Pivot problem

Similar Questions

• On the use of PIVOT problem

  Hi all.

  I use of Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 and the following query:

  SELECT *.

  Of

  (SELECT code_combination_id, period_name, nvl (sum (begin_balance_dr + period_net_dr - begin_balance_cr - period_net_cr), 0))

  OF gl_balances

  ) PIVOT (nvl (sum (gb.begin_balance_dr + gb.period_net_dr - gb.begin_balance_cr - gb.period_net_cr), 0))

  I always get the error "Missing key word".

  Can someone please give me a hand on this?

  Octavio

  Hello

  because your statement is not complete, missing the PIVOT 'FOR' clause.

  that is to say:

  Select * from)

  Select times_purchased, state_code

  customers t

  )

  Pivot

  (

  Count (state_code)

  for state_code ("NY", "CT", "NJ", "FL", "MO")

  )

  order of times_purchased

  Please check: Re: 4. How can I convert rows to columns?

  and 11 g - pivot.html

  For a few examples.

  Kind regards.

  Alberto

• Oracle pivot problems

  < h3 > basically what I need is to generate a report that convert values to single column into multiple columns and aggregate data.
  All the RptDate that are < current year are lump together. Status = 0 are the filter out.
  
  My database is Oracle 9i release 9.2.0.1.0

  This is the info table
  ID      RptDate       Status  
  JMN    01-Mar-08      1
  JMN    01-Mar-08      1
  JMN    05-Jun-09      1
  JMN    14-Dec-10      1
  JMN    23-Jan-11      0
  JMN    26-Feb-11      1
  BEN    01-Mei-08      1
  BEN    01-Jul-08      1
  BEN    22-Nov-09      1
  BEN    23-Nov-09      1
  BEN    14-Dec-10      1
  BEN    23-Jan-11      1
  BEN    29-Jan-11      1
  BEN    26-Feb-11      1
  BEN    21-Mar-11      1
  KEN    07-Mei-07      1
  KEN    04-Jan-08      1
  KEN    28-Feb-08      1
  KEN    22-Nov-09      1
  KEN    23-Nov-09      1
  KEN    14-Dec-10      1
  KEN    23-Jan-11      1
  KEN    29-Jan-11      1
  KEN    26-Feb-11      1
  KEN    21-Mar-11      0
  KEN    01-Apr-11      1
  
  
  Expected output
  ID      PreviousYear  Jan  Feb  Mar  Apr  Mei  Jun  Jul  Aug  Sep  Oct  Nov  Dec  Total
  JMN     4               0    1   0    0    0   0    0    0     0     0    0    0      5
  BEN     5               2    1   1    0    0   0    0    0     0     0    0    0      9
  KEN     6               2    1   0    1    0   0    0    0     0     0    0    0     10

  This solution can give you the right EXIT, take a look...

  SELECT ID,
  Sum (case when RptDate<= trunc(sysdate,'yyyy')-1="" then="" 1="" else="" 0="" end)="" previousyear="">
  sum (case when trunc (RptDate, 'month') = trunc(sysdate,'yyyy') then 1 else 0 end) jan.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 1) then 1 else 0 end) Feb.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 2) then 1 else 0 end) mar.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 3) then 1 else 0 end) Apr.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 4) then 1 else 0 end) may,
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 5) then 1 else 0 end) June,.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 6) then 1 else 0 end) Jul.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 7) then 1 else 0 end) aug.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 8) then 1 else 0 end) Ms.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 9) then 1 else 0 end) oct.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 10) then 1 else 0 end) nov.
  sum (case when trunc (RptDate, 'month') = add_months (trunc (sysdate, 'yyyy'), 11) then 1 else 0 end) dec.
  sum (case
  When the status not ('Void', 'Pending', 'Error') then 1
  otherwise 0 end) Total
  Info
  When the status not ('Void', 'Pending', 'Error')
  Group by ID
  order by 2

  Concerning
  Rahul MRC

• Problem with pivot table

  Hello.
  
