Link to database to a partitioned table

Similar Questions

• To access large partitioned tables over a database link - traps?

  Hello
  
  We are in the middle of a business acquisition, and I have a question on the use of links to database access efficiently to large tables. There are two distinct geographical database instances, both on Oracle 10.2.0.5 sitting on Linux boxes.
  
  The main forum (PSHR) contains a PeopleSoft HR system and pays and is sitting in our data center.
  
  The secondary instance (HGPAY) runs a payroll application home grown and is in a different datacenter to PSHR.
  
  The requirement is to allow PeopleSoft (PSHR) to display data of payroll (one employee at a time) targeted to the secondary instance.
  
  For example in HGPAY
  
  CREATE TABLE MY_PAY_DATA AS
  SELECT TO_CHAR (A.RN, ' 00000000') 'EMP' - it is a figure 8 leading 0 unique identifier
  '20110' | TO_CHAR (B.RN) "PAY_PRD" - it is a format of exercise more than fifteen days in the year (01-27)
  C.SOME_KEY - it is the element of remuneration being considered - effectively randomly
  , 'XXXXXXXXXXXXXXXXX' "FILLER1.
  , 'XXXXXXXXXXXXXXXXX' "FILLER2".
  , 'XXXXXXXXXXXXXXXXX' "FILLER3".
  FROM (SELECT ROWNUM 'RN' FROM DUAL CONNECT BY LEVEL < = 300) has
  , (SELECT ROWNUM 'RN' FROM DUAL CONNECT BY LEVEL < = 3) B
  (SELECT TRUNC (ABS (DBMS_RANDOM. (Random())) 'SOME_KEY' FROM DUAL CONNECT BY LEVEL < = 300) C
  ORDER OF PAY_PRD, EMP
  
  HGPAY. MY_PAY_DATA is the range partitioned on EMP (approximately 300 employees by partition) and the list below partitioned on PAY_PRD (3 pay periods a secondary partition). I limited the above create statement to represent a sub-partition of data.
  Every employee generates an average of 300 lines in this table each pay period. The table has about 180 million lines and all fifteen days more.
  
  In PSHR
  
  CREATE VIEW PS_HG_PAY_DATA (MEP, PAY_PRD SOME_KEY FILLER1, FILLER2, FILLER3)
  AS SELECT EMP, PAY_PRD SOME_KEY FILLER1, FILLER2, MY_PAY_DATA@HGPAY FILLER3
  
  PeopleSoft would then generate SQL along the lines of
  
  SELECT * FROM PS_HG_PAY_DATA WHERE EMP = '00002561' AND PAY_PRD = '201025'
  
  The link between data centers where PSHR and HGPAY sit isn't the best in the world, but I expect dozens of hits per day rather than thousands, so I think that the link must have sufficient bandwidth to meet the requirements.
  
  I tried a quick test on two instances of size production test and it works because it presents the data, when I look at the plan of the explain command that I can see that the remote database is only presenting the relevant secondary partition on PSHR rather than the entire table. Until I get in the back with a "job well done" - y at - it a witch hunt that I am absent using dblink to access the partitioned tables of big?

  Yes, it's just. A lot of it depends on exactly what happens in different "oops" scenarios - you are, for example, just burn some CPU extra until someone comes to the DBA and says "my query is slow" or saturating the network has an impact on critical applications or long random queries prevent some maintenance operations of partition.

  In my mind, the simplest possible solution (assuming you are using a username that is fixed in the database link) would be to create a profile on HGPAY for user defined for the link of database that set a value LOGICAL_READS_PER_CALL which was large enough to handle any request '' reasonable '' and low enough to quickly kill any session that has tried to do something 'stupid '. Obviously, you have to define 'stupid' in your particular environment where the scope of a 'simple reconciliation report' is not defined. If there is no political problem and you can adjust the values of profile to the wire when you encounter new reports that slowly increase what is considered '' reasonable '' is probably the most straightforward approach. If you have to put in a change request to change the parameter which must be reviewed by the Control Board change at its next quarterly meeting with the outsourced DBA seller, on the other hand, you could turn a report by 30 minutes in 30 hours over 30 days. However, in an ideal world, this is where I would start.

