Merge no SQL using analytical functions

Hi, the Sql tuning specialists:
I have a question about the merger of view inline.

I have a simple vision with the analytical functions inside. When questioning him, he does not index.


VIEW to CREATE or REPLACE ttt
AS
SELECT EmpNo, deptno,
ROW_NUMBER() over (PARTITION BY deptno ORDER BY deptno desc NULLS last) part_seq
EMP AAA

-That will do full table for emp scan
Select * from TT
WHERE empno = 7369


-If I do not view use, I use the query directly, the index is used
SELECT EmpNo, deptno,
ROW_NUMBER() over (PARTITION BY deptno ORDER BY deptno desc NULLS last) part_seq
EMP aaa
WHERE empno = 7369


question is: How can I force the first query to use indexes?

Thank you

MScallion wrote:
What happens if you use the push_pred flag:

Nothing will happen. And it would be a bug if he would.

select * from ttt
WHERE empno=7369

and

SELECT empno,deptno,
row_number() OVER (PARTITION BY deptno ORDER BY deptno desc NULLS last) part_seq
FROM emp aaa
WHERE empno=7369

are two logically different queries. Analytical functions are applied after + * resultset is common. So first select query all rows in the emp table then assign ROW_NUMBER() to recovered lines and only then select a line with empno = 7369 her. Second query will select the table emp with empno = 7369 line and only then apply ROW_NUMBER() - so since emp.empno is unique ROW_NUMBER returned by second query will always be equal to 1:

SQL> select * from ttt
  2  WHERE empno=7369
  3  /

     EMPNO     DEPTNO   PART_SEQ
---------- ---------- ----------
      7369         20          4

SQL> SELECT empno,deptno,
  2  row_number() OVER (PARTITION BY deptno ORDER BY deptno desc NULLS last) part_seq
  3  FROM emp aaa
  4  WHERE empno=7369
  5  /

     EMPNO     DEPTNO   PART_SEQ
---------- ---------- ----------
      7369         20          1

SQL> 

SY.

Tags: Database

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               30            1          6
    
  • Problem with analytical function for date

    Hi all

    ORCL worm:
    Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production
    PL/SQL Release 11.2.0.2.0 - Production
    "CORE 11.2.0.2.0 Production."
    AMT for Linux: Version 11.2.0.2.0 - Production
    NLSRTL Version 11.2.0.2.0 - Production