  I have a pivot table, and it should update that I change the value of selectOneChoice. I can only view some data in a PivotTable when I choose a value for the first time in selectOneChoice. If I select another value in the SelectOneChoice the PivotTable that is not updated.
  
  Here is my PivotTable:
  

   
   <dvt:pivotTable id="pivotTable1"
                              value="#{bindings.TValoresMatrizEnViewUp1.pivotTableModel}"
                              binding="#{backingBeanScope.backing_valoresMatriz.pivotTable1}"
                              contentDelivery="immediate" var="matrix"
                              visible="false" partialTriggers="::socCodigo"
                              rendered="true" 
                             >
                <dvt:dataCell>
                  <af:inputText value="#{matrix.dataValue}"
                              valueChangeListener="#{backingBeanScope.backing_valoresMatriz.alteraPivot}"
                              autoSubmit="true"
                              partialTriggers="it5"
                              id="it5"/>
                              
                </dvt:dataCell>
              </dvt:pivotTable>

  Can someone help me?
  
  My JDeveloper is 11.1.1.4.0
  
  Thank you

  Hi Marcos,

  Open your page definition and together in the iterator tag refresh properties = 'always' and cacheResults = "false"...

  That that it will solve your problem.

  Kind regards

  Renan

• OBIEE 11 g: problem view Pivot.

  Hello

  I've created a report using the pivot table view. Available to view as below

  

  my guest is the default value of the 2014 fiscal year.

  How to show the shop for current month.

  I won't show for previous months only for Jan - 15.

  Kind regards

  Srinivas.

  Month (CURRENT_DATE) returns a number, which requires the OP have a column with the number of months in the time dimension.

  And ask the OP for the previous month, but I guess that's the previous month, not based on the current date (we are in April and he refers to Jan - 15 as the previous month).

  Not knowing what the other columns are available in its dimension of time to produce the value of 'Jan-15' will be easier with the variable repository (and in this case the variable will always be correct based on the latest data loaded into the DB).

• Table PIVOT (10.2.0.4.0) problem

  Hi all!
  
  Given the following data set:
  

  CREATE TABLE unpivoted
  (
     id    NUMBER,
     typ   VARCHAR2 (30),
     val   VARCHAR2 (30)
  );
  
  INSERT INTO unpivoted VALUES (1, 'A', 'A123456');
  INSERT INTO unpivoted VALUES (1, 'B', 'B455245');
  INSERT INTO unpivoted VALUES (2, 'A', 'A835666');
  INSERT INTO unpivoted VALUES (2, 'B', 'B126832');
  INSERT INTO unpivoted VALUES (2, 'C', 'C123456');
  INSERT INTO unpivoted VALUES (3, 'C', 'C545662');
  INSERT INTO unpivoted VALUES (3, 'D', 'D525254');
  INSERT INTO unpivoted VALUES (3, 'E', 'E636656');

  Using only SQL and avoiding scalar subqueries, how can I get the data to display as well?
  

  ID    A        B        C        D        E
  ===== ======== ======== ======== ======== =======
  1     A123456  B455245  <NULL>   <NULL>   <NULL>
  2     A835666  B126832  C123456  <NULL>   <NULL>     
  3     <NULL>   <NULL>   C545662  D525254  E636656

  I understand that it probably involves some kind of operation of pivot, but I'm just not smart enough to apply the examples I've seen elsewhere in my data!
  
  Thank you very much!

  Hello

  Welcome to the forum!

  In any version (Oracle 8.1 or higher) you can do this way:

  SELECT       id
  ,       MIN (CASE WHEN typ = 'A' THEN val END)   AS a
  ,       MIN (CASE WHEN typ = 'B' THEN val END)   AS b
  ,       MIN (CASE WHEN typ = 'C' THEN val END)   AS c
  ,       MIN (CASE WHEN typ = 'D' THEN val END)   AS d
  ,       MIN (CASE WHEN typ = 'E' THEN val END)   AS e
  FROM       unpivoted
  GROUP BY  id
  ORDER BY  id
  ;
  

  Many examples you saw maybe used to COUNT or SUM instead of MIN. You can use a function of aggregation with this technique.

