The modbus two registers to float data conversion

Similar Questions

• I use the MODBUS library and can receive data, but I can send it very well?

  Hello

  I use the Modbus Library to communicate with a VFD to control a fan. I use the master write and read vi. I can write data to the drive mechanism and get the fan to do what I want. The VFD is supposed to send a package of confirmation after I told him to do something and I can also read its records. When debugging the VI it shows that the problem is that the buffer always reads zero and the VI timesout. If I look at the USB adapter lights to RS 485, I use to interface with the drive mechanism, I see that the flashes of light RX immediately after I send a message. So I should have something in the buffer. Does anyone have any suggestions?

  Aaron

  OK, here's what has happened to those who have this problem. In the series Receive.vi MB The bytes to the Port of property node has been reading 0 even if there was something in the buffer. Executing the program was then stuck in a loop until it expired and never went to read anything of serial port buffer. I didn't spend too much time wondering why that VI has not worked and created my own. Within a period appropriate after writing to the serial port, I used the same bytes to the Port property node and was able to get the exact number of bytes to the stream and then VISA vi the number of bytes to read. I received the message of the right answer and everything seemed good. But of course that NO! Then I experimented with different speeds of writing to the drive mechanism to get the fan to operate at different speeds. I found a small range of speeds where I get no response to the VFD, either in operation or by sending me a response packet. After a while, I found that there is a mistake in the LRC-8 code in the MODBUS library OR. It does not prescribe that the LRC will be a two-character value. So if your LRC is proving to be a single character such as F value (which should be 0F) you get an incomplete MODBUS message. This has been easily corrected in the vi LRC8 saying "number in hexadecimal string" vi to produce output with a minimum width of two. Then everything worked fine. Moral of the story, it's the MODBUS library is awkward.

• Conversion of modbus hex-data of registers to float

  Hello

  I use the modbus Protocol to read an analog value from a module.

  The webpanel of the module displays the hex value and the float value. The modbus function only returns the hex value.

  09FD is 0,780

  How can I convert the hex value returned in the float?

  There is also a modbus-funtion for this:

  public public static float GetSingle (ushort highOrderValue, ushort lowOrderValue)

  But I have tried all sorts to use it without success. (It works, but it does not return the correct value)

  Thanks for help

  
  

• Modbus: two words float

  I write the values for my meter with modbus/TCP and the set point is a float on 2 registers.

  Documentation, says this:

  Floating point parameters are 4 bytes long and are mapped to two consecutive Modbus
  registers. The floats are single precision IEEE (1 sign bit, exponent fraction of 23 bits and 8-bit) format. The
  first register contains 16 32 bits, the second register contains bit 15-0.

  The modbus library sends unsigned words, so how I break a float in two words, corresponding to the above requirements.

  Thank you!

  
  

• My laptop recognizes the drive but does show that two files named "My Data Sources" and "Bootsect.

  original title: old Hard Drive Access

  I have recently had problems with my pc, I decided that I will buy a new Tower, but I really need to get some files off the old hard drive, I bought and pregnant for the SATA drive out of my old pc. I'm now trying to get the files on my old drive through my laptop. The laptop is running Vista. My laptop recognizes the drive but does show that two files named "My Data Sources" and "Bootsect. When looking at the properties it shows that the majority of the disc is full, only 30 gigs for free the 160 GB drive. I don't understand why I can't access to find one of my old files. Help, please!

  Hello

  ·          These files are encrypted?

  Step 1: Step 1: temporarily disable the security software and check if it makes a difference.

  http://Windows.Microsoft.com/en-us/Windows-vist/disable-antivirus-software

  Note: Make sure to allow him to return so that your computer is protected.

  Step 2: Run a check disk.

  http://Windows.Microsoft.com/en-us/Windows-Vista/check-your-hard-disk-for-errors

• Receive error message when calculating the two fields with different date format

  I'm more familiar with SQL Server and Oracle, then after a search online without success, I ask here.

