Support SQL parameters and a non-existent column

Similar Questions

• BlackBerry Z10 impossible access contacts or messages and the non-existent hub

  I got a Z10 now and during the installation I noticed that if I clicked on the "contacts" or "text messages'icons are not." I thought when I transferred all the data from my old divide that would correct itself, but it does not.

  None of my contacts or forwarded messages, and I Redid the transfer twice. My call log was transferred, but all entries are number only, no names. And I can't seem to be able to add these numbers to my contacts. I can't even enter the contacts and enter all my previous Info manually.

  I have no hub blackberry either and I asked the people who are in the same room to send me messages but I don't get them. I tried to reboot the device several times but nothing moves. I seem to be able to BBM surveys send, but not receive them.

  Seems that the only thing I can do is to make and receive calls and use the internet browser.

  Can any ideas on how I fix? I will go back to the store I had the phone of the future, but really looking for some information at this time if possible.

  Thank you.

  G

  Hi G and welcome to the community of BlackBerry Support Forums!

  Have you made software updates on your BlackBerry Z10? If this is not the case, there may be one available. You can do the update through the BlackBerry Link with your device, or by going to settings > software updates on the device itself.

  Thank you.

• ROLLUP and display Non-existing lines

  This query generates the results except that I wish I had a total average and overal final (excluding the GPA 'No'). Shown that XXX in the sample output. Is it possible in a single query, or do I need the Union for the summary?
  
  In addition, if possible, how can I write instructions so that the lines that doesn't exist may not be not can be displayed on the output? Example: he has no GPAs in the range of 0.1 to 0.9. My query results show not the first two rows, however, users would like to see these lines displayed regardless of the existence or not.
  

              
  GPARange            Count  Avg
                              
  0.1 - 0.6  (F )            0      0.00
  0.7 - 0.9  (D-)            0      0.00
  1.0 - 1.2  (D )            1      
  1.3 - 1.6  (D+)            1     
  1.7 - 1.9  (C-)            4      
  2.0 - 2.2  (C )           20    
  2.3 - 2.6  (C+)           81
  2.7 - 2.9  (B-)          189
  3.0 - 3.2  (B )          387
  3.3 - 3.6  (B+)          452
  3.7 - 4.9  (A )          316
  NO GPA                   271
  TOTAL                   XXXX    X.XX

  SELECT academic_period, 
         stu_population, 
         College,  
          CASE 
              WHEN ((MBA_GPA)) <= 0.6 then '0.1 - 0.6 (F )' 
              WHEN ((MBA_GPA)) <= 0.9 then '0.7 - 0.9 (D-)' 
              WHEN ((MBA_GPA)) <= 1.2 then '1.0 - 1.2 (D )'
              WHEN ((MBA_GPA)) <= 1.6 then '1.3 - 1.6 (D+)'
              WHEN ((MBA_GPA)) <= 1.9 then '1.7 - 1.9 (C-)'
              WHEN ((MBA_GPA)) <= 2.2 then '2.0 - 2.2 (C )'
              WHEN ((MBA_GPA)) <= 2.6 then '2.3 - 2.6 (C+)'
              WHEN ((MBA_GPA)) <= 2.9 then '2.7 - 2.9 (B-)'
              WHEN ((MBA_GPA)) <= 3.2 then '3.0 - 3.2 (B )'
              WHEN ((MBA_GPA)) <= 3.6 then '3.3 - 3.6 (B+)'
              WHEN ((MBA_GPA)) >  3.6 then '3.7 - 4.9 (A-)'
              WHEN ((MBA_GPA)) is null then 'No GPA' 
          ELSE
              'What Happened'
         END as GPARange,
         count(id), round(avg(mba_gpa),2) AVG_GPA
  FROM gpa_stat
  where stu_population='F'
  and academic_period ='200940'
  GROUP BY  stu_population,  
            academic_period,
          CASE 
              WHEN ((MBA_GPA)) <= 0.6 then '0.1 - 0.6 (F )' 
              WHEN ((MBA_GPA)) <= 0.9 then '0.7 - 0.9 (D-)' 
              WHEN ((MBA_GPA)) <= 1.2 then '1.0 - 1.2 (D )'
              WHEN ((MBA_GPA)) <= 1.6 then '1.3 - 1.6 (D+)'
              WHEN ((MBA_GPA)) <= 1.9 then '1.7 - 1.9 (C-)'
              WHEN ((MBA_GPA)) <= 2.2 then '2.0 - 2.2 (C )'
              WHEN ((MBA_GPA)) <= 2.6 then '2.3 - 2.6 (C+)'
              WHEN ((MBA_GPA)) <= 2.9 then '2.7 - 2.9 (B-)'
              WHEN ((MBA_GPA)) <= 3.2 then '3.0 - 3.2 (B )'
              WHEN ((MBA_GPA)) <= 3.6 then '3.3 - 3.6 (B+)'
              WHEN ((MBA_GPA)) >  3.6 then '3.7 - 4.9 (A-)'
              WHEN ((MBA_GPA)) is null then 'No GPA' 
          ELSE
              'What Happened'
         END,
            rollup(college)
  order by 1, 2, 3, 4;

