the list of numbers between two columns

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• Numbers between two columns

  Hello

  I would like to create sequential numbers between these two columns of the specified table.

  Existing data in the table

  Column1	Column2
  5	7
  13	14
  18	19
  24	27
  29	29

  power required:

  5

  6

  7

  13

  14

  18

  19

  24

  25

  26

  27

  29

  Could someone help me with this please.

  Thank you.

  XQUERY solution:

  with

  data in the form of

  (select 5 Column1, Column2 7 Union double all the)

  Select 13,14 in union double all the

  Select 18,19 Union double all the

  Select 24,27 Union double all the

  Select double 29,29

  )

  Select n

  data,.

  XMLTable)

  "xs:integer ($s) at xs:integer ($e).

  passing of Column1 as "s",.

  Column2 like 'e '.

  columns

  path number n '. »

  )

  /

  N
  ----------
  5
  6
  7
  13
  14
  18
  19
  24
  25
  26
  27

  N
  ----------
  29

  12 selected lines.

  SQL >

  SY.

• Need help on the list of months between two Dates

  Hi all
  
  I have a table which has startdate and enddate and need a select to list all the months between these two dates for each given ID.
  I did some tests and could not figure out how to get the startdate and enddate table (instead of hard coding) tests in the select statement.
  
  Could someone please help on this (Oracle 11 g 2),
  Thanks in advance!
  
  
  

  create table testing(
  id          number,
  start_date  date,
  end_date    date);
  insert into testing values(100, to_date('05-FEB-2011', 'DD-MON-YYYY'), to_date('28-MAY-2011', 'DD-MON-YYYY'));
  insert into testing values(200, to_date('20-JUN-2011', 'DD-MON-YYYY'), to_date('28-DEC-2011', 'DD-MON-YYYY'));
  commit;
  
  select * from testing;
  
          ID START_DAT END_DATE
  ---------- --------- ---------
         100 05-FEB-11 28-MAY-11
         200 20-JUN-11 28-DEC-11
  
  Elapsed: 00:00:00.01
  
  *for testing.id = 100:*
  select to_char(add_months(to_date('05-FEB-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
   from (select level l
         from dual
      connect by level <= months_between(trunc(to_date('28-MAY-2011', 'DD-MON-YYYY'), 'MONTH'),
                                         trunc(to_date('05-FEB-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);
  
  DATES
  -----------------
  2011-Feb
  2011-Mar
  2011-Apr
  2011-May
  
  Elapsed: 00:00:00.01
  
  *for testing.id = 200:*
  select to_char(add_months(to_date('20-JUN-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
   from (select level l
         from dual
      connect by level <= months_between(trunc(to_date('28-DEC-2011', 'DD-MON-YYYY'), 'MONTH'),
                                         trunc(to_date('20-JUN-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);
  
  DATES
  -----------------
  2011-Jun
  2011-Jul
  2011-Aug
  2011-Sep
  2011-Oct
  2011-Nov
  2011-Dec
  
  7 rows selected.

  SQL> select * from testing
    2  /
  
          ID START_DAT END_DATE
  ---------- --------- ---------
         100 05-FEB-11 28-MAY-11
         200 20-JUN-11 28-DEC-11
  
  SQL> select  id,
    2          to_char(add_months(start_date,column_value - 1),'YYYY-Mon') dates
    3    from  testing,
    4          table(
    5                cast(
    6                     multiset(
    7                              select  level
    8                                from  dual
    9                                connect by add_months(trunc(start_date,'MM'),level - 1) <= end_date
   10                             )
   11                     as sys.OdciNumberList
   12                    )
   13               )
   14    order by id,
   15             column_value
   16  /
  
          ID DATES
  ---------- --------
         100 2011-Feb
         100 2011-Mar
         100 2011-Apr
         100 2011-May
         200 2011-Jun
         200 2011-Jul
         200 2011-Aug
         200 2011-Sep
         200 2011-Oct
         200 2011-Nov
         200 2011-Dec
  
  11 rows selected.
  
  SQL> 
  

  SY.

• How to write a query for the data exchange between two columns?

  How to write a query for the data exchange between two columns?
  
  I tried a request, does NOT work.
  

  update tmp t1 set t1.m1=t1.m2 and t1.m2=(select t2.m1 from tmp t2 where t2.student_id = t1.student_id)

  Thank you.
  
  Published by: user533361 on October 23, 2009 14:04

  Just plain and simple:

  update tmp t1
   set t1.m1=t1.m2,
       t1.m2=t1.m1
  /
  

  SY.

