updated victory 8 to 8.1, how ensure the recovery partition is the same

Similar Questions

• in iBooks author, how can I change the book ID?  I update often books and hand but ID remains the same, so it caused problems when others discover.  I wish it were as if it were a new book with a new code.

  in iBooks author, how can I change the book ID?  I update often books and hand but ID remains the same, so it caused problems when others discover.  I wish it were as if it were a new book with a new code.

  From the link 'related items' below, see:

  Give your book a new internal ID.

• Whenever I have shut down my computer it detects 2 updates. I checked the updates of Windows and it seems to be the same ones every day.

  Whenever I have shut down my computer it detects 2 updates. I checked the updates of Windows and it seems to be the same ones every day. And they did so why they keep needing to be updated? They are: a security update for .NET Framework 2.0 SP2 and 3.5 SP1 on Windows Server 2003 and Windows XP x 86 (KB2518864) and: Security Update for Microsoft .NET Framework 2.0 SP2 on Windows Server 2003 and Windows XP x 86 (KB2539631)

  Visit the Microsoft Solution Center and antivirus security for resources and tools to keep your PC safe and healthy. If you have problems with the installation of the update itself, visit the Microsoft Update Support for resources and tools to keep your PC updated with the latest updates.

  UTC/GMT is 16:02 Friday, September 23, 2011

• Is it OK to delete the update number 2 after the new update has been entered IE number 6 of the same program?

  to delete the update number 2 after the new update has been entered IE number 6 of the same program

  original title: he is allowed to delete the previous updates of files

  Hi Carl,

  I suggest you go through this article to Java which can be useful.

  Why should I remove old versions of Java in my system?

  Removal of previous versions of the .net Framework is based on the applications that are running on the computer.

  For applications, if you have an application based on any .NET Framework on the computer, you cannot delete it since you have need to support the application runs correctly.

  .NET framework 3.5 SP1 includes .NET Framework 2.0 SP2 and 3.0 SP2. This means that .NET Framework 2.0 and 3.0 can not be deleted because they are the sine qua non of .NET Framework 3.5 SP1. If you have any application based on .NET Framework 3.5 SP1, please do not remove .NET 2.0 SP2, 3.0 SP2 and 3.5 SP1.

  I would also not to uninstall the security updates that are important for the security of your computer.

• I am a member creative cloud. I want to install the same applications from my laptop to my new desktop computer. I need to purchase another license? otherwise how do the same thing for my new desktop computer

  I am a member creative cloud. I want to install the same applications from my laptop to my new desktop computer. I need to purchase another license? otherwise how do the same thing for my new desktop computer

  I have it! Thank you

• How can I stop auto-updates and keep UserAccounts asking if I was the same update

  User accounts in W7 has no option to not be reminded about the same updates again [I won't need not and cannot use] every thirty minutes or more for a few days. If I click on Yes, I get a message saying that I don't need but 30 minutes later AU wonder again. I am a research student and I can't have important experiences, interrupted by updates in XP, I turned off and then automatic update make the updates when it is safe for me to do, but I can't find a way to do this in W7. I unchecked automatically updated in Java, Windows, Office and these programs I could access, but I still get notified.

  Hello
  Welcome to the Microsoft answers site.
   
  You can try to disable automatic updates, the folloe as follows:
   
  1. open Windows Update by clicking the Start button, all programs and then click Windows Update.
  2. in the left pane, click on change settings.
  3. Select the desired option.
   
  Under recommended updates, select the include updates in downloading, installing or informs me of the box updated recommended, and then click OK.  If you are prompted for an administrator password or a confirmation, type the password or provide confirmation.
   
  Please see the link below:

  Activate the update or disable automatic
  http://Windows.Microsoft.com/en-us/Windows-Vista/turn-automatic-updating-on-or-off
   
  About user accounts, please visit this link:
  http://social.Microsoft.com/forums/en-us/whssoftware/thread/bedd7d54-c17a-49B2-B738-65b9b1c3b6db/

  You can also disable the notification from the center of the action, follow these steps:

  1. click on the Start button to display the Start Menu. Then select Control Panel.
  2. the Control Panel window opens now.

  Click on system and security of the Control Panel window.

  3. the system and security of control panel section opens. Here you can see the center of the Action link.

  4. click on the link the Action Center to open the Action Center window.
  You can finish the first malware scan of this screen.

  5. click on the button scan now to open the window of Windows Defender scan
  Enable / disable Notifications

  Now to change the behavior of notification and enable or disable messages, the Action Center settings edit link can be used from the left pane of the window for Action Center.

