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• How to link grade labor benefits

  Dear,

  I want to link grade for labour benefits 'tailor-made '. Thus, at first the user will come base per academic year salary 'where rank appears in the line.

  The user will select the shade in the section of the page, then the user will enter the amounts for each benefits from this grade. as the following table:

  6th year (Page)
  Housing - Single (pay online)	$$$$
  Housing _ married	$$$$$

  Once the user select what benefits will be affected by the position, will assign the appropriate value.

  I wrote in my original code, if declarations of instance:

  IF ("Housing_Allowances_Options" == [[Housing_Allowances_Options._Single_Housing]])

  IF ("Grade" == [[Grade.Grade_6]])

  "Housing allowances Grade"="6"-> "housing-Single;

  ENDIF

  Now, I must do this for each category and for each allocation option? they have about 22 rank and around 15 compensation - what is sense?

  Please let me know if you have any advice. Thank you in advance.

  Hello

  You can make dynamic using the numeric index and converting it to a string and then concatenate with 'rank '.

  In the definition of your smart list, make sure that your digital index is 1 for 'Grade 1', 2 for "class 2" etc. "." Then Member 'Rank' will contain, 1, 2, 3 etc. When assigned a value of smart list.

  This way you can simply do

  IF ("Housing_Allowances_Options" == [[Housing_Allowances_Options._Single_Housing]])

  "Housing allowance" = @MEMBER (@CONCATENATE (@NAME ("Grade"), @CalcMgrIntegerToString (@MEMBER ("Grade")))-> "housing-Single;

  ENDIF

  I just doubt that @CalcMgrIntegerToString (@MEMBER ("Grade")) will really assess the Member 'Rank' or go to deem it a member/string. I used the same logic for a client of mine before, but I had done a CDF to get the text value of the SmartList in the relational database from the schedule so I didn't have this potential problem.

• I shoot a video with a very good HD camcorder, unfortunately it was a very low light so now my video is very dark, but with very good exhibitions. Please can I do for this video it was 2 long hours of lighting

  I shoot a video in a very low light arena now my video is very dark is there a way I can light up to make nice please

  Have you tried this grade in Premiere Pro?

• Need help with rank-marks

  I got this task, but don't know how to do it. Can someone help me?

  • Ranks method will return an array of characters, which are the grades corresponding to the whole of brands in the table of marks. The notes are assigned using the following lower limits for the corresponding marks: for category A, the lower limit is 90; for category B is 75; for category C, it's 60; for category D, it is 50; It's class E, 45; and F is the score for all other brands. A better solution for this method would not have values for the coded hard lower limit, but would use a table for these values, which would allow for the category to change limits.
  • The gradeDistn method accepts an array of characters, which are assigned ranks for the array of brands, such as returned by the method of grades . The gradeDistn method returns an array of integers containing the distribution of ranks, which corresponds to the number of occurrences of each grade in the marks awarded. The characters used for grades have been set. The returned array should provide the distribution order of category A to category F.

  This is my code (brands is give in the code):

  public class ProcessMarks {}

  private static final int NMARKS = 125;

  private double final static average = 65.0;

  public private static final double std = 15.0;

  public static int [] getMarks() {}

  Random rand = new Random(1001L);

  int brand;

  int [] theMarks = new int [NMARKS];

  int n = 0;

  While (n < NMARKS) {}

  brand = (int) Math.round (std * rand.nextGaussian () + average);

  If (score > = 0 & & mark < = 100)

  theMarks [n ++] = marks;

  }

  TheMarks return;

  }

  public static int gradeDistn() {}

  int a, b, c, d, e, f;

  a = b = c = d = e = f = 0;

  int [] getMarks() = grade;

  for (int i = 0; i < grade.length; i ++) {}

  If (grade [i] > = 90) {}

  a = a + 1;

  }

  ElseIf (grade [i] > = 75) {}

  b = b + 1;

  }

  ElseIf (grade [i] > = 60) {}

  c = c + 1;

  }

  ElseIf (grade [i] > = 50) {}

  d = d + 1;

  }

  ElseIf (grade [i] > = 45) {}

  e = e + 1;

  }

  else {}

  f = f + 1;

  }

  }

  How to return a, b, c, d, e, f?

