Is there a difference in quality between folios online and offline?

Similar Questions

• What does offline or online when you say: servicing an image Windows 7 to add the new application online? and what is the difference between the online and offline maintenance image

  What does offline or online when you say: servicing an image Windows 7 to add the new application online? and what is the difference between the online and offline maintenance image

  Your question it will be better answered in forum Windows 7 installation and deployment on TechNet:

  Windows 7 installation, Setup, and Deployment Forum

• Why is there a difference in length between 24 fps and fps 23 976 timelines with the same clip?

  I was working on a project of 23 976 fps and I tried to import a short animated sequence of 44 TIFFs in my scenario in my first CS5.

  I imported the sequence, interpreting the film at 23 976 fps (such as it was made in AE) to check before sending it to a finished House.

  First issue. Even if I set the framerate 23 976, first CS5, indicates me 23.98 on interpreting window film. I assumed it as a rounded number.

  When I drag the attachment to my 23 976 sequence, the clip shows 43 (!) length of frames on the info panel. It lacks an image. The sequence in the original video, it really lacks a framework.

  I decided to do a test. And placed the same clip, interpreted the same way on a sequence of 24 frames per second, and the clip shows as length of 44 executives on the info panel.

  How can we, same clip shows the different quantity of frames (I don't mean time, but just raw images), on different times? It makes no sense at all! If my sequence has 44 frames, it should show in the form of 44 independent frames of the scenario that I imported it. Am I entitled?

  Just for test, I ve imported from the same sequence on AE, and in it shows as 44 frames on a timeline 23 976. How can I trust to first frame interpret in this way?

  Just one thing. The scene used as basis for the animation of the AE, has 44 executives, and it was measured and cut in a 30s film on the same first which is having this weird behavior.

  Can someone explain to me what Just happened? It s driving me crazy!

  Thanks in advance

  Mauricio Mendes

  Before you import the sequence of images, go to Edit > Preferences > media... and together the basis of split time at 23.976.

• Is there a difference in performance between Automation Plug-ins and script system?

  We currently have a tool that, through the system of script, merges the layers by mask layer groups, exports and then moves to the next group of layers.  There is a custom logic and channel fusion that sometimes occurs in the fusion of a group of individual layers.  These operations occurred in the scripting system (in fact, c# through make calls of direct function through Photoshop), and there are pictures where these operations take about 30-40 minutes to complete on very large images.

  Is there a difference in performance between the actions in this way rather than having these actions occur in an Automation plug-in do?

  Thank you

  Using the DOM or the ActionDescriptor, ActionList, ActionReference API? There is a significant slow down using the DOM when looping through the layers. I have that as something to improve, but for a document with large layers, I would recommend trying to get the layer + layer 100 + value County via ActionDescriptor and loop them in this way. It is however a lot of work! I hope I can improve quickly and you won't have to deal with the drafting of a workaround.

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  Is there a way to differentiate between a conference and music on my I Pod Touch?

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  -iTunes U

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• Is there a difference in features between the version of the apple store and the best version to buy for the Apple Watch?

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  The user guide will be useful > https://help.apple.com/watch/

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• The difference in performance between wins 8 and win 7.

  What performance difference is there between winning 8 and win 7, or does go through whats in win 8 which is not in win 7?

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• Great color and differences of tone between DW CS3 and PS CS3

  I am running PS CS3 and DW, on a MacBook Pro connected to a second screen.  I calibrated and profiled two screens on the same graphics card using i1, and all shots are using an sRGB profile.  Looking at browsers beside there are differences in color, Safari is way out there.  What is strange, is that there is a big difference between DW and PS, I would say that two program windows are side by side on the same screen, with the same time.  DW shows the web page that publishes the blow, and PS has the same open photo, (she has been optimized during recording) socket in the pictures of my local site folder.  Any ideas?

  Thank you

  Chris

  Hello

  You can check that your PS program does not use the setting of sRGB, adobe, but in general there is no real solution to the problem. Especially if you're designing for the web, (how many users never calibrate their monitor, except by the eyes?) as for the difference in the programs, you can calibrate your graphics programs to use a specific setting / profile of color, but as dreamweaver is not a graphics program, it will use the settings of your system.

  The reason why I mentioned my previous answers was to point out that nobody has solved this satisfactory problem to my knowledge, see - http://forums.adobe.com/search.jspa?resultTypes=DOCUMENT&resultTypes=MESSAGE&resultTypes=C COMMUNITY & resultTypes = TASK & resultTypes = PROJECT & resultTypes = SOCIAL_GROUP & resultTypes = COMMENT & peopleEnabled = true & q = color + problems.

