Paging query needed help for large table - force a different index
I use a slight modification of the pagination to be completed request to ask Tom: [http://www.oracle.com/technology/oramag/oracle/07-jan/o17asktom.html]Mine looks like this to extract the first 100 lines of everyone whose last name Smith, ordered by join date:
SELECT members.*
FROM members,
(
SELECT RID, rownum rnum
FROM
(
SELECT rowid as RID
FROM members
WHERE last_name = 'Smith'
ORDER BY joindate
)
WHERE rownum <= 100
)
WHERE rnum >= 1
and RID = members.rowid
The difference between this and ask Tom is my innermost query returns just the ROWID. Then, in the outermost query we associate him returned to the members table ROWID, after that we have cut the ROWID down to only the 100 piece we want. This makes it MUCH more (verifiable) fast on our large tables, because it is able to use the index on the innermost query (well... to read more).The problem I have is this:
SELECT rowid as RID
FROM members
WHERE last_name = 'Smith'
ORDER BY joindate
It will use the index for the column predicate (last_name) rather than the unique index that I defined for the column joindate (joindate, sequence). (Verifiable with explain plan). It is much slower this way on a large table. So I can reference using one of the following methods:SELECT /*+ index(members, joindate_idx) */ rowid as RID
FROM members
WHERE last_name = 'Smith'
ORDER BY joindate
SELECT /*+ first_rows(100) */ rowid as RID
FROM members
WHERE last_name = 'Smith'
ORDER BY joindate
Whatever it is, it now uses the index of the column ORDER BY (joindate_idx), so now it's much faster there not to sort (remember, VERY large table, millions of records). If it sounds good. But now, on my outermost query, I join the rowid with the significant data in the members table columns, as commented below:SELECT members.* -- Select all data from members table
FROM members, -- members table added to FROM clause
(
SELECT RID, rownum rnum
FROM
(
SELECT /*+ index(members, joindate_idx) */ rowid as RID -- Hint is ignored now that I am joining in the outer query
FROM members
WHERE last_name = 'Smith'
ORDER BY joindate
)
WHERE rownum <= 100
)
WHERE rnum >= 1
and RID = members.rowid -- Merge the members table on the rowid we pulled from the inner queries
As soon as I did this join, this goes back to the use of the index of predicate (last_name) and perform the sort once he finds all the corresponding values (which can be a lot in this table, there is a cardinality high on some columns).My question therefore, in the query full above, is it possible that I can get to use the ORDER of indexing BY column to prevent having to sort? The join is what makes go back to using the predicate index, even with notes. Remove the join and just return the ROWID for these 100 records and it flies, even over 10 millions of documents.
It would be great if there was some generic hint that could accomplish this, such as if we change the table/column/index, do not change the indicator (indicator FIRST_ROWS is a good example of this, while the INDEX indicator is the opposite), but any help would be appreciated. I can provide explain plans for the foregoing, if necessary.
Thank you!
Tags: Database
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Concerning
Etbin
Edited by: Etbin on 3.2.2013 09:01
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rp0428 post - something to remember. -
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guys this is just. as an extension of this post that Frank was helping me. IM reposting because my needs change slightly and im having a hell of a time trying to change the query.
Here are the previous post.
need help with query can find data back please help.
dataCREATE TABLE "FGL" ( "FGL_GRNT_CODE" VARCHAR2(60), "FGL_FUND_CODE" VARCHAR2(60), "FGL_ACCT_CODE" VARCHAR2(60), "FGL_ORGN_CODE" VARCHAR2(60), "FGL_PROG_CODE" VARCHAR2(60), "FGL_GRNT_YEAR" VARCHAR2(60), "FGL_PERIOD" VARCHAR2(60), "FGL_BUDGET" VARCHAR2(60) )
I need to find the year of greater subsidy for the granting by a period setting.Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7600','4730','02','11','00','400'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','1','100'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','1','0'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7600','4730','02','11','1','400'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('360055','360055','7200','4730','02','10','1','400'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('360055','360055','7600','4730','02','10','1','400'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','14','200'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7600','4730','02','10','14','100'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','14','200'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','2','100'); Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','11','2','600');
Once I found the great year, I need to check the value of the period 14 this grant for the previous year and add it to the amount of the budget for this grant. However if there is an entry in the biggest year for period 00 so I need to ignore the period 14 of the previous year and the current calculation period + (current period - more great year 00)
hope that makes sense, so in other words, with the new data above. If I asking me a second period of the grant year 11. I'd end up with $800
because the greatest year is 11 it contains one point 0 with $ 400, so my total should be
amount of period $2,600
period $0 400 - period $2 600 = $200
600 + 200 = $800
If I have question period 1 grant 360055 I'd end up just with 800 grnt year 10.
