Update sql need help for hierarchy table

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  I use a slight modification of the pagination to be completed request to ask Tom: [http://www.oracle.com/technology/oramag/oracle/07-jan/o17asktom.html]
  
  Mine looks like this to extract the first 100 lines of everyone whose last name Smith, ordered by join date:

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  (
      SELECT RID, rownum rnum
      FROM
      (
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  It will use the index for the column predicate (last_name) rather than the unique index that I defined for the column joindate (joindate, sequence). (Verifiable with explain plan). It is much slower this way on a large table. So I can reference using one of the following methods:

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  FROM members
  WHERE last_name = 'Smith'
  ORDER BY joindate

  SELECT /*+ first_rows(100) */ rowid as RID 
  FROM members
  WHERE last_name = 'Smith'
  ORDER BY joindate

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  FROM members,           -- members table added to FROM clause 
  (
      SELECT RID, rownum rnum
      FROM
      (
          SELECT /*+ index(members, joindate_idx) */ rowid as RID   -- Hint is ignored now that I am joining in the outer query
          FROM members
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          ORDER BY joindate
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  ) 
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  It would be great if there was some generic hint that could accomplish this, such as if we change the table/column/index, do not change the indicator (indicator FIRST_ROWS is a good example of this, while the INDEX indicator is the opposite), but any help would be appreciated. I can provide explain plans for the foregoing, if necessary.
  
  Thank you!
  

• I need help for the upgrade of my current system.

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• [8i] need help for updating/fixing work table

  I work in an old database:
  Oracle8i Enterprise Edition Release 8.1.7.2.0 - Production
  PL/SQL Release 8.1.7.2.0 - Production
  CORE 8.1.7.0.0-Production
  AMT for HP - UX: 8.1.7.2.0 - Production Version
  NLSRTL Version 3.4.1.0.0 - Production
  
  I'm trying to fix a work schedule, and I'm not exactly sure how do. I am accustomed to querying data, do not make changes to the data...
  
  Some examples of data:

  CREATE TABLE     test_cal
  (     clndr_dt     DATE     NOT NULL
  ,     work_day     NUMBER(3)
  ,     clndr_days     NUMBER(6)
  ,     work_days     NUMBER(5)
  );
  
  INSERT INTO     test_cal
  VALUES     (TO_DATE('12/30/2010','mm/dd/yyyy'), 254, 11322, 7885);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('12/31/2010','mm/dd/yyyy'), 255, 11323, 7886);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/01/2011','mm/dd/yyyy'), 0, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/02/2011','mm/dd/yyyy'), 0, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/03/2011','mm/dd/yyyy'), 1, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/04/2011','mm/dd/yyyy'), 2, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/05/2011','mm/dd/yyyy'), 3, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/06/2011','mm/dd/yyyy'), 4, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/07/2011','mm/dd/yyyy'), 5, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/08/2011','mm/dd/yyyy'), 0, NULL, NULL);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/09/2011','mm/dd/yyyy'), 0, 11332, 7895);
  INSERT INTO     test_cal
  VALUES     (TO_DATE('01/10/2011','mm/dd/yyyy'), 6, 11333, 7896);

  Note: 2010-12-31 is the last time that I am 100% sure that the data in the table are good. After that, clndr_days and work_days are absent or at least in the case of work_days, are not correct No.
  
  It is a question of both parties, since I need to set the clndr_days and the work_days. (You can fix probably both with a single statement, but I broke it into two to start, to simplify it for me).
  
  I show only 12 days in my sample data, but really, the table stretches in a number of years and pass another 5 years.
  
  PART 1: determination of clndr_days
  
  I've implemented this request:

  SELECT     clndr_dt
  ,     work_day
  ,     work_days
  ,     clndr_days
  ,     min_clndr_day + r_num     AS clndr_days_test
  FROM     (
       SELECT     t.*
       ,     MIN(clndr_days)     OVER(ORDER BY clndr_dt)     AS min_clndr_day
       ,     ROW_NUMBER() OVER(ORDER BY clndr_dt)-1     AS r_num
       FROM     test_cal t
       WHERE     clndr_dt     >= TO_DATE('12/31/2010','mm/dd/yyyy')
       )
  ;

  Who gives the right clndr_days (like clndr_days_test), but I don't know how to get that in the table.
  
