Similar Questions

• Problem solver!

  Hi guys,.

  I'm having a problem with my first anoing, I grab than a formula to the Solver and this formula cause a bug in the first.

  It gives me the bad answear for the "T" variable, the result is always a number about a value that I have used a previous equation.

  The formula is: X = A * COS (W * T) -> periodic motion

  I want to solve the variable T, but when a go at T, the spectacle of the calculator a wrong value, of course, I know the correct answear.

  The values I used:

  X: 0.075-> particle position

  R: 0.15-> amplittude

  W: 628.32

  Angle mode: Radians

  The interesting thing is, it always come with a specific value for em A X, if I use other values, it did not happen.

  Sometimes the first gets even a bug and I need to reset the back button.

  Software version:

  2013-11-25 (5447)

  CASE version: 1.1.0 - 27

  Serial number xxxxxxxxxx

  Can someone help me?

  P.S. I deleted your post for secutiry serial number. That is the information you probably don't want available to the public. -HP moderator of the Forum

  Put in a comme.0002 for your T estimate, then press SOLVE. There are hundreds of solutions just in the range 0 < X < 1 due to fast oscillations in your function. Without providing an initial starting value, there is no way for the calculator to know that the roots will locate it.

  Remember that you can press the button of the FIELD and see the sides left and right of the equation plotted against them. You will see that your X line intersects your cos field in many, many places.

• Calibration system as a solution of nonlinear equations

  Nice day

  The challenge of the day is to provide a calibration for a release of the accelerometer, expressed as a binary value.

  I have an accelerometer whose operating range can be set (±2g, ±4g ±8g).  The accelerometer itself then generates a binary value to 16-bit resolution.  Therefore, only 2 ^ 16 value (0-65535) represents an acceleration value of which depends on the lines we have.

  So we make the asumption that the response is linear, which allows us to claim:

  Acceleration = scale x value binary + Offset

  I have three axes of a value of data, accelerometer A, B and C.  If I hold the stationary accelerometer, the only thing that I should be reading is acceleration due to gravity, g.  It makes me of the relationship

  (A) ^ 2 + (B) ^ 2 + (C) ^ 2 = g ^ 2

  Since then, in any direction, the magnitude of the combination of all the three readings of the acceleration must be the gravitational acceleration (and that shouldn't change little matter which side you happen be pointing the accelerometer).

  What gives me, then, is a non-linear relationship of 6 variables (scale factors three and three shifts). I should be able to take six measures in an arbitrary orientation that will give me six output values of each had.  Then I should be able to get out the scale factors and offsets for each accelerometer, either in terms of g or with respect to which, in my opinion, g is.

  So, my question is how can I get Labview to do this?  I see that there is a tool to solve linear equations, but I don't see one appropriate for the non-linear case.  I'm also very comfortable believing that I'm just missing it :-)

  Thank you!

  Since the help file detail to the nD nonlinear system Solver.vi:

  Formula Variables VI analysis

  The formula analysis screws accept only the following variables:

  Note  These same variables to specify the description of the chain of the formula for the adjustment of non-linear curve VI.

  a, a0,..., a9

  b, b0,..., b9

  .

  .

  .

  z, z0,..., z9

  For variable and function names, only lower-case letters are allowed. Screw interpret case as errors.

  1. I found this by opening the Panel before the nonlinear Solver VI when executing your VI. The error information said that there was a problem with the formula.

  2. I replaced the Scale__ and Offset__ variables with a0, a1, b0, b1, c0 and c1 in tables X and f (x).

  3. I have expanded the values start and end - 10 and 10.

  This seems to work much better. At least it runs.

  Lynn

• Caveat "the formula uses a Boolean value instead of a number" would dismiss

  Hello!

  I do a "Calculator" to get estimates of price for the projects, according to which processes the customer wants.

  Rates for each process are added in another table, and I use the list of control buttons to enable or disable the various processes.

  Here is an example of a formula:

  

  D3 determines if the part of the project modeling is performed, so the price will be or will not be calculated.

  If D3 is true, the result is multiplied by 1, give me a positive amount. If false, the result will be multiplied by 0, 0, so nothing to add to the final cost he send me some.

  Same for B4 in the same formula.