  Hello

  user1069723 wrote:
  This query generates the results except that I wish I had a total average and overal final (excluding the GPA 'No'). Shown that XXX in the sample output. Is it possible in a single query, or do I need the Union for the summary?

  Yes, you can do it in a single query, using ROLLUP. You don't need a UNION.

  In addition, if possible, how can I write instructions so that the lines that doesn't exist may not be not can be displayed on the output? Example: he has no GPAs in the range of 0.1 to 0.9. My query results show not the first two rows, however, users would like to see these lines displayed regardless of the existence or not.

  That's exactly what outer joins: they display data in a table with data from a second table, if all relevant data are found. The data in the first table are displayed if there is a match. If there is no match, all the columns in the second table are set to NULL. If you want to treat NULL values as 0, use NVL, as I did when displayijng average, below.

  In this problem, which is of the first table, the table has one line per degree, which is displayed even if no line in the result set is in this range of grade?
  You should have such a table. The information on where the beaches begin and end, what letter grades are associated with each and so on, are given. Data belong to the tables, not hardcoded in queries. If next year, they decide to change where the limit between D + and C-falls, or to add a group A, an authorized user can make the change to a table. No matter how many queries use grade ranges, no programmer will need to change any question.
  Here's how you can create a table of this type:

  CREATE TABLE     GPA_Range
  AS
  SELECT  0.0 AS low_gpa, 0.7 AS high_gpa, '0.1 - 0.6 (F)'  AS display_txt, 'F'  AS letter_txt     FROM dual     UNION ALL
  SELECT  0.7 AS low_gpa, 1.0 AS high_gpa, '0.7 - 0.9 (D-)' AS display_txt, 'D-' AS letter_txt     FROM dual     UNION ALL
  SELECT  1.0 AS low_gpa, 1.3 AS high_gpa, '1.0 - 1.2 (D)'  AS display_txt, 'D'  AS letter_txt     FROM dual     UNION ALL
  SELECT  1.3 AS low_gpa, 1.7 AS high_gpa, '1.3 - 1.6 (D+)' AS display_txt, 'D+' AS letter_txt     FROM dual     UNION ALL
  SELECT  1.7 AS low_gpa, 2.0 AS high_gpa, '1.7 - 1.9 (C-)' AS display_txt, 'C-' AS letter_txt     FROM dual     UNION ALL
  SELECT  2.0 AS low_gpa, 2.3 AS high_gpa, '2.0 - 2.2 (C)'  AS display_txt, 'C'  AS letter_txt     FROM dual     UNION ALL
  SELECT  2.3 AS low_gpa, 2.7 AS high_gpa, '2.3 - 2.6 (C+)' AS display_txt, 'C+' AS letter_txt     FROM dual     UNION ALL
  SELECT  2.7 AS low_gpa, 3.0 AS high_gpa, '2.7 - 2.9 (B-)' AS display_txt, 'B-' AS letter_txt     FROM dual     UNION ALL
  SELECT  3.0 AS low_gpa, 3.3 AS high_gpa, '3.0 - 3.2 (B)'  AS display_txt, 'B'  AS letter_txt     FROM dual     UNION ALL
  SELECT  3.3 AS low_gpa, 3.7 AS high_gpa, '3.3 - 3.6 (B+)' AS display_txt, 'B+' AS letter_txt     FROM dual     UNION ALL
  SELECT  3.7 AS low_gpa, 999 AS high_gpa, '3.7 - 4.9 (A-)' AS display_txt, 'A-' AS letter_txt     FROM dual     UNION ALL
  SELECT  NULL,            NULL,             'No GPA',                         NULL             FROM dual;
  