    I have a problem with the analtical for the date function. I'm trying to group records based on timestamp, but I'm failing to do.
    Could you please help me find where I'm missing.
    This is the subquery. No issue with this. I'm just posting it for reference. 
    select sum(disclosed_cost_allocation.to_be_paid_amt) amt,
        substr(reference_data.ref_code,4,10) cd,
        to_char(external_order_status.status_updated_tmstp, 'DD-MON-YYYY HH24:MI:SS') tmstp,
        DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID id
      FROM Deal.Fee_Mapping_Definition ,
        Deal.Fee_Index_Definition ,
        Deal.Fee_Closing_Cost_Item,
        Deal.Closing_Cost,
        Deal.Document_Generation_Request,
        deal.PRODUCT_REQUEST,
        deal.External_Order_Request,
        deal.External_Order_Status,
        deal. DISCLOSED_CLOSING_COST,
        deal.DISCLOSED_COST_ALLOCATION,
        deal.reference_data
      WHERE Fee_Mapping_Definition.Fee_Code                    = Fee_Index_Definition.Fee_Code
      AND Fee_Index_Definition.Fee_Index_Definition_Id         = Fee_Closing_Cost_Item.Fee_Index_Definition_Id
      AND Fee_Closing_Cost_Item.Closing_Cost_Id                = Closing_Cost.Closing_Cost_Id
      AND CLOSING_COST.PRODUCT_REQUEST_ID                      = Document_Generation_Request.Product_Request_Id
      AND closing_cost.product_request_id                      = product_request.product_request_id
      AND Product_Request.Deal_Id                              = External_Order_Request.Deal_Id
      AND external_order_request.external_order_request_id     = external_order_status.external_order_request_id
      AND external_order_request.external_order_request_id     = disclosed_closing_cost.external_order_request_id
      AND DISCLOSED_CLOSING_COST. DISCLOSED_CLOSING_COST_ID    = DISCLOSED_COST_ALLOCATION.DISCLOSED_CLOSING_COST_ID
      AND Fee_Index_Definition.Fee_Index_Definition_Id         = Disclosed_Closing_Cost.Fee_Index_Definition_Id
      AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id   = Reference_Data.Reference_Data_Id
      AND Document_Generation_Request.Document_Package_Ref_Id IN (7392 ,2209 )
      AND External_Order_Status.Order_Status_Txt               = ('GenerationCompleted')
      AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id  IN ( 7789, 7788,7596 )
      AND FEE_MAPPING_DEFINITION.DOCUMENT_TYPE_REF_ID          = 1099
      AND Document_Generation_Request.Product_Request_Id      IN
        (SELECT PRODUCT_REQUEST.PRODUCT_REQUEST_id
        FROM Deal.Disclosed_Cost_Allocation,
          Deal.Disclosed_Closing_Cost,
          DEAL.External_Order_Request,
          DEAL.PRODUCT_REQUEST,
          Deal.Scenario
        WHERE Disclosed_Cost_Allocation.Disclosed_Closing_Cost_Id = Disclosed_Closing_Cost.Disclosed_Closing_Cost_Id
        AND Disclosed_Closing_Cost.External_Order_Request_Id      = External_Order_Request.External_Order_Request_Id
        AND External_Order_Request.Deal_Id                        = Product_Request.Deal_Id
        AND product_request.scenario_id                           = scenario.scenario_id
        AND SCENARIO.SCENARIO_STATUS_TYPE_REF_ID                  = 7206
        AND product_request.servicing_loan_acct_num              IS NOT NULL
        AND product_request.servicing_loan_acct_num               = 0017498379
          --AND Disclosed_Cost_Allocation.Disclosed_Cost_Allocation_Id = 5095263
        )
      GROUP BY DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID,
        External_Order_Status.Status_Updated_Tmstp,
        Reference_Data.Ref_Code,
        disclosed_cost_allocation.to_be_paid_amt
      order by 3 desc,
        1 DESC;
    
    Result:
    2000     1304-1399     28-JUL-2012 19:49:47     6880959
    312     1302     28-JUL-2012 19:49:47     6880958
    76     1303     28-JUL-2012 19:49:47     6880957
    2000     1304-1399     28-JUL-2012 18:02:16     6880539
    312     1302     28-JUL-2012 18:02:16     6880538
    76     1303     28-JUL-2012 18:02:16     6880537
    