  This formula is repeated all over the chart, with minor changes to add more complex options, but it's all the same.

  Everything works fine, but I got those blue triangles warning me of "the formula uses a Boolean value instead of the number". That's fine with me, I like the use of the Boolean types, and they make my formulas work well in my calculator. How can I reject the blue triangles?

  

  They are a little annoying. And they do not really correspond with the general style of my calculator.

  I saw someone talking other types of formulas, with SEARCH and yews, but who is really complicated and I don't know how to do... Especially for a simple calculator

  Is there a way to simply do not display warnings?

  Using the version 3.6.2 on a MacBook Pro, OSX El Capitan 10.11.5

  Thank you!

  Hi Sinshassan,

  I don't know a way to escape your blue flags except to make a formula which is consistent with the expected numbers. It is not difficult.

  

  My formula D2 = yew (AND(D1,B2), C2, 0)

  The IF statement tests the two D1 AND B2. If they are true, then it indicates the value of C2 your carbon Modeling::High Poly #1, if one or both are false (unchecked) then 0 is displayed.

  Give it a try.

  Quinn

• Function to solve any formula

  Hello
  
  I have a requirement like, I have a string of the form as "A + B - C * D". I take this string as input to a function/procedure that will calculate this formula and provide an output of result. The values of the A, B, C, D are stored in a separate table. Please help me.
  
  Kind regards
  Kone

  You need to write dynamic code and use bind variables. This however not a good idea, despite the use of bind variables. Many different formulas means a lot of sliders not shareable. This will be problematic - and can lead to fragmentation of memory in the Shared Pool errors and memory.

  Then there's security and risk of SQL injection. And then there are architectural decisions - PL/SQL is the right place to deal with this problem of race-Dynamics-formula ?

  Assuming that these questions are analyzed globally and PL/SQL is the environment to use, the basic approach is this:

  SQL> create or replace package Calculator as
    2
    3          --// list of variables
    4          type TVariableList is table of number index by varchar2(30);
    5          variable        TVariableList;
    6
    7          function Calc( formula varchar2 ) return number;
    8  end;
    9  /
  
  Package created.
  
  SQL>
  SQL> create or replace package body Calculator as
    2
    3          function Calc( formula varchar2 ) return number is
    4                  cur     integer;
    5                  res     number;
    6                  rc      integer;
    7                  varName varchar2(30);
    8          begin
    9                  --// create and parse a cursor
   10                  cur := DBMS_SQL.Open_Cursor;
   11                  DBMS_SQL.Parse(
   12                          cur,
   13                          'begin :result := '||formula||'; end;',
   14                          DBMS_SQL.native
   15                  );
   16
   17                  --// bind the variables in the cursor
   18                  varName := variable.First;
   19                  while varName is not null loop
   20                          --// if the variable occurs in the formula, bind it
   21                          if InStr( formula, varName ) > 0 then
   22                                  DBMS_SQL.Bind_Variable( cur, varName, variable(varName) );
   23                          end if;
   24                          varName := variable.Next( varName );
   25                  end loop;
   26
   27                  --// bind the output bind variable that was added
   28                  DBMS_SQL.Bind_Variable( cur, 'result', res );
   29
   30                  --// execute the cursor (dynamic PL/SQL block)
   31                  rc := DBMS_SQL.Execute( cur );
   32
   33                  --// read the output bind variable and close the cursor
   34                  DBMS_SQL.Variable_Value( cur, 'result', res );
   35                  DBMS_SQL.Close_Cursor( cur );
   36
   37                  --// return the formula result
   38                  return( res );
   39          end;
   40
   41  end;
   42  /
  
  Package body created.
  
  SQL>
  SQL> --// setup variables used in formulas
  SQL> begin
    2          Calculator.variable('A') := 10;
    3          Calculator.variable('B') := 100;
    4          Calculator.variable('C') := -1;
    5          Calculator.variable('D') := 0;
    6  end;
    7  /
  
  PL/SQL procedure successfully completed.
  
