Name of the function mutilated in the call library function node

Similar Questions

• How do I get the name of the caller (no contacts) that displays on the incoming call screen?

  Hi all
  1. work on the version of BB storm (9500/9530 Simulator) is v4.7.0.75
  2 opportunity BB JDE v4.7

  3. signed request

  4. the request is:

  I need to get the name of the appellant on the screen programmatically incall.
  I have observed that there are some providers will provide some default/a name on-screen incall.

  Note: I am not match the number of incall in contacts and look for the name.

  How do I get the name of the caller (no contacts) that displays on the incoming call screen?

  can any body help on this.

  Thanks in advance

  Ratna-

  There is no API that provides this information.  You can get the number of incoming callers, but not the name of caller ID.

• Get the name of the caller from an application when the Crier - executing.

  Hi all

  Here, I'll be back with a new problem which goes as follows:

  Suppose that my xyz application stores some contacts (just like in the book addresses/phone book).

  Other contacts are by default stored in my Blackberry address book.

  Suppose I get a call on the handset with my app xyz running in background. All I need is to retrieve the name of the caller of the xyz application and view this name as"Akash Calling... ' instead of '+ 919999999788 calling... ". "assuming that the caller details are present in the said application, his name and none of the details in the actual address book. Is it feasible. If so, please suggest.

  Thanks in advance!

  everything in that this is done incoming call:

  1. you retrieve the number of the caller in the earpiece of the phone

  2. you get the name that corresponds to this number in the background application

  3. you create an entry in address book with this name and number

  After callIncoming is executed, the system call screen is displayed. The phone app checks if it can find the number in the address book. It finds the number and displays the name.

  After that the call is accepted or rejected remove you the address book entry.

• BlackBerry Tour 9630 smartphones does not display the name of the caller

  Hello

  I have a Tour 9630, version sw 5.0.0.732.  When the phone rings, it does not display the name of the caller, their telephone number, although this number is in my address book.  Once I answer the call, the name will be displayed.

  Naturally, I would like to know who is the caller before I answer!  :-)

  I found a few messages, ask something similar, although for different model phones.  Some of them suggest that I have to disable protection for the content... but I can't find it in the options.  Even in the User Guide, it contains instructions (go to Options > Security Options > General settings... but there is no "General settings" on my phone.)

  If anyone knows how to solve this problem, I would be very grateful!

  Kind regards

  Options > Security > encryption > include contacts.

  There could be other solutions... Try these:

  1. make sure that you set your own country code to the Phone Dialer screen > Options > smart dialing.
  Set your country code in this format: "+ xx" where xx = country code. Some countries have two or three-digit country Codes. Do not place not the '+' in the entrance of your contact.
  * In the United States, the value of this country as '+ 1' Code and place your local area code in the appropriate box (this normally the default setting in a new BB).

  2. in the same place, change the length of National number for the number of digits corresponding to your country (since some countries have less than 10 as that set by default in the BB). Check out the total numbers, less country code. Do not place not the '+' in the entrance of your contact.
  * For example, some countries have a total number to 8 (more than 3 for the country code). You must enter '8 '.

• Display number and the name of the caller

  Greetings,

  I have an Iphone 6 IOS 9.3.3 when I get a call, is only to show the name of the appellant, I want to view calling name and number.

  I tried so hard, but I have found no Solution.

  There is no option for this on the lock screen.

  Go to application phone and select newer and type the phone number.

• Z10 Z10 ILA BlackBerry does not display the name of the caller of the stored contacts.

  My Z10 does not display the names of the callers stored in contacts with a prefix or area code. For example, an incoming call on contact JOHN SMITH, whose number is stored as + 44 7976 667668 shows not her name but just 07976 667668, but if the number of JOHN SMITH has been stored as 07976 667668 (without + 44) then the incoming call appears her name. Does anyone know how to remedy this? or is it a design error / omission by RIM?

  This is a known issue with the software currently.  Please visit KB33685

• Name of the caller is not showing blackBerry Smartphones don't not (single issue)

  Dear all,

  I wonder if anyone can help please. When I receive calls on my Blackberry Curve 8900 - the name of the appellant are not displayed on the screen (only the phone number). I saved all the names in my address book. I find it quite frustrating (I never know that name and had to memorize numbers).

