partitioned for large logs table

Similar Questions

• Look for the partition for the fact table

  Oracle version: Oracle 10.2
  
  I have a table of facts with daily partitions.
  I'm insertion of test data in this table for the old date 20100101.
  
  I am able to insert that record into this table as below
  insert into fact_table values (20100101,123,456);
  
  However I noticed that the partition for this date does not exist in the table (all_tab_partitions) more I'm not able to select the data using
  
  Select * from facT_table partition (d_20100101)
  
  but I am able to extract the data using
  
  Select * from facT_table where date_id = 20100101
  
  could you get it some please let me know how to find the partition in which these data could be inserted
  and if the partition date 20100101 is not present so why put so that the date doesn't work?

  user507531 wrote:
  However I noticed that the partition for this date does not exist in the table (all_tab_partitions) more I'm not able to select the data using

  Select * from facT_table partition (d_20100101)

  Wrong approach.

  but I am able to extract the data using

  Select * from facT_table where date_id = 20100101

  Correct approach.

  could you get it some please let me know how to find the partition in which these data could be inserted
  and if the partition date 20100101 is not present so why put so that the date doesn't work?

  Who says that the date is invalid. ? It is a partition of the range - which means that each partition covers a range. And if you bothered to read in the SQL Reference Guide on how the definition of a partition of the range, you will notice that each partition is defined with the value end of the range it covers. There is no starting value - as the end of the previous partition is the "+ border +" between this and the previous partition.

  I suggest that before you use a database feature first become familiar you with it. Another evil to use and making assumptions wrong about it, more than likely outcomes.

• How to use partitioning for large table

  Hello
  
  ******************
  Oracle 10 g 2/Redhat4
  RAC database
  ASM
  *******************
  
  I have a TRACE table that will also grow very fast, in fact, I 15,000,000 lines.
  
  TRACES (IDENTIFICATION NUMBER,
  NUMBER OF COUNTRY_NUM
  Timestampe NUMBER,
  MESSAGE VARCHAR2 (300),
  type_of_action varchar (20),
  CREATED_TIME DATE,
  DATE OF UPDATE_DATE)
  
  Querys who asked for this table are and make a lot of discs!
  
  --------------------------------------------------------
  Select count (*) as y0_
  TRACES this_
  where this_. COUNTRY_NUM =: 1
  and this_. TIMESTAMP between: 2 and: 3
  and lower (this_. This MESSAGE) as: 4;
  ---------------------------------------------------------
  SELECT *.
  FROM (SELECT this_.id,
  this_. TIMESTAMP
  Traces this_
  WHERE this_. COUNTRY_NUM =: 1
  AND this_. TIMESTAMP BETWEEN: 2 AND: 3
  AND this_.type_of_action =: 4
  AND LOWER (this_. MESSAGE) AS: 5
  ORDER BY this_. TIMESTAMP DESC)
  WHERE ROWNUM < =: 6;
  -----------------------------------------------------------
  
  I have 16 distinct COUNTRY_NUM in the table and the TIMESTAMPE is a number that the application is inserted into the table.
  
  My question is the best solution to resolve this table is to use partitioninig for a smal parts?
  I have need of a partitioning using a list by date (YEAR/month) and COUNTRY_NUM, is there a better way for her?
  
  NB: for an example of TRACES in my test database
  
  1 Select COUNTR_NUM, count (*) traces
  Group 2 by COUNTR_NUM
  3 * order by COUNTR_NUM
  SQL > /.
  
  COUNTR_NUM COUNT (*)
  
  194716 1
  3 1796581
  4 1429393
  5 1536092
  6 151820
  7 148431
  8 76452
  9 91456
  10 91044
  11 186370
  13 76
  15 29317
  16 33470

  Hello

  Yes and part is that you can remove the whole score once you don't need "of them. I think you should be good to go. Let me know if you have any other questions.