  For more info on pivots, see the FAQ forum {message identifier: = 9360005}

  Thanks for posting the CREATE TABLE and INSERT statements; It's really useful!

• Problem with the conditional formatting according to pivot

  Hi all
  
  OBIEE version 10.1.3.3.3
  I have a measurement with the following condition column
  
  Measure:
  -Case when DATE < VALUEOF ("CC_DATE") and the actual amount of another amount, then end
  
  Here CC_DATE is variable repository
  
  I created a column duplicated by the following condition
  
  Double column:
  BOX WHEN Date < VALUEOF("CC_DATE") then end if 0-1
  
  And try to use duplicate column in a measure of conditional formatting, however I do not succeed
  
  any suggestion to solve this problem?
  
  
  Thank you
  SMA

  SMA,

  Check the link below if you want to put in shape measures based on the intersection of the dimension. A variant of the above link.
  http://www.obinotes.com/2010/10/format-cellmeasure-value-based-on-row.html

  J
  -bifacts
  http://www.obinotes.com

• Pivot query problem

  All (running 11.2 OEL on 5),
  I'm fighting figuring how to get the result I want to with the following data:
  

  CREATE TABLE REGION_LOOKUP 
     (     REGION_ID NUMBER NOT NULL ENABLE, 
       REGION VARCHAR2(5) NOT NULL ENABLE, 
       PRIMARY KEY ("REGION_ID") ENABLE
     )
  / 
  CREATE TABLE IND_REVENUE 
     (     ID NUMBER, 
       IND_REV_DATE VARCHAR2(30), 
       IND_REVENUE NUMBER, 
       REGION_ID NUMBER, 
       CONSTRAINT IND_REVENUE_PK PRIMARY KEY (ID) ENABLE
     )
  /
  INSERT INTO REGION_LOOKUP (REGION_ID, REGION VALUES(1,'EMEA');
  INSERT INTO REGION_LOOKUP (REGION_ID, REGION VALUES(2,'LAD');
  INSERT INTO REGION_LOOKUP (REGION_ID, REGION VALUES(3,'APAC');
  INSERT INTO REGION_LOOKUP (REGION_ID, REGION VALUES(4,'NAS');
  INSERT INTO REGION_LOOKUP (REGION_ID, REGION VALUES(5,'JAPAN');
  /
  INSERT INTO IND_REVENUE VALUES(1,'10-Jun',73.10,4);
  INSERT INTO IND_REVENUE VALUES(2,'10-Jul',49.30,4);
  INSERT INTO IND_REVENUE VALUES(3,'10-Jun',3.20,2);
  INSERT INTO IND_REVENUE VALUES(4,'10-Jul',0.30,2);
  INSERT INTO IND_REVENUE VALUES(5,'10-Jun',28.60,3);
  INSERT INTO IND_REVENUE VALUES(6,'10-Jul',12.40,3);
  INSERT INTO IND_REVENUE VALUES(7,'10-Jun',64.00,1);
  INSERT INTO IND_REVENUE VALUES(8,'10-Jul',19.80,1);
  INSERT INTO IND_REVENUE VALUES(9,'10-Jun',6.60,5);
  INSERT INTO IND_REVENUE VALUES(10,'10-Jul',4.70,5);
  /

  Here's what I would get. The column date 10 - Jun 10 - Jul is 'dynamic', and there will be a new column each month.
  