  Thank you in advance for your help! Best regards, Irene

  Hello and welcome to the Forums of Support BlackBerry.com.

  It could be one of the three solutions... Try these:

  1. make sure that you set your own country code to the Phone Dialer screen > Options > smart dialing.
  Set your country code in this format: "+ xx" where xx = country code. Some countries have two or three-digit country Codes. Do not place not the '+' in the entrance of your contact.
  * In the United States, the value of this country as '+ 1' Code and place your local area code in the appropriate box (this normally the default setting in a new BB).

  2. in the same place, change the length of National number for the number of digits corresponding to your country (since some countries have less than 10 as that set by default in the BB). Check out the total numbers, less country code. Do not place not the '+' in the entrance of your contact.
  * For example, some countries have a total number to 8 (more than 3 for the country code). You must enter '8 '.

  3. you probably have "Content Protection" located on your address book.
  Look at the Options > Security > General settings. Scroll down to the content Protection > include addresses = no

• [JS, CS2] Is there a variable that contains the name of the calling script?

  Hello

  I need to have a script to get to know his own name.

  It's because I have a situation where I have a find/replace routine to clean up and text style that I need to run on a few different types of stories (I work for a newspaper and they are in the sense of "default body copy," in the page","section of the arts", etc), but most of the routine of find/replace is the same for each of them.  My colleagues should be able to have each of the routines to be in different scripts so that they can click on them.  So I want each script specialist to have nothing in it but a statement #include that will be #include the text of a main entry.  That way, whenever I have to make changes, I can't save as 1 million slightly different versions.

  So if I need to be able to determine the name (or the path) of the script that has been called, then the script can then perform some necessary specialized actions for this type of story.  Is it possible to do?

  It would be something like the $argv php variable [0].

  Thank you.

  I don't think I understand what you mean by,

  is it possible to pass parameters to the Indesign scripts directly (like the rest of the argv PHP array)?

  Where these variables should come from? Please provide details.

  You can send parameters to a script as in the following example (in examples of javascript)

  DoScriptParameters.jsx
  A JavaScript InDesign CS3
  //
  Shows how to send parameters to a script called for help
  the doScript method.
  var myParameters = ["Hello from DoScript", "Your message here"];
  var myJavaScript = "alert (\"First argument:------"arguments [0] + \"\\rSecond argument: \ "+ arguments [1]);"; "
  app.doScript (myJavaScript, ScriptLanguage.javascript, myParameters);
  If (File.fs == "Windows") {}
  var myVBScript = "msgbox arguments (1), vbOKOnly, \"First argument:------"& arguments (0) ';
  app.doScript (myVBScript, ScriptLanguage.visualBasic, myParameters);
  }
  else {}
  var myAppleScript = "say the application \"Adobe InDesign CS3_J\\rdisplay dialog box (\"First argument\ ' & point 1 of arguments & return & \"Second argument:------"& point 2 of arguments & return & end say" ';).
  app.doScript (myAppleScript, ScriptLanguage.applescriptLanguage, myParameters);
  }

• Formula to return the name of the hierarchy to another node

  People,

  I thought it would be easier explained with a mock excel upward. I hope you understand.

  Background:

  Two hierarchies are ministries, the two beeding seeded in diferent target system.  When a new Member is added in the TFTP hierarchy, she also will be added to the hierarchy of Essbase, but with a different number. Custom.EssbaseName is in the TFTP hierarchy and contains the Convention of naming its equal TFTP Essbase.

  I need to create a property derived for my Essbase hierarchy. This property must evaluate each node in the hierarchy of Essbase, he must go to the TFTP hierarchy and finds its node name as the value in the Custom.EssbaseName property and then return its name of node TFTP.

  Please see the cells in gray, I hope that some of you are able to help this pressing issue!

  

  Hello

  Assuming you'd be on 11.1.2.3 and above all, try this.

  var worm is node. Version;

  var essnodename is node. ABBREV;

  var esspropval ="";

  var psftHier = worm. HierByAbbrev ("TFTP");

  var psftTop = psftHier.TopNode;

  var arrpsft = psftTop.GetDescendants ();

  for (idx = 0; idx<>

  esspropval = arrpsft [idx]. PropValue ("Custom.EssbaseName");

  {if(esspropval==essnodename)}

  return arrpsft [idx]. ABBREV;

  }

  }

  Return ' ';

  I would like to know if it works.