  As always, the document everything, especially not intuitive or things potentially misleading:

  COMMENT ON COLUMN gpa_range.low_gpa IS 'Lowest numerical grade inside this range.';
  COMMENT ON COLUMN gpa_range.low_gpa IS 'Lowest numerical grade in THE NEXT range.  This value is OUTSIDE of the range';
  

  You may prefer to assign impossible low_gpa and values of high_gpa (as -2 and -1) to the line "No. GPA. It is completely arbitrary, time-consuming and potentially confusing, but he'd reach out more easily.

  If you cannot create such a table, you can use a subquery that is almost identical to the CREATE TABLE statement above in all the requests he needs.

  This is the main query to do what you asked:

  WITH      interesting_gpa_stat     AS
  (
       SELECT     college
       ,     mba_gpa
       FROM     gpa_stat
       WHERE     stu_population     = 'F'
       AND     academic_period     = '200940'
  )
  ,     all_colleges     AS
  (
       SELECT DISTINCT     college
       FROM             interesting_gpa_stat
  )
  SELECT        c.college
  ,        r.display_txt           AS gparange
  ,        COUNT (s.college)             AS count
  ,        NVL ( AVG (s.mba_gpa)
              , 0
              )               AS avg
  FROM                all_colleges          c
  CROSS JOIN        gpa_range          r
  LEFT OUTER JOIN        interesting_gpa_stat     s     ON (     c.college     =  s.college
                                              AND     r.low_gpa     <= s.mba_gpa
                                            AND     r.high_gpa     >  s.mba_gpa
                                         )
                                OR (     c.college     =  s.college
                                   AND     r.low_gpa     IS NULL
                                         AND     s.mba_gpa     IS NULL
                                         )
  GROUP BY  ROLLUP ( c.college
                    , r.display_txt
             )
  ORDER BY  c.college
  ,            r.display_txt
  

  Without the data from the sample and the results desired from these data, I had to make several assumptions.

  For example, I assumed you wanted to have several colleges in the same result. For each college, there will be a production line for all ranges of quality in the gpa_range table, regardless of whether if any matches are found in the gpa_stat table. It's okay if it is the only College if the result set.

  The query includes a total for each college and set a total for all the results.

  No filtering (e.g. stu_population = 'F') needs to be done in the subquery interesting_gpa_stat. You could get without the subquery, but filtering conditions that would be in the WHERE clause would have to be added to outer join conditions.

  NULL values are ignored in all global funcitons, so nothing special has to make the lines remain in the group "No GPA" to distort averages. The NVL function 0 presents itself as average when no grades were found in other lines always cause this average to apperar 0 in 'No GPA' lines, too. If you prefer NULL in this column, then place the NVL inside a CASE expression.