  I use developer PL/SQL with DB Oracle 11g Release 11.2.0.2.0 Enterprise 64-bit

  MyTable:

  ID_Number VarChar2

  Date of Date_Received

  Select ID_Number,

  Date_Received,

  To_Date (substr (ID_Number, 1.6), "YYMMDD") SentDate,.

  Date_Received - NumDays To_Date (substr (ID_Number, 1.6), "YYMMDD")

  FROM MyTable

  Where substr (ID_Number, 7.3) in ('ABC', 'ABD')

  and length (Trim (translate ((substr (ID_Number, 1,6)), '0123456789',' '))) a null value

  ID_Number Date_Received SentDate NumDays

  131002ABC1654106 10/16/10/2013-2013 14 2

  131004ABD8813899 4/12/2013-4/8/2013 4

  131014ABD1844832 10/16/10/14 OF 2013-2013 2

  Sometimes the first 6 characters in the ID_Number aren't the numbers and length (Trim (translate deletes records))

  I want just the records where NumDays > 2

  I tried to put the request in a subquery and using where NumDays > 2 outside.  I also tried using the calculation directly in the Where clause.  Without it in Where clause it works very well, with him in a place, I get the following error:

  ORA-01931: Date format picture ends before converting all of the input string

  
  

  I don't know how to put the two dates in the same format.  I tried to declare the format without result.  I don't understand how I can calculate in the selection, but do not use the same calculation in Where clause.

  Thank you for your help.

  Hello

  SQL is a language to describe the desired results.  How the system gets these results belongs to you don't have much say about which conditions will be applied when.

  One place where you can control the order of things is a CASE expression.  When you say

  CASE

  WHEN condition_1

  THEN expression_1

  END

  You can be sure that expression_1 will be evaluated only when cond_1 is set to TRUE.

  Try something like this:

  WITH got_sent_date AS

  (

  SELECT id_number, date_received

  CASE

  WHEN the TRANSLATION (SUBSTR (id_number, 1, 6)

  , 'x' 0123456789 '.

  , 'x'

  ) IS NULL

  THEN TO_DATE (SUBSTR (id_number, 1-6)

  , "YYMMDD".

  )

  END AS sent_date

  FROM MyTable

  WHERE (id_number, 7, 3) SUBSTR ("ABC", "ABD")

  )

  SELECT id_number

  date_received

  sent_date

  , date_received - sent_date AS num_days

  OF got_sent_date

  WHERE date_received > sent_date + 2

  ;

  If you would care to post some sample data (CREATE TABLE and INSERT statements) and the results desired from this data, I was able to test this.

  Of course, you'll still errors of execution if id_number starts with 6 digits, but they do not have to be valid, for example '131100' or '130229'.  This is one of the reasons why the date information storage in VARCHAR2 columns are a bad idea.  To work around this problem, see

  https://forums.Oracle.com/message/4255051

• Problem with the two EA DEVELOPER SQL DATA MODELING 3.0.0.665 and 3.1

  I created a model of very large data using SQL Developer data 3.0.0.665 and 3.1 EA maker. Its having a lot of check constraints. Whenever I am the design of the fence and the DOF and reopening export to import the DDL file failure to import completely check constraints. It is important to check constraints, but without any range of values inside. Its very frustrating because whenever you open import ddl, you must manually add again all the details of data check range constraint.
  
  OS: Windows XP.
  Check in the two EA Developer SQL Data Modeler 3.0.0.665 and 3.1
  
  -------------------------------------------
  Here are the contents of the .dmd file.
  -------------------------------------------
  * <? XML version = "1.0" encoding = "UTF - 8"? > *.
  * < OSDM_Design class = "oracle.dbtools.crest.model.design.Design" name = 'Admin_Panel' id = "9BE18B0A-6C67-2E5B-00DE-BD8312189ECB" version = "3.41" > * "
  * < createdBy > administrator < / createdBy > *.
  * < Createduserid > 2011-10-17 08:32:18 UTC < / Createduserid > *.
  * < Admin_Panel ownerDesignName > < / ownerDesignName > *.
  * < false capitalNames > < / capitalNames > *.
  * < designId > 9BE18B0A-6C67-2E5B-00DE-BD8312189ECB < / designId > *.
  * < / OSDM_Design > *.
  
