query to resolve the name

question: need to know the oderno missing between test_order and test_tran, and get the name of the associated provider
Looking for the final result looks like this:
orderno item vid vendorname isssue1 issue2
1004    water 2   vend2 
I can leave the orderno missing but stuck on the seller's behalf. Can U help? Thank you.

Select * from test_order where orderno not in (select B.orderno from test_tran B)



an abridged version of samp tables

CREATE TABLE 'TEST_ORDER '.
(THE NUMBER (10.0) OF "ORDERNO" NOT NULL,)
'THE POINT' VARCHAR2 (50) NOT NULL,
NUMBER (3,0) 'VID' NOT NULL,
KEY ELEMENTARY SCHOOL ("ORDERNO")
)
/

insert into TEST_ORDER (orderno, item, vid)
values(1001,'candy',2)
insert into TEST_ORDER (orderno, item, vid)
values(1002,'book',1)
insert into TEST_ORDER (orderno, item, vid)
values(1003,'fruit',3)
insert into TEST_ORDER (orderno, item, vid)
values(1004,'water',2)
/

CREATE TABLE 'TEST_TRAN '.
(THE NUMBER (10.0) OF "ORDERNO" NOT NULL,)
NUMBER (3,0) 'VID' NOT NULL,
'PUBLIENT1' VARCHAR2 (50).
"ISSUE2' VARCHAR2 (50)
)
/


insert into TEST_TRAN (orderno, vid, issue1, issue2)
values (article 1001,1, 'false', null)
insert into TEST_TRAN (orderno, vid, issue1, issue2)
values(1002,2,'ok',null)
insert into TEST_TRAN (orderno, vid, issue1, issue2)
values (1003,3, 'load bed', null)

/



CREATE TABLE 'TEST_VENDOR '.
(THE NUMBER (3,0) 'VID' NOT NULL,)
VARCHAR2 (50) 'NAME' NOT NULL,
"ADDR" VARCHAR2 (50) NOT NULL
)
/

insert into TEST_vendor (vid, addr)
values(1,'vend1','addrv1')
insert into TEST_vendor (vid, addr)
values(2,'vend2','addrv2')
insert into TEST_vendor (vid, addr)
values(3,'vend3','addrv3')
SQL> set linesize 200
SQL> column item format a20
SQL> column issue1 format a20
SQL> column issue2 format a20
SQL>
SQL> SELECT test_order.orderno, test_order.item, test_order.vid, test_vendor.NAME,
  2         NULL issue1, NULL issue2
  3    FROM test_order, test_vendor
  4   WHERE test_order.vid = test_vendor.vid
  5     AND NOT EXISTS (SELECT NULL
  6                       FROM test_tran
  7                      WHERE test_order.orderno = test_tran.orderno);

   ORDERNO ITEM                        VID NAME                                               ISSUE1               ISSUE2
---------- -------------------- ---------- -------------------------------------------------- ------
      1004 water                         2 vend2

SQL> 

Tags: Database

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