  }

  Public Shared Sub main (String [] args) {}

  System.out.println ("A:" + a);

  System.out.println ("B" + b);

  System.out.println ("C:" + c);

  System.out.println ("D:" + d);

  System.out.println ("E:" + e);

  System.out.println ("F:" + f);

  }

  Result should achieve:

  A: 10
  B: 30
  C: 105
  D: 75
  E: 35

  F: 10

  joker3000 wrote:

  I got this task, but don't know how to do it. Can someone help me?

  How to return a, b, c, d, e, f?

  the way of obvisual to do so is using a card (for example a hash table).

  But IMHO, you should follow a more OO as corner and create a custom class of quality who knows when starting a brand and knows also the neighbouring grade handmade brand more if it doen't belong to the real category...

  You need an instance of this class for each grade.

  The class gets method (int mark) in which objects compared the mark given with ist minPoints and increments the number when the brand is pretty good.

  The rank of class also overrides the toString method which is pronts ist name and its number.

  Then your method would return a list of objects of quality which you could get out in a loop or just simply passing to System.out.println ()...

  class Grade {
    private final String name;
    private final int minPoints = 0;
    private final Grade lesserGrade; // each grade knows about the next worse
    private int count =0;
    public Grade (String name, int minPoints, Grade lesserGrade){
    this.name = name;
    this.minPoints = minPoints;
    this.lesserGrade=lesserGrade;
    }
  
    /** if mark is lower that this grades minPoints the next worse grade tries to count it.*/
    public void count(int mark){
      if (mark >= minPoints) {
         count++;
      } else{ // when mark is not good enough for this grade try the next worse ...
       lesserGrade.count(mark);
    // this is some kind of recursion although calls are not on same object.
      }
    }
    public String toString(){...}
  }
  public List gradeDistn(){
    Grade grade=null;
    List gradeList = new ArrayList();
  
    // there is no worse grade that the worst, so its OK to pass null...
    grade = new Grade("F",0,grade);
    gradeList.add(grade); 
  
    grade = new Grade("E",45,grade);
    gradeList.add(0, grade);  
  
    grade = new Grade("D",50,grade);
    gradeList.add(0, grade);
    // add all grades the same way
  
    for(int mark : getMarks()){
      grade.count(mark); // all the magic is done in the Grade class...
    }
    return gradeList;
  }
  

  Good bye

  DPT

• Pantone value for custom spot colors

  Hello

  I'm working on a project package that was created by another agency and was picked by my agency for future prints/changes.  I am trying to label all the PMS values used in the work of the printer; However, I came across one called color, "SILVER COUNCIL KNOCKOUT".  On the original final design, it's a bright silver strip where the name of the hair dye. I assumed that this grade has been created by the previous Agency.

  
  My question is how to find the value of that color PANTONE (if possible), OR whether it would be best to choose another color of PMS equivalent? I work in Illustrator CS6 on an iMac.

  Thank you in advance!

  You can choose your own PMS, but you can convert exsiting Pantone color chart with the command reset: https://www.rockymountaintraining.com/adobe-illustrator-convert-cmyk-swatches-to-pantone/

• Need help with Oracle SQL merge records according to date and term dates

  Hi all

  I need help to find this little challenge.

  I have groups and flags and effective dashboards and dates of term against these indicators according to the following example:

  GroupName	Flag_A	Flag_B	Eff_date	Term_date
  Group_A	THERE	THERE	20110101	99991231
  Group_A	N	N	20100101	20101231
  Group_A	N	N	20090101	20091231
  Group_A	N	N	20060101	20081231
  Group_A	N	THERE	20040101	20051231
  Group_A	THERE	THERE	20030101	20031231
  Group_B	N	THERE	20040101	99991231
  Group_B	N	THERE	20030101	20031231

