View 4.0 update number 2 with sophos

Hi I'm Stefano from Italy,

I have a problem with my Windows XP virtual machine, in fact recently I installed the new version of the sophos endpoint server, I've updated my master VM and then I did a recompose to update all my VM 40.

Now, I noticed that all of my virtual machine slowed down when sophos server is online, while the result ok when sophos server is offline.

Help me please

Thank you

Best regards

AntiVirus in VDI environments can cause a strain on the backend disk configurations and slow down easily in the environment.    Have you read the whitepaper deployment of VMware Vew AV?  http://www.VMware.com/files/PDF/VMware-view-AntiVirusDeployment-WP-en.PDF

Tags: VMware

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    http://docs.Oracle.com/CD/B28359_01/server.111/b28286/statements_9016.htm

    MERGE INTO bonuses D
       USING (SELECT employee_id, salary, department_id FROM employees
       WHERE department_id = 80) S
       ON (D.employee_id = S.employee_id)
       WHEN MATCHED THEN UPDATE SET D.bonus = D.bonus + S.salary*.01
         DELETE WHERE (S.salary > 8000)
       WHEN NOT MATCHED THEN INSERT (D.employee_id, D.bonus)
         VALUES (S.employee_id, S.salary*.01)
         WHERE (S.salary <= 8000);
    
  • Update of table with invalid identifiers

    Hello!

    I use a third-party plug-in and that comparisons of chemical structures. I want to update a table with the values of the other when the plugin matches two rows. However, I'm a problem invalid identifier.

    Two tables:
    PLATES: a VARCHAR2 columns of PLATE_SMILES, IN_DB
    INVEST: a VARCHAR2 columns of SMILES

    The operator is a binary: jc_compare (PLATE_SMILES, SMILES) = 1 (or 0 if they do not match)

    I want my query to say: "If comparison SMILES, PLATE_SMILES = 1, define IN_DB = 1 for row" - effectively asking if PLATE_SMILES exists in the table INVEST.

    I tried a number of "renditions", all identifiers not valid donations. Here is an example:

    Update (select plate. PLATE_SMILES, plate. IN_DB, invest. SMILES
    plate PLATES
    INVEST invest
    WHERE jc_compare (PLATE_SMILES, SMILES) = 1)
    set plate. IN_DB = 1;


    ORA-00904: "FLAT". "" IN_DB ": invalid identifier


    I hope that this should be an easy fix, and any help is greatly appreciated!

    Hello

    You have

    UPDATE (SELECT plate.plate_smiles,
                   plate.in_db,
                   invest.smiles
            FROM   plates plate, invest invest
            WHERE  jc_compare ( plate_smiles, smiles) = 1)
    SET    plate.in_db = 1;   -- Error here
    

    PLATE is not known outside the display online. Just remove it.

    Concerning
    Peter

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