Please help me good people.

The guy uses a presar io CQ58 NOTEBOOK PC... The PC told me three times to create a backup one i made, then aftr three days, the PC was stop by a display message wit a blue background. Then I ddnt read as wel wel very messege bt it was somthng like restart the PC press ENTER. What the what. So now that my PC cannot restart an all it show is a capital letter J on the upper left... (hard drive). What can I do to bring these portable baby bk to life?

The message means that your computer's HARD drive is dead or dying. You can replace the hard drive relatively inexpensively... maybe $70. If you have not written a set of recovery discs you can order from HP for usually about $16.

If you want to post the complete model number and product of the laptop we can offer suggestions on a replacement hard drive. The service manual online for most models also and will guide you through the replacement hard drive.

http://support.HP.com/us-en/document/c00033108

Tags: Notebooks

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      /* Scenario3 NULL can be equal to any value if there is only one value to equate with 
        In the below case we have ONE VALUE  that can equate with null so DONT ASSIGN ANY IDS*/
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     SELECT 17540300 ID , 'AMARONE' LAST_NAME , 'JOSEPH' FIRST_NAME , NULL MIDDLE_NAME FROM DUAL
    
     )
     Select * from names
     
     o/P Required
     ID    LAST_NAME    FIRST_NAME    MIDDLE_NAME
    
    47540310    WO      ROBERT          C
    99999990    WO      ROBERT          W                   -- New Sequence Number
    99999991     WO      ROBERT         X                   -- New Sequence Number
    47540300    AMATUZIO    ALBERT    J
    99999992    AMATUZIO    ALBERT                          -- New Sequence Number
    99999993    AMATUZIO    ALBERT    L                     -- New Sequence Number
    17540300    AMARONE    JOSEPH    J
    17540300    AMARONE    JOSEPH    
    Thank you

    Published by: new learning June 7, 2012 14:12

    I do not understand what does this line:

    FIRST_VALUE (fn_get_person_id) - sequence to function

    I feel that the only difference with my query is to select distinct values, do not consider duplicates. Correct me if I'm wrong.

    For me, this should give the same result as your query:

    WITH NAMES AS ( /* Scenario1 -- Three dirrerent people so assign Three diffrrent ID, keeping 1 id as is and assign two
    new ids from sequence*/
                   SELECT   47540310 ID,
                            'WO' LAST_NAME,
                            'ROBERT' FIRST_NAME,
                            'C' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   47540310 ID,
                            'WO' LAST_NAME,
                            'ROBERT' FIRST_NAME,
                            'C' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   47540310 ID,
                            'WO' LAST_NAME,
                            'ROBERT' FIRST_NAME,
                            'W' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   47540310 ID,
                            'WO' LAST_NAME,
                            'ROBERT' FIRST_NAME,
                            'X' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   /* Scenario2 NULL can be equal to any value if there is only one value to equate with
                     In the below case we have two values that can equate with null so assign three diffrent ids */
                   SELECT   47540300 ID,
                            'AMATUZIO' LAST_NAME,
                            'ALBERT' FIRST_NAME,
                            'J' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   47540300 ID,
                            'AMATUZIO' LAST_NAME,
                            'ALBERT' FIRST_NAME,
                            NULL MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   47540300 ID,
                            'AMATUZIO' LAST_NAME,
                            'ALBERT' FIRST_NAME,
                            'L' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   /* Scenario3 NULL can be equal to any value if there is only one value to equate with
                     In the below case we have ONE VALUE  that can equate with null so DONT ASSIGN ANY IDS*/
                   SELECT   17540300 ID,
                            'AMARONE' LAST_NAME,
                            'JOSEPH' FIRST_NAME,
                            'K' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   17540300 ID,
                            'AMARONE' LAST_NAME,
                            'JOSEPH' FIRST_NAME,
                            'Y' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   17540300 ID,
                            'AMARONE' LAST_NAME,
                            'JOSEPH' FIRST_NAME,
                            NULL MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   17540300 ID,
                            'AMARONE' LAST_NAME,
                            'JOSEPH' FIRST_NAME,
                            'M' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   17540300 ID,
                            'AMARONE' LAST_NAME,
                            'JOSEPH' FIRST_NAME,
                            'M' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   99999999 ID,
                            'LO' LAST_NAME,
                            'CHRISTY' FIRST_NAME,
                            NULL MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   99999999 ID,
                            'LO' LAST_NAME,
                            'CHRISTY' FIRST_NAME,
                            'M' MIDDLE_NAME
                     FROM   DUAL
                   UNION ALL
                   SELECT   99999999 ID,
                            'LO' LAST_NAME,
                            'CHRISTY' FIRST_NAME,
                            'M' MIDDLE_NAME
                     FROM   DUAL),
     sel_names AS (  SELECT id
                              , last_name
                              , first_name
                              , middle_name
                              , COUNT (middle_name) OVER (PARTITION BY id ORDER BY middle_name) cnt
                              , ROW_NUMBER () OVER (PARTITION BY id  ORDER BY middle_name) rown
                           FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
                       ORDER BY 1, 2, 3, 4
                       )
    SELECT 8888888 new_id, id, last_name, first_name
         , middle_name
      FROM sel_names
     WHERE cnt > 1 AND rown > 1;
    