  Becomes more complex, you can use the resource manager to kill applications running too long on the wall clock. Since the network will almost certainly the bottleneck, it is probably unlikely that the limitation of the CPU will do much good - probably you can saturate the network with a very small amount of CPU. Limitation in my mind of the network is an additional step in complexity according to the specifics of your situation and what you are competing with.

  Justin

• importing into a partitioned table of interval 11g

  as I took export utility simple partition table 8i exp not rained so 100 k lines in there.
  
  and imported with the import utility in the interval of 11g partitioned based on the date column.
  
  There were imported, but did not what I expected...
  
  If we execute the simple insert for partition interval 11g command, it create new partition automatically according to the strategy of partition.
  
  Here's the demo...
  
  created range partitioned table on the date with shift interval column...
  
  CREATE TABLE TEST.xxx_HIST
  (
  xxx_DATE DATE NOT NULL,
  P_ROLL_CONVENTION CHAR (2),
  R_ROLL_CONVENTION CHAR (2),
  P_COMPOUNDING_IND CHAR (2),
  R_COMPOUNDING_IND CHAR (2),
  P_CALC_METHOD CHAR (2),
  R_CALC_METHOD CHAR (2),
  P_SPREAD_AMT NUMBER (28,12).
  R_SPREAD_AMT NUMBER (28,12).
  
  )
  partition by range (xxx_DATE)
  interval (numtoyminterval(3,'MONTH'))
  store (security)
  (
  values of pQ1 lower partition (to_date('2010-01-01','yyyy-mm-dd'))
  ) IN PARALLEL.
  
  
  -IMPORTED FROM ROWS IN THE TABLE...
  
  ======================================================================
  Connected to: Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
  With partitioning, OLAP, Data Mining and Real Application Testing options
  
  Export file created by EXPORT: V08.01.07 direct
  
  CAUTION: objects have been exported by SYSTEM, not by you
  
  . import of xx_ARCH in TEST objects
  . . import of 141749 lines imported from the table 'xxx_HIST '.
  Import completed successfully without warnings.
  ========================================================================
  
  
  
  -HE HAS A LOT OF DATES OF DIFF IN THERE...
  
  
  
  SQL > SELECT COUNT (DISTINCT xxx_DATE) TEST.xxx_HIST;
  
  COUNT (DISTINCT xxx_DATE)
  -----------------------------
  1371
  
  
  28-MARCH 06
  10 FEBRUARY 06
  9 FEBRUARY 05
  20 FEBRUARY 02
  3 JUNE 02
  10 MAY 04
  26 DECEMBER 03
  31 JANUARY 03
  
  xxx
  ---------
  21 JULY 08
  31 OCTOBER 05
  25 APRIL 08
  28 APRIL 08
  12 OCTOBER 06
  DECEMBER 21 07
  28 DECEMBER 04
  
  
  -BUT STILL ALL DUMPED INTO A PARTITION
  
  
  SQL > SELECT nom_partition FROM DBA_TAB_PARTITIONS WHERE TABLE_OWNER = 'TEST ';
  
  NOM_PARTITION
  ------------------------------
  PQ1
  
  It all dumped in a partition...
  
  fact partition interval 11g creates the partition automatically in function whose lines if imported... when we import lines in there...? or am I missing something?
  
  any idea guys?

  Seems to be a poor strategy for me because if I am not mistaken, there is no way to specify the order of the imported lines. If you import a line with the date max as your first row... bang, you get a range partition created for you and the rest falling.

  I think you'd be better import these data into a table in step and then by a

  insert into new_fancy_partition_table
  select *
  from old_8_temporary_imported_table
  order by date_column asc
  

  Or create the partitions manually.

  I just realized that you specify a partition in your create table statement (missed that on cursory inspection). And I think you misunderstand how the interval works... it's for values LARGER than the existing partitions ONLY...

  http://download.Oracle.com/docs/CD/E11882_01/server.112/e10592/statements_7002.htm#SQLRF01402

  "
  INTERVAL clause

  Use this clause to set the interval of partitioning the table. Range partitions are partitions based on a digital range interval or datetime. * They extend from range partitioning by commanding the database to automatically create partitions of the specified range or interval when the data inserted in the table exceed all the partitions.* range
  "

  Published by: Tubby on August 16, 2010 18:32

  Additional document link.

• after image restore, backup partition table is different

  Hello

  He is a 2012 Macbook mid Pro with El Capitan and Bootcamp.

