Top n characters of a string using package

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• How to remove special characters from the string using translate() without typing all special characters?

  Hi all

  I am trying to remove special characters without the help of regular expressions.

  translate (the column name or string,'!@#$ & * (* () _) * "" :} {?}) >? /, «, » ')

  I want to eliminate this manual process to give all special characters using a chr() or ascii() function.

  Please show me the way.

  Thanks in advance

  Similar to the solution of Michael...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
  2, i like (select level 1 c from dual connect by level<=>
  3 less
  4 Select + 32 (level-1) double connect by level<=>
  5 less
  6 select + 58 (level-1) double connect by level<=>
  7 less
  8 select + 91 (level-1) double connect by level<=>
  9 less
  10. Select 123 + (level-1) from dual connect by level<=>
  11 less
  12. Select 255 double
  13            )
  14, ts as (select level r, substr (str, level 1) c
  15 t
  16 connect by level<=>
  17             )
  18, tf as (select row_number() (order for r) r
  19                    ,ts.c
  20 TS
  21 I join on (i.c = ascii (ts.c))
  22             )
  23 select replace (sys_connect_by_path(c,'!'),'! ') Str
  24 TF
  25 where connect_by_isleaf = 1
  26 connect r = prior r + 1
  27 * start with r = 1
  SQL > /.

  STR
  -----------------------------------------------------------------------------------------------------------------------
  Thisisthemostamazingtest¸astringcosting5000

  Or something as horrible as this...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
  2, I like (select replace (sys_connect_by_path (chr (c), 'A'), 'A') as tr)
  3 of)
  4 select c, rownum r
  5 (select 32 + (level-1) as the double connection by level c<=>
  6                         union
  7 select + 58 (level-1) double connect by level<=>
  8                         union
  9 select + 91 (level-1) double connect by level<=>
  10 the union
  11. Select 123 + (level-1) from dual connect by level<=>
  12 union
  13. Select 255 double
  14 tri 1
  15                        )
  16                  )
  17 where connect_by_isleaf = 1
  18 log r = prior r + 1
  19 start with r = 1
  20            )
  21 select translate (str, 'A' |) TR, 'A') as str
  22 * t, I
  SQL > /.

  STR
  --------------------------------------------------------------------
  Thisisthemostamazingtest¸astringcosting5000

• Changeparticular the characters of a string using regular expressions...

  Hi all
  I'm writing a function using the function of expression regular oracles REGEXP_REPLACE but I could not succeed until now.
  
  My problem is as follows, I have a text in a column say "Scott Sdfdfs Sdfd" I want to replace all the s and S with X characters and make the text looks like "XdfXdf XdfdfX Xdfd".
  
  It is possible by using regular expressions in oracle?
  Can you give me some clue?
  
  Thank you

  select
    regexp_replace('sdfsdf Sdfdfs Sdfd',
                   's|S', 'X') Replaced
  from dual;
  

  REPLACED
  ------------------
  XdfXdf XdfdfX Xdfd 
  

• To delete the characters only at the beginning of a string using regexp_replace

  I want to be able to delete the characters in a string only until the first numeric value.  If it takes place after the digital, I want to keep them.

  "for example"AB1234' becomes '1234', 'AB1234C' becomes ' 1234 C.

  It might be also spaces and other types of characters at the beginning.  I tried this:

  Select

  regexp_replace ('ABC1234', ' [^ [: digit:]]').

  regexp_replace ('AB 1234',' [^ [: digit:]]').

  regexp_replace ('AB 01234',' [^ [: digit:]]').

  regexp_replace ('AB1234C', ' [^ [: digit:]]').

  regexp_replace ('^ 1234', ' [^ [: digit:]]').

  regexp_replace ('* #1234Z ',' [^ [: digit:]]')

  OF THE DOUBLE

  For all except "AB 01234' returned '1234' so it retains the digital.    For "AB 01234' it returns correctly '01234'

  The bad are those with a character after digital, for example "AB1234C".

  I know it I'm missing something here, can someone please help with this?

  Thank you

  SQL> with t
    2  as
    3  (
    4  select 'ABC1234' str from dual
    5  union all
    6  select 'AB 1234' str from dual
    7  union all
    8  select 'AB 01234' str from dual
    9  union all
   10  select 'AB1234C' str from dual
   11  union all
   12  select '^1234' str from dual
   13  union all
   14  select '*#1234Z' str from dual
   15  )
   16  select str
   17       , regexp_replace(str, '^[^[:digit:]]+') str_new
   18    from t;
  
  STR      STR_NEW
  -------- --------
  ABC1234  1234
  AB 1234  1234
  AB 01234 01234
  AB1234C  1234C
  ^1234    1234
  *#1234Z  1234Z
  
  6 rows selected.
  

• replace characters in the string

  Hi all

  Is it possible to index the characters in a string as if it were a table and remove them from the second position and now. I just want with the first letter or number so that I can later concatenate strings to it.

  Thanks for any help!

  -Michael

  Hi Michael,

  Yes. Use the function "Sring subset. At the beginning the value 0 (default value) and the length of 1.

  This will give you the first character in the string.

  Steve

• Formula to replace characters in a string

  Hi all

  Is it possible to replace characters in a string somewhere if the string has no specific pattern for these characters? I use the replacestr function to replace characters in a string (i.e. ABC), but the chain is in the ABC format * where * are two random characters. The result I'm looking for is to replace ABC * with the NodeID.