  As you can see, group_A had the same combination of (N, N) flag for three successive periods. I want to merge all the time periods with the same indicators in one. Where entry into force will be the most early (underlined) time period and end date will be later (underlined)

  So the final result should look like this:

  GroupName	Flag_A	Flag_B	Eff_date	Term_date
  Group_A	THERE	THERE	20110101	99991231
  Group_A	N	N	20060101	20101231
  Group_A	N	THERE	20040101	20051231
  Group_A	THERE	THERE	20030101	20031231
  Group_B	N	THERE	20030101	99991231

  Thanks for your help

  Here's the DDL script

  drop table TMP_group_test;

  create table TMP_group_test (groupname varchar2 (8))

  , flag_a varchar2 (1)

  , flag_b varchar2 (1)

  , eff_date varchar2 (8)

  , term_date varchar2 (8)

  );

  insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20110101 ', ' 99991231');

  insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20100101 ', ' 20101231');

  insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20090101 ', ' 20091231');

  insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20060101 ', ' 20081231');

  insert into TMP_group_test values ('Group_A', 'n', 'Y', ' 20040101 ', ' 20051231');

  insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20030101 ', ' 20031231');

  insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20040101 ', ' 99991231');

  insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20030101 ', ' 20031231');

  commit;

  Post edited by: user13040446

  It is the closest, I went to the solution
  

  
  

  I create two rows;

  Rnk1: partition by group name, order of eff_date / / desc: this grade will sort the records of the most recent and handed to zero for each group\

  Rnk2: (dense) partition by group name, flag_A, flagb: this grade for each combination of group\flag gives a number so that they are classified as "families".

  Then I use the function analytic min

  Min (eff_date) more (partition of GroupName, rnk2): the idea is that, for each Member of the same family, the new date is the min of the family (and the max for the date of the term), at the end I just need separate so that the duplicates are gone

  Now the problem. As you can see from the query below, records of 1 and 6 (as identified by rownum) are identified in the same family, because they have the same combination of flag, but they are not successive, so everyone must keep its own date of entry into force.

  If only I can make the distinction between these two that would solve my problem

  
  

  Query:

  
  

  Select rowNum,GroupName, flag_a, flag_b, eff_date, term_date, rnk1, rnk2

  , min (eff_date) more than (partition by GroupName rnk2( ) min_eff

  Of

  (

  Select rowNum,

  GroupName , flag_a , flag_b , eff_date , term_date

  rank() more than (partition by GroupName stopped by eff_date desc) rnk1

  DENSE_RANK() more than (partition by GroupName order by flag_A flag_B ( ) rnk2

  de dsreports . tmp_group_test

  ) order by rowNum

  Hello

  user13040446 wrote:

  Hi KSI.

  Thanks for your comments, you were able to distinguish between these lines highlight, but lost lines 2,3,4 which are supposed to have the same date min = 20060101.

  Please see the table wanted to see the final result I want to reach

  Thanks again

  This first answer is basically correct, but in the main query, you want to use the function MIN, not the analytical function aggregation and GROUP BY columns with common values, like this:

  WITH got_output_group AS

  (

  SELECT GroupName, flag_a, flag_b, eff_date, term_date

  ROW_NUMBER () OVER (PARTITION BY GroupName

  ORDER BY eff_date

  )

  -ROW_NUMBER () OVER (PARTITION BY GroupName, flag_a, flag_b)

  ORDER BY eff_date

  ) AS output_group

  OF tmp_group_test

  )

  SELECT GroupName, flag_a, flag_b

  MIN (eff_date) AS eff_date

  MAX (term_date) AS term_date

  OF got_output_group

  GROUP BY GroupName, flag_a, flag_b

  output_group

  ORDER BY GroupName

  eff_date DESC

  ;

  The result I get is

  GROUP_NA F F EFF_DATE TERM_DAT

  -------- - - -------- --------

  Group_A Y 20110101 99991231 Y

  N Group_A 20101231 20060101 N

  Group_A N 20051231 20040101 Y

  Group_A Y Y 20031231-20030101

  Group_B N Y 99991231 20030101

  which is what you asked for.