    As you can see I have just replace the table with a view of inline using SELECT DISTINCT *.

                           FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
    

    For the new id I put a dummy value 888888, you can use a function or sequence according to your needs.

    Kind regards.
    Al

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    Hello

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    373453429       99000000        LUNA        JOSE                                  33065
    442303062       99000000        LUNA        JOSE       S                          442303062
    30088775765     990000878       BILL        RAY        M                          30088775765
    30088775766     990000878       RAY         BILL                                  30088775766
    30088775767     990000878       RAY         BILL       MAX                        30088775767
    30088775768     990000878       RAY         BILL       MICHEL                     30088775768
    399998776       9901111         ELLISON     LAWRANCE                              399998776 
    399998777       9901111         ELLISON     LAWRANCE    J        JR               399998777  
    399998778       9901111         ELLISON     LAWRANCE    JAMES    SR               399998778
    399998779       9901111         ELLISON     LAWRANCE    JACK     JR               399998777
    Thank you

    Hello

    Interesting problem!

    That's what you asked for:

    WITH    got_min_we_pid  AS
    (
         SELECT     merge_names.*
         ,     MIN (we_pid) OVER ( PARTITION BY  first_name
                                     ,                  last_name
                            ,            middle_name
                            ,            suffix
                            )     AS min_we_pid
         FROM    merge_names
    )
    ,     possible_matches       AS
    (
         SELECT     CONNECT_BY_ROOT min_we_pid     AS min_we_pid
         ,     we_pid                    AS leaf_we_pid
         FROM     got_min_we_pid
         WHERE     CONNECT_BY_ISLEAF  = 1
         START WITH   we_pid                = min_we_pid
         CONNECT BY   first_name             = PRIOR first_name
              AND  last_name                = PRIOR last_name
              AND  SUBSTR ( 'x' || middle_name
                       , 1
                       , LENGTH ('x' || PRIOR middle_name)
                       )                   = 'x' || PRIOR middle_name
              AND  'x' || middle_name    > 'x' || PRIOR middle_name
              AND  'x' || suffix        = 'x' || PRIOR suffix
    )
    ,     got_match_cnt     AS
    (
         SELECT DISTINCT
              min_we_pid
         ,     leaf_we_pid
         ,     COUNT (DISTINCT leaf_we_pid) OVER (PARTITION BY  min_we_pid)     AS match_cnt
         FROM     possible_matches
    )
    SELECT       c.*
    ,       NVL (p.leaf_we_pid, c.min_we_pid)     AS merge_wepid
    FROM              GOT_MIN_we_pid  c
    LEFT OUTER JOIN      got_match_cnt   p   ON  p.min_we_pid     = c.min_we_pid
                                      AND p.match_cnt     = 1
    ORDER BY  c.last_name
    ,            c.first_name
    ,       c.middle_name
    ;
    