  SQL>
  SQL> --// execute some formulas
  SQL> select Calculator.Calc( ':A + :B * :C' ) as RESULT from dual;
  
      RESULT
  ----------
         -90
  
  SQL> select Calculator.Calc( ':B / :A * :C' ) as RESULT from dual;
  
      RESULT
  ----------
         -10
  
  SQL> select Calculator.Calc( ':D + :C' ) as RESULT from dual;
  
      RESULT
  ----------
          -1
  
  SQL> 
  

• How to use formulas to extract a picture from the base of the summary sheet

  Hi, I have a database of over 1,000 products. each has a picture. and I want to extract the picture of a product to see the summary of this product. And I hope

  and every time I change the name of the product indicates the corresponding picture in his column. I tried the lookup function, but is does not work. I used the DRAG & DROP

  to put the photo in the database. How can I solve this problem? Thanks Yanni [email protected]

  

  Hi Tulip.

  What you ask is likely not possible in number.

  Cells in a table of numbers can act as "containers" for images. Images can be placed in the cells only as a 'picture fill", which is the 'format' rather than 'content '.

  'Format' can be changed by using a formula.

  You might try experimenting an AppleScript script to copy the actions you would take to make the transformation thi "by hand." While such a solution may be possible, it is not one that I can recommend.

  To include images that can be changed according to what data are placed in another field in the record, you will need to probably upgrade the capabilities of "Manager of the list" numbers to a real database application, like FileMakerPro, making fields "container" include that can contain an image 'data' rather than 'filler '.

  Kind regards

  Barry

• First HP: help using the command CAS.solve (STRING1, STRING2) within a program

  Hello and hope you can help me with my problem!

  I write a somewhat complicated program (operating mode no case) who has a subroutine called STSOLVE where his entry is always a string from the main program that contains a formula as "'I' = 'V' / 'R', 'R'" and its goal is to replace all the variables contained in "" to the compatible standard CASE generated automatically variable (teiXX where XX is a unique number) and then use the command solve to assess this formula (say final temporary formula "tei1 = tei2 / ') tei3, tei3"). Before returning, he replaces the temporary variables, generated automatically with the original on the result, so the original formula will be sent back solved in the main program.

  My problem:

  It returns the result {UNDEF} or simply {} even in expressions that absolutely work if used with the command solve manually, in the main screen of calculators CASES when the CAS.solve command is used either! Even though I know that the entry of this order is correct according to the tutorials I've read in the forums, I can't work properly.

  I tried all methods of writing the order and I only managed to get a result when I wrote this:

  RPART1: = cas.expr (RPART1);

  RESLT: = case. Solve (RPART1, "tei2");

  .. .or RPART1 contains, say, the part 'tei1 = tei2/tei3' (NOT AS A STRING!) and "tei2" SHOULD be written as shown here, a chain, entered manually just for test (can be 'tei1' or 'tei3' too for this particular case). However, if I put "tei2" in RPART2 of local variable in the subroutine as a string and then pass this variable to the solve command, say:

  RPART1: = cas.expr (RPART1);

  RESLT: = case. Solve (RPART1, RPART2);  RPART2 contains the string "tei2", "tei1" or "tei3.

  Here again, I get a {} as a result!

  I tried so already a lot of things that I don't know exactly what mention here, but I hope I described the main situation enough to start detailed and of course, I'll give you any other information you might need to give me more help. I tried to paste the entire subroutine, or even the entire program, but I don't have any windows pc to connect the first HP and copy the program. I am writing from an Android Tablet and I should maybe type the everything here is not very easy, I will of course if you ask.

  Perhaps, I should also note that the generated vars tei1, tei2 etc. do not exist as variables in the calculator, but if I copy channels same as the program tries to run in the command CAS.solve and manually write in case screen (not a string of course) then they get solved without problems.

  Hope to get help and learn from you and I wish I could found more help about it online, but it seems very difficult and also all the tutorials I found on the cas.solve command in the programs did not work in my case!

  Andreas

  It works, or is this not the problem?

  CAS.solve ("tei1 = tei2/tei3", "tei2");

  I get output: {tei1 * tei3} which is correct.

• Since I have downloaded 8.0.1 pinch zoom does not work anymore. How to solve this?

  Since I have downloaded 8.0.1 pinch zoom does not work anymore. How to solve this?

  You can restore the zoom feature by changing the related values of downtown on the topic: config page.