• How to view the menu of bookmarks in two columns

  Firefox 3.6.7 under Windows 7. I wish I had the menu bookmark appears in two columns to avoid the bottom of the scroll list.

  Sorry, it's not a function for this integrated into Firefox.

  See if this extension fits your needs.
  https://addons.Mozilla.org/en-us/Firefox/addon/74381/

  Read all the comments from the user before installing it, there might be a problem on Win7 or with later versions of 3.6. versions #.

• Dynamic calculation of the number of days between two dates in a table

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  Hi BO123,

  BO123 wrote:

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  one of the way to do this by calling ajax on change of end_date.

  See the sample code given below to fetch the resulting duration and making the field read only after calculation

  Step 1: Change your page

  under CSS-> Inline, put the code below

  .row_item_disabled {
    cursor: default;
    opacity: 0.5;
    filter: alpha(opacity=50);
    pointer-events: none;
  }
  

  Step 2: Create on demand Ajax process I say CALC_DURATION

  Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call

  Declare
    p_start_date  date;
    p_end_date    date;
    p_duration number;
  Begin
    p_start_date  := to_date(apex_application.g_x01);
    p_end_date    := to_date(apex_application.g_x02);
  
     --do your calculation and assign the output to the variable p_duration
    select p_end_date - p_start_date into p_duration
      from dual;
  
    -- return calculated duration
    sys.htp.p(p_duration);
  End;
  

  Step 3: Create the javascript function

  Change your page-> the function and the declaration of the Global Variable-> put the javascript function

  You must extract the rowid in the first place, for which you want to set the time, see line 2

  assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

  See no line no 8 how set the value returned by the process of ajax at the duration column

  Replace your column to the respective column identifiers in the code below

  function f_calulate_duration(pThis) {
    var row_id  = pThis.id.substr(4);
    var start_date = $('#f06_'+row_id).val();
    apex.server.process ( "CALC_DURATION", {
    x01: start_date,x02: $(pThis).val()
  }, { success: function( pData ) {
  // set duration to duration column
  $('#f08_'+row_id).val(pData);
  // disable duration column
  $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
  });
  }
  

  Step 4: choose the end date call the javascript function

  Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below

  onchange="javascript:f_calulate_duration(this);"
  

  
  

  hope this helps you,

  Kind regards

  Jitendra
  

• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

• Thick border line between two columns

  Hello all;
  
  I have a requirement where the user must be able to distinguish between two columns hnce asking a thick line, rather than the usual 'by default'.
  
  Everything is 'Default' until then.
  I clicked on properties of the 1st column and in the section "Border", I chose "Custom" and made the right wall of the cell in black color.
  I see a thick border now, but it has eliminated the 'default' border separating lines. His party make the entire column look like a single cell.
  
  I don't want any change with the exception only of the border of a column of a black line.
  
  Any help is greately appreciated.
  
  Thank you!

  The column properties-> Options of Style CSS custom (HTML only)-> use custom CSS Style->
  the following CSS code
  border-right-width: 1px; border-right-color: green;

  or go with someone with the necessary changes

  Appreciate if you score as correct if it works

  Published by: Srini VIEREN on December 11, 2012 16:43

• List of years between two dates

  Hello

  I am new to Livecycle Designer and learning I will.

  I have a few questions related to the same question.

  1. is it possible to create a list of years between two dates, especially the exercises? (I'm in Australia so it's July 1 to June 30).

  for example

  User between two dates in date fields:

  (Start Date of the project field) July 1, 2012 and (end Date of the project field) 30 June 2015

  Have an auto list to fill out as below:

  (List)

  2013

  2014

  2015

  or ideally

  (List)

  2012/13

  2013/14

  2014/15

  linking this (if possible).

  2. is it possible to have to repeat the lines created automatically in a table for each of the fiscal years indicated in the list above?

  If either / both of them are possible help that someone could provide would be very appreciated.

  Thank you

  Ivan

  Hello

  Please find an example that shows what I think you would do here - https://workspaces.acrobat.com/?d=F9t-rLq3bapw2d-XY0dRuQ

  I ran a few test cases and did not include the error handling to keep the code as easy to read as possible.

  If you open the form and look at the code in the click event of the update button, then that's where all the magic happens.

  Hope this helps

  Malcolm

• Can I synchronize the activity of health between two watches from Apple?

  I have two Apple - one for work, one for out watches. If I change watches in the middle of the day, the follow-up of the first watch of activity is not synchronized with the second watch. Is it possible to enable this so that the follow-up activity is specific for the whole day?