  Published by: Frank Kulash, 28 June 2009 05:03

• pl sql join and select the join columns. """" t"" c": invalid when debugging

  I noticed the error to the cc. Countries that appears because cc is not yet there at compile time (I had that
  Search this forum).
  
  is it not a small bit of developer of sql oracle is not a compilation from the outside to the inside/core but
  rather in the form of top-down?
  
  I'm fine with my conclusion? If so, how to do otherwise, that is, by specifying that cc.country is
  a column of countrycodes attached with table 6?
  
  
  SELECT DISTINCT 0,
  2,
  SUBSTR ("metable', 0, 1"): "_ABC";
  "ABC_". "metable,"
  "ABC". CC. country,
  '+'
  FROM table 6
  LEFT JOIN COUNTRYCODE cc
  ON cc. Code = metable
  WHERE metable IS NOT NULL
  AND <>metable "

  OK, but this:

  SELECT DISTINCT 0,
  2,
  SUBSTR('metable', 0, 1) || '_ABC',
  'ABC_' || 'metable',
  'ABC ' ||cc.Country ,
  '+'
  FROM table6
  LEFT JOIN COUNTRYCODE cc
  ON cc.Code = metable
  WHERE metable IS NOT NULL
  AND metable ''
  

  Is not a correct SQL statement - there are very obvious errors, so the error you get is maybe not quite relevant.

  It works:

  SELECT COUNT(cc.Country)
  FROM table6
  LEFT JOIN COUNTRYCODE cc
  ON cc.Code = metable
  WHERE metable IS NOT NULL;
  

  So, get a simple query that works first.

• Concatenate two columns and store it in the existing column

  Hi all

  I created a form based interactive report and need help on that. In the report, I want to display a column with label the CANDIDATE's FULL NAME by concatenating the existing columns in the same table.

  Am mentioning the details and the following questions:

  Table name: CANDIDATE_DETAILS

  Column 1: CANDIDATE_FNAME (first name) Data Type: CHAR (50)

  Column 2: CANDIDATE_LNAME (family name) the data type: CHAR (50)

  Column 3: CANDIDATE_FULLNAME (full name) Data Type: CHAR (100)

  If in the case of column 3 that is, CANDIDATE_FULLNAME is not created in the database, I could have written in query to create one using the concatenation of columns 1 and 2 of the column

  ALTER TABLE CANDIDATE_DETAILS ADD CANDIDATE_FULLNAME TANK (100 CHAR)

  AS (CANDIDATE_FNAME |) ' ' || ( CANDIDATE_LNAME)

  Since then, I have already created CANDIDATE_FULLNAME column, I just change or simply store the concatenation of Column1 and Column2. I tried to use under request, but his does not work:

  ALTER TABLE CANDIDATE_DETAILS

  CHANGE CANDIDATE_FULLNAME ACE (CANDIDATE_FNAME |) ' ' || CANDIDATE_LNAME)

  Also I'm checking the code under SQL Workshop-> SQL commands by entering the query below and his works fine.

  Select CANDIDATE_FNAME. ' ' || CANDIDATE_LNAME

  of 'CANDIDATE_DETAILS '.

  but do not know where to enter this code in "The Page Creator" that without creating an additional column in the database my needs can be met.

  Please let me know if you need more information and really appreciate any assistance.

  Thank you

  Verhasselt

  Hello

  If the requirement is to display the columns and their contents concatenated in a third, you can try this:

  1. create a new column in the report by adding code to the selection of the report:

  Select CANDIDATE_FNAME, CANDIDATE_LNAME, "'"CANDIDATE_FULLNAME"'CANDIDATE_DETAILS'"

  2. in the page editor, select the "CANDIDATE_FULLNAME" column and his correspondents "formatting of column" > "HTML Expression" describe what you like:

  #CANDIDATE_FNAME # #CANDIDATE_LNAME #.

• Force evaluation of the rules for the non-existent entities and unknown attributes...

  Hi all
  
  I have another issue potentially easy for the gurus of the OPA in this forum - there must be a simple explanation to this question but I'm just not see it.
  