  • Browser.Gesture.Pinch.in -> cmd_fullZoomReduce
  • Browser.Gesture.Pinch.in.Shift-> cmd_fullZoomReset
  • Browser.Gesture.Pinch.out-> cmd_fullZoomEnlarge
  • Browser.Gesture.Pinch.out.Shift-> cmd_fullZoomReset
  • Browser.Gesture.Pinch.Latched-> false

  To open the topic: config page, type Subject: config in the address bar (address) and press the 'Enter' key, as you type the url of a Web site to open a Web site.
  
  If you see a warning then you can confirm that you want to access this page.

  • Use the filter at the top bar of the on: page config to more easily spot a preference.
  • Preferences that have changed also show "BOLD" (user set).
  • Preferences can be reset to the default value using the context menu if they are set of users
  • Preferences can be changed via the context menu: Edit (string or integer) or toggle (Boolean)

• HP problem first Solver (bug?)

  Solve (r = f ^ (a - ln (f)), f)

  correctly gives the solution f = e ^(quad formula)

  BUT, if I replace the 'a' in the above with any number between 0 and 1, for example, solve (r = f ^ (0, 5 - LN (f)), f), it gives an incorrect answer.

  What it does is to replace the 1/2 power in the quadratic formula, by a multiple of 1/2 instead - IE. Instead of

  e ^ (b + (c)^(1/2)) (correct answer).

  It gives

  e ^ (b + (c)*(1/2)) (it wrong - this simplifies down to something like d * r for some d - and it took me a long time to find what she does!)

  is this a bug with the command solve or I just hurt?

  I noticed a similar problem when solving 2nd order of. When simplifying a solution (using the display button 'to increase'), he sometimes changes things like e ^(x*3) in e ^(x^3). Unfortunately I don't have a simple example of it yet!

  Three things here.

  First of all, it's really not a good idea to use tiny e as a variable because that could also be interpreted as e ^ 1 and it can be confusing, that's who. Second, when you put an approximate value as 0.5 you no longer are not a symbolic resolution. Like most systems of CASE 1.  is interpreted as "an approximate 1 floating-point value" and not "and exact symbolic whole." You should do an "exact (0.5)' instead.5 or well" 1/2 "directly.". "

  Thirdly, I think you may have spotted a problem. Well, this has already been resolved and runs a connectivity kit update, you will have the version the most recent where it works correctly even solve approximately.

• By using the Greek letter on solve!

  Hi guys,.

  Maybe it is a common task, but I have a question. is not possible to use the Greek letter on solve?

  I tried to enter Greek letters, but I can't do it, the answear solve that isn't a good argument!

  Is this possible?

  Yes, you can.

  However, don't forget that the first he wants currently variables exist * before * they are used for the first time. There are two ways to create what will be most useful to you.

  1 store a value in the variable in the home screen. For example, enter AΔ: = 0 in the home screen, and then press ENTER. Then, it will ask "do you want to create a variable called AΔ. Press OK. You can now use AΔ in Solver as a variable. If you press VARS, you'll see under the menu button "user".

  2. If you want the variable to remain around permanently, you can add it to the request and that it becomes a variable defined by the user. To do this, go the the implementation of the resolution (or the saved copy of it) and go to the screen of programs (SHIFT-1). Select the first item in the list marked a label (App). You can now add in "EXPORT AΔ;" to the top line. This will create a user variable called AΔ which is part of the request. It will show the key VARS, the APP-> < AppName >-> program.

  Now you can use AΔ in your formula.

  Remember that A - Z and theta are "predefined" and always there. That is why those who work without any additional steps.

• 3.5 numbers formula "name of the journal.

  He continues to be for me that I need to access the name of a worksheet in a formula.

  The standard solution in Excel is easy to find in several focus groups.

  = Right (Cell("filename",a1), Len (Cell("filename",a1)) - Find ("]", Cell ("filename", a1), 1))

  It is just as easy to understand how to put custom formulas in the cells VBA macros in order to access some of the data that had been pasted from the Clipboard by the same VBA macro. Everyone let me know where to find a documentation full of the interface of automator for the numbers, please?

  I always have a hard time to understand why these useful information are kept secret from me if want to use it as part of the Apple software?