  After repeated with Bootcamp (Windows 10 Pro) problems I started using Image of Terabyte for Linux in order to safeguard this Macbook. Forums terabyte that people know that the Image of Linux (such as Image for Windows) is able to create a reliable backup, but also to restore - restore an entire disk image or restoring individual partitions.

  I followed their instructions precisely and activated the two options "restore first Beach" and "TPG hidden OS" (as one terabyte official, Member of the forum wrote) when restoring a partition.

  Unfortunately, it did not work! Bootcamp was no longer visible in the start screen or wasn't visible, but not start.

  What I found was that I had to keep the two options (see above) with DISABILITIES.

  Then I could restore some partition images - and 10 Windows in Bootcamp is bootable.

  Well, it was the long introduction.  I'm sorry.

  Now my question is:

  Is this something that has changed my partition table?

  Before restoring an Image for backup of Linux for the first time, I had this partition table:

  localhost: ~ root # fdisk/dev/disk0

  Disk: geometry / dev/disk0: 60801/255/63 [976773168 sectors]

  Signature: 0xAA55

  From end

  #: cyl hd s - cyl hd s id [Start - size]

  ------------------------------------------------------------------------

  1: EA 1023 254 63 - 1023 254 63 [1-409639]

  2: AF 1023 254 63 - 1023 254 63 [409640-857906448] HFS +.

  3: AB 1023 254 63 - 1023 254 63 Boot Darwin [858316088-1269536]

  * 04:07 1023 254 63-1023 254 63 [859586560-117186560] HPFS/QNX / TO THE

  BUT:

  After failed attempts to restore and work finally restore my partition table operation is different:

  Fdisk/dev/disk0

  Disk: geometry / dev/disk0: 60801/255/63 [976773168 sectors]

  Signature: 0xAA55

  From end

  #: cyl hd s - cyl hd s id [Start - size]

  ------------------------------------------------------------------------

  1: EA 0 0 2 - 1023 255 63 [1-409639]

  2: AF 25 102 15 - 1023 255 63 [409640-857906448] HFS +.

  3: AB 1023 0 57 - 1023 255 63 Boot Darwin [858316088-1269536]

  * 04:07 1023 199 8-1023 255 63 [859586560-117186560] HPFS/QNX / TO THE

  Everything seems to work fine, but I wonder if the different appearance of the partition table can be a problem?

  For example, compare:

  1: EA 1023 254 63 - 1023 254 63]

  3 o

  409639]

  TO

  1: EA 0 0 2 - 1023 255 [63 3 o 409639]

  It's the output of 'diskutil list ':

  localhost: ~ root # diskutil list

  / dev/disk0 (internal, physical):

  #: NAME SIZE TYPE IDENTIFIER

  0: GUID_partition_scheme * GB 500,1 disk0

  1: disk0s1 EFI EFI 209.7 MB

  2: Apple_HFS Macintosh HD 439,2 GB disk0s2

  3: disk0s3 Apple_Boot Recovery 650.0 MB HD

  4: Microsoft database BOOTCAMP 60.0 GB disk0s4

  And the output of 'TPG - r - vv show/dev/disk0':

  See the TPG: / dev/disk0: mediasize = 500107862016; SectorSize = 512; blocks = 976773168

  See the TPG: / dev/disk0: MBR suspicious to sector 0

  See the TPG: / dev/disk0: Pri GPT to sector 1

  See the TPG: / dev/disk0: GPT Sec at sector 976773167

  start index size summary

  0 1 MBR

  1 1 Pri GPT header

  2 32 table GPT Pri

  34 6

  40 409600 1 part TPG - C12A7328-F81F-11D2-BA4B-00A0C93EC93B

  409640 857906448 2 part TPG - 48465300-0000-11AA-AA11-00306543ECAC

  858316088 1269536 3 part TPG - 426F6F74-0000-11AA-AA11-00306543ECAC

  859585624 936

  859586560 117186560 4 part TPG - EBD0A0A2-B9E5-4433-87C0-68B6B72699C7

  976773120 15

  976773135 32 table dry GPT

  976773167 1 dry GPT header

  Out of 'gdisk/dev/disk0:

  localhost: ~ root # gdisk/dev/disk0

  GPT fdisk (gdisk) version 1.0.1

  WARNING: Open with shared lock devices will not have their

  table partition automatically reloaded!

