Pencil on C6 erases the previous lines

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  Hello

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  Good afternoon

  I have the following problem:

  I have an IR on a table that contains the values of daily clock of energy (gas and electricity).

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  Baerenmarke wrote:

  I have the following problem:

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  Now, I want to set up a calculated column that contains the daily consumption.
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• incremensum under condition (condition is the value of the sum of the previous line)

  Hello
  I know that is a little tricky but I need to know the credit of a client after each invoice.
  so if sum(invoice_val-previous_credit) > 0, then the credit is 0 credit else is previous_credit-invoice_val.
  As you can see to dermine the credit value of the current row, it is necessary to check the value of the previous row. Is it possible to somehow?
  
  E.G.
  If the situation in the table is the following:

  ID_CLIENT     ID_invoice     invoice_VAL
  8.789     220.227     120,47
  8.789     238.342     109,76
  8.789     246.388     121,69
  8.789     258.163     137,45
  8.789     268.969     138,67
  8.789     295.455     145,16
  8.789     311.395     138,92
  8.789     327.104     138,96
  8.789     340.793     -335,18
  8.789     375.451     129,14
  8.789     386.650     125,57
  8.789     398.606     124,18
  8.789     428.166     31,66
  8.789     435.844     25,93
  8.789     447.639     34,32
  8.789     462.137     -43,64
  8.789     475.613     -110,39
  8.789     485.022     92,29
  8.789     495.807     91,67

  I need something like this:

  ID_CLIENT     ID_invoice     invoice_VAL credit
  8.789     220.227     120,47     0,00
  8.789     238.342     109,76     0,00
  8.789     246.388     121,69     0,00
  8.789     258.163     137,45     0,00
  8.789     268.969     138,67     0,00
  8.789     295.455     145,16     0,00
  8.789     311.395     138,92     0,00
  8.789     327.104     138,96     0,00
  8.789     340.793     -335,18     335,18
  8.789     375.451     129,14     206,04
  8.789     386.650     125,57     80,47
  8.789     398.606     124,18     0,00
  8.789     428.166     31,66     0,00
  8.789     435.844     25,93     0,00
  8.789     447.639     34,32     0,00
  8.789     462.137     -43,64     43,64
  8.789     475.613     -110,39     154,03
  8.789     485.022     92,29     61,74
  8.789     495.807     91,67     0,00

  Thank you very much
  
  Published by: 4ndr34 on January 28, 2010 13:38

  Hello

  4ndr34 wrote:
  Thanks, but the model is not available in oracle9 :(

  Are - that you mentioned before?
  It's a good idea to include your version number whenever you ask a question, especially if the version is as old as Oracle 9.

  Here's an analytical solution that must work at Oracle 9 (and more):

  WITH     e     AS
  (
       SELECT     hiredate
       ,     CASE
                 WHEN  job     IN ('PRESIDENT', 'SALESMAN')
                 THEN  -sal
                 ELSE  sal
            END     AS sal2
       ,     ROW_NUMBER () OVER ( ORDER BY  hiredate
                                 ,            empno
                         ) AS rnum
       FROM     scott.emp
  )
  ,     got_grp_start     AS
  (
       SELECT     h.*
       ,     CASE
                 WHEN  sal2 >= 0
                 THEN  0
                 WHEN  EXISTS ( SELECT    NULL
                                   FROM      e   l
                             JOIN      e   m     ON     m.rnum     >= l.rnum
                             WHERE     l.rnum     < h.rnum + 0     -- See note below
                             AND      m.rnum     < h.rnum + 0     -- See note below
                             GROUP BY      l.rnum
                             HAVING      SUM (m.sal2) < 0
                           )
                 THEN  0
                 ELSE  1
            END          AS grp_start
       FROM     e     h
  )
  ,     got_grp          AS
  (
       SELECT     got_grp_start.*
       ,     SUM (grp_start) OVER (ORDER BY rnum)     AS grp
       FROM     got_grp_start
  )
  SELECT     hiredate
  ,     sal2
  ,     GREATEST ( SUM (-sal2) OVER ( PARTITION BY  grp
                                          ORDER BY         rnum
                          )
             , 0
             )     AS credit
  FROM     got_grp
  ORDER BY     rnum
  ;
  

  The EXISTS subquery in got_grp_start does not work (at least in Oracle 10.2.0.3.0 or 11.1.0.6.0) if it refers to "h.rnum", but it does if it refers to "h.rnum + 0" or "h.rnum - 0". ".

  The sole purpose of subquery e is to produce a useful set of raw data, including a simple expression (rnum) that can be used in sorting. You probably have something like e, according to your actual table.

  If you need a separate calculation for, say, all the departments, and then add PARTITION BY analytical clauses.

• Sum of value in the previous lines?

  Hello!
  
  I have a result of an sql statement that looks like
  
  Value of type date
  01.04.2009 00:00:00 0
  01.04.2009 00:00:00 3
  01.04.2009 00:00:00 3
  01.04.2009 00:00:00 4
  01.04.2009 00:00:00 3
  01.04.2009 00:00:00 3
  01.04.2009 00:00:00 3
  01.04.2009 00:00:00 3
  
  What I'm trying to do is a new column add_months (Date, sum ((Value) of the real line as well all the lines above the actual line). So the result should look like
  
  Result date V
  01.04.2009 00:00:00 0 01.04.2009 added 0 months
  01.04.2009 00:00:00 3 01.07.2009 added 0 + 3 months
  01.04.2009 00:00:00 3 01.10.2009 added 0 + 3 + 3 months
  01.04.2009 00:00:00 4 01.02.2010 added 0 + 3 + 3 + 4 months
  01.04.2009 00:00:00 3 01.05.2010 added 0 + 3 + 3 + 4 + 3 months
  01.04.2009 00:00:00 3 01.08.2010 and so on
  01.04.2009 00:00:00 3 01.11.2010
  01.04.2009 00:00:00 3 01.02.2011
  
  I can only use pure sql and it should work on 10g.
  
  Thanks for any help
  ----
  Carsten

   DT                       VALUE RES               ***
  

  Have you written naughty? ;-)

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  Hello

  I'm doing two XY plots in a chart, but the data are not generated at the same time, how can I add a new path in the same XY graph without losing the earlier.

  I enclose my code to show you my problem...

  See attached file that can demonstrate.

  When your parcels have the same number of points then by default values (0) will be added to the plot which is having less number of points. you could write code that adds NaN values to the shorter table.

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  Hello

  The attached screenshot is a test results multi line string. Each line of the chain consists of a date, time and numbers representing results.

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• How to make a graphic inside a while loop to maintain the previous values

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