  It does not work:

  UPDATE     test_cal
  SET     clndr_days     =     (
                      SELECT     min_clndr_day + r_num
                      FROM     (
                           SELECT     t.*
                           ,     MIN(clndr_days)     OVER(ORDER BY clndr_dt)     AS min_clndr_day
                           ,     ROW_NUMBER() OVER(ORDER BY clndr_dt)-1     AS r_num
                           FROM     test_cal t
                           WHERE     clndr_dt     >= TO_DATE('12/31/2010','mm/dd/yyyy')
                           ) c
                      WHERE     c.clndr_dt     = ???  -- how do I make this equal whatever the clndr_dt is for the record I'm updating?
                      )
  WHERE     clndr_dt     >      TO_DATE('12/31/2010','mm/dd/yyyy')

  and I don't know how to operate...
  
  
  PART 2: Fixing work_days
  
  Then, I can't set up a query for work_days.
  
  That's what I have so far, but it does not work quite right, and then it must also be as well an UPDATE statement:

  SELECT     clndr_dt
  ,     work_day
  ,     work_days
  ,     clndr_days
  ,     min_work_day + r_num     AS work_days_test --this isn't right, when work_day is 0 work_days_test should be the previous work_day not the minimum work_day
  FROM     (
       SELECT     t.*
       ,     MIN(work_days)     OVER ( ORDER BY clndr_dt)     AS min_work_day
       ,     CASE
                 WHEN     work_day     <> 0
                 THEN     ROW_NUMBER()     OVER ( PARTITION BY     CASE
                                                    WHEN     work_day <> 0
                                                    THEN     1
                                                    ELSE     2
                                               END
                                       ORDER BY     clndr_dt
                                     )
                 ELSE     0
            END               AS r_num
       FROM     test_cal t
       WHERE     clndr_dt     >= TO_DATE('12/31/2010','mm/dd/yyyy')
       )
  ;

  (When I tried to use LAG, that did not work either, because you can have more than 1 non consecutive working day and so it only works for the first day of non-working to have the correct work_days, and then it is to be wrong again)
  
  That's what I want my table to look like in the end:

  CLNDR_DT                   WORK_DAY       WORK_DAYS CLNDR_DAYS_TEST
  ------------------- --------------- --------------- ---------------
  12-31-2010 00:00:00         255.000       7,886.000    11,323.000
  01-01-2011 00:00:00            .000       7,886.000    11,324.000
  01-02-2011 00:00:00            .000       7,886.000    11,325.000
  01-03-2011 00:00:00           1.000       7,887.000    11,326.000
  01-04-2011 00:00:00           2.000       7,888.000    11,327.000
  01-05-2011 00:00:00           3.000       7,889.000    11,328.000
  01-06-2011 00:00:00           4.000       7,890.000    11,329.000
  01-07-2011 00:00:00           5.000       7,891.000    11,330.000
  01-08-2011 00:00:00            .000       7,891.000    11,331.000
  01-09-2011 00:00:00            .000       7,891.000    11,332.000
  01-10-2011 00:00:00           6.000       7,892.000    11,333.000

  (Sorry for all the additional decimals)
  
  Published by: user11033437 on January 11, 2012 13:40

  Hello

  Thanks for posting the CREATE TABLE and instructions INSERT, the desired output that is very clear, and your attempts; It's all very useful. It would also be useful to explain how you get the desired based on the sample results. There's always a chance, a person could get by chance good results for the wrong reasons with the small set of sample data, but allows you to get complete wrong results with your data would cause.
  It seems that clndr_days is the total number of days elapsed since some point of conventional departure (perhaps when the company started), and that work_days is the total number of days of work to a starting point. It seems that work_day is 0 when the day is not a working day, and otherwise, the total number of working days so far in the calendar year. Is this fair?

  You said the data after December 31, 2010 is not reliable. Did you mean that two columns (clndr_days and work_days) are not reliable, but the rest of the data is reliable? In other words, are you sure there is only one line a day even after that 2010 and the work_day column is accurate? If so, you can do this:

  UPDATE       test_cal     m
  SET       (clndr_days, work_days) =
  (
       SELECT     MIN (clndr_days) + COUNT (*) - 1          -- clndr_days
       ,     MIN (work_days)  + COUNT ( CASE
                                             WHEN  work_day > 0
                                  AND   clndr_dt > TO_DATE ('12/31/2010', 'MM/DD/YYYY')
                                  THEN  1
                              END
                               )               -- work_days
       FROM     test_cal
       WHERE     clndr_dt     BETWEEN     TO_DATE ('12/31/2010', 'MM/DD/YYYY')
                      AND     m.clndr_dt
  )
  WHERE     clndr_dt     > TO_DATE ('12/31/2010', 'MM/DD/YYYY')
  ;
  

  You are right: it is possible to set the two columns at the same time.