  Scanning partition table:

  MBR: hybrid

  BSD: absent

  APM: absent

  TPG: present

  Found a valid GPT with hybrid MBR; using GPT.

  Command (? for help): p

  Disk/dev/disk0: 976773168 sectors, GiB 465.8

  Logical sector size: 512 bytes

  Identifier (GUID) of disc: 38A2E667-6E00-4C0F-BD78-C95979E3CFAE

  Partition table contains up to 128 entries

  First usable sector is 34, last usable area is 976773134

  The partitions will be aligned with the boundaries of sector 8

  Space is free total 957 sectors (478,5 KiB)

  Starting number (sector) end (sector), Code name of size

  409639 40 1 MiB EF00 EFI 200.0

  2 409640 858316087 409.1 giB AF00 Macintosh HD

  3 858316088 859585623 619.9 MiB AB00 Recovery HD

  4 859586560 976773119 55.9 giB 0700 BOOTCAMP

  Any ideas?

  Another question:

  Is it possible to save the table to partition like that?

  DD if = / dev/sda of = gptandmbr bs = 512 count = 34

  Thank you very much

  NEUMAC

  In Fdisk, the CHS numbers are arbitrary on modern disks. They are the time of BIOS and old disks with CHS geometry. Puts BCA from Mac 0-1023 (1024 cylinders), 0-255 (256 heads) and 0-63 (64 sectors). Modern disks far exceed those numbers and would drain them. Must match what is the triplet of start/end/size and it fits in GPT and MBR. You can put arbitrary 0,0,0 for CHS and you will see all issues on GPT disks.

  Please do not use TBIL to restore W10 to circa 1970-80 disks.

• How to configure the partition table for SSD?

  Drive: 32 GB SSD

  I accidentally delete without backup partition table information and would like to know how to put the partition table, I can access the tools of partition table, but do not know how to define.

  Does anyone have any suggestions?

  Thanks in advance for your suggestions

  Hello

  Thanks for posting your query in Microsoft Community.

  The SSD could be seen in the disk management window, and you could name and set up as another hard drive internal. To create a partition or volume on a hard disk, you must be logged in as an administrator, and there must be unallocated disk space or free space in an extended hard disk partition. To repartition your hard drive, please consult the following link and check if it helps.

  I can I repartition my hard disk?

  Additional information:

  Create a new Partition on a hard disk in Windows 7

  Hope this information is useful. Let us know if you need more help, we will be happy to help you.

• Cannot install Windows on this disk selected disk.the has a MBR partition table. On EFI systems, windows can be installed only on GPT disks.

  Cannot install Windows on this disk selected disk.the has a MBR partition table.

  On EFI systems, windows can be installed only on GPT disks.

  When I try to install WS2008R2 in my turn lenovo G580 i5-3210 as a dual-boot option.

  Hello Pratap ReddyBh,

  As you try to install Windows Server 2008 R2, it would be better for you to ask your question in the TechNet Windows Server forums.
  Click on the link here for TechNet.

  Thank you

  Marilyn

• Reuse of blocks released upward in partitioned table

  Hello world

  I have a database creates a new partition and after a certain retention counter old partitions are deleted. This is done every day. We had some problem sometime before, so we disabled the partition drop script until it is revised for the partitions are not deleted for now. But we're going to delete all the files in the old partitions on a daily basis so that later, when we allow rear drop partition script it will not push the system.

  Now the problem is though that we delete the lines of the old partitions that continues to increase the size of the storage space, which means that it does not use the freed block. Please correct me if I'm wrong here, to my knowledge when the records in a table is removed the blocks going to the freelist for subsequent data inserts.

  The method above does not apply to the partitioned table is? If the space is released only if the partition is deleted? Thank you for you're your time and your answers. Very much appreciated.

  Database: Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0

  OS: Oracle Solaris 10 SPARC 64 bit

  I have a database creates a new partition and after a certain retention counter old partitions are deleted. This is done every day. We had some problem sometime before, so we disabled the partition drop script until it is revised for the partitions are not deleted for now. But we're going to delete all the files in the old partitions on a daily basis so that later, when we allow rear drop partition script it will not push the system.

  If possible, you should use TRUNCATE so that high tide is reset. It will be much faster to delete lines.