  Thank you

  Denzz

• What is the name of the Servlet library?

  Hello
  
  I'm trying to load a (Prototype VirtualTrainer-Java) application without .jws file in JDeveloper 10.1.3.4. Nearly there, but have compilation errors when using reconstruction in the project right-click menu, as shown below. The errors seem to indicate JDev cannot find three things: the HttpServlet API and a library of custom tags and a filter:
  

  Project: C:\webapps\VirtualTrainer\ViewController\ViewController.jpr
     C:\webapps\VirtualTrainer\ViewController\src\com\jsfcompref\trainer\backing\Login.java
         Error(14,8): HttpServletResponse not found 
         Error(15,8): HttpSession not found 
     C:\webapps\VirtualTrainer\ViewController\src\com\jsfcompref\trainer\components\ScrollerTag.java
         Error(55,34): Tag not found  in class javax.faces.webapp.UIComponentTag in class com.jsfcompref.trainer.components.ScrollerTag
     C:\webapps\VirtualTrainer\ViewController\src\com\jsfcompref\trainer\security\SecurityFilter.java
         Error(6,8): Filter not found 
         Error(7,8): FilterChain not found 
         Error(8,8): FilterConfig not found Error(9,8): ServletException not found 
         Error(10,8): ServletRequest not found 
         Error(11,8): ServletResponse not found 
         Error(12,8): HttpServletRequest not found 
     C:\webapps\VirtualTrainer\ViewController\public_html\app\main.jsp
         Error(126): Unable to instantiate tag: t:scroller (class: com.jsfcompref.trainer.components.ScrollerTag)  Make sure that the tag class is available and that the tag library containing the class is not excluded from this application.
         Error(126): Unable to find class for bean: null defined by tag with class: com.jsfcompref.trainer.components.ScrollerTag
         Error(142): scroller must be terminated with /> or %> not >
     C:\webapps\VirtualTrainer\ViewController\public_html\app\edit_te.jsp
         Error(142): Unable to instantiate tag: t:scroller (class: com.jsfcompref.trainer.components.ScrollerTag)  Make sure that the tag class is available and that the tag library containing the class is not excluded from this application.
         Error(142): Unable to find class for bean: null defined by tag with class: com.jsfcompref.trainer.components.ScrollerTag
         Error(158): scroller must be terminated with /> or %> not >

  To solve the problem of HttpServlet, I tried project properties - > library-> add library..., but I do not know which library to add. I tried J2EE and Servlet Runtime, but two of them cause only a lot more errors.
  
  So my questions are:
  1. is the way I use Project Properties-> correct libraries?
  2. If this is the case, what is the library in the list to add?
  
  Thanks a lot for your help!
  
  
  Newman

  Just for the record, I was able to compile the Prototype VirtualTrainer-Java project once I added
  JSF Core 1.0 and JSF HTML 1.0 for JSP tag libraries
  and
  Duration JSP
  JSF
  Servlet Runtim
  for libraries.

• get the name of the calling user

  Hello
  
  I wrote a set of procedures PLSQL and he created in a user schema specific USER_A. procedures and functions in this package are used by other users in the database, for example USER_B.
  So I USER_B connection to the database and calling procedures using the qualified name USER_A.PACKAGE_NAME syntax. PROCEDURE_NAME.
  
  According to this scenario, how can I like this last knowledge of PROCEDURE_NAME who called me to find out it was USER_B who performed my procedure?
  
  Thanks for your help!
  JP.
  
  Published by: [email protected] on October 23, 2008 10:06

  You can use any USER in code, the latter contains the Login of the user.

• What is the right way to specify the location of the shared library in an a .lvlib function call library function node?

  I'll have a bit of a problem with how to specify the location of library shared in a call library function node it is a VI that is part of a library of LV. Here's a little background which may help.