  From this window, change the checkboxes for messages from Action Center notification like Windows Update, Windows Firewall, Virus Protection etc. Click OK to save the settings.

  Thank you and best regards,
  Azam - Microsoft technical support.

• How bookmart the same site twice (or more) at the same time?

  I'm running on firefox 36.0.1. and windows 7. I would like to bookmark the site even more than once at the same time. But firefox just appears as "edit bookmark" but does not allow me to another bookmark to the same Web site. So, how can I create multiple bookmark for the same site at the same time? I remember that firefox used to allow this, but it is not disabled?

  In the early days, it was possible to save bookmarks on the same page, but that was considered a bug and has been deleted. Now you can use copy/paste to duplicate in the dialog box (Ctrl + Shift + b or library "Show all bookmarks"). For example, select a bookmark in the pane right, Ctrl + c Ctrl v, then you can rename the copy and move it where you want.

• Does not update, said prev version needs to update and restart. It of not, get the same error

  Old version of Firefox running. Tried to update and get the message that a previous version has not finished installing and computer needs to reboot to finish. I restart, then try to install the new version, but just get the same error. I also tried to uninstall and start again, but got the same exact message he needed to finish the update before it could be installed.
  Suggestions?
  Thank you!

  Do a cleaning (re) install and delete the folder of the program Firefox (C:\Program Files\Mozilla Firefox\).

  Download a new copy of Firefox and save the file to the desktop.

  • Firefox 8.0.x: http://www.mozilla.com/en-US/firefox/all.html

  Uninstall your current version of Firefox if possible.

  • Do NOT remove the data of a personal nature when you uninstall the current version or you lose your bookmarks and other data in the profile folder.

  Delete the program folder Firefox before installing newly downloaded copy of the Firefox installer.

  • It is important to remove the Firefox program folder to delete all the files and make sure that there is no problem with the files that were the remains after uninstallation.

  Your bookmarks and other profile data stored in the Firefox profile folder and will not be affected by a relocation, but make sure that you do not select delete data of a personal nature if you uninstall Firefox.

  • http://KB.mozillazine.org/Profile_folder_-_Firefox
  • http://KB.mozillazine.org/Profile_backup
  • http://KB.mozillazine.org/Standard_diagnostic_-_Firefox#Clean_reinstall

• Siri handsfree works intermittently after updating iOS 9.2. Anyone else having the same problem?

  Siri handsfree works only intermittently after updating iOS 9.2. I have a Mustang from 2015 with my ford touch. Siri handsfree worked perfectly before the update. Now when I use it it disconnects sometimes. Anyone else having the same problem?

  Yes, I have the same problem with my Ford Escape of 2013 using MFT version 3.8 (just installed).  Use IPhone with IOS 9.2 6.  I can call him only intermittently SIRI when I use the long pull on the switch.  Also, when I do it, SIRI goes my audio setting that I played (usually USB iPod) to BT audio.  I'm trying to see if the fix suggested elsewhere for the BT audio works but were unable to invoke SIRI to check.  Ford Sync experts were of great help and finally told me to go to the dealer.  I read somewhere after a 'google' search a person represents himself as a guy HE said it's a problem of IOS and Ford does not change (code) until we as customers.  That's all I know right now.

• I tried for months run updates, but every time I tried I get the same error (80004002).

  1. I'm running Windows Vista 64.
  2. error "windows can not find updates
  3. I tried "Fix it", did not work
  4. check out the services, all right there
  5. Please help, Im losing my mind!

  Having the same problem except with Vista 32 bit.  Read everything that support technique microsoft, tried all the fixes. One of the patches will not work because he had problems connecting to the server. Hard to fix something when the fix does not work. Good luck with your problem, I am at the point of screw up windows all together.

• delivery of mail with 5510 e error - print. updates and connection are ok. a friend has the same problem.

  I checked all of the updates and connections for my new printer.  As far as I can tell, I've checked everything that needs to be checked and everything is good.  But I still have the error of mail delivery when e-printing.  And my friend has the same problem with his new b111a 5510.  What could be the problem?  Regular, printing, scanning, and so on work fine with my wireless connection.