  What PROBLEM you encounter who pushed you to 'disable' the drop?

  Now the problem is though that we delete the lines of the old partitions that continues to increase the size of the storage space, which means that it does not use the freed block. Please correct me if I'm wrong here, to my knowledge when the records in a table is removed the blocks going to the freelist for subsequent data inserts.

  Correct - but only "freelist" will NOT be used for removable direct-path.

  My guess is that your new data every day are INSERTED in BULK. If, then Oracle just formats new blocks and fills them directly and does not use the free list.

  Do you use inserts of direct-path for new data?

• CTXCAT index on partitioned tables

  Hi all

  I use an oracle 11.2 database and try to use the index for a sample application oracle CTXCAT.

  I saw that oracle reference documentation "the CTXCAT index can't stand table and index partitioning, not...» "in http://docs.oracle.com/cd/B28359_01/text.111/b28303/ind.htm#BEIIEAFD

  But I was able to create a CTXCAT index on a partitioned table query to use it successfully.

  So can someone tell me exactly it meaning in the documentation of oracle developer "CTXCAT index does not support index and table partitioning?

  Thanks in advance,

  Mor.

  This simply means that you cannot create a LOCAL partitioned index on a table partitioned using the CTXCAT indextype. There is not probably the creation of a global index (ie. covering all partitions) on a partitioned table.

  The wording could be clearer.

• Drop the link of database in oracle 11g

  I created a schema with the name of sapsmc which has all the privileges, then I created 1 link of database. Now, I want to drop this database link, but I can't able to drop this error.

  «SQL error: ORA-00604: error occurred at recursive SQL level 1 ORA-20101: Sorry, can't remove any object without the permission of live database SAPGateWay.» ORA-06512: at the level of the 5 00604 line. 00000 - 'error occurred at recursive SQL level %s' * Cause: an error occurred during the processing of a recursive SQL statement (a statement applicable to the internal dictionary tables). * Action: If the situation described in the next error on the stack can be corrected, do so; otherwise contact Oracle Support.

  Then I tried to delete the user SYS, while doing this that I got below error.

  SQL error: ORA-02024: database not found link 02024. 00000 - "database link not found" * Cause: database to remove link is not found in the dictionary * Action: correct the name of the database link

  Please help me I appreciate your efforts.

  ORA-20101: Sorry, can't remove any object without the permission of live database SAPGateWay.

  There is not much we can do about it.

  It is an exception defined by the user, probably from a FRONT DROP trigger defined at the level of the database, which prevents people from dropping objects.

  Contact, one who is responsible (DBA?) about how to proceed.

• partition table

  When we need to use the partition table?

  Partitioning defined

  The concept of divide and conquer has been around since the time of Sun Tzu (500 BC). Recognizing the wisdom of this concept, Oracle applied to management of large tables and indexes. Oracle has continued to evolve and refine its capabilities of partitioning since its first implementation of the Oracle 8 range partitioning. Oracle 8i and 9i, Oracle has continued to add features and new methods of partitioning. The current version of Oracle 9i Release 2 continues this tradition by adding new features to the list partitioning and partitioning method new range-list.

  When the partition

  There are two main reasons to use partitioning in an environment of VLDB (very large database). These reasons are related to improving the management and performance.

  Partitioning offers:

  • Management at the level of individual partition for data loads, creating indexes and reconstruction, and backup/restore. This may cause more quickly down, because only actively managed individual partitions are not available.
  • Performance of the queries increased by selecting only the relevant partitions. This process of weeding out the partitions that do not contain the data required by the application via a technique called the size of the partition.

  Use the partitioning:

  • When a table reaches a size "large". Large being defined according to your environment. Greater than 2 GB should always be considered for partitioning of tables.
  • What performance benefits outweigh the extra management issues related to partitioning.
  • When the archive data is on a calendar and repetitive. For example, data warehouses are usually given for a certain period of time (rolling window). Old data is then output to archive.

• 11g auto States meet on partitioned tables

  Ive looked at notes

  Collecting statistics on partitioned Table 10g and 11g (Doc ID 1417133.1()

  and
  

  Database RAC DataGaurd and APPS: DBMS_STATS enhancements in Oracle Database 11g

  11.2.0.2

  Ive just noticed that automatic statistics maintenance night window collect works at the level of the table, but not on the scores of partitioned tables (stats white poster) still a global stats meet at the end of week doesn't work.   If someone looked before can you specify

  I need set at the database level so that a change will result in that all my partitioned tables get analyses during the race every night.  IM guess incremental = true.

