Put the ID attributes on all nodes
HelloI have a similar to the following XML
< root >
< elem >
< subElem >
< / subElem >
< / elem >
< elem >
< subElem >
< / subElem >
< subElem >
< / subElem >
< / elem >
< / root >
I'm putting a lot of 'Id' attributes on each item for easy access. I want a result similar to
< root >
< elem id = "1" >
< subElem id = "1" >
< / subElem >
< / elem >
< elem id = "2" >
< subElem id = "1" >
< / subElem >
< subElem id = "2" >
< / subElem >
< / elem >
< / root >
"So I can't access the second"sub"in the second /root/elem/@id="2"/sub/@id="2 item.
You have no way to put this attributes "Id" using XQuery or another way. I prefer a non programmatic method (that is, using Oracle, not Java).
I tried with the function this way InsertChildXML
Update xmlTable
Set insertChildXML = xmlField (xmlField, ' / root//*','@id','nothing');
It works, but how can I put the Id numbers for each element and each subitem?
Another way is to use XQuery, but now I get poor results.
Any help?
Thank you.
José Domingo Hernández
Published by: jdhernandez on Sep 2, 2009 08:28
Without knowing all the details of why you are trying to add an attribute id, beyond the 'easy access', why not just use an XPath like
/ root/elem [2] / subElem [2]
Instead of
/root/elem/@ID="2"/sub/@ID="2".
My Xpath using XML, said to get the second subElem in the second comp in the root node. This is in agreement with what your application, on the assumption that nothing reorganizes the XML during your treatment.
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