  It's a shame that you are using Oracle 8.1. The command MERGE, which was new in Oracle 9.1, is much clearer and more effective. If you could use MERGE, you can essentially use the code you have posted in the middle of a MERGE statement.

  Education of UPDATE above assumes that, for the incorrect days, clndr_days and work_days will be never less than the last exact value. If this is not the case, the solution is a bit more complicated. You can avoid this problem and to make the statement faster too, by simply hard-code the last exact value of clndr_days and work_days in the UPDATE statement, where I used min. (this looks like a situation where the efficientcy is not a big problem, however. "You'll probably never make this exact UPDATED once again, so if it runs in 1 second or 10 minutes maybe not much of importance.)

  Sorry, I don't have an Oracle 8 database to test this. It works in Oracle 9.2, and I do not think that it uses all the features that are not available to the point 8.1.

• Need help for query flat_file type clobdata oracle table data.

  Hi Sir,
  
  I need help to query oracle table flat file data having given clob type.
  

  Oracle Version:
  
  Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
  PL/SQL Release 10.2.0.1.0 - Production
  "CORE     10.2.0.1.0     Production"
  TNS for 32-bit Windows: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  
  
  Source table
  
    CREATE TABLE order_details 
     (     QUEUE_SEQNUM NUMBER(10,0) NOT NULL ENABLE, 
       LINE_SEQNUM NUMBER(10,0) NOT NULL ENABLE, 
       CHAR_DATA CLOB, 
       OPTIMISTIC_LOCK_KEY NUMBER(20,0)
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  COLUMN FOR CHAR_DATA FLAT_FILE
  

  EU,6067AT,AT10,000000402004,NexiumGERDManagementProject,Z435,,ZZ29,NIS-GOLD,AT
  EU,6067AT,AT10,000000402038,NIS-OEU-ARI-2007/1,Z450,,ZZ29,NIS-OEU-ARI-2007/1,AT
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  EU,6067AT,AT10,000000402040,D1443L00044SeroquelXRRuby,Z450,,ZZ29,D1443L00044,AT
  EU,6067AT,AT10,000000402041,NIS-GEU-DUM-2008/1,Z450,,ZZ29,NIS-GEU-DUM-2008/1,AT
  EU,6067AT,AT10,000000402042,SonstigeAktivitätenLCM,Z450,,ZZ29,.,AT
  EU,6067AT,AT10,000000402134,D1680L00002Saxagliptin,Z450,,ZZ29,D1680L00002,AT
  EU,6067AT,AT10,000000402199,SeroquelWaveNIS,Z450,,ZZ29,NIS-NEU-DUM-2009/1,AT
  EU,6067AT,AT10,000000402313,SeroquelExtra(D1443L00082),Z450,,ZZ29,D1443L00082,AT
  EU,6067AT,AT10,000000402517,AtlanticD5130L00006(AZD6140),Z450,,ZZ29,D5130L00006,AT
  EU,6067AT,AT10,000000554494,ArimidexSt.Gallen(13+2),Z142,,ZZ09,,AT
  EU,6067AT,AT10,000000554495,ArimidexASCO(5delegates),Z142,,ZZ09,,AT
  EU,6067AT,AT10,000000554496,ArimidexSanAntonio6delegates,Z142,,ZZ09,,AT
  EU,6067AT,AT10,000000554497,ArimidexBreastCancerSummit(13+2),Z130,,ZZ09,,AT
  EU,6067AT,AT10,000000554498,ArimidexEIH(15delegates),Z130,,ZZ09,,AT
  EU,6067AT,AT10,000000554499,ArimidexNIFA(200delegates),Z135,,ZZ09,,AT
  EU,6067AT,AT10,000000554500,ArimidexNIFAworkshops(8x25),Z135,,ZZ09,,AT
  EU,6067AT,AT10,000000554501,ArimidexPraktischeGyn.Fortbildung,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554502,ArimidexAGO,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554503,ArimidexHämato/OnkologieKongress,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554504,ARIMIDEXGYNäKOLOGENKONGRESS,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554505,ArimidexChirurgenkongress,Z147,,ZZ09,,AT

  EXPECTED RESULTS:
  

  AFFIRM_CODE COMPANY_CODE INTERNAL_ORDER_CODE INTERNAL_ORDER_DESC ENIGMA_ACTIVITY             SUB_ACTIVITY_CODE IN_AFF_IND ORDER_TYPE EXTERNAL_ORDER COUNTRY        
  EU          6067AT       AT10                 000000402004       NEXIUMGERDMANAGEMENTPROJECT     Z435           NULL        ZZ29       NIS-GOLD        AT             
  EU          6068AT       AT11                 000000402005       NEXIUMGERDMANAGEMENTPROJECT     Z435           NULL        ZZ29       NIS-GOLD        AT             