    
    But, when I try to group the timestamp using analytical function,
    
    
    select amt 
            ,cd 
            ,rank() over(partition by tmstp order by tmstp desc) rn 
    from 
    (select sum(disclosed_cost_allocation.to_be_paid_amt) amt,
        substr(reference_data.ref_code,4,10) cd,
        to_char(external_order_status.status_updated_tmstp, 'DD-MON-YYYY HH24:MI:SS') tmstp,
        DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID id
      FROM Deal.Fee_Mapping_Definition ,
        Deal.Fee_Index_Definition ,
        Deal.Fee_Closing_Cost_Item,
        Deal.Closing_Cost,
        Deal.Document_Generation_Request,
        deal.PRODUCT_REQUEST,
        deal.External_Order_Request,
        deal.External_Order_Status,
        deal. DISCLOSED_CLOSING_COST,
        deal.DISCLOSED_COST_ALLOCATION,
        deal.reference_data
      WHERE Fee_Mapping_Definition.Fee_Code                    = Fee_Index_Definition.Fee_Code
      AND Fee_Index_Definition.Fee_Index_Definition_Id         = Fee_Closing_Cost_Item.Fee_Index_Definition_Id
      AND Fee_Closing_Cost_Item.Closing_Cost_Id                = Closing_Cost.Closing_Cost_Id
      AND CLOSING_COST.PRODUCT_REQUEST_ID                      = Document_Generation_Request.Product_Request_Id
      AND closing_cost.product_request_id                      = product_request.product_request_id
      AND Product_Request.Deal_Id                              = External_Order_Request.Deal_Id
      AND external_order_request.external_order_request_id     = external_order_status.external_order_request_id
      AND external_order_request.external_order_request_id     = disclosed_closing_cost.external_order_request_id
      AND DISCLOSED_CLOSING_COST. DISCLOSED_CLOSING_COST_ID    = DISCLOSED_COST_ALLOCATION.DISCLOSED_CLOSING_COST_ID
      AND Fee_Index_Definition.Fee_Index_Definition_Id         = Disclosed_Closing_Cost.Fee_Index_Definition_Id
      AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id   = Reference_Data.Reference_Data_Id
      AND Document_Generation_Request.Document_Package_Ref_Id IN (7392 ,2209 )
      AND External_Order_Status.Order_Status_Txt               = ('GenerationCompleted')
      AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id  IN ( 7789, 7788,7596 )
      AND FEE_MAPPING_DEFINITION.DOCUMENT_TYPE_REF_ID          = 1099
      AND Document_Generation_Request.Product_Request_Id      IN
        (SELECT PRODUCT_REQUEST.PRODUCT_REQUEST_id
        FROM Deal.Disclosed_Cost_Allocation,
          Deal.Disclosed_Closing_Cost,
          DEAL.External_Order_Request,
          DEAL.PRODUCT_REQUEST,
          Deal.Scenario
        WHERE Disclosed_Cost_Allocation.Disclosed_Closing_Cost_Id = Disclosed_Closing_Cost.Disclosed_Closing_Cost_Id
        AND Disclosed_Closing_Cost.External_Order_Request_Id      = External_Order_Request.External_Order_Request_Id
        AND External_Order_Request.Deal_Id                        = Product_Request.Deal_Id
        AND product_request.scenario_id                           = scenario.scenario_id
        AND SCENARIO.SCENARIO_STATUS_TYPE_REF_ID                  = 7206
        AND product_request.servicing_loan_acct_num              IS NOT NULL
        AND product_request.servicing_loan_acct_num               = 0017498379
          --AND Disclosed_Cost_Allocation.Disclosed_Cost_Allocation_Id = 5095263
        )
      GROUP BY DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID,
        External_Order_Status.Status_Updated_Tmstp,
        Reference_Data.Ref_Code,
        disclosed_cost_allocation.to_be_paid_amt
      order by 3 desc,
        1 DESC);
    
    Result:
    312     1302            1
    2000     1304-1399     1
    76     1303            1
    312     1302            1
    2000     1304-1399     1
    76     1303            1 
    
    
    Required output:
    312     1302            1
    2000     1304-1399     1
    76     1303            1
    312     1302            2
    2000     1304-1399     2
    76     1303            2
    THX
    Rod.

    Hey, Rod,

    My guess is that you want:

    , dense_rank () over (order by  tmstp  desc)  AS rn 
    

    RANK means you'll jump numbers when there is a link. For example, if all 3 rows have the exact same last tmstp, all 3 rows would be assigned number 1, GRADE would assign 4 to the next line, but DENSE_RANK attributes 2.

    "PARTITION x" means that you are looking for a separate series of numbers (starting with 1) for each value of x. If you want just a series of numbers for the entire result set, then do not use a PARTITION BY clause at all. (PARTITION BY is never required.)
    Maybe you want to PARTITIONNER IN cd. I can't do it without some examples of data, as well as an explanation of why you want the results of these data.
    You certainly don't want to PARTITION you BY the same expression ORDER BY; It simply means that all the lines are tied for #1.

    I hope that answers your question.
    If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
    Explain, using specific examples, how you get these results from these data.
    Simplify the problem as much as possible.
    Always tell what version of Oracle you are using.
    See the FAQ forum {message identifier: = 9360002}

    Published by: Frank Kulash, August 1, 2012 13:20

  • Help me on the analytic function

    Hello

    I use oracle version
    SQL> select * From v$version;
    
    BANNER
    ----------------------------------------------------------------
    Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64bit Production
    PL/SQL Release 9.2.0.8.0 - Production
    CORE    9.2.0.8.0       Production
    TNS for Solaris: Version 9.2.0.8.0 - Production
    NLSRTL Version 9.2.0.8.0 - Production
    I have a following tables
    CREATE TABLE emp_info(emp_id number,ename varchar2(10),chk_date date);
    