  -------------------------------------------------------------------------------
  An example how the check constraints to get dirty.
  -------------------------------------------------------------------------------
  Initial check constraint is as below:
  ======================
  ALTER TABLE test_table
  ADD CONSTRAINT Active_Flag_ck
  CHECK (Active_Flag IN ('A', 'I'))
  *;*
  
  Below how it occurs once I have imported the ddl and re-export:
  ============================================
  ALTER TABLE test_table
  ADD CONSTRAINT Active_Flag_ck
  (CHECK)
  *;*
  
  I'm in trouble as I already in the middle of the my development using SQL Developer Data Modeler.
  
  Please help me soon.
  
  Jean

  Hi John,.

  Every time I'm fence design and export the ddl and reopening through the import of the DDL file

  Why are you doing this? Once the DDL file is imported and then save the drawing and open simply saved design, no need to generate the DDL and import it every time that you start Modeler data.
  On the list of values - forced as this CHECK (Active_Flag IN ('A', 'I')) are imported as constraint check plain and not as a list of values.
  There are the more specific elements import of check constraint - they are defined as type database constraint that you select during the import. Accordingly if you import your DOF as Oracle 10 g DDL, then you will get forced correct check in DDL generated for Oracle 10 g and Oracle 11 g. Constraint of evil will be generated for Oracle 9i. You can move the constraint for Oracle 9i (in the check constraint dialog box) or generic if it can be treated as such constraint.

  I logged for DOF bad bug.

  Philippe

• dynamic double bit data conversion

  It could be very simple, but I was confused. I have current data and average data as in code. I want to build the table using these data, save them on my hard drive and open in word with header (current and average)

  Problems:

  I have data from two sources in lead generation and versions table as shown entry table to write on the worksheet vi. I get the error source is dynamic and double sink is a bit. It is the most difficult part of my life to find out what range of conversion to use.

  When I run the vi (lets assume the good range of conversion is connected and there is no conversion error) pops up the dialog for path that comes up constantly on dialog

  Ideally I want appears on the screen when I press on would go so that I can browse location to save the file, and once the path is specified vi works continuously and the data is written to the worksheet while vi is running.

  Thanks a lot for reading and help

  See you soon

  Welcome to the evil world of dynamic data. What you really want to use is the merging of signals feature. When you do this a dynamic data conversion will be automatically added between the signals to merge and writing on a spreadsheet file.

  You can consider using writing to the file position as directly accepts dynamic data.

  With respect to the path, use a shift register.

• Find the median of a set of data

  I have a table that looks like this:

  Range	Set of data: range values	Data set b: range values
  0.00 - 0.99	35	67
  1.00 - 1.99	35	40
  2.00 - 2.99	49	54
  3.00 - 3.99	41	45
  4.00 - 4.99	36	38
  5.00 - 5.99	31	34
  6.00 - 6.99	22	29
  7.00 - 7.99	30	20
  8.00 - 8.99	24	16
  9.00 - 9.99	16	11
  10.00 - 10.99	15	10
  11.00 - 11.99	12	5
  12.00 - 12.99	11	1
  13.00 - 13.99	5	2
  14.00 - 14.99	5	1
  15.00 - 15.99	2	0
  16.00 - 16.99	1	0
  17.00 - 17.99	2	0
  18.00 - 18.99	1	0

  How can I find the median interval for each set of data (A and B)?

  Thanks for your help!

  Median and range are two different things from what I remember. Can you please send a link to a Web site that could describe what a "median line"?

  Median is the average of a set of data (even counting data sets usually take the average < average > the values of two intermediate points)

  Range is simply the max - min.

  Jason

• My macpro is backup in the capsule of time even when I was at work, which means that the time capsule is consumed my data plan. Can anyone suggest a way I can have it the backup only when my mac pro and time capsule is in the same local wifi

  my mac pro is backup in the capsule of time even when I was at work, which means that the time capsule is consumed my data plan. Can anyone suggest a way I can have it the backup only when my mac pro and time capsule is in the same local wifi

  If the Time Capsule and MacBook Pros are not on the same network, the MacBook is not backup in the time Capsule. You probably see what snapshots leaving MacBook on the local disk, until the two are reconnected. If you don't want that to happen, disable Time Machine on a different network.