  Or a level table, it looks like additional dbms_stats.set_prefs = true will work according to the above.  ID rather self-employment prepare tho so I did not do it at the table level.

  How can I change nightly differential work = true if that's what is necessary?

  Thank you.

  ignore this.  We had a bug that disabled our auto stats every night gather running works now.

  I opened a call, asides stats collection not... the real answer to my question (which Im sure some of you knew anyway) is that the incremental stats every night together stats if (score > 10% Rassi) and overall stats are collected if (total variations in all partitions stale > 10%)...

  If the stats are gathered first at the partition level and based on these changes that the overall statistics are developed.

• Compression is disabled when performing the update on partitioned tables

  
  Hi all

  I'm on Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0.

  My question is related to the Compression of the Oracle.

  I have an infra partitioned table enabled with Compression of the base. Active compressed State, I update some columns in this table (command Update Normal and merger as well) but the end result shows the increase in the size of the table and the compression is still in the ACTIVE State. After that, if I compress the secondary partition explicitly the table back to its original size.

  Is this a bug? I read a whitepaper on 11g itself, compression is turned on in the case of all DML operations, so why this behavior?

  Thank you

  Ishan

  Ishan,

  take a look at http://docs.oracle.com/cd/E11882_01/server.112/e25494/tables.htm#CJAGFBFG , it seems that the distinction between OLTP and compression of base is sometimes a bit vague ("operations that allow compression include:...") "), but I also find the statement"insert rows inserted without using direct-path access and updated rows are uncompressed. "So I would say it's not a bug but a limitation of the service. Updates just to not mix well with compression.

  Martin

• modifies an existing large partitioned table to automatically add the partitions

  Hello world
  
  According to me, it is not possible to modify an existing large partitioned table, to add partitions automatically as you insert it into this one. What would be the best way to do this? Dbms_redefinition? DEC + copy dependant rename?
  
  Any ideas?
  
  Thank you.
  
  current version:
  Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
  With partitioning, Real Application Clusters, Automatic Storage Management, OLAP,.
  Options of Data Mining and Real Application Testing

  >
  According to me, it is not possible to modify an existing large partitioned table, to add partitions automatically as you insert it into this one. What would be the best way to do this? Dbms_redefinition? DEC + copy dependant rename?

  Any ideas?
  . . .
  I guess what I'm looking for is
  ALTER TABLE XXX INTERVAL DEFINED (NUMTOYMINTERVAL(1,'MONTH'));

  The following problem, I see is my required interval varies 01 hours of daylight at the time month 01 day 01 01 of the following month.
  >
  The best way to do it is to change your way of thinking.

  Do not be afraid to break the Oracle actually trying things. Just ALTER the table.

  drop table part_test cascade constraints;
  
  create table part_test(id number, entry_date date)
  partition by range (entry_date)
  (
  partition old_years values less than (to_date('01/01/2013 01:00:00', 'mm/dd/yyyy hh24:mi:ss')),
  partition jan_2013 values less than (to_date('02/01/2013 01:00:00', 'mm/dd/yyyy hh24:mi:ss'))
  )
  
  insert into part_test values(1, to_date('01/01/2013 00:00:00', 'mm/dd/yyyy hh24:mi:ss'));
  
  insert into part_test values(2, to_date('01/01/2013 02:00:00', 'mm/dd/yyyy hh24:mi:ss'));
  
  alter table part_test set interval(numtoyminterval(1,'MONTH')); 
  
  insert into part_test values(2, to_date('02/01/2013 02:00:00', 'mm/dd/yyyy hh24:mi:ss'));
  
  SQL> set serveroutput on
  SQL> select partition_name, high_value
    2  from dba_tab_partitions
    3  where table_name = 'PART_TEST';
  
  PARTITION_NAME
  ------------------------------
  HIGH_VALUE
  --------------------------------------------------------------------------------
  
  OLD_YEARS
  TO_DATE(' 2013-01-01 01:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  
  JAN_2013
  TO_DATE(' 2013-02-01 01:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  
  SYS_P225
  TO_DATE(' 2013-03-01 01:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  
  SQL>
  

  Note the limit of the score for SYS_P225 that was created? It includes the same ' time 1' of the highest range partition that existed before the ALTAR.