    CREATE TABLE emp_month(emp_id number,emp_month_date date,chk_amt number(10,2));
    
    insert into emp_info VALUES (101,'PAUL',to_date('01-MAR-2009','DD-MON-YYYY'));
    insert into emp_info VALUES (102,'JOHN',to_date('01-APR-2009','DD-MON-YYYY'));
    insert into emp_info VALUES (103,'KRIS',to_date('01-MAY-2009','DD-MON-YYYY'));
    
    
    insert into emp_month values (101,'01-DEC-2008',1432);
    insert into emp_month values (101,'01-JAN-2009',1412);
    insert into emp_month values (101,'01-FEB-2009',1632);
    insert into emp_month values (101,'01-MAR-2009',1672);
    --
    insert into emp_month values (102,'01-DEC-2008',2678);
    insert into emp_month values (102,'01-JAN-2009',2786);
    insert into emp_month values (102,'01-FEB-2009',2883);
    insert into emp_month values (102,'01-MAR-2009',2653);
    insert into emp_month values (102,'01-APR-2009',2653);
    --
    insert into emp_month values (103,'01-NOV-2008',2343);
    insert into emp_month values (103,'01-DEC-2008',2311);
    insert into emp_month values (103,'01-JAN-2009',3122);
    insert into emp_month values (103,'01-FEB-2009',3412);
    insert into emp_month values (103,'01-MAR-2009',3312);
    insert into emp_month values (103,'01-APR-2009',3315);
    insert into emp_month values (103,'01-MAY-2009',4321);
    I use following the QUERY for results. Is it possible to get these same results using ANALYTICAL functions
    or I would appreciate any solution better than this.
    Select e.emp_id,e.ename,e.chk_date,sum(chk_amt) year_amt
    from emp_month em
    ,(select emp_id,ename,chk_date
    from emp_info)e
    where e.emp_id = em.emp_id
    and em.emp_month_date between trunc(e.chk_date,'YY') AND e.chk_date
    group by e.emp_id,e.ename,e.chk_date

    user12212962 wrote:

    I use following the QUERY for results. Is it possible to get these same results using ANALYTICAL functions

    or I would appreciate any solution better than this.

    I have no idea why you need analytic function. I know: there is no need to view inline in your query:

    SQL> Select e.emp_id,e.ename,e.chk_date,sum(chk_amt) year_amt
      2  from emp_month em
      3  ,(select emp_id,ename,chk_date
      4  from emp_info)e
      5  where e.emp_id = em.emp_id
      6  and em.emp_month_date between trunc(e.chk_date,'YY') AND e.chk_date
      7  group by e.emp_id,e.ename,e.chk_date
      8
    SQL> /
    
        EMP_ID ENAME      CHK_DATE    YEAR_AMT
    ---------- ---------- --------- ----------
           102 JOHN       01-APR-09      10975
           101 PAUL       01-MAR-09       4716
           103 KRIS       01-MAY-09      17482
    
    SQL> Select e.emp_id,e.ename,e.chk_date,sum(chk_amt) year_amt
      2  from emp_month em,
      3       emp_info e
      4  where e.emp_id = em.emp_id
      5  and em.emp_month_date between trunc(e.chk_date,'YY') AND e.chk_date
      6  group by e.emp_id,e.ename,e.chk_date
      7  /
    
        EMP_ID ENAME      CHK_DATE    YEAR_AMT
    ---------- ---------- --------- ----------
           102 JOHN       01-APR-09      10975
           101 PAUL       01-MAR-09       4716
           103 KRIS       01-MAY-09      17482
    
    SQL> 
    

    SY.

  • Is there a shorter way (better) with analytical functions?

    Here's a little test scenario:
    create table t 
    ( id   number,
      pos  number,
      typ  number,
      m    number);
      
    insert into t values (1,1,1,100);
    insert into t values (1,2,1,100);
    insert into t values (1,3,2, 50);
    insert into t values (2,1,3, 30);
    insert into t values (2,2,4, 70);
    insert into t values (3,1,1,100);
    insert into t values (3,2,2, 50);
    insert into t values (4,1,3, 30);
    insert into t values (4,2,5, 80);
    insert into t values (4,3,3, 30);
    insert into t values (5,1,3, 30);
    insert into t values (5,2,6, 30);
    insert into t values (6,1,2, 50);
    insert into t values (6,2,7, 50);
    insert into t values (6,3,2, 50);
    insert into t values (7,1,4, 70);
    insert into t values (7,2,4, 70);
    insert into t values (7,3,4, 70);
    For each id, I want to add all the values of m only when they have a different type. It would be a long journey:
    with t1 as
      (select 
         id, 
         typ, 
         min(m) m1 
       from t
       group by id, typ)
    select
      id,
      sum(m1) f
    from t1
    group by id
    order by 1;
    
