Force evaluation of the rules for the non-existent entities and unknown attributes...

Hi all

I have another issue potentially easy for the gurus of the OPA in this forum - there must be a simple explanation to this question but I'm just not see it.

The problem that I am having with several of my rules, it's that the conclusion is not evaluated due to the non-existent entity instances or unknown entity attributes. As an example of the first scenario, I have a rule that checks for the existence of an instance of an entity with a type and status. The conclusion is evaluated as if there is at least an instance of this entity, otherwise, the conclusion remains unknown.

Similarly, I wrote an equation to annualize all its (financial) obligations in a case, where the frequency of the obligation can be weekly, fortnightly, monthly, etc.. I created an attribute for each type of frequency, which are then added to the equation. The issue in this example, is that the equation does not conclude if there is not a value for each attribute in the equation. For example, if:

assign 1 = A + B + C

where A = 1, B = 2 and C is unknown, does not examine the attribute from 1 to 3, but will remain unknown. Logically, I expect that the lack of a digital defaults to 0, and rather unknown attribute value, but this is not the case.

I looked at the 'Certain and known operator rule examples' help topic to try to understand how assign a value to an unknown attribute, but the example at the bottom of the topic page does not provide a sufficient explanation as to how the logic:

point of the total team = team 1 round points + points of the round 2 team + team of turn 3 points

the team of the round 1 points = 0 if
Round 1 team points (such as recorded by the team) is unknown

the team from round 2 points = 0 if
etc.

It seems from the example that there are 2 attributes used to the same variable: [team of the Tower, 1 points] and [team of the round 1 points (such as recorded by the team)]. It is not clear to me how the original equation can be concluded if the values are stored in the alternate attribute [points of the round 1 team (such as recorded by the team)] etc.

I have also considered using fragments of rule by the help topic "Prove an attribute using multiple rules", while I could use two equations separated to set the value of an attribute according to the circumstances, that is to say:

assign 1 = A + B + C

1 = 0 if attribute
attribute 1 is unknown

This attempt results in a logic loop error, probably because I am trying to set the value of an attribute based on the same attribute value.

Any help will be greatly appreciated!
Philippe

Hi Philippe,.

I suggest the following way to solve this problem, although there are other ways too.
You can use a table of rules for it.

Open a Working Document, and then press 'Alt + Z' created a rules table.

Use the following rule: -.
Keep the text in bold in the left-hand column and the text in italics as a condition for the title in the right column. Use a correct indentation during the compilation of the rules.

-------------------------------------------
Attribute 1
-------------------------------------------
*0*     any
A is unknown or

Uncertain East
and
any
B is unknown or
B is uncertain
and
any
C is unknown or
C is uncertain
----------------------------------------------
Has any     
B is unknown or
B is uncertain
and
any
C is unknown or
C is uncertain
----------------------------------------------
A + B C is unknown or     
C is uncertain
-----------------------------------------------
A+B+C in the opposite case     

Thank you
Sofiane

Tags: Oracle Applications

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