• migration in partitioned table

  Hello world
  
  I need to migrate on a two table range-list partitioned table, one of them is partitioned list, the other is not. The largest contains 400 million lines (partitioned), the smallest contains 90 million lines. The database cannot insert all of the table at a time, so I started to migrate the tables into pieces. I have two options:
  
  1 create pieces using a date_field (IDO_ID)
  2. create the pieces with the help of a generated field (MIGR_RANK) using the list field (TAB_KOD) and a number generated randomly, which limits the lines to migrate a line no more than 1 million of partitioning
  
  My questions are the following:
  1. is it possible that the insert is slow due to the large number (about 750) list partitions? Can I use the 2. method, inserting only one partition? Or a kind of simple is enough for partitioning columns? How does the insert works in Oracle for a partitioned table? Especially in a range-list partitioned table?
  2. How can I adjust the database to migrate two tables in one step (if possible)?
  
  Thanks in advance,
  Gabor
  
  Published by: csiszgab on Sep 28, 2012 07:47

  Whenever you provide post your Oracle version 4-digit (result of SELECT * FROM V$ VERSION).
  >
  I need to migrate on a two table range-list partitioned table, one of them is partitioned list, the other is not. The largest contains 400 million lines (partitioned), the smallest contains 90 million lines. The database cannot insert all of the table at a time, so I started to migrate the tables into pieces. I have two options:
  >
  -Oracle is certainly able to process the entire table in one so why do you say otherwise?

  You can speed up insert PARALLEL aid (for the source and target tables), using the direct-path load (APPEND indicator) and NOLOGGING mode on the target table.
  >
  1. is it possible that the insert is slow due to the large number (about 750) list partitions? Can I use the 2. method, inserting only one partition? Or a kind of simple is enough for partitioning columns? How does the insert works in Oracle for a partitioned table? Especially in a range-list partitioned table?
  >
  Your "2" is not just insert in a partition. You said your target table was partitioned ' range-list' but your source is only 'list' partitioned. Therefore a partition target: data from the "one" won't a single list.

  Load using the entire table at once without (other than the partition key) index on the target table.

• Create index partition in the partition table tablespace

  Hello
  
  I am running a work custom that
  
  * Creates a tablespace by day
  * Creates the daily table partition in the created tablespace
  * Removes the days tablepartition X
  * Removes the storage space for this partition of X + 1 day.
  
  The work above works perfectly, but it has problems with the management of the index for these partitioned tables. In the old database (10g - single node), all indexes and partitions exist in a BIG tablespace and when I imported the table creation script in the new database, I changed all the partitions table & index to go in their respective space.
  
  For example:
  
  Table_name... Nom_partition... Index_Part_name... Tablespace_name
  ============...================............====================...........=================
  TABL1... TABL1_2012_07_16... TABL1_IDX_2012_07_16... TBS_2012_07_16
  TABL1... TABL1_2012_07_15... TABL1_IDX_2012_07_15... TBS_2012_07_15
  
  
  But now, when the job is run, it creates the index in the tablespace TBS_DATA default.
  
  Table_name... Nom_partition... Index_Part_name... Tablespace_name
  ============...================.............====================...........=================
  TABL1... TABL1_2012_08_16... TABL1_IDX_2012_08_16... TBS_DATA
  TABL1... TABL1_2012_08_15... TABL1_IDX_2012_08_15... TBS_DATA
  
  
  I can issue alter index rebuild to move the index to its tablespace default, but how can I make sure that the index is created in the designated tablespace?
  
  NOTE: the partition/tablespace management work that I run only creates the partition of the table and not the index.
  
  
  The new env is a cluster of CARS of 2 nodes 11 GR 2 on Linux x86_64.
  
  
  Thanks in advance,
  aBBy.

  try something like this

  ALTER table tab_owner.tab_name add the partition v_new_part_nm
  values less (to_date('''|| v_new_part_dt_formatted ||'') ((', "DD-MON-YYYY)) tablespace ' | part_tbs
  update the index (ind1_name (partition ind_partition_name tablespace ind_part_tbs)
  ind2_name (partition tablespace ind_part_tbs ind_partition_name))
  ;