  So looks like it's maybe a problem with the E-mail address provided by your internet provider, you send from,

  What I would say as a test is to create an email account with g mail and or yahoo and try to send the e-mail to your eprint/E-mail account and see if it accepts the email too, make sure you have your printer the value Accept e-mail for all users, you can do so by logging into Eprint Center and then enter these parameters and select this option

• update of table with similar registration information using the same key

  Version: 11.1.0.7.0

  We have large table probably 30 M records

  -test code table follows

  create table people)

  person_id number,

  first name varchar2 (50).

  middle_name varchar2 (50).

  last_name varchar2 (50)

  );

  insert into persons (person_id, first_name, last_name, middle_name) values (1, 'JOHN', 'A', 'DOE');

  insert into people (person_id, first_name, last_name, middle_name) values (1, 'JOHN', ","DOE");

  insert into persons (person_id, first_name, last_name, middle_name) values (1, 'JOHN', 'ADAM', 'DOE');

  insert into persons (person_id, first_name, last_name, middle_name) values (2, 'JOHN', ' C ', 'DOE');

  insert into people (person_id, first_name, last_name, middle_name) values (2, 'JOHN', ","DOE");

  insert into people (person_id, first_name, last_name, middle_name) values (3, 'JOHN', ","MOE");

  insert into persons (person_id, first_name, last_name, middle_name) values (3, 'JOHN', 'FRANK', 'MOE');

  I am trying to write more efficient code to take the middle name of the most complete and updated all records with the same KEY (person_id) with her.

  Expected result:

  1, JOHN, ADAM, DOE

  1, JOHN, ADAM, DOE

  1, JOHN, ADAM, DOE

  2, JOHN, C., DOE

  2, JOHN, C., DOE

  3, JOHN, FRANK, MOE

  3, JOHN, FRANK, MOE

  Hello

  Here is an example of the use of the aggregate LAST instead of the function ROW_NUMBER analytic function:

  MERGE INTO dst people

  WITH THE HELP OF)

  WITH got_longest_middle_name AS

  (

  SELECT person_id

  , MIN (middle_name) DUNGEON (DENSE_RANK LAST ORDER OF LENGTH (REPLACE (middle_name, '.')))

  AS longest_middle_name

  AMONG the people

  WHERE middle_name IS NOT NULL

  GROUP BY person_id

  )

  SELECT person_id

  longest_middle_name

  Got_longest_middle_name c - c is for candidates

  WHERE DOES NOT EXIST)

  SELECT 1

  AMONG the people

  WHERE person_id = c.person_id

  AND c.longest_middle_name NOT AS REPLACE (middle_name, '.'). '%'

  )

  )             src

  WE (dst.person_id = src.person_id)

  WHEN MATCHED THEN UPDATE

  SET dst.middle_name = src.longest_middle_name

  WHERE dst.middle_name <> src.longest_middle_name

  OR dst.middle_name IS NULL

  ;

  I suspect that this may be a little faster, but try it on your system with your data to make sure.

• How did the same predicate is completed access and filter?

  SELECT select, j.job_title, d.department_name

  OF e hr.employees, hr.departments d, hr.jobs j

  WHERE e.department_id = d.department_id

  AND e.job_id = j.job_id

  AND select LIKE 'a % ';

  Execution plan

  ----------------------------------------------------------

  Hash value of plan: 975837011

  ---------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ---------------------------------------------------------------------------------------------

  | 0 | SELECT STATEMENT | 3. 189. 7 (15) | 00:00:01 |

  |* 1 | HASH JOIN | 3. 189. 7 (15) | 00:00:01 |

  |* 2 | HASH JOIN | 3. 141. 5 (20) | 00:00:01 |

  | 3. TABLE ACCESS BY INDEX ROWID | EMPLOYEES | 3. 60. 2 (0) | 00:00:01 |

  |* 4 | INDEX RANGE SCAN | EMP_NAME_IX | 3 | | 1 (0) | 00:00:01 |

  | 5. TABLE ACCESS FULL | JOBS | 19. 513. 2 (0) | 00:00:01 |

  | 6. TABLE ACCESS FULL | DEPARTMENTS | 27. 432. 2 (0) | 00:00:01 |

  ---------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - access("E".") DEPARTMENT_ID "=" D ". ("" DEPARTMENT_ID ")

  2 - access("E".") JOB_ID '=' J '. ("' JOB_ID ')

  4 - access ("E". "Last_name" LIKE 'A %') "

  filter ("E". "LAST_NAME" LIKE 'A %') "

  I understand not only how to select column is evaluated by the access and filter? Can someone there explain please? Or recommend me an article or document that explain this predicate excatly explains to explain the plan?

  Thanks in advance.

  Near NightWing.

  I believe that the predicate can be used to access THE index entries and if entries of access could include potentially "false positives" then filtering is required to remove the FPs.

  This filtering can be done in the same step of the operation (such as access) or as an extra step.