• Hello need help with the opacity mask.

  Hello need help with the opacity mask. I hope someone out there can help

  I inherited a logo that appears to use a Logo of OM has a shape with a grad. This grad at first sight is not used in the Grad scheme and there is not editable.  Looking at the transparency palette I find an OM (pic1) output option. If I choose what the grad on separates it from the page of the form, that is from there I can change/remove as required (Note2).

  However, sometimes (he did no change), I'll be back to the same original form and output option is grayed out and is no longer available. Or I go to the similar shape that has the same treatment and I can't go out OM (pic3)

  The only difference is the thumbnail in the transparency palette, which is strong in pic1 and rated on pic3. What Miss me?    I'm not clear what the advantage is simply OM using the Grad palette to apply a grad in my form, but until I can get rid of OM who is there, I can't comfortably apply to the grad I want.

  The white gradient LHS I have no problem with. I choose fortunately only and each time get the possibility of release of OM.
  

  

  The other thing weird. When I select the white gradient. Sometimes, the exit option is in the palette without going through the drop-down list (Fig 4).

  Other times seems not that OM has already been applied, because the palette gives me the ability to mask rather than liberation (5 photos). Until I go to the drop down and then I find Release is an option after all.

  What is the difference here?   Not much of a problem, because either way I can release OM to be able to change the grad.

  The file is passed through several hands and play anywhere to try to resolve issues, and many stops and save slot, so something along the line was of course done a logo and not the other because of the difference, but I can't for the life of me see what that.

  

  I hope someone can help. Very appreciated

  
  

  See you soon

  Dave

  Dave,

  I've (mis) understanding the issues, you can account for the box to the right in the main palette transparency (called thumbnail) here.

  Illustrator help | Transparency and blending modes

  represents the masking objects.

  Some of your screenshots show no object mask, so it only is not really a mask even if do the opacity mask has been clicked and there seems to be one in the layers palette, wherever you look.

  I think that it is perhaps the issue.

• hierarchical sql (part 2) - error: duplicate rows

  Following up on my previous question:
  
  This hierarchical query has the duplicate in the result set rows:
  
  Select record_id, parentid, name from my_table
  connect by parentid = prior record_id
  siblings arrested by name;
  
  Thanks for help.
  
  ----------
  
  My table has five columns:
  
  rank (number)
  score (number)
  name (varchar)
  record_id (number)
  ParentId (number)
  
  A parentid is a record_id at a higher level in the hierarchy.
  A parentid is a record_id at a higher level in the hierarchy.
  Rank and Score are used to control (tri) each level of the hierarchy.
  
  The data looks like this:
  
  grade - score - name - record_id - parentid
  
  --------------------------------------------------------------------------------
  1 - 1 - name1 - 101-0
  1 - 2 - name2 - 102-0
  1 - 3 - name3 - 103-0
  2 - 1 - name4 - 104-101
  2 - 2 - name5 - 105-101
  2 - 1 - name6 - 106-102
  2 - 2 - Marque7 - 107-102
  2 - 1 - name8 - 108-103
  2 - 2 - name9 - 109-103
  
  Desired results set:
  
  grade - score - name - record_id - parentid
  --------------------------------------------------------------------------------
  1 - 1 - name1 - 101-0
  2 - 1 - name4 - 104-101
  2 - 2 - name5 - 105-101
  1 - 1 - name2 - 102-0
  2 - 1 - name6 - 106-102
  2 - 2 - Marque7 - 107-102
  1 - 1 - name3 - 103-0
  2 - 1 - name8 - 108-103
  2 - 2 - name9 - 109-103

  Missing the BEGINNING WITH...?

  SQL> select record_id, parentid, name
    2  from my_table
    3  --Added START WITH
    4  start with parentid = 0
    5  connect by parentid = prior record_id
    6  order siblings by name;
  
   RECORD_ID   PARENTID NAME
  ---------- ---------- ----------
         101          0 name1
         104        101 name4
         105        101 name5
         102          0 name2
         106        102 name6
         107        102 name7
         103          0 name3
         108        103 name8
         109        103 name9
  
  9 rows selected.
  