  Concerning

• Find the right Partition for swap Partiton when there are PARTITION and SUBPARTITION

  Hi all

  I have a small problem:

  I want to find the right cause of partitions of the partition key.  I have a partition and a Subpartition (sample - table in annex).

  I leave the database to generate the partition (and name), the name is generated. I need to find for the exchange of partition

  the right of Partition has cause of a given value of the partition key (in this case EVOD_PART_DATE and 20141101 value).

  When I try to find the right partiton name, I would use generally not:

  SELECT DISTINCT dbms_rowid.rowid_object(ROWID) data_object_id
     FROM F_CONTRACT_EVENT
     WHERE  EVOD_PART_DATE = TO_DATE ('20141101','YYYYMMDD')
  

  Okay, I get 2 rows, I'm expecting one, but cause the result are the subpartions, I get this:

    SELECT *  FROM ALL_OBJECTS WHERE DATA_OBJECT_ID IN ( 155159,155154);
  

  I see:

  EVO_DM    F_CONTRACT_EVENT    SYS_SUBP4292    155159    155159    TABLE SUBPARTITION
  EVO_DM    F_CONTRACT_EVENT    SYS_SUBP4287    155154    155154    TABLE SUBPARTITION
  

  But I don't want the subparts, I want the PARTITON!

  The table:

  CREATE TABLE "EVO_DM"."A0_F_CONTRACT_EVENT" 
     ( "EVOD_DDATE_ID_VALID_FROM" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDATE_ID_VALID_TO" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DTIME_ID_START" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DSUST_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCHAN_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DARTI_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCAMP_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DUSAG_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOPSY_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDEVI_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DSHOP_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DPLFO_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DACCO_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDECL_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOBJT_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOFFR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCNTR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCURR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCONT_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DIVWC_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "DD_SUBSCRIPTION_ID" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "SINGLE_ISSUE" NUMBER(8,0) DEFAULT 0, 
      "SUBSCRIPTION" NUMBER(8,0) DEFAULT 0, 
      "RENEWAL" NUMBER(8,0) DEFAULT 0, 
      "CONVERSION" NUMBER(8,0) DEFAULT 0, 
      "DOWNLOAD" NUMBER(8,0) DEFAULT 0, 
      "UPDATES" NUMBER(8,0) DEFAULT 0, 
      "NET_VALUE_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "GROSS_VALUE_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "COMMISSION_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "TAX_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "POSITION_NR" NUMBER(3,0) DEFAULT -1, 
      "DD_ORDER_NR" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "EVOD_SOURCE_CD" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "FLAG_STOCK_RELEVANT" NUMBER(1,0) DEFAULT '0' NOT NULL ENABLE, 
      "RENEWAL_NR" NUMBER(3,0) DEFAULT -1, 
      "EVOD_DDATE_ID_SUBSCRIPTION" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DPRCG_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
    
     EVOD_PART_DATE DATE  GENERATED ALWAYS AS ( TRUNC(TO_DATE(TO_CHAR(EVOD_DDATE_ID_VALID_FROM),'YYYYMMDD'),'MM')) VIRTUAL)
  PARTITION BY RANGE(EVOD_PART_DATE)
  interval(NUMTOYMINTERVAL (1,'MONTH'))
  SUBPARTITION BY LIST(EVOD_SOURCE_CD)
  SUBPARTITION TEMPLATE(
  SUBPARTITION "P_ITUNES"  VALUES ('ITUNES') ,
  SUBPARTITION    "P_WSP"  VALUES ('WSP'),
  SUBPARTITION   "P_GOOGLE"  VALUES ('PLAYSTORE'),
  SUBPARTITION   "P_DEFAULT"  VALUES ('~') ,
  SUBPARTITION   "P_AMAZON"  VALUES ('AMAZON_EREADER', 'AMAZON_MANUELL', 'AMAZON_TABLET') ,
  SUBPARTITION    "P_MSD"  VALUES ('MSD')
  )
  (
   PARTITION P01 VALUES LESS THAN (TO_DATE('200310','YYYYMM')) SEGMENT CREATION DEFERRED
  )
  PARALLEL 10  ;
  

  Any ideas?