  The problem that I am having with several of my rules, it's that the conclusion is not evaluated due to the non-existent entity instances or unknown entity attributes. As an example of the first scenario, I have a rule that checks for the existence of an instance of an entity with a type and status. The conclusion is evaluated as if there is at least an instance of this entity, otherwise, the conclusion remains unknown.
  
  Similarly, I wrote an equation to annualize all its (financial) obligations in a case, where the frequency of the obligation can be weekly, fortnightly, monthly, etc.. I created an attribute for each type of frequency, which are then added to the equation. The issue in this example, is that the equation does not conclude if there is not a value for each attribute in the equation. For example, if:
  
  assign 1 = A + B + C
  
  where A = 1, B = 2 and C is unknown, does not examine the attribute from 1 to 3, but will remain unknown. Logically, I expect that the lack of a digital defaults to 0, and rather unknown attribute value, but this is not the case.
  
  I looked at the 'Certain and known operator rule examples' help topic to try to understand how assign a value to an unknown attribute, but the example at the bottom of the topic page does not provide a sufficient explanation as to how the logic:
  
  point of the total team = team 1 round points + points of the round 2 team + team of turn 3 points
  
  the team of the round 1 points = 0 if
  Round 1 team points (such as recorded by the team) is unknown
  
  the team from round 2 points = 0 if
  etc.
  
  It seems from the example that there are 2 attributes used to the same variable: [team of the Tower, 1 points] and [team of the round 1 points (such as recorded by the team)]. It is not clear to me how the original equation can be concluded if the values are stored in the alternate attribute [points of the round 1 team (such as recorded by the team)] etc.
  
  I have also considered using fragments of rule by the help topic "Prove an attribute using multiple rules", while I could use two equations separated to set the value of an attribute according to the circumstances, that is to say:
  
  assign 1 = A + B + C
  
  1 = 0 if attribute
  attribute 1 is unknown
  
  This attempt results in a logic loop error, probably because I am trying to set the value of an attribute based on the same attribute value.
  
  Any help will be greatly appreciated!
  Philippe

  Hi Philippe,.

  I suggest the following way to solve this problem, although there are other ways too.
  You can use a table of rules for it.

  Open a Working Document, and then press 'Alt + Z' created a rules table.

  Use the following rule: -.
  Keep the text in bold in the left-hand column and the text in italics as a condition for the title in the right column. Use a correct indentation during the compilation of the rules.

  -------------------------------------------
  Attribute 1
  -------------------------------------------
  *0*     any
  A is unknown or

  Uncertain East
  and
  any
  B is unknown or
  B is uncertain
  and
  any
  C is unknown or
  C is uncertain
  ----------------------------------------------
  Has any     
  B is unknown or
  B is uncertain
  and
  any
  C is unknown or
  C is uncertain
  ----------------------------------------------
  A + B C is unknown or     
  C is uncertain
  -----------------------------------------------
  A+B+C in the opposite case     

  Thank you
  Sofiane

• Try the following: where is my profine stored? It will take you to non-existing buttons etc. It is for the most part iof support.

  This is a general problem: 'help sysytem' structure has been changed (perhaps in part I dion can't Koe) then the flow of questions from the ends up to non-existent (existing is more..) tips, suggestions, or instructions set how, not more existing or operating.
  Very frustrating.
  I raise my profile under Linux on the terminal with something like "find - name *.mab"and got it in a split second." None of the ways suggested later in the help worked!
  This is a general question for site designers, thanks for help [actually: it's the Help menu...]. Welcome,
  Giancarlo.
  Please follow the trail of help: you will get what I say, sorry. g.

  @Zenos. Thank you very much for your screenshot, which solved the issue.
  I have a Tundebird for Linux version, which, as far a s I see, is somewhat different from what you have. The previous version had not all submenus as you show, however, he recent update I made 'my' Thunderbird earned him almost to what you posted simply we had different programs.
  I suggest that it closed the thread. Thaks to all to help.
  Giancarlo.