  What about Safari, if you think that the problem with color is a problem, try the problems with type- http://www.antigrain.com/research/font_rasterization/index.html.

  PZ

• Is there a way to sync between my table and my phone? I don't want to have my office involved.

  I would like to sync between my Tablet and phone. I don't want to share with the office. Is there a way to do this?

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• Difference of path between primary key and a Unique Index

  Hi all
  
  Is there a specific way the oracle optimizer to treat differently the Primary key and Unique index?
  
  Oracle Version

  SQL> select * from v$version;
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
  PL/SQL Release 11.2.0.3.0 - Production
  CORE    11.2.0.3.0      Production
  TNS for IBM/AIX RISC System/6000: Version 11.2.0.3.0 - Production
  NLSRTL Version 11.2.0.3.0 - Production
  
  SQL> 

  Sample data test for Index Normal
  

  SQL> create table t_test_tab(col1 number, col2 number, col3 varchar2(12));
  
  Table created.
  
  SQL> create sequence seq_t_test_tab start with 1 increment by 1 ;
  
  Sequence created.
  
  SQL>  insert into t_test_tab select seq_t_test_tab.nextval, round(dbms_random.value(1,999)) , 'B'||round(dbms_random.value(1,50))||'A' from dual connect by level < 100000;
  
  99999 rows created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> exec dbms_stats.gather_table_stats(USER_OWNER','T_TEST_TAB',cascade => true);
  
  PL/SQL procedure successfully completed.
  
  SQL> select col1 from t_test_tab;
  
  99999 rows selected.
  
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 1565504962
  
  --------------------------------------------------------------------------------
  | Id  | Operation         | Name       | Rows  | Bytes | Cost (%CPU)| Time     |
  --------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT  |            | 99999 |   488K|    74   (3)| 00:00:01 |
  |   1 |  TABLE ACCESS FULL| T_TEST_TAB | 99999 |   488K|    74   (3)| 00:00:01 |
  --------------------------------------------------------------------------------
  
  
  Statistics
  ----------------------------------------------------------
            1  recursive calls
            0  db block gets
         6915  consistent gets
          259  physical reads
            0  redo size
      1829388  bytes sent via SQL*Net to client
        73850  bytes received via SQL*Net from client
         6668  SQL*Net roundtrips to/from client
            0  sorts (memory)
            0  sorts (disk)
        99999  rows processed
  
  SQL> create index idx_t_test_tab on t_test_tab(col1);
  
  Index created.
  
  SQL> exec dbms_stats.gather_table_stats('USER_OWNER','T_TEST_TAB',cascade => true); 
  
  PL/SQL procedure successfully completed.
  
  SQL> select col1 from t_test_tab;
  
  99999 rows selected.
  
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 1565504962
  
  --------------------------------------------------------------------------------
  | Id  | Operation         | Name       | Rows  | Bytes | Cost (%CPU)| Time     |
  --------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT  |            | 99999 |   488K|    74   (3)| 00:00:01 |
  |   1 |  TABLE ACCESS FULL| T_TEST_TAB | 99999 |   488K|    74   (3)| 00:00:01 |
  --------------------------------------------------------------------------------
  
  
  Statistics
  ----------------------------------------------------------
            1  recursive calls
            0  db block gets
         6915  consistent gets
            0  physical reads
            0  redo size
      1829388  bytes sent via SQL*Net to client
        73850  bytes received via SQL*Net from client
         6668  SQL*Net roundtrips to/from client
            0  sorts (memory)
            0  sorts (disk)
        99999  rows processed
  
  SQL> 

  Examples of test when using primary key data
  

  SQL> create table t_test_tab1(col1 number, col2 number, col3 varchar2(12));
  
  Table created.
  
  SQL> create sequence seq_t_test_tab1 start with 1 increment by 1 ;
  
  Sequence created.
  
  SQL> insert into t_test_tab1 select seq_t_test_tab1.nextval, round(dbms_random.value(1,999)) , 'B'||round(dbms_random.value(1,50))||'A' from dual connect by level < 100000;
   
  99999 rows created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> exec dbms_stats.gather_table_stats('USER_OWNER','T_TEST_TAB1',cascade => true);
  
  PL/SQL procedure successfully completed.
  
  SQL> select col1 from t_test_tab1;
  
  99999 rows selected.
  