  I do a lot of measures using spectrometers photo from several manufacturers.  Someone in my company developed a C DLL library, which provides a simple API for all the different spectrometers. To facilitate this DLL to use in LabVIEW, I wrote a .lvlib that wraps all the functions.  When I want to use the API, I simply include the .lvlib file in my project that allows me to drag and drop the wrapper s VI on my block diagram. When I created the .lvlib of VI, I specified the path in the call library node. /. * so it will always look in the local application to the DLL directory when I run.

  The problem is, when I load demand, LabVIEW you asks for the location of the DLL even if it's just there in the local directory! I tried to put copies of the DLL in the directory with the .lvlib, but he still refuses to find the DLL loading.  What I am doing wrong?

  You should in this simple case enter the full path to the DLL by navigating to it. If the DLL is on the same volume/drive that the VI containing the call library node LabVIEW will be internally store the relative path from the VI to the DLL (but still show the absolute path). If you move the DLL and screw together (so the relative location of the DLL to the VI remains the same) LabVIEW will always find the DLL.

  I don't think that the lvlib would add nothing to that.

• When I use the library function node call in real time, is loaded only once for all or load the DLL whenever it is called?

  When I use the library function node call in real time, is loaded only once for all or load the DLL every time when it is called?

  I have a critical application in real time, in which I use a piece of DLL function developed in C++.  It is ok?  Make sure any senior developer?

  Thank you in advance.

  The user interface thread is the thread that is used to update the user interface. It's slow. And it's supposed to be that way because humans are slow.

  The call library function node can be configured as this thread to use in the configuration for it dialog box. Please visit the LabVIEW documentation on how to do this.

• How to use the node function call library for a function in the dll with the data SUB type

  Hi all

  I would ask for your kind help

  I am facing a problem with the call library node.

  I have a C++ (stdcall) function, which has Sub as data type

  XXXX error code (hwnd, lid, getValue, * Sub data1, * Sub data2)

  data1 and data2 types are constantly changing based on the value of 'getValue '.

  Mainly I can use the call library node several times and adapt each node according to the types of data data1, data2 and extract the values and use in the code. Here is no question. Real question is:

  My question:

  How can I use a node of library time call and make a case according to the 'getvalue', who will control the data1, data2 data type. Here I really seeking solutions.

  My tests:

  I used varaints as entry to the libray call node of the data1, data2 and selected parameters in the call libraby node as "Adapt to type. Here labview just crashed.

  I appreciate your suggestions to feedbackand.

  Thank you

  Karine

  You must allocate enough space for data1 and data2, and then pass a pointer to this space. An easy way to do this is the function to initialize table. Set the U8 type and size for the number of bytes required. Pass this array to the function as a pointer of table data.

  After the function call returns, you need to extract the data in the table. You can do it manually, but a simple approach is to use the array of bytes to a string. Then, in a housing structure, use Unflatten chain to convert the string to the correct data type. This method also converts the "endianness" which will be probably necessary; Be sure to only set all entries for unflatten correctly.

• Why the DLL function performed by call library node fails when the Vi is reopened?

  Development system

  OS: Windows XP

  LabVIEW: version 10.0

  DLL: Custom

  Compiler: Visual C++ 6.0

  Function prototype: __declspec (dllexport) const char * test (void)

  We have developed a DLL to use.  Compile the DLL itself.  The DLL includes a function test.  The test function validates the functional capabilities of the DLL.  I followed the examples online, and I used the tool to import shared library in LabVIEW.  The screw created use the call library node.

  When I create a VI by calling the function in the DLL test customized by using the call library node the VI runs the test DLL function flawlessly.  I close the VI.  When I re - open the VI and run it, I get an error code of the DLL.  However, if I go on the schema and define the path of the DLL in the library call Configuration node once again the VI then runs the test DLL function perfectly again.

  I have set the path of the DLL in the library call Configuration node everytime I open the VI.  The examples that I downloaded from the community don't require this.  What could be the missing DLL?  What Miss me?

  I solved the problem.

  I had create the DLL by using the following steps for VC 6.0:

  1. new project

  2. Select the Appwizard (DLL) MFC

  3. Select the regular DLLS using the MFC shared DLLS

  4 Yes for source file comments

  5 finishing

  The DLL must be on the VI search path.  The easiest way was to have the DLL in the same directory as the VI.