• I am retiring this year and want to know how close my Adobe company account permanently as it will be attached to a non-existent address

  I am retiring this year and want to know how close my Adobe company account permanently as it will be attached to a non-existent address

  Hello

  IF you have an individual subscription creative cloud you can refer simply to manage your Adobe Creative Cloud membership

  In case you have a subscription to the team and you wish to cancel, you must contact Adobe customer for cancellation. Also if you want to discount the team membership to someone else that can be done as well.

  Team cloud Creative Live subscription, you can refer to manage your creative cloud Adobe for the membership of the teams. for the change of the admin

  If you bought through Adobe re seller then you need contact customer contact customer service Adobe to change to admin

• I have a serial number and product code the product disc, but cannot download my Adobe Photoshop CS6 on my Macbook Pro.  All the instructions say "double-click install.app" but this seems to be a non-existent option on my computer.  I even bought a Super

  I recently bought a Macbook Pro and can not download my Photoshop CS6 extended.  I have a serial number and product code the product disc, but, but still am not able to download my product.  All the instructions say "double-click install.app" but this seems to be a non-existent option on my computer.  I even bought a drive USB superdrive for the sole reason to put in my product directly drive download and it does not work either.

  I also tried to install directly from the site Web Adobe - my serial code was denied, but I only used it on my old laptop, so it is supposed to work again.

  It seems equally clear that Adobe did the download of older products as difficult as possible for past clients.  This is ridiculous. I spent hours trying to get this to work and have gotten nowhere.  Does anyone have advice for me?

  It is not known if you encounter a problem downloading or installation problem, but it looks to be an installation problem.

  If it's really a problem downloading, file links are below.

  Available downloadable Setup files:

  • Suites and programs: CC 2014 | CC | CS6 | CS5.5 | CS5 | CS4, CS4 Web Standard | CS3
  • Acrobat: DC | XI, X | 9,8 | 9 standard
  • First Elements: 13 | 12 | 11, 10 | 9, 8, 7
  • Photoshop Elements: 10, 11, 12, 13. 9,8,7
  • Lightroom: 6| 5.7.1| 5 | 4 | 3 | 2.7 (win),2.7 (mac)
  • Captivate: 8 | 7 | 6 | 5
  • Contribute: CS5 | CS4, CS3

  Download and installation help links Adobe

  Help download and installation to Prodesigntools links can be found on the most linked pages.  They are essential; especially steps 1, 2 and 3.  If you click on a link that does not have these listed steps, open a second window by using the link to Lightroom 3 to see these "important Instructions".

  window using the Lightroom 3 link to see these "important Instructions".

• List of all existing columns and then format and data format?

  Hello gurus,
  
  I'm new to OBIEE and I have an obligation to check the format of the column and the format of data for all of the existing column while generating an analysis report. Y at - it anyway I can enumerate all the columns that are exposed and there list column format and the format of data?
  
  To check the column individual properties I know there is an option called 'Properties of the column' but want to know that all at once to go.
  
  Kindly help me and thanks in advance.
  
  Thank you

  I do not think that you have nothing in his answers to get this, go to the repository and utilities-> dictionary of metadata generate giving columns and the data type.

  Assign points if it helps

  ~ Srix

• Support for non-EXISTENT slate TPT

  It's amazing the number of negative threads I have seen/created myself regarding slate TPT and Lenovo has not yet responded to any of them.

  I never thought I'd be THAT disappointed by Lenovo. You guys have always exceeded my expectations, but when it comes to slate TPT, you fell below my same my low standards.

  As mentioned in the thread "how to save this product", many of these problems can be solved, leaving only the development community to participate in debugging, testing and improving the existing code for these devices. More and more every day, I see devices are victims of erroneous code, incorrect test and other factors which can be corrected by the presence of many developers working on a device not just a few. Every forum I visit has the same problem. But guess what Lenovo, those who have a community of development behind them, problems and their resolution are less likely to have complainants or bad taste and the apparatus or the company that makes them.