  Thanks for Berlin

  First of all - the DOF you posted is INVALID - you do not specify a delayed segment creation for partitions. Specify you for the table.

  Also, you must remove the DEFAULT value - 1 for the partitioning column. The value '-1' cannot be converted to a valid date for the virtual partitioning column value.» The default value is useless and will give confusion around the year exception err when the exception should actually provide a NULL value for a column not null.

  The documentation explains how to use the EXCHANGE PARTITION and has the code example

  Maintenance of Partitions

  Exchange a Partition of a partitioned Table interval

  You can exchange of range partitions in a partitioned table interval. However, you must make sure that the partition of the interval was created before that you can swap partition. You can leave the database create the partition in the partition of the interval of locking.

  The following example shows an Exchange partition for the interval_sales table, range-partitioned using the monthly from partitions of 1 January 2004. This example shows how to add data to the table using charge Exchange partition for June 2007. Assume there is only a local index on the interval_sales table and equivalent index have been created on the interval_sales_june_2007 table.

  LOCK TABLE interval_sales  PARTITION FOR (TO_DATE('01-JUN-2007','dd-MON-yyyy'))  IN SHARE MODE;    ALTER TABLE interval_sales  EXCHANGE PARTITION FOR (TO_DATE('01-JUN-2007','dd-MON-yyyy'))  WITH TABLE interval_sales_jun_2007  INCLUDING INDEXES;
  

  Note the use of the FOR syntax to identify a partition that has been generated by the system. The name of the partition can be used by querying the *_TAB_PARTITIONS view of data dictionary to find the partition system-generated name.

  Given that the last paragraph? That's what showed Solomon.

  NOTE:-special attention to the FIRST paragraph. If you use segment carried OVER creating the partition you want to Exchange could NOT have been created yet.

  Make SURE that you lock the partition as the example shows, or you will get an exception if it has not been created.

  Also - we know NOT what PROBLEM you're trying to solve.

  If you exchange a PARTITION of a table subpartitioned your working table should actually be partitioned using the SAME parttioning as the subparts in the source table:

  See my response in this thread:

  https://forums.Oracle.com/forums/thread.jspa?threadID=2482090&TSTART=30

  In this thread I have provide the code example illustrating how the table should be created and made Exchange.

• Request: Make these more fast screws for large tables

  Hey everybody,

  Did anyone mind take a look at these two screws? They work very well for small data sets, but they are starting to take up to 200ms each for large arrays (~ 5000 rows x 2 columns). The first actually sends data to the 2nd, so the total delay when running these screws may be 400, 500 ms. Too much to use them in real time.

  Reminder of how they are used:

  The user can click or click-and - dragging on a graph of intensity to create a card to die to test. These VI are run to update a list of that die are selected and a list of how the machine will move. In mode click - drag, these VI create a very big delay in the response of the public Service.

  First VI:

  The entrance is a 2D table 1 or 0, indicating the test or not test. The output is a 2D line (Nx2) table, column numbers should be probed.

  Second VI:

  The entrance is a table 2D (Nx2) R, C numbers (from the 1st VI). This VI calculates a relative movement of the current matrix with the following matrix. The output is a table 2D (Nx2) of the relative motions (Y, X). Example: ((2,4), (5.1)) back in ((0,0), (3, -3)).

  I've already cut the running time up to half of what it was, but it is still not fast enough. And Yes, the limits of error are not connected, I know :-)

  Screws (also attached):

  

  

  So, what do you think? Is there some Subvi I don't know which completely replaces the 1st VI? Is one of the Subvi I use inherently slow?

  
  

• Linksys WRT54GL do not connect for its "incoming log Table?

  Hello.