  I don't even want for a complete solution, but just for a general idea that would allow me to continue to understand me.

  Thanks in advance!

  Could you give a general idea of the specific problem you want to solve?  A screenshot would be useful. Wayne explains how here.

  The approximate equivalent of VBA is AppleScript, which can be run in Automator, but is often performed outside the Automator too.  Seethis site for examples of automating AppleScript of numbers as well as the other iWorks applications.  There are other examples to macscripter.net, and of course in these forums.

  You can really have a script paste data and also, if necessary, insert a formula that access to these data, if you can not do UDF (user-defined functions) in number.  They are notoriously slow to no Excel anyway, so no big loss.

  We need more information about what you're trying to do.

  SG

• for loop in formula node does not

  Hello

  I; m trying to use for loop in the node of the formula, but it is does not work. I want the output (y1) product value in certain range (a and d, and of course one is smaller than d). I ' do not use primitive labview since a and d are keep changing (both are variable). I tried to put "return 0;" after the y1 equation but the error popup.

  The issue of the loop works not because it gives the last value (I average would be ""). It does not begin with an (initial) value.

  Please help me how to solve this problem...

  Pls ignore other variables not used in the equation. Thank you!! A lot

  Your code works.

  

  But why you use loop?
  You get the last value, so you can get it in a single step with x correct;

  Also why you say that can not use primitives?
  If you use wire instead of terminals or local variable States values constant.

  Y1, y1_2, y1 3 is the same values calculated differently.

  

• Cannot insert field or paste into the existing local Variable (Boolean container)

  Cannot insert field or paste into the existing local Variable (Boolean container)...  TestStand 4.1.

  It is very strange, especially since I've done it before.

  'Paste' and "insert field" selections are grayed out and disabled in the context menu.  I tried everything I could imagine and tried various combinations of positions.  I'm sure it's something simple, bu redicoulously, I can't find the redicule to solve this annoying problem issue.

  The local variable is a container of Boolean.  It has 90 elements and I need to add one more.  I can not change / rename or do something with this Local.  Must be karma (for those who know me in the LabVIEW forum).  Usually, you do a right click, insert field and that's where...  Not this one...

  Anyone seen this before?  Closing and re-opening TestStand doesn't change anything.  There is a collection in LabVIEW that feeds the local section in TestStand.

  It is a container of data custm type.  To change flags are ok (edit is allowed).  Can't think of any other valuable information...

  He finds...

  It should be edited in the Data Types...  It was not automatic after reloading the prototype of LabVIEW.

  I knew it was something stupid that I didn't...  I became close... but had not sought far enough.

  I was looking at the range of Types, but not in the file of the sequence...

  

• Error CheckExpression for a Boolean constant

  I have a LabVIEW VI, with ExpressionEdit TestStand control, in which the user will enter a constant or an expression of TS for a Boolean control. I put this text to the ExpressionEditor control using nodes TestStand ActiveX and ValidateEvaluationType. It works without any problem. The next step will be CheckExpression, which actually gives the same error for the correct values. Even if the expression is a simple true or False, error information are expected Boolean or string or FALSE or TRUE, or..., find number {comma floating 64}. How is - it possible and how do I fix this?

   

  Thank you

  George S

  Hi Doug,.

  I solved the problem. I had used the joint box as one of controls & so to add its values (FALSE, TRUE, MIXED), as AdditionalEvaluationConstants in the ExpressionEdit ActiveX control. Since in the next step, I enter False for another Boolean control, this fake is associated with constant evaluation of the joint box (which is in fact a numeric type) resulting in a type mismatch error. Now, I've removed the AdditionalEvaluationConstants after Mixed checkbox is selected & now the Boolean True/False is detected correctly & there is no error. Thank you for your help.

  Thank you

  George S

• Disable/force Boolean controls

  Suppose I have two Boolean controls A and B.

  Now I would like to diseble control B and force it to false when A = true.

  I know I can do it by changing properties (value and disable) B control via a "property node.

  Am I wrong?

  Now, what happens if both controls are integrated in a cluster? I'm still able to disable one of them according to the value of the other?

  Hi tommpogg,

  to solve this puzzle for everyone else: right-click the control on the front (!) and select "create-> property node.