  Good day.

• Why the parent class does not report data for child in LVOOP class?

  Attached is a practical program that I wrote to learn about the legacy with LVOOP.

  I have the impression of OOP is a Parent class describes the type of object.  Then the children inherent description of the parent.  The child may also have additional qualities, but it still contains the description of the parent.  If a child does not have a VI bearing the same name as the parent and the parent VI will be loaded and executed.

  My questions:

  (1) why does the Parent.lvclass:Read.vi not report 'Child' in the channel indicator when the child write VI has been sent?

  2) matches the data of the child, do not at all seen by the parent company even when it has the same definition (that's the String)?  I understand that the Parent do not know anything about the unique child elements, but I think we should know about the common themes which inherited the child.

  Here is my sample code:

  

  These are two different sets of data. The parent class has a data set containing the string, the class of the child also has a data set containing the string, but both of these channels are separated.

  This can be made apparent, by changing the names of the channels based on their respective categories:

  

  What you want is for your children, class VI write to access the data of the parent class. You can do this with a simple data VI member access in VI of the child:

  

• the 1900 myRIO FPGA multi channel data acquisition

  Hello world

  I would ask you for help in my program acquisition and generation of data. The main task of this program is to measure 4-channel adjustable sampling rate (2 kHz and less) and to generate an analogue signal in up to 50 kHz sampling frequency.

  I created two loops and everyone is dedicated to different operation. The first loop is to measure data, or in writing to the DMA FIFO and the second loop is dedicated to the generation of signals. I adjust the main parametrs of the two loops in a host of vi.

  But what is my problem. I compile the program in the FPGA of myRIO without any problems and I can run too but the problem is that sometimes, especially when I adjust the lower sampling frequency of the loop to measure to the rank of channel changes measured and I see that the signal that is connected to osciloskop AI0 channel on channel AI3. When I stop the program, set the higger sampling frequency and run it again, it works well and the signal is on the right channel. Could someone help me with this problem? I tried to check all the forums that I know, but I did find an article or a discussion of a similar problem.

  Thanks a lot... :-)

  Andrew,

  I just solved the problem. I thought about it again and I got the idea to change the size of the DMA buffer on the side of myRIO. I expanded the buffer of 1023 elements in 2047 and it works well and I can change the sampling without problems.

• The most effective way to log data and read simultaneously (DAQmx, PDM) high data rates

  Hello
   
  I want to acquire the data of several Modules cDAQ using several chassis to
  high data rates (100 k samples per second if possible). Let's say the measurement time is 10 minutes and we got a large number of channels (40 for example). The measured data is written to a PDM file. I guess, the memory or the HARD disk speed is the limits. For the user, there must be a possibility to view the selection of channels in a graph during the measurement.

  My question: what is the best and most effective way to save and read data at the same time?

  First of all, I use an architecture of producer-consumer and I don't want to write and display the data in the same loop. I expect two possibilities:

  [1] to use the 'DAQmx configure logging.vi' with the operation 'journal and read' to write the data to a PDM file. To display the data in a second loop, I would create a DVR samples documented and 'sent' the DVR for the second loop, where the data will be displayed in a graph (data value reference). This method has the disadvantage that the data of all channels is copied into memory. Correct me if I'm wrong.

  [2] use 'DAQmx configure logging.vi', but only with the "journal" operation to write the data to a PDM file. To view the selected data, I had read a number of samples of the TDMS file in the second loop (I'm currently writing the TDMS file). In this case, I have only one copy data from the selected channels (not), but there will be more HARD drive accesses necessary.

  What is the most effective and efficient solution in this case?

  Are there ways to connect and read data with high frequencies of sampling?

  Thank you for your help.

  You say that the measurement time is 10 minutes. If you have 40 channels and you enjoy all CHs at 100 kHz, it is quite a number of values.