  ReplaceStr (propvalue (Core.Abbrev), ABC, ID (), T),) This formula works, but is either two additional characters in the end, after ABC. How can I cut that?

  Thank you

  If)

  Not (Equals (Integer, length (PropValue (Core.ABBREV)), length (ReplaceStr (PropValue (Core.ABBREV), ABC, T))),

  ReplaceStr (PropValue (Core.Abbrev), PropValue (Core.Abbrev), ID (), T),

  PropValue (Core.Abbrev)

  )

• How to remove the first few characters of a string of liquid

  I would like to delete the first three characters of a string of liquid. The question is how.

  If I use the markup according to liquid when I know what are the first characters

  {{it. {{["Estate status'] | strip_html | remove_first:"11."}}

  It will remove the 11 characters.

  But if I don't know what are the first characters, this markup can I use to get "RID" of the first three characters?

  I tried 'split' and 'slice', but it must always know what characters to split or slice.

  Thanks for any help.

  Kind regards

  Carla

  Assign a value into slices and you can have table data that you can get out.

• Bunch of Oracle on the special characters in a string - translate?

  How to remove special characters in a string, it can contain. , (space), etc.

  SELECT TRANSLATE('123.456 (90-90)', '', '') FROM DUAL
  

  Basically I want to undress and to compare with the db value.

  WHERE TRANSLATE(TABLE.NUMCODE, '', '')  = TRANSLATE('123.456 (90-90)', '', '') 
  

  Use TRANSLATE, since you're on 9i. For example:

  TRANSLATE (your_string,'X,. #! % @$ ^ & * () _-+=', 'X')

  Removes all the s characters in ', #! % @$ ^ & * () _-+=' of your_string.

  SY.

• last 3 characters of a string

  How to get the last 3 characters of a string occuring after a character / alphabet  without using REGEXP_SUBSTR ? 
  
  Ex: 10000A001 is the string.
  
  Note: -  I want to use it in Oracle reports 6i, therefore i cannot use the statement REGEXP_SUBSTR 
  
  Sanjay

  Hello

  substr('10000A001',-3)
  

• How to remove the first 11 characters of a string

  With the help of ' XML Publusher Desktop / generator model for Word / 5.6 Build 45'
  
  I use XML Publisher. With the help of a RTF model, to generate purchase orders by email of the purchase of the Oracle.
  
  The fields are drawn from the XML code generated by Oracle.
  
  One of the fields is the place of delivery Description field.
  
  Will appear in the report as follows:
  
  * & lt;? SHIP_TO_LOCATION_NAME? & gt; *
  
  When I attach a test XML file in Word and view the output, one of my test case returns a description of the site:
  
  DON'T code USE County Hall of Global location
  
  What I have to do is to remove the * DO NOT USE * according to the description of the location.
  
  I could do is a Find / Replace, or a substring to ignore the first 11 characters from the string. But I don't know how to do it.
  
  Any help would be much appreciated, because it is a production problem that is causing a bit of a small problem for us!
  
  Thank you very much.

  Hello
  Maybe you know this syntax :)

  Rahul

• Firefox Help my firefox top bar has been changed, I used to be able to get the file to bookmarks Format printed, and other services that I have found useful when you take information from the internet, where they went, I want them back?

  Firefox help

     Search
  

  "Found 0 results for" my firefox top bar has been changed, I used to be able to get the bookmarks printed Format file, and other services that I have found useful when taking information from the internet, I found bookmarks to the right of the new game to the top, but it seems not instantly friendly where they went, I want that they come back? »

  See:

  • https://support.Mozilla.org/en-us/KB/menu%20bar%20is%20missing

• Remove 10 characters of this string

  How to remove the last 10 characters of any string?

  

  \

  Keep throwing me these easier!

• separate the characters in a string

  Hello

  Y at - it an easy way of seprerate characters in a string

  For example if I have a string 'abcdef '.

  I want to seprate it in an array of 7 elements, where each element is a character in the string.

  Thank you

  Hi reza_sed,

  the attached picture shows one solution.

  Mike

• I publish the YEAR edge .oam.  In Dreamweaver, I insert .oam and get this error: pathname contains Unicode or characters double - bye, try using ascii.

  I publish the YEAR edge .oam.  In Dreamweaver, I insert .oam and get this error: pathname contains Unicode or characters double - bye, try using ascii.

  Thanks Nancy, I managed to do the work.  When in DW, I had no defined site and tried to insert the oam in

  a new html.  As soon as I set up a site and created a new html then oam all the inserts work very well.

  Thanks for your help.

• extract characters from a string

  Hi gurus,
  I want to extract the first, third, fifth, seventh... characters in a string.
  not to extract characters from a subset of characters in a select query in oracle 9i database.
  
  for example (1):
  Assume that a string like this "SUE" is that I am 'ACEGI"of the source string
  and the source can be any valid string, I just give an example here.
  
  Example (2) of "kalpataru' in klatau'
  
  Please guide me for this

  for 9i:

  SQL> with t as (
   select 'ABCDEFGHIJ' str from dual union
   select 'kalpataru' from dual
  )
  --
  --
   select str,
          trim(extract(xmlagg(xmlelement(e, substr(str,level,1)) order by level),'//text()')) str2   from t
    where mod(level,2) = 1
  connect by level <= length(str) and prior str = str and prior sys_guid() is not null
    group by str
  /
  STR        STR2
  ---------- --------------
  ABCDEFGHIJ ACEGI
  kalpataru  klaau