  Sorry, my bad. Without database at hand, I'll try 'baby steps' (borrowed from Frank) so you don't confuse it with errors that I might add (happens far too often already, but at least you won't "swallow" as forum members think is one of the main goals of this fighter - help her learn - providing not only the proverbial fish.)
  Search the Forum - your problem is one of its best sellers. Watching {message identifier: = 10694602} ("split string into" was the key word used in research) you can try something as

  select table_row,
         level clob_row,
         regexp_substr(char_data,'[^' || chr(13) || chr(10) || ']+',1,level) the_line
    from (select to_char(queue_seqnum)||':'||to_char(line_seqnum) table_row,
                 char_data
            from order_details
         )
   connect by regexp_substr(char_data,'[^' || chr(13) || chr(10) || ']+',1,level) is not null
          and prior char_data = char_data
          and prior table_row = table_row
          and prior sys_guid() is not null
  

  to get all the s the_lineall CLOB and after that the use of the example even to get your columns of each the_line.

  Concerning

  Etbin

  Edited by: Etbin on 3.2.2013 09:01

  .. .but I m connected to do things according to the instructions, I can't do something.

  Used to happen to me too and I did as told to the but only after explaining any disadvantages, I was aware of in time. The last sentence is usually: "O.K. now be just and Don't come back with that kind of thing when it turns out that this isn't the right thing."
  rp0428 post - something to remember.

• I Iconia Tab A500, running 3.0, need help for upgrade by using a microsd card, got Acer download update

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  It is important before you have the correct version of the update, it's different for different regions of the world, and you will not be able to upgrade the (for example) Brazil version from the US site.

• Need help for PL/SQL Script

  If I wanted to give access to all my tables in my schema to a role, how could I do that.
  
  Thus, rather than run a query for each table 100 times, looking for something
  who would have a loop.
  
  For each Table in my schema, give select, update and insert, but remove it from user role?
  
  ?
  
  Thank you advance, 10 G here.

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      END LOOP;
  END;
  /
  

  SY.

• Need help for the conversion of the Date

  Hi all

  Your expert input is much appreciated.

  Have a problem where it is my master table structure, whenever there is an update/delete/insert on the main table
  There's a trigger that insert an entry in the Audit table.
  
  SQL > cpp_Master Desc;
  Number of Ent_id
  Date of Ent_date
  
  SQL > Desc Cpp_Master_Audit
  Number of Ent_id
  Date of Ent_date,
  Insert_type varchar2 (1)
  
  The problem is that when we insert the Sub record in the table, the ent_date column appears in this way.
  
  SQL > INSERT INTO CED.cpp_Master (ENT_ID, Ent_date)
  VALUES (6030902, TO_DATE (1 JANUARY 01 00:00:00 ', ' HH24: PUT DD/MM/YYYY "));

  SQL > SELECT * FROM CED.cpp_Master;

  6030902 01/01/0001

  SQL > SELECT * FROM CDS. Cpp_Master_Audit;

  6030902 01/01/0001

  But when I update the date is coming up as below

  SQL > update ced.cpp_Master set Ent_date = to_date (' 1 March 01', ' dd-mon-YYYY "") where ent_id = '6030902';
  SQL > commit;

  Tried under updates so

  (

  Update ced.cpp_Master set Ent_date = ' March 1 01' where ent_id = '6030902';

  Update ced.cpp_Master set Ent_date = to_char (' 1 March 01', ' dd-mon-YYYY "") where ent_id = '6030902';

  )

  Whenever the output below always. (Insert has no problem, just update a problem)

  I wonder why when there is an insertion of the date value is "01/01/01" in (Cpp_Master_Audit), but when I update the date value is "01/01/2001" ".

  I need the value to insert as "01/01/01", as all that was updated in Master table (Cpp_Master)

  SQL > SELECT * FROM CED.cpp_Master;

  6030902 01/01/2001

  
  
  My request to trigger:
  
  CREATE OR REPLACE TRIGGER CDS. CPP_AUDT
  AFTER INSERT OR UPDATE OR DELETE
  ON CED.cpp_Master REFERENCING OLD AS OLD AGAIN AS NEW
  FOR EACH LINE
  DECLARE
  l_action_code VARCHAR2 (1);
  BEGIN

  IF THE INSERTION
  THEN
  l_action_code: = 'I ';
  ELSIF UPDATE
  THEN
  l_action_code: = 'U ';
  ON THE OTHER
  l_action_code: = ';
  END IF;