  Is it me or does Linksys WRT54GL v1.1, with its v4.30.13, no newspaper "Incoming log Table" firmware? I see nothing in http://192.168.0.1/Log_incoming.asp (Yes, I changed its default IP 192.168.1.1). However I can't get logs in his outgoing. I guess only inbound log table is logging blockades and other data.

  Thank you in advance.

  I think that there is a problem with the firmware. Read this.

• Syntax for exchanging a partition with an empty table

  Hello
  
  I have a PLP_2001FY partition and I want to share this partition with an empty table (ex: DRB_WHOLE_DATA_TEMP) structured as DRB_WHOLE_DATA (this table already exists).
  
  Thank you

  Do you mean that you want to fill the empty array with the contents of the partition?

  If so:

  insert into DRB_WHOLE_DATA_TEMP select * from DRB_WHOLE_DATA partition (plp_2001fy)
  

• Move the data from the partitions again tablespace - direct table filled by ETL

  Hello

  We have a large composite table date-range/hash partitioned table (using time partitioning 11.2.0.3 range)

  1 partition for each month and each such partition 4 under separate partitions.

  We want to move some data from most significant storage but also direct table and inserted in all the days as part of the data warehouse and large table want to ensure

  operations below result in errors in the data loading procedure

  Suppose also should not take long to run lines 40 million or more each month.

  Select *.

  Of user_tab_partitions

  Where table_name = 'CUSTOMER_TRANSACTION '.

  And nom_partition like 'SYS % '.

  1. (1) Alter table retailer_transaction and rename partition < nom_partition > CUST_PART_ < YYYYMM >
  1. (2) tablespace create dedicated for the month of the affected partition
  1. ((3) alter table retailer_transaction move tablespace subpartition < sys... > < partition_tablespace > created in 2) above

  ALTER table retailer_transaction change the default attributes for the partition < CUST_PART < YYYYMM > < tablespace in 2 above > tablespace)

  4 global index which would eventually rebuild afterwards due to the transition if movement makes no valid.

  Several local bitmap indexes that belong to partitions.

  Thoughts?

  Thank you

  I agree in a good store of data, everything should be according to the best practices ETL or guideline. I guess it is a FACT table, because it's big enough. A method that I can share (followed in the real world big DW) is "ELP" IE Partition Exchange loading. You can find the basic architecture of the Internet.

  The basic architecture is as

  The source (in your case partitioned) Table--> (unpartitioned) intermediate Table--> Table possible target (partitioned)--> the cleaning activities (and overtime).

  You can use any ETL tool for this (I won't mention any other reasons).

  Later, you can delete the original table and use that new table as your FACT table, your application will be available all the time. There are drawbacks as most uses of double-spaced, other than normal ETL these work will take certain amount of resources so that other ALS etc. In addition, if you load a few current days during these activities you plan / program accordingly.

  Your demo is also fine, but regular ETL may fail because you rename the partitions (some uses of ETL tool partition name, in case you ever ELP) also unusable global indexes can cause failure (you have local too?).

• Calculate the elapsed time between the horodateurs log Table

  Hello

  I'm looking for some codes SQL allows to calculate the elapsed time between the timestamps in a log table.  The log table has some STOP-START operations.

  I just want to calculate the elapsed time between the START and PAUSE of Transactions, as well as START and EXECUTE transactions.

  So, in the example below, the time spent must be:

  START 09:15 break 09:20 (5 Minutes)
  START 09:30 to 09:45 (15 Minutes) FULL

  Total elapsed time for LOG_ID 1234 should be 20 minutes.  This excludes the 09:20 at 09:30 BREAK at the START time.

  LOG_ID	SEQ_NUM	LOG_TYPE_CD	CRE_DTTM
  1234	1	BEGINNING	09-15 - 2013:09:15:00
  1234	2	BREAK	09-15 - 2013:09:20:00

  1234

  3

  BEGINNING

  09-15 - 2013:09:30:00

  1234

  4

  ALL THE

  09-15 - 2013:09:45:00

  Any suggestions?