    Here's how it works:
    First of all, we take care of the exact replica, by finding the we_pid lowest for each group defined by (first_name, last_name, middle_name, suffix). For example, the two lines for Jose Luna (no middle name) are assigned to the min_we_pid = 33065. It is this min_we_pid, not the original we_pid, that is used in all future operations.
    Then we are all names other names that are similar, but more comprehensive, using a CONNECT BY (subquery possible_matches) query. The parents in this query are stored with short middle_names, and children are lines that have first_name, last_name identical and suffix, but middle_names longer. I concatenated the x at the beginning of all middle_names for comparisons, to treat the NULL as being less at, but similar to something else. Is so, that we had a group of lines with identical names (and suffixes) with the exception of the middle_names, then
    NULL middle_name might be a parent got ', "DEB" and "DEBORAH",.
    A ' would be a parent of "DEB" and "DEBORAH", and
    "DEB" would be a parent of 'DEBORAH '.
    By following this chart until we find the lines that have no children, we may associate each short middle_name with the similar longer middle_name, or names. At this point, we will have "BILL RAY" as the ancestor of 'RAY MAX BILL' as well as "RAY MICHEL BILL". Here comes the following subquery, got_match_cnt. If notes how many descendants are associated with each ancesotor, in other words, how much longer names might match a name more runs. If this number is greater than 1, we do not consider one of the matches. That is why match_cnt = 1 is one of the join conditions in the main query, where each row in the theoriginale table is related to its more relative, when it exists, and if it is unique.

  • Please help me with my imac beachballing running El Capitan

    My imac is in trouble and my mental well-being is threatened!

    If you could please help, it would be most appreciated.

    I've included an etrecheck report:

    EtreCheck version: 2.9.12 (265)

    Report generated 2016-06-25 12:37:55

    Download EtreCheck from https://etrecheck.com

    Time 01:45

    Performance: Excellent

    Click the [Support] links to help with non-Apple products.

    Click [details] for more information on this line.

    Problem: Beachballing

    Description:

    Incredibly slow at the same time. Sometimes freezes completely and will not be closed. None of the keyboard shortcuts will help you. I need to use the power button on the back to turn it off.

    And even then, sometimes, after the reboot, the problem persists. And other times, I need to restart several times.

    Hardware Information:

    iMac (27 inch, at the end of 2013)

    [Data sheet] - [User Guide] - [warranty & Service]

    iMac - model: iMac14, 2

    1 3.4 GHz Intel Core i5 CPU: 4 strands

    8 GB of RAM expandable - [Instructions]

    BANK 0/DIMM0

    OK 4 GB DDR3 1600 MHz

    BANK 1/DIMM0

    OK 4 GB DDR3 1600 MHz

    0/DIMM1 BANK

    Vacuum

    BANK 1/DIMM1

    Vacuum

    Bluetooth: Good - transfer/Airdrop2 taken in charge

    Wireless: en1: 802.11 a/b/g/n/ac

    Video information:

    NVIDIA GeForce GTX 775M - VRAM: 2048 MB

    iMac 2560 x 1440

    Software:

    OS X El Capitan 10.11.5 (15F34) - since startup time: less than an hour

    Disc information:

    ST1000DM003 disk HARD APPLE disk0: (1 TB) (rotation)

    EFI (disk0s1) < not mounted >: 210 MB

    Macintosh HD (disk0s2) /: 999,35 go-go (585,40 free) - 3 errors

    Drive failure!

    Recovery HD (disk0s3) < not mounted > [recovery]: 650 MB

    USB information:

    GenesysLogic USB3.0 Hub 2 TB

    Seagate Backup + Desk 2 TB

    EFI (disk1s1) < not mounted >: 315 MB

    Seagate Backup Drive (disk1s2) Volumes/Seagate Backup plus Drive: 2,00 (1.03 free) tuberculosis

    Apple Inc. BRCM20702 hub.

    Apple Inc. Bluetooth USB host controller.

    Apple Inc. FaceTime HD camera (built-in)

    Burr-Brown of TI USB Audio CODEC

    Reader SuperDrive for MacBook Air Apple Inc..

    GenesysLogic USB2.0 hub

    Lightning information:

    Apple Inc. Thunderbolt_bus.

