Size of directory trees

Is there a way to see the directory sizes of trees at the same time?

It's your lucky day...

http://www.Jam-software.com/treesize_free/

Tags: Windows

Similar Questions

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    Hello

    I had to reinstall the operating system and now when a user connects to a directory tree is created as a "user. HAND '. Why is this and I correct?

    Thank you
    Doug

    If "user. MAIN", user is the name of the logged in user and MAIN is the name of the computer, and this directory is created in the"\Documents and Settings"folder, then this is probably the result of a corrupt user profile.  To retrieve, select from the following items:

    "How to recover damaged Windows XP user profile"
      <>http://support.Microsoft.com/kb/555473 >

    "How to copy data from a corrupted to a new profile in Windows XP user profile"
      <>http://support.Microsoft.com/kb/326688 >

    Usually corrupt profiles are accompanied by corruption of system files, so an operation "chkdsk" with the /F or/r option is a step in careful follow-up interview:

    "How to perform disk error in Windows XP check"
      <>http://support.Microsoft.com/kb/315265 >

    HTH,
    JW

  • Windows directory tree

    Hello:

    I'm running Vista 32 bit Home Premium ofn a HP laptop.

    I had opened a window showing disks on my computer, via Start > computer.

    At that time, he had two panels in the main window.

    The right panel shows the list of drives.

    The left panel shows a directory tree.

    I clicked on something about high to the left of the left panel,

    and the information displayed in the left panel changed to a list of Favorites.

    How can I get the directory tree in the left panel?

    Thanx

    DaleB

    Hello:

    I found the solution:.

    If you click on Start > computer and lool at the list or Details "view,"

    in the right panel, you will see a list of your disks.  In the left panel.

    you will see a directory tree.  If you do not, in the left panel, look at all

    the descent of the upper part of the left panel.  There, you will see

    the term files, with one pointing triangle (arrow).

    Click it, and the directory tree will reappear.  To hide the

    directory tree, click Folders at the bottom of the list to the top

    in the left panel.  Clciking on records is just a switch for hide/show

    the directory tree.

    DaleB

  • Cannot delete directory tree

    I had a request are able to convince Windows to screw up its file structure in two folders. When I try to delete the directory runaway tree I get the message error "the folder contains items whose names are too long for the Recycle Bin.  After choosing the option Yes it is followed by another error message "the name of the source file is larger that can be supported by the file system. Try to move to a place that has a way more short name, or try renaming to shorter name (s) before performing this operation. ', then' the file name may be too long for the destination folder. You can shorten the file name and try again, or try a location with a shorter path "."
    The end result is that the directory tree cannot be deleted.
    I think there may be a third-party tool out there to remedy this wrong behavior of the BONE from the window.
    I had hoped that Microsoft would provide a way to correct that a fault that is OS allowed to occur.

    I had a request are able to convince Windows to screw up its file structure in two folders. When I try to delete the directory runaway tree I get the message error "the folder contains items whose names are too long for the Recycle Bin.  After choosing the option Yes it is followed by another error message "the name of the source file is larger that can be supported by the file system. Try to move to a place that has a way more short name, or try renaming to shorter name (s) before performing this operation. ', then' the file name may be too long for the destination folder. You can shorten the file name and try again, or try a location with a shorter path "."
    The end result is that the directory tree cannot be deleted.
    I think there may be a third-party tool out there to remedy this wrong behavior of the BONE from the window.
    I had hoped that Microsoft would provide a way to correct that a fault that is OS allowed to occur.

    Place the blame in the wrong place.

    Too many times have I given ridiculous people with file names and folders structures.

    You may be able to create a link to a directory close to the files you want to learn to (probably something similar was done by the application that supposedly does this) using something like the old command SUBST to start a directory/drive (or give the impression that even when it starts) at a different point than the original reality (google for the subst command.)

    You could read this too...

    http://www.bryantwebconsulting.com/blog/index.cfm/2012/1/19/getting-around-Windows-7-destination-path-too-long-error-when-deleting-files

  • How can I remove a directory tree that is too deep?