            ID          F
    ---------- ----------
             1        150 
             2        100 
             3        150 
             4        110 
             5         60 
             6        100 
             7         70 
    but I wonder, is it possible to get this result with a single statement select using analytic functions, something like
    select 
      id, 
      sum(m) over (partition by distinct typ) F    -- this does not work. It's only an idea how it might look like
    from t
    group by id;

    This is firstly a collection with the id, type with calculation of the min for each id, type the combination.
    By subsequently for each id of the sum of the minutes (for each combination of id, type for this particular id) is summarized.

    select distinct
     id, sum(min(m)) over (partition by id)
    from data
    group by id, typ
    order by id
    

    Published by: chris227 on 15.03.2013 07:39

  • Purpose of the ORDER BY clause in the analytic function Min Max

    I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.

    user10566312 wrote:
    I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.

    It is a good point that many developers are not so aware. As far as I understand it the way it works.

    Some analytical functions do not need an order by or windowing clause (SUM, COUNT, MIN, etc.). If there is no specified window, then the full score is the window.
    As soon as you add a command also add you a windowing clause. This window has the default value of 'rank ofrows between unbounded preceding and current_row. So as soon as you add an order by clause, you get a sliding window.

    Documentation: http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm

    windowing_clause
    ...
    You cannot specify this clause unless you specified the order_by_clause. Window limits defined by the clause RANGE you can not specify only a single expression to the > order_by_clause. Please refer to 'Restrictions on the ORDER BY Clause'.

    example of

    with testdata as (select 10 numval, level lv from dual connect by level < 10)
    select lv, numval, sum(numval) over () sum1, sum(numval) over (order by lv) sum2
    from testdata;
    
    LV NUMVAL SUM1 SUM2
    -- ------ ---- ----
     1     10   90   10
     2     10   90   20
     3     10   90   30
     4     10   90   40
     5     10   90   50
     6     10   90   60
     7     10   90   70
     8     10   90   80
     9     10   90   90 
    

    Published by: Sven w. on 25 Sep 2012 16:57 - default behavior has been corrected. Thanks to Chris

  • May result by analytic function that follows

    Hi all

    I am currently using oracle 10g.

    create table
    CREATE TABLE fortest
    (  PROD             VARCHAR2(40 BYTE),
      prodvalues     number);
    INSERT statement
    insert into fortest values ('dental',10)
       insert into fortest values ('dental',4)
        insert into fortest values ('dental',13)
         insert into fortest values ('dental',3)
          insert into fortest values ('vision',2)
           insert into fortest values ('vision',11)
           insert into fortest values ('vision',33) 
            insert into fortest values ('vision',7)
    I need the output as follows
    prod        prodvalues <5         prodvalues >=5 and less than 10               prodvalues >=10
    dental         2                                     0                                      2
    vision         1                                     1                                      2
    first column should give me separate prod, prodvalues5 column: should give me the number of similar prod with prodvalues less than 5, same thirdcolumn should have County of similar prod with prodvalues > = 5 and prodvalue < 10 and so on.

    Please, not the names of columns of the output tables are just for reference, and I will not use them.


    Thanks in advance.

    Hi Bob,

    You don't have to use analytical functions. Here's a solution that doesn't use analytical functions:

    with temp as (select prod, case
                               when prodvalues <=5 then 1
                               else                    0
                               end  as prod5,
                               case
                               when prodvalues >=5 and prodvalues <10 then 1
                               else                    0
                               end  as prod5_10,
                               case
                               when prodvalues >= 10 then 1
                               else                    0
                               end  as prod10
                               from fortest)
                               select prod,sum(prod5) as prod5 ,  sum(prod5_10) as prod5_10 ,sum(prod10) as prod10
                               from temp
                               group by prod
    
  • With the help of analytical functions

    Hi all

    I'm using ODI 11 g (11.1.1.3.0) and I'm doing an interface using analytical functions in the column map, something like below.
    Salary on (partition of...)

    The problem is that when ODI saw the sum he considers this an aggregate function and the group. Is it possible to understand that it is not an aggregate in ODI function?


