  Say the WM? "No modem found"? or "Radio OFF"?

  BTW, did you also install the Toshiba value added package?
  Also, the RF power control utility must be installed.
  http://EU.computers.Toshiba-Europe.com/innovation/download_drivers_bios.jsp
  It is essential to get the 3G correctly to work.

  > I looked Bios: nothing is displayed regarding the brodband modem.
  It is correct.
  There is no entry in the Bios about 3G.

  Post edited by: Xyran

• RACIALLY DISPARAGING DICTIONARY ENTRIES

  Why do the IPhone dictionary for "ignorant" entries and the expletive "*" mentions and Hat are inaccurate and racially derogatory to African-Americans?

  Here's the definition I found on my iPhone for "ignorant."  (I use iOS 9.2).  How in the world does this have a "inaccurate...» "part?

  

  About the insult, it is hard to imagine that one specific you are talking about, but I suspect that the result is similar to the foregoing.

• Fracture of reverse broadband?

  I'm trying to optimize a large FPGA VI and was a few simple tests to determine using FPGA and the calendar for some elements of heavy use. I was comparing broadband with normal fracture. I use a cRIO-9066. What I found was that of the entries to the broadband divide, in this case, appear to be reversed.

  

  The equivalent normal fracture works as expected, even if it takes more time and resources. Has anyone else seen elsewhere? If so, is there a workaround?

  DGrayStratasys,

  Try to perform a cleaning on your code block diagram. You will notice that the control of X is actually connected to the entrance of Y on the function of a high flow rate and vice versa.

• The broadband divide

  Deal all,

  I develop a VI FPGA to calculate the least quadratic average, over 19 samples acquired with 9223 module e/s OR cRIO-9012 controller and chassis cRIO-9118. You can see that my code in the LMS snipped attachment.

  I have problems with understanding the setting of flow to the section for configuration of the function execution Mode to divide broadband within a SCTL. When I set this variable to 1 cycle/sample, it seems to me that the correct results after the function of division broadband are coming after the latency time of the function. Thus, for example in this case after 30 cycles. But when I put the possible maximum value, in this case 29 cycles/sample, I never get a correct result of the division, and the result is always on the increase until the maximum number that goes to zero and start to increase in the same way. So I really do not understand this function.

  Can someone please give me more information about the function broadband divide? At least more information about the flow setting.

  Thank you very much.

  Kind regards

  Nikola

  Hello Nikola,

  You need 30 cycles to get a valid result - no matter what bitrate is defined. When you set the control to the value 1/cycle you can subscribe a value to each cycle. The calculation is in pipeline and intermediate results are stored in shift registers.

  When you set 30cycles value, all 30 cycles only you can feed a new value. The advantage is, it costs less resources that piplines are less necessary.

  I think that the valid output is not wrong all the time, it is true once every 30 cycles and miss you maybe looking at the face before of the VI. Use the "valid output' 'ready for the entry' control of the power/reading of new values. Alternatively, you can use 1cycle by value if you have resources left on the chip,

  Kind regards

  René

• HPC6180 function to scan lost all-in-one photosmart when changing the broadband providers

  After changing the broadband providers I could no longer use the functions to scan my printer on the network. Print still works perfectly, but when I tried to scan I got a message telling me that the scanner could not be found.

  It is a symptom that is very similar to the one described elsewhere on the forums - but the problem in my case was not fixed by any amount of uninstall and reinstall the software. If all goes well, describing the fix here I can someone else save a lot of time.

  When the scanner is installed first the device name is stored somewhere, and even if the software is uninstalled and reinstalled L4 is still remembered the old name.

  The diagnostic scanner utility shows clearly a name that cannot be 'ping' because it is not the same as the new name for the printer. The suffix shown by the diagnostic Scanner differs from that shown in an IPCONFIG/all (the connection-specific DNS suffix).

  Thus, in may a case my original router was distributing the domain suffix '.» «Home» so my printer was HPxxxx.home for the scanner software. When I installed a new router that he used the ".config" suffix if the printer has become HPxxxx.config and the software couldn't find it (even when re-installed).

  It seems that ONLY the scanner software uses this mechanism to talk to the printer - printing features are not affected. But with the scanner software you're looking for the wrong name it can't possibly work. Even if you re-install the software or 'fix' references. Home in the registry to point to HPxxxx.config something somewhere modifies the registry return entries.

  SOLUTION:

  Find a way to change the router to distribute a different suffix - the same as your old router. In my case it was impossible in the GUI of the router then I 'saved' the configuration of the router in a modified file - the name of the suffix in the file text - and re - load configuration in the router.