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 1727568366
  
  ---------------------------------------------------------------------------------
  | Id  | Operation         | Name        | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT  |             | 99999 |   488K|    74   (3)| 00:00:01 |
  |   1 |  TABLE ACCESS FULL| T_TEST_TAB1 | 99999 |   488K|    74   (3)| 00:00:01 |
  ---------------------------------------------------------------------------------
  
  
  Statistics
  ----------------------------------------------------------
            1  recursive calls
            0  db block gets
         6915  consistent gets
            0  physical reads
            0  redo size
      1829388  bytes sent via SQL*Net to client
        73850  bytes received via SQL*Net from client
         6668  SQL*Net roundtrips to/from client
            0  sorts (memory)
            0  sorts (disk)
        99999  rows processed
  
  SQL> alter table t_test_tab1 add constraint pk_t_test_tab1 primary key (col1);
  
  Table altered.
  
  SQL> exec dbms_stats.gather_table_stats('USER_OWNER','T_TEST_TAB1',cascade => true); 
  
  PL/SQL procedure successfully completed.
  
  SQL> select col1 from t_test_tab1;
  
  99999 rows selected.
  
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 2995826579
  
  ---------------------------------------------------------------------------------------
  | Id  | Operation            | Name           | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT     |                | 99999 |   488K|    59   (2)| 00:00:01 |
  |   1 |  INDEX FAST FULL SCAN| PK_T_TEST_TAB1 | 99999 |   488K|    59   (2)| 00:00:01 |
  ---------------------------------------------------------------------------------------
  
  
  Statistics
  ----------------------------------------------------------
            1  recursive calls
            0  db block gets
         6867  consistent gets
            0  physical reads
            0  redo size
      1829388  bytes sent via SQL*Net to client
        73850  bytes received via SQL*Net from client
         6668  SQL*Net roundtrips to/from client
            0  sorts (memory)
            0  sorts (disk)
        99999  rows processed
  
  SQL> 

  If you see here the same even as the statistics were gathered,
  * In the 1st table T_TEST_TAB, table always use FULL table access after creating indexes.
  * And in the 2nd table T_TEST_TAB1, table uses PRIMARY KEY as expected.
  
  Any comments?
  
  Kind regards
  BPat

  >
  * In the 1st table T_TEST_TAB, table always use FULL table access after creating indexes.
  * And in the 2nd table T_TEST_TAB1, table uses PRIMARY KEY as expected.
  >
  Yes - for the first table a full table scan will be used as the currently selected column is nullable and indexes do not include null values.

  The index can be used for the second query, since all the data (first column) is available between the index and there may be no NULL values because of the primary key. If you check constraints, you find that the there is now a CHECK constraint to ensure that the first column cannot be null.

  For a full and interesting discussion see the explanation of this and a related issue on the question I ask in this thread
  What SYS tables (not seen) contain the value NULL spec /not/ column definition? and my response he posted: 23 April 2012 09:02

  I ask the question is based on a question here which is similar to yours
  Columns becoming nullable after a fall of primary key?

• Difference in size between wall Source and program?

  I'm new at first and started using it because I love how sturdy it is great. When I drag a clip in a Source (Group?) monitor, the video preview is a different size if I slide the same clip in the program monitor. When I try export the clip, it exports to the same size as the program preview screen which has a large black borders even if the original for this clip has no borders. I would like the project to export more closely to the size of the preview of the Source monitor. When I'm in the area of export settings, click the option use the same parameters as the source file, but it still has black borders.

  I assume this has something to do with reports l / h? But then I don't know why something would have black borders if I choose to use the settings from the original source. I'm not really difficult to get rations of exact great aspect at the moment, I'm just curious to know what the difference is between dragging a clip in the source monitor and program monitor. This is the same exact clip that I am dragging in both. Because now I understand how the slightly larger clip in the program monitor by allowing eligible and right margins by expanding the video preview, that she grows in the exporting region and does not cause any reduction in video quality. Only complaint is that I have to play with the eligible margins on all the separate clips that come with different files to make them fit into one video.

  All this makes sense? Is there a setting somewhere that will import a file to have the same dimensions, when I try and then export it?

  In short:

  Import a file. When I drag him in the Panel of the sequence, the previews show with black borders when the original video clip did not. How can I have that happen?

  Many thanks (assuming that I have provided information to evacuate to produce a clear answer)

  When you create a new project you are presented

  with a setting of the sequence to the choice menu.

  You can skip this step by pressing "Cancel", then import your media

  and create the type of sequence that best adapts to your images.

  Try this:

  

  And to better understand what is happening, look at this:

  How to choose the right sequence settings?

• Differences in hardware between Portege M700 and M750

  I have about 40 Porteges a mix between M700 and M750, I need to know the differences of hardware and driver between the two for the purpose of Ghosting.

  I think the only difference is that the M700 uses the chipset Intel Santa Rosa (9xx series), and the M750 uses the newer Montevina (4 x series) chipset.