  IF (l_action_code = 'I'
  OR l_action_code = '
  OR (l_action_code = 'U'
  AND (NVL (: OLD.)) ENT_ID, 0) NVL <>(: NEW.) ENT_ID, 0)
  OR NVL (TO_CHAR (: OLD.)) Ent_date, ' mm/dd/yyyy'),
  'X') <>
  NVL (TO_CHAR (: NEW.)) Ent_date, ' mm/dd/yyyy'),
  « X »)
  )))
  THEN
  INSERT IN DEC. () Cpp_Master_Audit
  ENT_ID, Ent_date, Insert_type
  )
  VALUES (DECODE (: OLD.ent_id, NULL,: NEW.ent_id,: OLD.ent_id),)
  DECODE (l_action_code, 'I',: NEW.) Ent_date, 'd', NULL, 'U', DECODE (: NEW.) Ent_date,: OLD. Ent_date, NULL,: NEW. Ent_date)),
  Insert_type l_action_code);

  END IF;
  END;
  /

  You wrote that ent_date is of type DATE

  SQL > cpp_Master Desc;

  Number of Ent_id

  Date of Ent_date

  so DO NOT fill with a chain, but with a date, and you have correct data in it.

  This:

  Update ced.cpp_Master set Ent_date = 1 March 01 ' where ent_id = '6030902';

  is simply wrong that fill you your column DATE with a string and your NUMBER column with a string filter too.
  

  
  

  Use

  Update ced.cpp_Master

  Set Ent_date = TO_DATE('01-MAR-0001','DD-MON-YYYY') where ent_id = 6030902;

  and you will have no problems (as long as the NLS_DATE_LANGUAGE parameter is set correctly to support abbreviations English months)

  HTH
  

• I need help for my printer/scanner/copier to work with my computer

  I have a problem for my computer to connect with my printer/scanner/copier.  I need help!

  Hi GraceEverts,

  ·         What exactly happens when you try to connect printer/scanner/copier to work with my computer?

  ·         You receive an error message?

  ·         What is the brand and model of the printer/scanner/copier?

  I suggest to check the following items and check if it helps.

  To add a printer attached to your computer

  http://www.Microsoft.com/resources/documentation/Windows/XP/all/proddocs/en-us/sag_setup_indirect_printer.mspx?mfr=true

   

  To install new or updated printer drivers to update

  http://www.Microsoft.com/resources/documentation/Windows/XP/all/proddocs/en-us/print_drivers_install_updatew.mspx?mfr=true

   

  Resources for the resolution of the printer in Windows XP problems

  http://support.Microsoft.com/kb/308028

   

  Printer in Windows problems

  http://Windows.Microsoft.com/en-us/Windows/help/printer-problems-in-Windows

   

  To install a scanner or digital camera

  http://www.Microsoft.com/resources/documentation/Windows/XP/all/proddocs/en-us/scanner_camera_add.mspx?mfr=true

  Hope this information helps.

• I need help for Windows Vista black screen during the connection, even with the login screen removed

  Hey, I have a problem in Windows Vista:

  I've been updating / updated my graphics card and it is the graphics card, I'm updating, after a while, a black screen will appear (PITCH BLACK) and I there is no cursor and I tried Ctrl + Alt + Delete, but nothing seems to work, after I turned off my laptop, starts to load then it was the new dark night! (NO LOGIN SCREEN). Then I turned off my laptop then I constantly pressed f8, then I pressed "Computer repair" then it loads then my screen showed "Another user", then I clicked it then I had to type my ID but I have no details of connection, I pressed on enter with no connection details, but this still does not work because I had to type in my login information. I tried everything, then I went to safe mode and fact a password and changed my admin account type, then I rebooted my laptop, then I have constantly pressed f8 and pressed "Computer repair" then it loads and then my screen showed 'Another user' again... .
  
  PLEASE I NEED HELP! I WANT TO PLAY MY GAMES!

  Hello

  Follow the steps below:

   

  Method 1: Do the Startup Repair to fix the problem.

  See the following article for more information on the Startup Repair:

  Startup Repair: frequently asked questions

  http://Windows.Microsoft.com/en-us/Windows-Vista/startup-repair-frequently-asked-questions

   

  Method 2: Use the Bootrec.exe tool in the Windows recovery environment to troubleshoot and repair startup issues in Windows

  For instructions, see the following article:

  How to use the Bootrec.exe tool in the Windows recovery environment to troubleshoot and repair startup issues in Windows

  http://support.Microsoft.com/kb/927392

  Let us know if that helps.