The use of UTL_FILE error

I get the following error when you use the UTL_FILE procedure when using UTL_FILE. FOPEN procedure
the system account. I use Windows XP to NTFS.

SQL > create or replace directory FILE_DIR in "C:\". »
2.

Created directory.

SQL > grant read the FILE_DIR directory to the public;

Grant succeeded.

1 create or replace PROCEDURE file_upload IS
2 v_file_name VARCHAR2 (200);
3 v_file_type UTL_FILE. TYPE_DE_FICHIER;
4 v_line VARCHAR2 (1000);
5 BEGIN
6 v_file_name: = 'customers_ ' | To_char (sysdate, 'dd') | TO_CHAR (SYSDATE, 'MY'). TO_CHAR (SYSDATE, 'YYYY') |'. txt';
7 v_file_type: = UTL_FILE. FOPEN ('FILE_DIR', 'V_FILE_NAME', 'r', 1000);
8 UTL_FILE. GET_LINE (v_file_type, V_LINE, 1000);
9 UTL_FILE. FCLOSE (v_file_type);
10 DBMS_OUTPUT. PUT_LINE (V_LINE);
11 * END;


SQL > exec file_upload;
BEGIN file_upload; END;

*
ERROR on line 1:
ORA-29283: invalid file operation
ORA-06512: at "SYS." UTL_FILE", line 475
ORA-29283: invalid file operation
ORA-06512: at "SYSTEM. FILE_UPLOAD", line 7
ORA-06512: at line 1


I appreciate if someone can help me in this regard.

Thanks in advance.

Concerning
Muhammad ALi

Hi, Muhammad,

When you say

v_file_type := UTL_FILE.FOPEN('FILE_DIR','V_FILE_NAME','r',1000);

you say the name of the file to read is literally "V_FILE_NAME".
I think you have to say that the name of the file in the variable named v_file_name. If so, remove the single quotes the second argument:

v_file_type := UTL_FILE.FOPEN('FILE_DIR', V_FILE_NAME ,'r',1000);

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