  If you need to install a utility/driver Intel Chipset that supports both chipsets.

• Difference in performance between the CTA and INSERT / * + APPEND * / IN

  Hi all

  I have a question about the ETG and "Insert / * + Append * / Into" statements.

  Suite deal, I have a question that I did not understand the difference in operating times EXADATA.

  The two tables of selection (g02_f01 and g02_f02) have not any partition. But I could partition tables with the method of partition by column "ip_id" hash and I tried to run the same query with partition tables. Change anything in execution times.

  I executed plan gather statistics for all tables. The two paintings were 13.176.888 records. The two arrays have same "ip_id' unique columns. I want to combine these tables into a single table.

  First request:

  Insert / * + append parallel (a, 16) * / in dg.tiz_irdm_g02_cc one

  (ip_id, process_date,...)

  Select / * + parallel (a, 16) parallel (16B) * / *.

  tgarstg.tst_irdm_g02_f01 a.,

  tgarstg.tst_irdm_g02_f02 b

  where a.ip_id = b.ip_id

  
  

  Elapsed = > 45: 00 minutes
  

  
  

  Second request:

  create table dg.tiz_irdm_g02_cc nologging parallel 16 compress for than query

  Select / * + parallel (a, 16) (b, 16) parallel * / *.

  tgarstg.tst_irdm_g02_f01 a.,

  tgarstg.tst_irdm_g02_f02 b

  where a.ip_id = b.ip_id

  Elapsed = > 04:00 minutes

  
  

  Execution plans are:

  
  

  1. Enter the statement execution Plan:

  Hash value of plan: 3814019933

  ------------------------------------------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | TempSpc | Cost (% CPU). Time |    TQ | IN-OUT | PQ Distrib.

  ------------------------------------------------------------------------------------------------------------------------------------------

  |   0 | INSERT STATEMENT.                  |    13 M |    36G |       |   127K (1) | 00:00:05 |        |      |            |

  |   1.  LOAD SELECT ACE | TIZ_IRDM_G02_CC |       |       |       |            |          |        |      |            |

  |   2.   COORDINATOR OF PX |                  |       |       |       |            |          |        |      |            |

  |   5:    PX SEND QC (RANDOM). : TQ10002 |    13 M |    36G |       |   127K (1) | 00:00:05 |  Q1, 02 | P > S | QC (RAND) |

  |*  4 |     IN THE BUFFER HASH JOIN |                  |    13 M |    36G |   921 M |   127K (1) | 00:00:05 |  Q1, 02 | SVCP |            |

  |   3:      RECEIVE PX |                  |    13 M |    14G |       |  5732 (5) | 00:00:01 |  Q1, 02 | SVCP |            |

  |   6.       PX SEND HASH | : TQ10000 |    13 M |    14G |       |  5732 (5) | 00:00:01 |  Q1 00 | P > P | HASH |

  |   7.        ITERATOR BLOCK PX |                  |    13 M |    14G |       |  5732 (5) | 00:00:01 |  Q1 00 | ISSUE |            |

  |   8.         STORE TABLE FULL ACCESS | TST_IRDM_G02_F02 |    13 M |    14G |       |  5732 (5) | 00:00:01 |  Q1 00 | SVCP |            |

  |   9.      RECEIVE PX |                  |    13 M |    21G |       | 18353 (3) | 00:00:01 |  Q1, 02 | SVCP |            |

  |  10.       PX SEND HASH | : TQ10001 |    13 M |    21G |       | 18353 (3) | 00:00:01 |  Q1, 01 | P > P | HASH |

  |  11.        ITERATOR BLOCK PX |                  |    13 M |    21G |       | 18353 (3) | 00:00:01 |  Q1, 01 | ISSUE |            |

  |  12.         STORE TABLE FULL ACCESS | TST_IRDM_G02_F01 |    13 M |    21G |       | 18353 (3) | 00:00:01 |  Q1, 01 | SVCP |            |

  ------------------------------------------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  4 - access("AIRDM_G02_F01".") IP_ID '= 'AIRDM_G02_F02'.' IP_ID")

  2 - DEC execution Plan:

  Hash value of plan: 3613570869

  ------------------------------------------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | TempSpc | Cost (% CPU). Time |    TQ | IN-OUT | PQ Distrib.