  In this case, I always try to approach under the conditions of use. If a measure is only 10 minutes, I just connect all PDM data and create a graphic module that could be in the same loop of consumers where connect you the data. You can always work on the raw data files big offline afterwards, the extraction of all the information you need (have a look at the product called NI DIAdem: http://www.ni.com/diadem/)

  The main issue is that the user needs to see in the graph (or perhaps a chart can be useful too). Lets say that the graph is 1024 pixels wide. It makes no sense to show multiple data to 1024 points, Yes? Every second will produce you 100 data points k per channel. What is the useful information, which should see your username? It depends on the application. In similar cases, I usually use some kind of data reduction method: I use a moving average (Point by point Mean.VI for example) with a size of the interval of 100. This way you get 100 data points of 1000 per channel every second. If you feed your graph every second with these average values, it will be able to data points in 1024 of the store (as a default) by channel (curve), which is a little more than 10 minutes, so that the user will see the entire measurement.

  So it depends on the frequency at which you send data to the consumer. For example, collect you values 1024 by iteration of the producer and send it to the consumer. Here you can make a normal means calc or a bearing (according to your needs) and he draw a graphic. This way your chart will display only the values of the last 10 seconds...

  Once I programmed some kind of module where I use a chart and not a graph, and the user can specify the interval of the absolute timestamp that is traced. If the data size is larger than the size of the chart in pixels, the module performs an average calculation in order to reduce the number of data points. Of course, if you need to see the raw data, you can specify an interval that is small. It all depends on how you program zoom functions, etc... In my case I hade a rate of 1 Hz, so I just kept all data in RAM limiting the berries to keep 24 hours of data, so that technicians could monitor the system. In your case, given the enormous amount of data, only a file read/write approach can work, if you really need access to all of the RAW data on the fly. But I hope that the values of working capital means will be enough?

• How to read the 16 bytes directly from the Modbus?

  Hello

  I got problem about the modbus register.

  Means I have call serial No. Which is given the address of 5000 and series not is 16 bytes and each has high and low-bit bytes.

  When I call using Modbus, so I can read the only first two bytes of address 5000 (4 bits) can you guide me please how I can read my serial No. bytes. Directly using modbus.

  Maybe I'm not good enough explanation so here I have attached a diagram that redbox right side indicate serial no.which I gave.

  LHS it not show the address of the register and the 12594 value is decimal maybe and then 16 bytes bytes.each has high and low bits.

  I want to make Vi the help that I can see my # of series directly on the front.

  right now I can only see 12594 value I want, I want to no.which series, I gave side pic HHR.

  Can you please guide me how I can do...

  also, I enclose example vi that I got from forum of NOR.

  Thank you in advance...

  It's basic Boolean math.

  Read the byte.  If you want to determine the value of a particular bit, you AND another value.  For bit 0 AND it with 1 for bit 1 AND 2.  ANDing with 128 will give you the value of bit 7 (bit 8 and higher).  If the result is 0, then the bit is set to false.  If the result is > 0, then the bit is true.

  Even easier is to take the number and convert it into a boolean number table function Boolean Array in the palette of the Boolean.  Then, you can index the particular Boolean you want from the table.

• WU repeatedly installs the same two updates. KB2686828 and KB2656839.

  I am repeatedly offered the same two updates that are installed automatically. When I try to install any other optional updates, they are downloaded but do not install. When I check the update history, there is no failure message or any indication the downloaded updates tried to install. I tried to install in the clean boot state that didn't work and I tried to fork to install. The two who installed do not add and remove programs. I also tried the update fix - it who said that had changed the location data. Is there anything else I can do? Thank you.

  Hi Kathleen,.

  Did you change your computer before this problem?

  This problem occurs when one of the following conditions is true:

  (a) an error has occurred during installation. The update has not been installed.

  (b) the update has been installed. However, a file was not updated to restart the computer.

  You can follow this link & check if the isuse persists:

  Troubleshooting Windows Update or Microsoft Update when you are repeatedly offered an update

  
  Reference: How to troubleshoot Windows Update, Microsoft Update and Windows Server Update Services installation issues?

  Hope the helps of information.