  Thanks for your time

  -DT

  Hello

  Thanks for posting the CREATE TABLE and INSERT.  be sure to post the results desired from these data.

  user13071913 wrote:

  Hi thanks for the help...

  The date is a true timestamp.  ...

  Here's a sample of CREATE TABLE and a few inserts.  3 ID transaction, each with a series of journal entries.

  CREATE TABLE 'LOG_TABLE_X '.

  (SELECT 'ID' CHAR (14 BYTES) NOT NULL,)

  ACTIVATE THE "LOG_TYPE_FLG" TANK (4 BYTES) NOT NULL,

  ALLOW "LOG_DTTM" DATE NOT NULL

  );

  ...

  I'm so confused.  Is log_dttm a TIMESTAMP, you said in the story, or is it a DATE, as you say in the CREATE TABLE statement, or is it a VARCHAR2 as Thur INSERT statements?  I'll assume it's a DATE.

  I left out an important step yesterday.  The computation of the last_start, we need to use a CASE statement so that we record only the time of events STRT.

  Here's the revised query:

  WITH got_last_start AS

  (

  SELECT id, log_type_flg, log_dttm

  LAST_VALUE (CASE

  WHEN log_type_flg = "STRT".

  THEN log_dttm

  END

  IGNORES NULL VALUES

  ) OVER (PARTITION BY id - can - be

  ORDER BY log_dttm

  ) AS last_start

  OF log_table_x

  )

  SELECT id, log_type_flg, log_dttm

  , (log_dttm - last_start) * 24 * 60 elapsed

  , SUM (log_dttm - last_start) OVER (PARTITION BY ID.

  ORDER BY log_dttm

  ) * 24 * 60 AS total_elapsed

  OF got_last_start

  WHERE log_type_flg IN ("CMPT", "PAUS")

  ORDER BY id, log_dttm

  ;

  Output of your sample data:

  ID LOG_ ELAPSED TOTAL_ELAPSED LOG_DTTM

  -------------- ---- ------------------- -------- -------------

  1111 PAUS 09-26 - 2013:09:09:58.17.17

  1111 CMPT 09-26 - 2013:10:09:58 1.00.83

  2222 CMPT 09-26 - 2013:12:09:58 180.00 180.00

  3333 CMPT 09-26 - 2013:10:09:42 59.73 59.73

  In Oracle, when you subtract one DATE from another DATE, the result is the NUMBER of days between them.  In the above query, I multiplied the past columns and total_elapsed by the number of minutes per day (24 * 60), to show the time in minutes.

• For a single table import failed...

  Hello
  On the production server, I reported a user db, let's call it PRD_USER, with tablespace PRD_TBL default.
  On the development server, I reported a user db, let's call it PRD_USER, with tablespace DEV_TBL default.
  On the production server, I use the db of exp utility to import as:
  IMP System/Manager of the user PRD_USER touser = PRD_USER = ignore = file_name = «...» ' log = «...» ».
  Succeeds the import for about 25 tables and indexes and constraints, but it fails for a single table with the error: {I don't remember the error ORA- and I do not have access currently} DEV_TBL tablespace does not exist.
  
  Of course this tablespace does not exist on production env. But how this problem arises because the default tablespace for the user is not DEV_TBL but PRD_TBL...?
  
  Do you have any idea what can be the cause and how can I overcome this problem when importing...? {Note: I gave a temporary solution... take the table creation sql script leaving aside the reference of the tablespace "DEV_TBL"}.
  
  The two servers work in exactly the same version of DB...
  Note: I use DB 10g v.2
  
  Thank you
  SIM

  If the table has Partitions, import strives to create the Partitions (in the CREATE TABLE statement) on the original table space.

  OR there is a LOB segment in the table import strives to create on the original table space.