  ------------------------------------------------------------------------------------------------------------------------------------------

  |   0 | CREATE TABLE STATEMENT.                  |    13 M |    36G |       |   397K (1) | 00:00:14 |        |      |            |

  |   1.  COORDINATOR OF PX |                  |       |       |       |            |          |        |      |            |

  |   2.   PX SEND QC (RANDOM). : TQ10002 |    13 M |    36G |       |   255K (1) | 00:00:09 |  Q1, 02 | P > S | QC (RAND) |

  |   3.    LOAD SELECT ACE | TIZ_IRDM_G02_CC |       |       |       |            |          |  Q1, 02 | SVCP |            |

  |*  4 |     HASH JOIN |                  |    13 M |    36G |  1842M |   255K (1) | 00:00:09 |  Q1, 02 | SVCP |            |

  |   5.      RECEIVE PX |                  |    13 M |    14G |       | 11465 (5) | 00:00:01 |  Q1, 02 | SVCP |            |

  |   6.       PX SEND HASH | : TQ10000 |    13 M |    14G |       | 11465 (5) | 00:00:01 |  Q1 00 | P > P | HASH |

  |   7.        ITERATOR BLOCK PX |                  |    13 M |    14G |       | 11465 (5) | 00:00:01 |  Q1 00 | ISSUE |            |

  |   8.         STORE TABLE FULL ACCESS | TST_IRDM_G02_F02 |    13 M |    14G |       | 11465 (5) | 00:00:01 |  Q1 00 | SVCP |            |

  |   9.      RECEIVE PX |                  |    13 M |    21G |       | 36706 (3) | 00:00:02 |  Q1, 02 | SVCP |            |

  |  10.       PX SEND HASH | : TQ10001 |    13 M |    21G |       | 36706 (3) | 00:00:02 |  Q1, 01 | P > P | HASH |

  |  11.        ITERATOR BLOCK PX |                  |    13 M |    21G |       | 36706 (3) | 00:00:02 |  Q1, 01 | ISSUE |            |

  |  12.         STORE TABLE FULL ACCESS | TST_IRDM_G02_F01 |    13 M |    21G |       | 36706 (3) | 00:00:02 |  Q1, 01 | SVCP |            |

  ------------------------------------------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  4 - access("AIRDM_G02_F01".") IP_ID '= 'AIRDM_G02_F02'.' IP_ID")

  Oracle version:

  Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0 - 64 bit Production

  PL/SQL Release 11.2.0.4.0 - Production

  CORE Production 11.2.0.4.0

  AMT for Linux: Version 11.2.0.4.0 - Production

  NLSRTL Version 11.2.0.4.0 - Production

  Notice how this additional distribution has disappeared from the non-partitioned table.

  I think that with the partitioned table that oracle has tried to balance the number of slaves against the number of scores he expected to use and decided to distribute the data to get a 'fair sharing' workload, but had not authorized for the side effects of the buffer hash join which was to appear and extra messaging for distribution.

  You could try the indicator pq_distribute() for the insert to tell Oracle that he should not disrtibute like that. for example, based on your original code:

  Insert / * + append pq_distribute parallel (a, 16) (a zero) * / in dg.tiz_irdm_g02_cc one...

  This can give you the performance you want with the partitioned table, but check what it does to the space allocation that it can introduce a large number (16) of extensions by segment that are not completely filled and therefore be rather waste of space.

  Concerning

  Jonathan Lewis

• differences in storage between 5 (A1428) and 5 (A1533)

  Hello

  I recently had to replace my iPhone 5 (A1428) with a 5 (A1533). I was not able to load my backup set on the new iPhone. Because they are the two 16 GB, I'm stumped. It should not be the same? Two iPhones have iOS 9.3.3. I can no longer boot the iPhone 5 because of water damage.

  Thanks for any idea!

  TJ.

  The free space on the old phone has been filled to the minimum? If so, this might be a reason for not being able to restore. During the restoration process the phone has need a bit more free space available as the size of the backup that you want to install.

  Any error messenges during the process?

• NB200 - only little difference in speed between the modules of RAM?

  Hello everyone,

  Recently installed Windows 7 on my NB200 and thought I would setup an extra RAM.

  The RAM only I could get, was 2 GB of 667 MHz, as opposed to the 800 MHz supplied with the NB200. I thought that double the RAM would more than offset the slight difference in mhz between the new and old Rams.

  As I understand it, it's only little practice speed difference of real world, between the 667 MHz and 800 MHz RAM, is - this correct?

  Also: The 2 GB of RAM, I had had twice the amount of chips on the RAM slot than the old. Should I be concerned? I'm worried that doubles the amount of chips in a little place could lead to problems of heat/cooling... Any opinions?

  Thank you!

  There is no much difference between 667 and 800, in fact, I think the CPU at 667 anyway, but 800 races comes because of the limited availability of 667 RAM.

  Cooling should not be a problem if the RAM uses the same calendar and turn at the same voltage as the original of the RAM.