  Region     10-Jun     10-Jul      Total
  APAC      $28.6     $12.4      $41.0
  EMEA      $64.0     $19.8      $83.8     
  JAPAN       $6.6      $4.7      $11.3
  LAD       $3.2      $0.3       $3.5
  NAS      $73.1     $49.3     $122.4
  Total     $175.5     $86.5     $262.0

  I think something like that (I'm stuck) but of course, this does not at all and is also hardcoded regarding columns.
  

  select rn, 10-Jun, 10-Jul, (10-Jun + 10-Jul) as Total from
  (select      RL.REGION_NAME as rn, RL.REGION as re, IR.IND_REVENUE as rev
   from      REGION_LOOKUP RL,
        IND_REVENUE IR where IR.region_id = RN.region_id)
  pivot (SUM(rev) for rn in
  ('10-Jun' as 10-Jun,
  '10-Jul' as 10-Jul))

  All great ideas?
  
  See you soon,.
  Andy
  
  Fixed the instructions insert, sorry about that. Copy and paste before the coffee is not good.

  Hi, Andy.

  A Tael says:
  A nice solution,

  Thanks, but what solution do you mean? There were at least 4 different solutions on this page.

  but is there a way to avoid the queue to a file?

  Do you mean the dynamic SQL solution? Yes, the coil is just a way to make the dynamic SQL statements.
  In SQL * more you can write the variable part of the query to a substitution variable (see below).
  In PL/SQL, you can assemble a select in VARCHAR2 variable.

  PROMPT     ==========  2. Dynamic Pivot using Substitution Variable  ==========
  
  --     *****  Preliminary Query:  *****
  
  COLUMN     sql_txt_col     NEW_VALUE     sql_txt
  
  WITH     all_jobs     AS
  (
       SELECT DISTINCT
            job
       ,     DENSE_RANK () OVER (ORDER BY job)     AS r_num
       FROM     scott.emp
  )
  SELECT     SYS_CONNECT_BY_PATH ( job || '''     THEN 1 END) AS '
                        || job
                        || '_CNT'
                        || CHR (10)               -- Newline, for legibility only
                     , ', COUNT (CASE WHEN job = '''     -- Delimiter, goes before each entry
                     )                                       AS sql_txt_col
  FROM     all_jobs
  WHERE     CONNECT_BY_ISLEAF     = 1
  START WITH     r_num = 1
  CONNECT BY     r_num = PRIOR r_num + 1
  ;
  
  --     *****  Main Query  *****
  
  SELECT     deptno
  &sql_txt     -- Ends with newline, so occupy that line
  FROM     scott.emp
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  /*
  EXPLANATION:
  
  Using a substitution variable is very similar to using a script.
  The main difference is that the output of the preliminary query has to
  go into one row.  This is done with SYS_CONNECT_BY_PATH, and getting
  that requires that the jobs be numbered with consecutive integers, 1, 2, 3, ...
  which we get from DENSE_RANK.
  
  The NEWLINE character was added just to make the output line easier
  to read during debugging.
  */
  

• Calculating pivot table problem

  Hello..
  PivotTable using separate columns for calculation... How to avoid it. ?
  
  For ex:
  
  My database of records are like
  
  region date_id___amt_
  01012009 1000 North
  01012009 1000 North
  01012009 1000 North
  01012009 1000 South
  01022009 1000 North
  01022009 1000 South
  01022009 1000 South
  
  My pivot table design is
  
  Line: region
  Measure: Amt
  Column: Date_id
  
  I get a response such as
  
  ___Amt
  01012009 01022009 _
  _ Of the 1000 1000 North
  _ Of the 1000 1000 South
  
  But I need an output like
  
  ___Amt
  01012009 01022009 _
  _ Of the 3000 1000 North
  1000 South _ 2000
  
  I think that PivotTable has taken a distinct value for the calculation...
  
  How could I get above exit... ?
  
  Published by: Mohan 8732779 on September 1, 2009 04:03

  Mohan,

  What I got from above, is that you need a sum of the column. To change the aggregation behavior for amt column to say you said the aggregation would be separate. Just change to change the formula in sum, that it looks like something like this flat is what you want to achieve is not it?