  My apologies, this has become much longer and more detailed that I intended it to be. :-(

  If I understand correctly,

  In terms of the explanation of the path, each step can include access and filtering process for "entries" (index or line). In the plan to explain the predicate section shows Information the use of predicate for step 'matching. "

  Some predicates can be "used" to ACCESS (ing) the entries, while the same or additional predicates (or even other) can be "used" to FILTER (ing) access entries (which have been consulted, but the optimizer is not sure that EACH AACCESSed entry is indeed a part of final result set). In such cases optimizer applies filtering predicate also during the operation stage. The optimizer can sometime even add additional operation steps or predicate [almost like a short circuit]

  So, using our previous configuration, allow us to run test cases.

  In this query we use AS predicate but the operand does NOT contain any 'wild' character In this case INDEX RANGE SCAN is performed, but since there is no wild characters are involved we can be sure that each entry using this predicate is indeed part of the final result set. This predicate Section shows that the predicate is used ONLY to access (index) entries.

  We know that the result set of this query is NULL lines.

  > explain plan for select v1 of tst where v1 as "A".

  ------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     7.     1 (0) | 00:00:01 |

  |*  1 |  INDEX RANGE SCAN | TSTV1_IDX |     1.     7.     1 (0) | 00:00:01 |

  ------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - access ("V1" = 'A')

  However, in this application, there is a wildcard character in the predicate, so while the INDEX RANGE SCAN step access entries using this predicate, it could potentially access entries that can be part of the final result set. So in the SAME step of the INDEX RANGE SCAN operation the predicate is also used for filtering. Since this is the only predicate, it may seem redundant.

  > explain plan for select v1 of tst where v1 like 'a % '.

  ------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |    24.   168.     1 (0) | 00:00:01 |

  |*  1 |  INDEX RANGE SCAN | TSTV1_IDX |    24.   168.     1 (0) | 00:00:01 |

  ------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - access ("V1" LIKE 'A %')

  filter ("V1" LIKE 'A %')

  If we add an another predicate as below (also includes wild character), it gets interesting. INDEX RANGE SCAN step performs two access AND filtering.

  Please note that the predicate 'V1' AS '%' is used to ACCESS and FILTER, fine FILTER uses additional predicates.

  > explain plan for select v1 of tst where v1 like 'A %' and v1 as "%c".

  ------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     7.     1 (0) | 00:00:01 |

  |*  1 |  INDEX RANGE SCAN | TSTV1_IDX |     1.     7.     1 (0) | 00:00:01 |

  ------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - access ("V1" LIKE 'A %')

  filter ("V1" IS NOT NULL AND "V1" LIKE 'A %') AND "V1" LIKE "%c"

  When we change the predicate 'V1' LIKE 'A %' to 'V1' > 'A', then we can use the predicate to access entries AND do not forget that each entry using this predicate are

  Indeed part of results if other predicates are met. In this case optimizer of must not filter on 'V1' > 'A', wherever it must continue to filter on 'V1' LIKE '%c '.

  > explain plan for select v1 of tst where v1 > 'A' and v1 as "%c".

  ------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     7.     1 (0) | 00:00:01 |

  |*  1 |  INDEX RANGE SCAN | TSTV1_IDX |     1.     7.     1 (0) | 00:00:01 |

  ------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - access("V1">'A')

  filter ("V1" IS NOT NULL AND "V1" LIKE "%c")

  Of course, if we do the predicate so that the entries are NOT accessible using the predicate, then for INDEX FULL SCAN (no Beach cannot be determined) operation comes into play and the predicate of ACCESS goes. All entries in the index are ALWAYS accessible (predicate applied no ACCESS) and FILTER predicate is applied.

  > explain plan for select v1 of tst where v1 like '%c %'

  ------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     8 S     1 (0) | 00:00:01 |

  |*  1 |  INDEX SCAN FULL | TSTV1_IDX |     1.     8 S     1 (0) | 00:00:01 |

  ------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - filter ("V1" IS NOT NULL AND "V1" LIKE '%A%c')

  For the example proposed by JL, two predicates are used in the INDEX RANGE SCAN step to access THE entries. In addition, we can be sure that all entries that are accessible with success using this predicate can be included in the final result set. So not necessary filtering.

  > explain plan for select v1 of tst where v1 > 'A' and v1<>

  ------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |    24.   168.     1 (0) | 00:00:01 |

  |*  1 |  INDEX RANGE SCAN | TSTV1_IDX |    24.   168.     1 (0) | 00:00:01 |

  ------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - access("V1">'A' AND "V1")<>

  Interestingly, when we change the 'B' in the previous query to 'A', change predicates of inequality, so we cannot use index. Optimizer knows this and switches for FTS and introduced an additional step of operation FILTER. In my view, the filter predicate can be applied in operation of FTS. Additional FILTER stage is the predicate as FALSE hard-coded value. It does not yet use our predicate of the query.