  Hemant K Collette

• I just installed a new 320G hard drive. I partitioned for OS 4G. Now it says I have no more space, because it is using the partition of 4 GB for everything instead of just the operating system. Please help and advise what should I do and how to do it. Tha

  Dell Dimension 2400 with XP.

  mjcandlec1,
  Welcome to the forums.  Firstly (and this is just my personal opinion) you can actually have a bit more large partition for the operating system.  Just to receive the updates and service packs and other.

  This article will show you how to change the default location of My Documents.  Also when you install programs then ensure you that you change the default installation directory, it will try to go on the C: drive.

  Mike - Engineer Support Microsoft Answers
  Visit our Microsoft answers feedback Forum and let us know what you think.

• I upgraded from vista ultimate to windows 7 64 - error message 0 x 80070490 windows can not find partition for temporary files

  I upgraded from vista ultimate to windows 7 64 - error message 0 x 80070490 windows can't find partition for temporary files - I have a lot of space and created a partition of 1 GB

  Hello

  Thanks for the reply.

  I suggest you to follow a few troubleshooting steps more and check if this helps you fix the problem on your computer.

  Method:

  Reset permissions
  ============

  1 if please download the subinacl.msi from the following link and save the patch to installation on the desktop:

  http://www.Microsoft.com/downloads/details.aspx?FamilyId=e8ba3e56-d8fe-4A91-93Cf-ed6985e3927b&displaylang=en#AffinityDownloads

  2. go to your desktop and double-click on the downloaded file.
  3. Please select the C:\Windows\System32 folder as the Destination folder during installation. Later, we will use this tool to reset the permissions on the current computer settings.

  4. click on the button 'Start' in the 'Search' bar type: "Notepad" (without the quotes) and press ENTER.
  5. copy the following commands, and then paste them into the opened Notepad window:

  off @echo

  Subinacl /subkeyreg HKEY_LOCAL_MACHINE/Grant = administrators = f
  Subinacl /subkeyreg HKEY_CURRENT_USER/Grant = administrators = f
  Subinacl /subkeyreg HKEY_CLASSES_ROOT/Grant = administrators = f
  Subinacl % lecteur_systeme % /subdirectories / Grant = administrators = f

  Subinacl /subkeyreg HKEY_LOCAL_MACHINE/Grant = system = f
  Subinacl /subkeyreg HKEY_CURRENT_USER/Grant = system = f
  Subinacl /subkeyreg HKEY_CLASSES_ROOT/Grant = system = f
  Subinacl % lecteur_systeme % /subdirectories / Grant = system = f

  @Echo =========================
  Completed @Echo.
  @Echo =========================
  @pause

  6. After you paste the above commands, please close the Notepad window. Choose "Save" when you are prompted to save the file. Type "reset.bat" as the file name and choose "Desktop" in the Panel on the left as the save location.

  7. refer to the desktop and right click the reset.bat file, then choose "Run as Administrator".
  8. you will see a window of type BACK treatment.

  NOTE: It may take several minutes, please be patient. When it is finished, you will be prompted with the message: "finished, press any key to continue."

  If the same thing happens, move to the next step.

  Run the upgrade by using the built-in Administrator

  ================================

  1. click the button start-> all programs-> Accessories.

  2. right click on command prompt and select "run as Administrator".

  3. click on continue when user account control window appears.

  4 copy the following command and press ENTER:

  NET user administrator / Active: Yes

  5 restart the computer and then log on the computer of this administrator account.

  6. run the upgrade to windows 7.

  Hope this information helps you.

• Partitioning of an existing Table using the EXCHANGE PARTITION

  Hi all

  I have one unpartitioned table I partitioned by Exchange, this table has several indexes and constraints (primary and foreign).