• hierarchical SQL

  Hello
  
  I'm looking for help with a hierarchical query.
  
  My table has five columns:
  
  rank (number)
  score (number)
  name (varchar)
  record_id (number)
  ParentId (number)
  
  A parentid is a record_id at a higher level in the hierarchy.
  Rank and Score are used to control (tri) each level of the hierarchy.
  
  The data looks like this:
  
  grade - score - name - record_id - parentid
  ----------------------------------------------------------
  1 - 1 - name1 - 101-0
  1 - 2 - name2 - 102-0
  1 - 3 - name3 - 103-0
  2 - 1 - name4 - 104-101
  2 - 2 - name5 - 105-101
  2 - 1 - name6 - 106-102
  2 - 2 - Marque7 - 107-102
  2 - 1 - name8 - 108-103
  2 - 2 - name9 - 109-103
  
  I would like to request to view the data in the following order:
  
  grade - score - name - record_id - parentid
  ----------------------------------------------------------
  1 - 1 - name1 - 101-0
  2 - 1 - name4 - 104-101
  2 - 2 - name5 - 105-101
  1 - 1 - name2 - 102-0
  2 - 1 - name6 - 106-102
  2 - 2 - Marque7 - 107-102
  1 - 1 - name3 - 103-0
  2 - 1 - name8 - 108-103
  2 - 2 - name9 - 109-103
  
  The simple query to get this sequence of result set is adequate. No need to fill or other characteristics.
  
  Thank you.

  All the columns in your sample have same agenda, so it is not possible to tell which column you want to sisters of the order. I'll assume by its name:

  select  *
    from  your_table
    start with parentid = 0
    connect by parentid = prior record_id
    order siblings by name
  /
  

  For example:

  with sample_table as (
                        select 1 grade,1 score,'name1' name,101 record_id,0 parentid from dual union all
                        select 1,2,'name2',102,0 from dual union all
                        select 1,3,'name3',103,0 from dual union all
                        select 2,1,'name4',104,101 from dual union all
                        select 2,2,'name5',105,101 from dual union all
                        select 2,1,'name6',106,102 from dual union all
                        select 2,2,'name7',107,102 from dual union all
                        select 2,1,'name8',108,103 from dual union all
                        select 2,2,'name9',109,103 from dual
                       )
  select  *
    from  sample_table
    start with parentid = 0
    connect by parentid = prior record_id
    order siblings by name
  /
  
       GRADE      SCORE NAME   RECORD_ID   PARENTID
  ---------- ---------- ----- ---------- ----------
           1          1 name1        101          0
           2          1 name4        104        101
           2          2 name5        105        101
           1          2 name2        102          0
           2          1 name6        106        102
           2          2 name7        107        102
           1          3 name3        103          0
           2          1 name8        108        103
           2          2 name9        109        103
  
  9 rows selected.
  
  SQL> 
  

  SY.

• Gray instead of black in PDF

  Hi all

  During the recording of my business card in the format pdf, black seems to go gray, and Im not sure the cause of it. I don't know if it's just a few settings in indesign. I can well imagine that because I placed photoshop images, the contrast of gray against black of the PS is very apparent.

  Someone had a similar problem and knows how to fix?

  Helen

  If you want the black depending on your images of Photosho, use the eydropper for color of a representative area, so what a shade. Do not use this grade for type.

• Can you please help me low grade that my 4.0 to 3.5 for the school system - 4.0 only is not supported by my system schools online, if I had known this I would not have updated.

  I have since moved from 3.5 to 4.0, that this version is not supported by online systems of my schools-so anytime there is a problem, they are unable to help him? Is there anyway for me to downgrade to 3.5. I'm already having problems, even entering the system!

  I really don't want to go back to IE, please help me downgrade to 3.5, so I can stay with you guys.

  Thank you very much for your help!

  Sincerely,
  Lindsay Walton

  If you switch to Firefox 3.5 you will lose historic navigation and cookies. If you switch to 3.6 you will not lose data.