  I find it funny that someone said to the OP, F - U on facebook because it's the holidays. Today its Christmas, next week's new year, the week after something else. Soon, the new Chinese year and who knows what else. These developers will never work on the device?

  Provide the community of development with the keys and see things quick how to turn for the better.

  TS

• How to update exists column on the table with the exact number and auto increment

  Hello

  I have a table with more than 10 million rows and there is a column called 'number_zaq', I want to update this column on line frist from 2000 and + 1 for the next all ranks.

  Update your_table

  Set number_zaq = rownum + 2000-1;

• Sort the existing column (for example: status) when the ColumnHeader click to grid VM

  Hello

  In Vsphere Webclient.

  Inventory-> grid VM:

  VMware provides a few existing columns, few are sortable such as name, State, etc on the click of columnHeader and few are not sortable.

  Is there a way to do an existing non-sortable column to the sortable?

  I wanted to do for the status"" column.

  Any help or suggestions will be much appreciated.

  Thanks in advance,

  Mayur

  If you want your newly added columns sortable, there is an example in the SDK which illustrates this.

  Please, look at the example of the chassisRackVSphere-ui .

              
              
                com.vmware.samples.chassis.column.name
                
                    
                      
                      #{name}
                      
                      
                          name
                      
                      
                      name
                      
                      name
                    
                
              
  

  The sortProperty should allow sorting. And of course your back-end service that supports. In the example, it is the chassisRackVSphere-service.

• My computer does not connect to the Internet. Event ID 7003, "the TCP/IP protocol driver service depends on the non-existent service below: IPSec."

  Hello!
  I am working on a Dell Inspiron 1300 laptop for a friend. She has Windows HP Home Edition, SP3 installed.
  He said that Saturday night he started to act funny and wouldn't connect to the Internet. There were a few popups then begins, and he did not know if they were connected to not go on the Internet.
  He had the rootkit.zeroaccess infection. I used Combofix to remove it. It won't always get on the Internet, either via a wi - fi or ethernet connection.
  Looking at the event viewer, I see event ID 7003, "the TCP/IP protocol driver service depends on the non-existent service below: IPSec."
  Then, event 7001, "(NLA) network location awareness service depends on the service protocol driver TCP/IP which could not start due to the following error: the dependency service does not exist or has been marked for deletion.".

  I copied ipsec.sys from another XP Home machine which worked and stuck in the Windows\System32\drivers directory and it still does not work.

  Any ideas are greatly appreciated!

  Dave

  Hello

  See this link:

  http://TechNet.Microsoft.com/en-us/library/cc958861.aspx

  http://www.Microsoft.com/technet/support/ee/transform.aspx?ProdName=Windows+operating+system&ProdVer=5.2&EvtID=7003&EvtSrc=Service+Control+Manager&lcid=1033

  Let us know the results.

• How can I get rid of non-existent drive (local disk Q :) that is displayed on the screen of my computer?

  original title: How do I get rid of non-existent hard disk that appears on my computer screen?

  I have a local disk (q) that loads automatically on my folder "Computer" [the folder that shows all hard drives and peripheral storage removable]. The drive does not exist and when I double click above it says "Q:\\ is not accessible access is denied." I unplugged my external hard drives, and these drives disappear from the screen by this disc remains still.  How can I get rid of him?

  I found an article from third party in which people have found a solution:

  Hide the Local disk (q) added by Office 2010 Beta

  I hope this helps! (you can back up the registry first)

  Change the settings of the REGISTRY can cause serious problems that may prevent your computer from starting properly. Microsoft cannot guarantee that problems resulting from the REGISTRY settings configuration can be solved. Changes to these settings are at your own risk

  Lisa
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.