  Thank you!

  N ° it is not possible to synchronize the activity of health between two watches from Apple.

• How to make the difference in percentage between two matrices?

  Hello everyone, I just want to ask how to make the difference in percentage between two binary matrices. This is to compare two images converted to matrices in LabView. Thank you.

  Well, in the current image interesting pixels are zero in the reference image. Here is a small example that would take all the zero 100% pixel, then look at the pixels of same in the other image to see how are always 0.

  Modify if needed.

  

• Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?

  Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?

  Hello

  2796614 wrote:

  Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?

  Of course, it is possible.  According to what the text file looks like to, you can create an external table that treats the text file as if it were a table.  Otherwise, you can always read the file in PL/SQL, using the utl_file package and INSERT of PL/SQL commands.

  You have problems whatever you wantt?  If so, your zip code and explain what the problem is.

  Whenever you have any questions, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the exact results you want from these data, so that people who want to help you can recreate the problem and test their ideas.  In this case, also post a small sample of the text involved file.

  If you ask about a DML operation, such as INSERT, then INSERT statements, you post should show what looks like the tables before the DML, and the results will be the content of the table changed after the DML.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

• Count the number of records between two values of keys (BTREE)

  How can I count the number of keys between two values?

  I use python driver and BTREE access method.

  = >

  Ideally, what I want is a set of whole time series data (intervals may change) to a given number of points on average. The keys are timestamps and the values are the data that it takes on average. I need to count the number of records between two timestamps so that I can divide this figure by the number of points I need and data on average. What is the best way to do it?  Or should I keep the timestamp constant intervals and use the RECNO access method?

  Thank you
  (first post btw... and why is there not a lot of people at stackoverflow that answering the questions of Berkeley DB?)

  BDB is an integrated db and there no internal counters or statistics you might grap to use for this.    You will have to do it manually.

  You can create a cursor, grap the records you want, whenever you get the next card that you bump a counter.

  If you are using RECNO, you can use a slider to obtain the number of registration (DB_GET_RECNO), and if all that you data is in

  sequentail records with no missing documents, you can find the total number of take the last rec #-original rec # + 1 to get a count.

  If you pass the SQL API, you can issue a SQL query to give you a count.  Select count (*) where...

  As you enter the data anyway, so better perhaps to count records as you go along.

  Thank you

  Mike

• find the difference in days between two dates

  Hello world
  
  I'm trying to find out the difference in days between two dates and the execution of the query that I'm passing
  
  SELECT TO_char(sysdate, 'dd/mm/yyyy') - TO_char('15/11/2011', 'dd/mm/yyyy') DAYS FROM DUAL
  
  the error I get is
  
  ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:
  
  Could someone please help.
  
  Thanks in advance

  user10636796 wrote:
  Hello world

  Thanks a lot for all the replies. I am trying to apply it in a statement to my table like this

  SELECT trunc (sysdate) - TO_char (date_last_recommended, ' dd/mm/yyyy') DAYS OF recommendation;

  SELECT trunc (sysdate) - TRUNC (date_last_recommended) DAYS OF recommendation;

• Calculate the difference in days between two Dates

  Hello

  I'm trying to understand how to calculate the difference in days between two dates using JavaScript in LiveCycle. (Minimum = JavaScript knowledge)

  Where 'Start_Date' and 'Current_Date' are the names of the two dates in the palette of the hierarchy. (the two Date/time field)

  * Current date is using the object > value > execution property > current Date/time

  I need a text or number field showing the difference in days. (Difference_in_Days)

  I noticed the following code is pretty standard among other responses:

  var

  Start_date = new Date (Start_Date);

  var

  Current_Date = new Date (Current_Date);

  var

  nAgeMilliseconds = Current_Date.getTime) - Start_date.getTime ();

  var

  nMilliSecondsPerYear = 365 * 24 * 60 * 60 * 1000 ;

  I know there is lack of code and code above are may not be not correct.

  Please notify.

  OK, that's because of the way that javascript and works of the calculate event.  The field will be filled with whatever the script resolves at the end of execution. Technically, your script does not have a value because the last thing you do is an assignment to a variable.  Change the last line as follows:

  Math.ABS ((firstDate.getTime)

  ((- secondDate.getTime (()) / (oneDay));

  (eliminate the variable assignment) and get rid of the app.alert.  Your script will "return" (have) regardless of the value of calculation from the East and which will be stored in the field.