I tried to edit this query you have provided me with no luck. I tried for several embarrassed day but I'm saying I can just do what im trying to do.
can you please help me.
Here's the query provided by frank kulash who graciously put it together for me.
MiguelWITH got_greatest_year AS ( SELECT fgl.* -- or whatever columns are needed , MAX ( CASE WHEN fgl_period = :given_period THEN fgl_grnt_year END ) OVER () AS greatest_year FROM fgl ) SELECT SUM (fgl_budget) AS total_budget -- or SELECT * FROM got_greatest_year WHERE ( fgl_grnt_year = greatest_year AND fgl_period = :given_period ) OR ( fgl_grnt_year = greatest_year - 1 AND fgl_period = 14 ) ;
Hi, Miguel.
You are waying that when larger year who has: given_period also a period = '00' (or '0', or whatever it is you want to use), then you want to double the budget of the given_period (subtract the '00' budget and do not count '14' year pevious)? If so, add another condition to the CASE statement that decides what you've summarized:
WITH got_greatest_year AS ( SELECT TO_NUMBER (fgl_grnt_year) AS grnt_year , fgl_period , TO_NUMBER (fgl_budget) AS budget , MAX ( CASE WHEN fgl_period = :given_period THEN TO_NUMBER (fgl_grnt_year) END ) OVER () AS greatest_year FROM fgl ) , got_cnt_00 AS ( SELECT grnt_year , fgl_period , budget , greatest_year , COUNT ( CASE WHEN grnt_year = greatest_year AND fgl_period = '00' THEN 1 END ) OVER () AS cnt_00 FROM got_greatest_year ) SELECT SUM ( CASE WHEN grnt_year = greatest_year -- New AND fgl_period = :given_period -- New AND cnt_00 > 0 THEN budget * 2 -- New WHEN grnt_year = greatest_year AND fgl_period = :given_period THEN budget WHEN grnt_year = greatest_year AND fgl_period = '00' THEN -budget WHEN grnt_year = greatest_year - 1 AND fgl_period = '14' AND cnt_00 = 0 THEN budget END ) AS total_budget FROM got_cnt_00 ;
You will notice it is the same as the previous query, I posted, with the exception of 3 lines marked 'new '.
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Published by: SeenuGuddu on February 27, 2011 03:39with a as ( Select Empno, Deptno ,sal, sal/SUMSAL Percent, case when rn<=5 then rn else null end rnm From (Select emp.*, Sum(Sal) Over() "SUMSAL", Row_number() Over(Order by sal Desc) rn From emp) ) select case when max(rnm) is not null then to_char(max(empno)) else 'Others:' end empno, case when max(rnm) is not null then max(deptno) else null end deptno, case when max(rnm) is not null then max(sal) else null end sal, to_char(sum(percent), '90.99') percent, max(rnm) rn from a group by rnm order by rnm
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Post edited by: Kevin Monahan
Reason: your title is too long
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------------------------------
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---------------------------------------
https://docs.Oracle.com/CD/E11882_01/AppDev.112/e41502/adfns_indexes.htm#ADFNS00504
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Tecra R840 - need help for installing the SSD
Hello
Sorry, again, but I really need help with that?
My new ssd (arriving in a few days) is a Plextor M5P which is 7 mm thick! My Tecra R840-16J have a thickness 9.5 mm HDD and what I've seen is no caddy!
I would be grateful all the tricks for installing the ssd drive in my Tecra!Thanks for your time,
Paulo
Hello Paulo
As far as I know that some models are available with drive HARD and some with SSD these models with SSD have small SSD support. SSD is fixed by 4 screws in this medium.
I put t really know how to help you now. Maybe you should contact the nearest Toshiba service provider and ask for help. I think they can check the part number of this door - or maybe order one for you.
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