  Well, don't know if he actually bypasses the operation of FTS. SQL trace can indicate that.

  > explain plan for select v1 of tst where v1 > 'A' and v1<>

  ---------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  ---------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |      |     1.     8 S     0 (0) |          |

  |*  1 |  FILTER |      |       |       |            |          |

  |   2.   TABLE ACCESS FULL | TST |    49.   343.     3 (0) | 00:00:01 |

  ---------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - filter (NULL IS NOT NULL AND NULL IS NOT NULL)

  Subsequently, optimizer decides to use the INDEX RANGE SCAN, even if the predicate is always an inequality. Go figure...

  > explain plan for select v1 of tst where v1 > 'A' and v1<=>

  -------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  -------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     8 S     0 (0) |          |

  |*  1 |  FILTER |           |       |       |            |          |

  |*  2 |   INDEX RANGE SCAN | TSTV1_IDX |     1.     8 S     0 (0) | 00:00:01 |

  -------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - filter (NULL IS NOT NULL)

  2 - access("V1">'A' AND "V1")<>

  As others have said, it is difficult to understand and predict the path, but fortunately Oracle doing the right thing, 99% of the time.

  VR

  Sudhakar

• Apply the CC updates, restart and CC says that I have the same updates again

  I have a computer which simply refuses to apply the updates.

  They abound, they say their installed/updated to date. But when I restart the computer, the same 21 updates keep coming back to the top.

  Any ideas?

  David

  Here's the solution to this problem:

  Reach:

  ~/Library/application support/Adobe.

  And remove AAM updaterInventroy, AAMUpdater or something similar

  Open the OOBE folder and delete the file opm.db.

  Then go to:

  / Library/Application support/Adobe.

  remove the updaterInventroy, AAMAdobeUpdater or AAMUpdaterInventory MAO

  Open the OOBE folder and delete the file opm.db.

  Sorry, intended to update this yesterday.

• FROM SHAPED DATENREPORT (how on the same page)

  Hello everyone
  
  Yes, I know that it is built in a design of two pages where the first is the form and the second report, but I want it for both on the same page so that you can see what he has on the report and add his own line to the table. Well, I could make the creation of a form, then by changing the page and then add another region. Alright. But then I don't know how to link them together so that the data is passed to the form of the report.
  
  Additionally, the form to fill the data must pass in two separate tables, because a table contains the details of the location and the other opinion about each store. Easy to do on PHP and mysql, but here I'm lost.
  
  Second thing that drives me crazy it is that I created a table named location as well as street postal code for a store and another for assessment so that customers or workers add a suite evaluate services etc.
  
  Well, I'm trying to create that shape, that I first talked about this would hold all fields and I do on a SQL query that contains the definitions of the two tables. My XE is completely empty from the remains of other applications, etc. I do the equijoin alright
  
  
  Select l.loc_id, l.company, l.postcode, l.street, l.town, e.eval_id, e.loc_id, e.locum_reg, e.date_booked, e.items, e.addicts, e.number_staff, e.attitude_staff, e.organisation, e.stock_filing, e.agency
  location, e-assessment
  where l.loc_id = e.loc_id
  
  and I get this annoying error all the time
  
  
  ORA-20001: unable to create the form on equijoin. ORA-20001: Error Page = 2 item = 'P2_LOC_ID' id = '1324114494879878' ORA-20001: error page 2 item = = "P2_LOC_ID" id = "1324114494879878" a same name something like existing at the level of applications. ORA-0000: normal end successfully
  
  Well, if this form consists of two tables, it must definitely something in common with them! How did the name of the element suppose to have another name? It is made with the wizzard so supposedly the wizzard you should know, but I tried two days 14 hours a day.
  
  no indication of how this problem would be invaluable for me
  
  Thank you
  
  Alvaro

  Alvaro:

  This help if you supplied alias names to the "loc - id" of each table column in the SQL query? Something like

  select l.loc_id location_loc_id, l.company, l.postcode, l.street,l.town, e.eval_id, e.loc_id evaluation_loc_id, e.locum_reg, e.date_booked, e.items, e.addicts, e.number_staff, e.attitude_staff, e.organisation, e.stock_filing, e.agency
  from location l, evaluation e
  where l.loc_id = e.loc_id
  

  CITY