  By,.
  Murielle.

• pivot table problem

  create the table mytable
  (
  name varchar2 (50).
  name varchar2 (50)
  )
  
  Insert the table mytable values ('mary', 'john')
  Insert the table mytable values ('mary', 'baby')
  Insert the table mytable values ('mary', 'lady')
  Insert the table mytable values ('sean', 'kate')
  Insert the table mytable values ('sean', 'terry')
  Insert the table mytable values ('kate', 'tom')
  Insert the table mytable values ('kate', 'lary')
  .
  .
  .
  
  my result of the query is
  
  last name first name
  Jean-Marie
  baby Marie
  Lady Mary
  Sean kate
  Sean Terry
  Tom Kate
  Kate lary
  
  I want to like this
  
  Mary kate sean
  
  John tom kate
  baby terry lary
  Lady
  
  
  It's not all data.
  the data are changeable.there are 3 name as name like sean John 2 2 lik kate and it will be 5 name like paul... I want as column name and surname as the data...
  Thanks for your help...
  
  

  Hello

  Try this:

  WITH     number_rows     AS
  (
       SELECT     name
       ,     surname
       ,     ROW_NUMBER () OVER
                 (     PARTITION BY     name
                      ORDER BY     surname
                 )     AS r_num
       FROM     mytable
  )
  SELECT     r_num
  ,     MAX (CASE WHEN name = 'mary'     THEN surname END)     AS mary
  ,     MAX (CASE WHEN name = 'sean'     THEN surname END)     AS sean
  ,     MAX (CASE WHEN name = 'kate'     THEN surname END)     AS kate
  FROM     number_rows
  GROUP BY     r_num
  ORDER BY     r_num;
  

  The output is not quite what you asked:

  .    R_NUM MARY       SEAN       KATE
  ---------- ---------- ---------- ----------
           1 baby       kate       lary
           2 jon        terry      tom
           3 lady
  

  You do not have to display r_num: I showed just to make things easier to understand.
  If the output should really include "Jean" rather than "jon", or if it should appear above 'baby', rather than below, so please explain.

  If the names in columns ("Mary", "sean" and "kate" in your sample data) should be determined at run time, you need dynamic SQL statements to generate a statement like the one above.
  The script below shows one way to do this in SQL * more.

  /*
  How to Pivot a Table with a Dynamic Number of Columns
  
  This works in any version of Oracle
  The "SELECT ... PIVOT" feature introduced in Oracle 11
  is much better for producing XML output.
  
  Say you want to make a cross-tab output of
  the scott.emp table.
  Each row will represent a department.
  There will be a separate column for each job.
  Each cell will contain the number of employees in
       a specific department having a specific job.
  The exact same solution must work with any number
  of departments and columns.
  (Within reason: there's no guarantee this will work if you
  want 2000 columns.)
  
  Case 0 "Basic Pivot" shows how you might hard-code three
  job types, which is exactly what you DON'T want to do.
  Case 1 "Dynamic Pivot" shows how get the right results
  dynamically, using SQL*Plus.
  (This can be easily adapted to PL/SQL or other tools.)
  */
  
  PROMPT     ==========  0. Basic Pivot  ==========
  
  SELECT     deptno
  ,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
  ,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
  ,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
  FROM     scott.emp
  WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  PROMPT     ==========  1. Dynamic Pivot  ==========
  
  --     *****  Start of dynamic_pivot.sql  *****
  
  -- Suppress SQL*Plus features that interfere with raw output
  SET     FEEDBACK     OFF
  SET     PAGESIZE     0
  
  SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql
  
  SELECT     DISTINCT
       ',     COUNT (CASE WHEN job = '''
  ||     job
  ||     ''' '     AS txt1
  ,     'THEN 1 END)     AS '
  ||     job
  ||     '_CNT'     AS txt2
  FROM     scott.emp
  ORDER BY     txt1;
  