  Now the printer is HP software and I can't figure out how to fix the HP software to recognize a new name.

  I hope someone saves some time - but unfortunately there are a lot of reasons that the scan function may suddenly stop working - as evidenced by the publication on the subject.

  Good luck!

  So, the SOLUTION is to re - configure your new router to use the same domain as your old router suffix. Router usually come with a configured arbitrary domain suffix - and the HP software is not resisted this development.

• Wild tangent

  where can I get the part of core of wt missing for Polar golf and polar bowler for windows 7?

  Hey seniorchief123,

  Wild Tangent is a software company specialized in online games video games.

  You get the Wild Tangent error message missing from the core component on your computer?

  If so, the error message appears when you try to play the games listed by you? Or the error is randomly launched?

  To resolve this problem, you will need to uninstall golf polar and polar bowler as these games require Wild Tangent to play.

  If you are having problems uninstalling, you can try with the Windows Installer Cleanup utility.

  Download it from:
  http://download.Microsoft.com/download/e/9/d/e9d80355-7ab4-45b8-80e8-983a48d5e1bd/msicuu2.exe

  To use the Windows CleanUp utility, follow these steps:

  1. click on start, point to programs and then click Windows Installer Clean Up.
  2. Select the program you want to remove, and then click on remove.
  3. click OK and then click on exit.
  This removes the entry from the database of the installer program. Once you completely remove the program, you can go ahead and proceed with the installation of the game.

  For more information about how to download, install and use the Windows Installer CleanUp utility, click the number below to view the article in the Microsoft Knowledge Base:

  Description of the Windows Installer CleanUp utility
  http://support.Microsoft.com/kb/290301

  After you run the utility, check and see if the Control Panel icon or Wild Tangent files still remain. If this is the case, follow the rest of these steps.

  Step 1: Open the registry editor.

  1. click on start, run and type REGEDIT and press enter
  2. click on the Plus sign (+) beside the following sections

  HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Control Panel\Cpls

  3. in the right column, look for the line of wtControlPanel, right-click on it and delete
  4. close the Windows registry

  Step 2: Delete the WildTangent folder in Program Files and Windows

  1. go to the C drive > Program Files
  2. right click on WildTangent and select Delete (if file exists)
  3. go back to the C drive and double click on Windows
  4. right click on the WT folder and select Delete (if file exists)

  After removing all traces of WildTangent, download games from the links below.

  Polar Golfer
  http://www.WildGames.com/games/polar-golfer

  Polar Bowler
  http://www.WildGames.com/games/polar-bowler

  Install games, run and check if the error disappears.

  Kind regards

  Shinmila H - Microsoft Support

  Visit our Microsoft answers feedback Forum and let us know what you think.

• iFFT is slow, if an entry is NaN

  Dear users,

  I write a response to a question that bothered me for some time. I work on, why a certain part of my program works slowly. Well, the answer was that the slow part executed an inverse FFT (Fast Fourier Transform) on an entry, which was a picture of NaN. IFFT receives an array of NaN, should orders of magnitude more time to process the data. On my table of 7601 cells, the report of the execution time averaged 0.1ms (to significant aid) of 120ms (using data NaN). I corrected the code with a structure of business as follows:

  

  I write this fact and the question, because I was surprised a lot to this behavior. I know, many functions can quickly and easily process data of NaN. But iFFT.

  See you soon,.

  
  

• Inverse problem LabWindows

  I have a program LabWindows which reads in the values of a 2D array, and then calculates the inverse by using InvMatrix.  My problem is that I don't know until the program starts how many values will be read in.  So I declare my matrix to be large enough to handle the maximum number of values, there could be.  Then, when I call InvMatrix, I get an error matrix is singular because the table has rows and columns of all zeros.  I know that the InvMatrix function has an entry for the size of the matrix, but the definition of this value to the size of the part not null matrix does not seem to solve the problem.  Any ideas how I can get around this?  Thank you!

  Short answer: you want to dynamically allocate the matrix account to your row/column settings.

  Long answer: dynamic allocation of 2D matrices is a little sensitive in c (especially since you don't know anything about what the CVI function is expecting in terms of the structure of the memory for the table).  If the CVI executes optimized assembler matrix waiting for a statically-allocated array, you may have to simulate the index layout and "flatten" your 2D matrix.  If you want all the details, you should check:

  http://c-FAQ.com/aryptr/dynmuldimary.html

  If you enable the C99 extensions in CVI, you might be able to take advantage of variable length arrays by allocating the table wished at run time.  I believe in memory, it will look like a standard static matrix structure, although I don't have much experience with C99 VLAs.