  Downgrade to Firefox 3.5 or 3.6 first of all uninstall Firefox 4, but do not select the option 'remove my Firefox personal data '. If you select this option, it will delete your bookmarks, passwords and other user data.

  Then you can install the latest version of Firefox 3.6 available to http://www.mozilla.com/en-US/firefox/all-older.html - it will automatically use your favorite courses, passwords etc.

  If you need to go to 3.5, you can get the latest version of Firefox 3.5 http://releases.mozilla.org/pub/mozilla.org/firefox/releases/3.5.18/win32/en-US/

  I recommend, to avoid possible problems with decommissioning, accessing your profile folder and delete the following files if they exist - extensions.cache, extensions.rdf, extensions.ini, extensions.sqlite and localstore.rdf. Delete these files will force Firefox to rebuild the list of installed extensions, check their compatibility and cancel the toolbar customizations.

  For more information on how to find your profile folder, see https://support.mozilla.com/kb/Profiles

• Why not given priority of a show of note sent anywhere in the grade received?

  In Thunderbird, you can set the priority of a mark composed and sent.
  However, I don't see any indication who give priority either the note which is sent in the sent folder or in the grade received. In particular, the recipient does not see the note as high priority and has therefore no indication that it is particularly urgent.

  It seems that the priority of Thunderbird feature is not operational.

  In a new window for the entry, you can set the priority of a message using:
  Options > priority > select an option for example. highest

  After sending, you can visualize this.
  Click on the "Sent" folder
  Click the "Select the columns to display" and select this option to display the column "priority." (you can set the "Priority" column in any folder)
  See image:

  In an email received you will see this in the source code and the full as headers:
  for example: X-Priority: 1 (high)

• Firefox continues to show that I need high-grade firefox but I have the most recent, how to stop it

  Popup message that I need to high-grade, fire fox, already have the most recent in a (No 26). Have uninstalled and reinstalled and still get the message that I need to up grade, have windows 7.

  Whenever you get a message / popup that software / files must be updated.
  
  DO NOT USE ONE OF THE LINKS PROVIDED.
  
  If this can be a legitimate message, could also be a Virus or Malware.
  No matter when you want or need to check updates.
  Go to the website of the real owner of the program in question.
  For example, for Firefox, go to Mozilla.org
  or Firefox in any language.

• can't up grade to Fire Fox 4.0.1

  When I go into Firefox, it keeps telling me, URGENT, my version of Firefox is no longer protected against online attacks. I then try to upgrade to version 4.0.1, which for me is click on, but I get pop up with options to store file or cancel it. I don't really know what version I have Fire Fox, but if its telling me that I need to up grade and not sure that I need to do something.
  Thank you.

  I imagine that the auto-updater in Firefox 3.5 is maybe not able to go directly to Firefox 4.

  1. Go to http://www.mozilla.com/firefox/
  2. Click on the Green download Firefox button (a prompt should appear asking you to save or open) - you probably already have this day
  3. Save the file Firefox 4 to the place where you download files (for example, your desktop or download folder)
  4. Firefox is completely closed
  5. Open the folder that you downloaded Firefox 4 to the .exe file and double-click the file

  I hope you should be good from there... or are you saving the file of questions?

• FPGA device configuration, package and speed grade.

  Hello.

  Where can I find the news of grade package and the speed of the FPGA inside of the PXI-7842R? I ask because I want to build a project XPS in the Xilinx XPS and program needs this info.

  I followed the example in the "how to use designs based on Xilinx Microblaze with NI LabVIEW FPGA 2009 and the R-series modules". There, he gives the info for the specific FPGA (PXI-7852R and PXI-7953R) they use. It's a Virtex5, ff676, xc5vlx50, level-1 speed, but the authors do not mention where one can find this info.

  Thank you

  Bill.

  Nevermind, found the info in this way:

  Instruments\LabVIEW national 2010\Targets\NI\FPGA\RIO\R Series\Pxi-7842r

  Bill.