  SPOOL     OFF
  
  -- Restore SQL*Plus features suppressed earlier
  SET     FEEDBACK     ON
  SET     PAGESIZE     50
  
  SPOOL     p:\sql\cookbook\dynamic_pivot.lst
  
  SELECT     deptno
  @@dynamic_pivot_subscript
  FROM     scott.emp
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  SPOOL     OFF
  
  --     *****  End of dynamic_pivot.sql  *****
  
  /*
  EXPLANATION:
  The basic pivot assumes you know the number of distinct jobs,
  and the name of each one.  If you do, then writing a pivot query
  is simply a matter of writing the correct number of ", COUNT ... AS ..."\
  lines, with the name entered in two places on each one.  That is easily
  done by a preliminary query, which uses SPOOL to write a sub-script
  (called dynamic_pivot_subscript.sql in this example).
  
  The main script invokes this sub-script at the proper point.
  In practice, .SQL scripts usually contain one or more complete
  statements, but there's nothing that says they have to.
  This one contains just a fragment from the middle of a SELECT statement.
  
  Before creating the sub-script, turn off SQL*Plus features that are
  designed to help humans read the output (such as headings and
  feedback messages like "7 rows selected.", since we do not want these
  to appear in the sub-script.
  Turn these features on again before running the main query.
  
  */
  

• Pivotal Satellite Pro 6100 problem

  One of the parties who bear the my monitor broke so I don't support my monitor, is their wherever I can find a replacement for this?

  Hi Mike

  All necessary and compatible parts can be ordered from the service provider authorized in your country. I imagine that the technician he will order the Toshiba head stock.
  Call the guys and ask the parts needed.

  It s simply ;)

• How can I rotate an image of a pivot point?

  Hello

  I have a problem, the rotation VI Imaq only rotate an image at its Center. My problem is that I need a pivot known to this point. How can I achieve this?

  Thank you

  Francesco.

  This message can help?
  http://forums.NI.com/T5/LabVIEW/rotate-an-image-by-specified-pixel/TD-p/2570453

• custom scaling button problem

  Hi, I'm trying to customize some controls, but I have a problem with the construction of a button. I replaced the central image by a more realistic appearance and now I want to change the scale to better understand my button again, but I can't put across the 'ladder' after I want to be able to better run the needle and I can't choose the position of the needle. I am attaching the file so you can view and maybe help me to make this more comfortable button thank you!

  to customize your Ctrl button, click on the 'key' to display the icon.then of "clips" you can do what you want with the image or the button of properties, including the streching the balance to make pivot 360 degs, maximum range, no ticks, ticks, etc... BTW, reorganize tab is practical by placing objects to the front or the rear of several images

  

• problem writing series cRIO

  I want to communicate between cRIO-9073, and PC, the master will cRIO. Now am with VISAS for communication, my problem is when I write from PC and read in RIO I can do. But when I write of RIO and read from PC I could not able to read. No value is coming. I don't know what I'm missing. Maybe the difference in speed? Do I have to change baud rate? Now, I put to 9600 in the two.

  Can someone please help?

  Am still not familiar with the serial port signals but I'm trying to help you. Just do a test: disconnect the cable from the RIO and just turned the numbers 2 and 3 of the serial port cable and run both at the same time code in the host. If you receive data properly, then the problem could be with the cable (right or pivot) option.

• When I open my browser Google Chrome I get error "could not find the translation file:...\pivot.ini [WPCTRL95] does not work.

  Hello

  I have the same problem. The error message appears when I open my browser Google Chrome (Yes, only that browser). The full message is: could not find the file:...\pivot.ini translation [WPCTRL95] will not run.
  What kind of changes? As far as I know, I did not bring changes of lipids to my computer or programs. The thing is that I for a moment, and I don't recall the exact moment when it appeared.

  Hello

  Please take a look at the thread similar here with a solution as possible.

  I hope this helps!