    Guardian:

    Mac App Store and identified developers

    Kernel extensions:

    / System/Library/Extensions

    NG.UDs.netusb.controller [no charge] (1.59-2016-06-06) [Support]

    Launch system officers:

    [loaded] 7 tasks Apple

    [loading] 159 tasks Apple

    [operation] 72 tasks Apple

    Launch system demons:

    [loaded] 47 tasks Apple

    [loading] 156 tasks Apple

    [operation] 87 tasks Apple

    Launch officers:

    [loading] com.citrix.AuthManager_Mac.plist (2015-03-17) [Support]

    [loading] com.citrix.ReceiverHelper.plist (2015-03-17) [Support]

    [operation] com.citrix.ServiceRecords.plist (2015-03-17) [Support]

    User launch officers:

    [loading] com.google.keystone.agent.plist (2016-03-05) [Support]

    Items in user login:

    iTunesHelper Application (/ Applications/iTunes.app/Contents/MacOS/iTunesHelper.app)

    Other applications:

    [ongoing] com.google.Chrome.62432

    [loading] 394 tasks Apple

    [operation] 181 tasks Apple

    Plug-ins Internet:

    Default browser: 601 - SDK 10.11 (2016-05-21)

    QuickTime Plugin: 7.7.3 (2016-05-21)

    CitrixICAClientPlugIn: 11.9.15 - SDK 10.9 (2015-03-17) [Support]

    3rd party preference panes:

    None

    Time Machine:

    Mobile backups: OFF

    Automatic backup: NON - automatic backup disabled

    Volumes to back up:

    Macintosh HD: Disc size: 999,35 GB disc used: 413,94 GB

    Destinations:

    Backup drive Seagate Plus [Local]

    Total size: 2.00 TB

    Total number of backups: 44

    An older backup: 18/10/2014, 17:07

    Last backup: 06 23, 2016, 19:32

    Size of backup drive: adequate

    Size of backup 2.00 TB > (disc 413,94 GB X 3)

    Top of page process CPU:

    3% WindowServer

    2% fontd

    0% kernel_task

    0% cloudpaird

    Top of page process of memory:

    636 MB kernel_task

    270 MB mdworker (15)

    197 MB Google Chrome Helper (2)

    QuickLookSatellite 139 MB

    Chrome Google 139 MB

    Virtual memory information:

    4.46 GB of free RAM

    3.54 GB of used RAM (1.69 GB being cached)

    Used Swap 0 B

    Diagnostic information:

    25 June 2016, 12:20:41 self-test - spent

    June 22, 2016, 20:17 ~/Library/Logs/DiagnosticReports/com.apple.Safari.SafeBrowsing.Service_2016-06-22-201700_ [redacted] .crash

    /System/Library/PrivateFrameworks/SafariSafeBrowsing.Framework/versions/A/com.a people. Safari.SafeBrowsing.Service

    June 22, 2016, 20:10:43 ~/Library/Logs/DiagnosticReports/com.apple.Safari.SafeBrowsing.Service_2016-06-22-201043_ [redacted] .crash

    June 22, 2016, 20:09:37 ~/Library/Logs/DiagnosticReports/com.apple.WebKit.Networking_2016-06-22-200937_ [redacted] .crash

    System/Library/Frameworks/WebKit.Framework/versions/A/XPCServices/com. Apple.We bKit.Networking.xpc/Contents/MacOS/com.apple.WebKit.Networking

    June 22, 2016, 20:07:30 [redacted] ~/Library/Logs/DiagnosticReports/com.apple.Safari.SafeBrowsing.Service_2016-06-22-200730_ .crash

    June 22, 2016, 19:53:59 ~/Library/Logs/DiagnosticReports/com.apple.Safari.SafeBrowsing.Service_2016-06-22-195359_ [redacted] .crash

    June 22, 2016, 19:45:57 [redacted] ~/Library/Logs/DiagnosticReports/com.apple.Safari.SafeBrowsing.Service_2016-06-22-194557_ .crash

    Hard drive appears to be faulty.

    It seems that you have current backups, so you should be able to recover if the drive completely fails.

    Run disk utility to repair the disk and also check the SMART State.

    When a player starts to falter, it is almost certain, it will fail. There is really no cover failures of IO because it indicates that the player no longer has the ability to remap bad blocks.

    If you have AppleCare, you can probably still get it replaced. However, they are fairly cheap these days and quite easy to replace yourself.

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