    I used ROBOCOPY to copy the contents of theC:\USERS\ALL USERS in an external drive USB FAT32.  I forgot to include the /XJ switch and, therefore, now have a directory tree that continues to repeat the Application data in a subdirectory.

    When I try to delete it, I get an error message:
    "The names of source files are larget that is supported by the file system."  Try to move to a location that has a shorter path name, or try renaming to name more short (s) before performing this operation. »

    I can't move any part of the directory tree or I can rename it.

    Anyway is to remove the directory tree without having to refomat the player?

    Found this utility that will at least give you an idea if you delete.

    http://www.purgeie.com/delinv/

    JS

  • Create a directory tree: how to call a global function from inside a for loop

    Hello

    I am trying to create a workflow that will create a directory tree in vCenter.

    Concept:

    Basically, I am trying to execute nested for loops for each level of the tree to the caller a global tree.

    Problem:

    The 1st loop for works and creates the file 'Dev '.  The second loop for does not work with error message:

    [19:16:16.219 2013-06-27] [I] building Dev folder
    [19:16:16.474 2013-06-27] [I] directory Built: Dev
    [19:16:16.476 2013-06-27] [I] the records building servers
    [19:16:16.480 2013-06-27] [I] TypeError: cannot find the createFolder function in dev object. (Workflow: TEST_TNG_New_Site_Folder_Structure / Scriptable task (item2) #36)

    I think it has to do with JavaScript not being not able to call a global function in a nested object (I'm not a programmer and don't know JavaScript, so don't shoot me on that :)

    Code: (will clean this up once I do work)

    var folderBase is ['Dev', 'DMZ', 'Prod', 'UAT'];.

    var folderT1 = ["servers", "Jobs"];

    var folderT2 = ['Window', 'Linux'];

    var folderT3 is ["Repo2', 'Repo3', 'Repo1', 'Repo4'];.

    var folderT4 is ["T1", "T2", "T3"];.

    Create the files folderBase level

    for (var i = 0, l = folderBase.length; i < l; i ++) {}

    var rootFolder = parentFolder;

    buildFolderTree (folderBase [i]);

    Create the files folderT1 level

    for (var j = 0, l = folderT1.length; j < l; j ++) {}

    var rootFolder = folderBase [i];

    buildFolderTree (folderT1 [j]);

    Create the files folderT2 level

    for (var k = 0, l = folderT2.length; k < l; k ++) {}

    var rootFolder = folderT1 [j];

    buildFolderTree (folderT2 [k]);

    Create the files folderT3 level

    for (var x = 0, l = folderT3.length; x < l; x ++) {}

    var rootFolder = folderT2 [k];

    buildFolderTree (folderT3 [x]);

    Create the files folderT4 level

    for (var y = 0, l = folderT4.length; y < l; y ++) {}

    var rootFolder = folderT3 [x];

    buildFolderTree(folderT4[y]);

    }

    }

    }

    }

    }

    function buildFolderTree (folderName) {}

    System.log ("Building folder" + folderName);

    rootFolder.createFolder (folderName);

    System.log ("directory of frame:" + folderName);

    }

    Any help will be appreciated.

    Thank you

    B

    Hello

    The createFolder() method returns the object VcFolder to the folder just created, for the new file to be used immediately.  Here is how I modified the code:

    Create the files folderBase level
    for (var i = 0; i)
    var newBaseFolder = buildFolderTree (parentFolder, folderBase [i]);
    Create the files folderT1 level
    for (var j = 0; j)
    var newT1Folder = buildFolderTree (newBaseFolder, folderT1 [j]);
    Create the files folderT2 level
    for (var k = 0; k)
    var newT2Folder = buildFolderTree (newT1Folder, folderT2 [k]);
    Create the files folderT3 level
    for (var x = 0; x)
    var newT3Folder = buildFolderTree (newT2Folder, folderT3 [x]);
    Create the files folderT4 level
    for (var y = 0; y)
    var newT4Folder = buildFolderTree (newT3Folder, folderT4 [y]);
    }
    }
    }
    }
    }

    function buildFolderTree (parentFolderObj, folder_name) {}
    System.log ("Building folder" + folderName);
    var newFolder = parentFolderObj.createFolder (folderName);
    System.log ("directory of frame:" + folderName);
    return NewFolder;
    }