    I tried to create an option to specify whether it is analytic, then updated IKM with no luck.
    < % if (odiRef.getUserExit("ANALYTIC").equals("1")) {% >}
    < %} else {% >}
    < % = odiRef.getGrpBy (i) % >
    < % = odiRef.getHaving (i) % >
    < %} % >

    Thanks in advance

    Seth,

    Try this thing posted by Uli:
    http://www.business-intelligence-quotient.com/?p=905

  • Analytical function in Oracle

    I have a situation where I partitioned a Recordset. If in one partition on this recordset, the value of a field (field name registered) is '45' I need to order the result of this partition by - "outdate" desc "this provision" desc and order the other partition of desc 'key',' sequence ' desc, desc "outdate."

    If the query looks like to.

    Select row_number() over (partition by the order of the keys in sequence) RowNo, key, seq, status, outdate, receivedate from table1 where...
    order by?


    RowNo status outdate Seq key provision
    1 200 0 24 9/13 / 2009 12/9/2009
    2 200 1 23 9/10 / 2009 9/09/2009
    3 200 2 24 9/09 / 2009 9/08/2009

    1 210 0 24 9/13 / 2009 12/9/2009
    2 210 1 * 45 * 9/09/2009-9/08/2009
    3 210 2 24 9/10 / 2009 9/09/2009

    So I need to get the query that will order the first series of partition by desc 'key',' order ' desc, desc "outdate" and the second set of partition (because the status of '45' exists in the second partition) by "outdate" desc "this provision" desc.

    The output of the query should look like

    RowNo status outdate Seq key provision
    1 200 0 24 9/13 / 2009 12/9/2009
    2 200 1 23 9/10 / 2009 9/09/2009
    3 200 2 24 9/09 / 2009 9/08/2009

    1 210 0 24 9/13 / 2009 12/9/2009
    2 210 2 24 9/10 / 2009 9/09/2009
    3 210 1 * 45 * 9/09/2009-9/08/2009

    I don't know if this is possible using the analytical function.

    I would appreciate if any can help me with that.

    Thanks in advance

    Hello

    Welcome to the forum!

    You can use analytical functions in the ORDER BY clause.

    I do not have your tables, so I'll use scott.emp to illustrate.

    The following query sorts first by deptno. After this, the sort order for the departments that contain at least one seller is:
    b job
    (b) ename
    DEPTNO = 30 is be the only Department with a seller, so it's the only sorting as shown above.
    Other departments will be sorted by
    (a) sal
    (b) job

    SELECT       deptno
    ,       ename
    ,       job
    ,       sal
    FROM       scott.emp
    ORDER BY  deptno
    ,            CASE
              WHEN  COUNT ( CASE
                                   WHEN  job = 'SALESMAN'
                          THEN  1
                         END
                       ) OVER (PARTITION BY deptno) > 0
              THEN  ROW_NUMBER () OVER ( PARTITION BY  deptno
                                          ORDER BY        job
                                ,            ename
                              )
              ELSE  ROW_NUMBER () OVER ( PARTITION BY  deptno
                                          ORDER BY        sal
                                ,            job
                              )
           END
    ;
    

    Output:

    .   DEPTNO ENAME      JOB              SAL
    ---------- ---------- --------- ----------
            10 MILLER     CLERK           1300
            10 CLARK      MANAGER         2450
            10 KING       PRESIDENT       5000
            20 SMITH      CLERK            800
            20 ADAMS      CLERK           1100
            20 JONES      MANAGER         2975
            20 SCOTT      ANALYST         3000
            20 FORD       ANALYST         3000
            30 JAMES      CLERK            950
            30 BLAKE      MANAGER         2850
            30 ALLEN      SALESMAN        1600
            30 MARTIN     SALESMAN        1250
            30 TURNER     SALESMAN        1500
            30 WARD       SALESMAN        1250
    

    The small set of sample data you posted, the results you want can be achieved simply through

    ORDER BY  key
    ,         outdate     DESC
    

    I guess it's just a coincidence.

    If you need help, post some examples of data that requires really looking at the status column to get good results. Display the data in executable form, such as CREATE TABLE and the instructions INSERT, olr, as Salim, a WITH clause. (Maybe you can simply add or change a couple of lines in the example Salim already posted data).

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