  ALTER TABLE notpart_table ADD (
      CONSTRAINT PK_KCESPITI PRIMARY KEY (K_CESP, TIPORD)
          USING INDEX TABLESPACE TBLS_CONTA,
      CONSTRAINT FK_KCONTO_CE FOREIGN KEY (K_CONTO) REFERENCES xxxx (K_CONTO));
  
  CREATE INDEX IX_NFATTURA_CE ON notpart_tab (ANNO_FATTURA, K_REGISTRO, K_REGFA, TIPORD)
      TABLESPACE TBLS_CONTA;
  
  
  
  
  

  after Create a partitioned Table Destination

  notpart_table2, I created the same constraints and indexes defined in notpart_table

  
  

  When I run

  
  

  ALTER TABLE notpart_table2
    EXCHANGE PARTITION PART_notpart_table2
    WITH TABLE notpart_table
    WITHOUT VALIDATION
    UPDATE GLOBAL INDEXES;
  
  
  
  

  I get: ora-02266

  Why?

  Thanks in advance for any help

  
  

  Post edited by: vigilant Rosario

  It is not exactly what you have. Very probably not partitioned table, you are partitioning is the parent to another table table:

  SQL > create table tbl1 (id number)
  2.

  Table created.

  SQL > alter table tbl1
  2 Add the constraint tbl1_pk
  3 primary key
  4.

  Modified table.

  SQL > create table tbl2 (id number)
  2.

  Table created.

  SQL > alter table tbl2
  2 Add the constraint tbl1_fk1
  3 foreign key
  4 references tbl1
  5.

  Modified table.

  SQL > insert into tbl1 values (1)
  2.

  1 line of creation.

  SQL > insert into tbl2 values (1)
  2.

  1 line of creation.

  SQL > create table tbl1_part (id number)
  2 partition by range (id)
  3 (partition p1 values less than (1000000))
  4.

  Table created.

  SQL >
  SQL > alter table tbl1_part
  Exchange 2 partition p1
  3 with table tbl1
  4 without validation
  5 update global indexes
  6.
  with table tbl1
  *
  ERROR at line 3:
  ORA-02266: permit to unique/primary keys in table referenced by foreign keys

  SQL >

  If so, of the foreign key and recreate it pointing to the partitioned table as parent after finished partitioning the table.

  SY.

• How add us partition on an existing table?

  Hi gurus,

  What would be the best way to add a partition to an existing table?

  Is there a simple documentation for example?

  Thank you

  What would be the best way to add a partition to an existing table?

  Is there a simple documentation for example?

  Was it something you were ask in an interview?

  You cannot add a partition to a table unless this table is a partitioned table.

  The table is already partitioned? If so, after the DDL.

  The Oracle documentation has examples of adding partitions to a table that is already partitioned

  Partition management

  Adding Partitions

  This section explains how to manually add partitions of a partitioned table and explains why partitions can be added specifically for partitioned more indexes.

  Adding a Partition to a partitioned Table range

  Use of the ALTER TABLE ... ADD PARTITION statement to add a new partition at the end 'high' (the point after the last existing partition). To add a partition at the beginning or in the middle of a table, use the SPLIT PARTITION clause.

• Cannot add the partition to an existing table.

  Hello

  I don't add the partition to an existing table that is not partitioned, get the error as a type of data not valid, then I'm not find syntax errors.

  ALTER TABLE MESSAGEX_XCHANGE

  ADD THE PARTITION OF RANGE (LAST_MODIFY_TIMESTAMP)

  (

  PARTITION old_data VALUES LESS THAN (To_TIMESTAMP('27/02/2014','DD/MM/YYYY')),

  You see for VALUES LESS THAN (To_TIMESTAMP('28/02/2014','DD/MM/YYYY')) of the PARTITION

  );

  Error report:

  SQL error: ORA-00902: invalid data type

  1. 00000 - "invalid data type".

  * Cause:

  * Action:

  Thank you

  Manon...

  You get this error because your edit statement has an invalid syntax. In addition, you cannot partition a table that is not already configured for partitioning!

  You have to physically re-create the partitioned table in order to add new partitions to it.