  • back or a script for recursivley travel through a directory tree and make a shortcut relitive to a file located in each directory

    Nice day

    I have a bunch of files that are located on a network computer that has a shared parent directory.  I need to create a shortcut to the .exe which are in each directory.  There are more than 1000 directories, so the creation of all the shortcuts by right-clicking on each one of them is out of the question.  Shortcuts created to point to the original files, even though I'm moving shortcuts to another system.  You should be able to run the exe file from the network share from any system on the network.  I use robocopy with like to copy the directory structure and all the files in each directory except the .exe due to their size.  I wish that the finished product to fit on a USB key so that I can plugin for any system and then run the program pointed to by the shortcut.  Basically, it will be a reference in offline mode that can be used on a system that is online.

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  • Paths of directory tree market

    Oracle Database 11g Enterprise Edition Release 11.2.0.3.0

    I have an external table returns a list of directory paths. Is there a built-in way to turn this into a foot of the tree? I would like to use the tree in an apex application market, where the issue. I had considered splitting on each node with regexp_substr and then do everything manually, but I guess there is something already done in this area, although as the forums search returned unanswered.

    WITH directory_listing AS 
      (SELECT '/root' 
         FROM DUAL
       UNION
       SELECT '/root/level1/level2/level3'
         FROM DUAL
       UNION
       SELECT '/root/level1'
         FROM DUAL
       UNION
       SELECT '/root/level1/level2'
         FROM DUAL)
    SELECT * FROM directory_listing
    

    Returns:

    LIST

    --------------------------

    / root

    / root/level1

    / root/Level1/Level2

    / root/Level1/Level2/Level3

    I wish the tree she can walk this list, so to be able to refer to a 'level' and of course the tree market, so connect by etc..

    Hello

    Thanks for posting the sample data.  Don't forget to post the exact results you want from the given sample data, too.

    Given a table like directory_listing, are you trying to create a table like this

    NODE_ID PARENT_ID NODE_NAME LISTING

    ---------- ---------- ---------- --------------------------

    1 root/root

    2 1 level1/root/level1

    3 2/root/level1/level2 level2

    4 3 level3/root/level1/level2/level3

    ?  If so, here is one way:

    Tree of CREATE TABLE AS

    WITH got_node_id AS

    (

    SELECT list

    SUBSTR (ad

    1 + INSTR (ad

    , '/'

    -1

    )

    ) AS node_name

    ROW_NUMBER () OVER (ORDER BY NULL) AS node_id

    OF directory_listing

    )

    SELECT c.node_id

    p.node_id AS parent_id

    c.node_name

    c.listing

    OF got_node_id c

    LEFT OUTER JOIN got_node_id p ON p.listing | '/'

    || c.NODE_NAME = c.listing

    ;

    This means that registration is unique in your original table.  Individual node_names need not be unique.  In other words, it is normal to have both "/ root/level 1/level 2 ' and ' / root2/level 1/level 2" where "level1" and "level2" are duplicated.

    It is convenient to have the liisting of your original table column.  However, if you do any DML on the table of the tree, then it will be difficult to keep specific list column, and you can always build using SYS_CONNECT_BY_PATH.  Decide for yourself whether or not you want the list column in the table from the tree.

  • Setting the size of the trees

    Hello

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    If my answer or the answer to another person has been useful or appropriate, please mark accordingly

  • Under media folder directory tree - is it possible

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    Please, advise.

    Thank you

    Andy

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    /; \applications\vod\media\test2

    If your application. XML would look like this:

    / ; ${VOD_COMMON_DIR}

    / ; ${VOD_DIR}

    /; \applications\vod\media\test1

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    So no need to change your .smil file, you can get it works this way.

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  • Impossible to import the directory NFS: no expandable tree

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    screenshot 2013-01-05 at 12.37.31 AM.png

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