What day of the month are updates released and how often?

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• First day of the month between 08:00 and 18:30

  DB version: 10.2.0.4
  
  Due to the nature of our the first working day of each month (like today 1 MS), the DB will be very busy.
  We execute a proc purge planned Windows Scheduler every 5 minutes every day.
  
  But the first day of every month (like today 1 MS), if it's a day of the week (Monday to Friday) we do not want this proc running between 08:00 and for dinner from 18:30.
  
  So, I thought including the logic in the procedure itself.
  
  How can I implement this?
  
  Edited by: user872043, Sep 1 2010 08:48

  Here is an example of using DBMS_SCHEDULER which should meet your needs:

  Create schedules

  BEGIN
          DBMS_SCHEDULER.CREATE_SCHEDULE
          ( schedule_name   => 'every_5_schedule'
          , repeat_interval => 'FREQ=MINUTELY; BYMONTHDAY=2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31; INTERVAL=5; BYSECOND=0'
          , comments        => 'Schedule to run every 5 minutes'
          );
  
          DBMS_SCHEDULER.CREATE_SCHEDULE
          ( schedule_name   => 'busy_hourly_schedule'
          , repeat_interval => 'FREQ=MINUTELY; BYMONTHDAY=1; BYHOUR=0,1,2,3,4,5,6,7,19,20,21,22,23; INTERVAL=5;'
          , comments        => 'Schedule to run every 5 minutes except certain hours on the first of the month'
          );
  
          DBMS_SCHEDULER.CREATE_SCHEDULE
          ( schedule_name   => 'busy_6pm_schedule'
          , repeat_interval => 'FREQ=MINUTELY; BYMONTHDAY=1; BYHOUR=18; BYMINUTE=30,35,40,45,50,55'
          , comments        => 'Schedule to run every 5 minutes from 6:30 - 7'
          );
  END;
  /
  

  There are three lists.

  every_5_schedule - runs every 5 minutes for all the days that are not on the first day of the month
  busy_hourly_schedule - runs every 5 minutes for the acceptable hours on the first day of the month
  busy_6pm_schedule - retrieves the half hour from 6:30 - 7 on the first day of the month.

  Then, create your business:

  Job creation

  BEGIN
          DBMS_SCHEDULER.CREATE_JOB
          ( job_name        => 'YOUR JOB'
          , job_type        => 'PLSQL_BLOCK'
          , job_action      =>'BEGIN YOURPROC; END;'
          , repeat_interval => 'EVERY_5_SCHEDULE, BUSY_HOURLY_SCHEDULE, BUSY_6PM_SCHEDULE'
          , enabled         => TRUE
          , comments        => 'Some comments'
          );
  END;
  /
   
  

  HTH!

• Monday the 1st business day of the month of 15 before and after 15.

  I want to choose the 1st Monday with the business day (Y) of a month (january), owned by the 15th of the month and after the 15th of the month.
  Whereas it should be 2 folders, 1 record should be before the 15th of the month with the word 'Monday' & Holiday (N) and 2nd record should be based on the 15th of the month
  with the word 'Monday' & Holiday (N).
  
  Table:-holiday
  Column
  ---------
  Time_Date - holiday - Time_Day
  2011-01-01 00:00:00 - N - Tuesday
  
  Please let me know the oracle query.
  
  Thanks and greetings
  R Rodriguez
  
  Edited by: 880353 August 19, 2011 05:14

  It's almost like this... just a matter of playing with the SQL to reorganize the command:

  Select
  min (case when TIME_DATE between trunc(sysdate,'MM') and trunc (sysdate, 'MM') + 13 and)
  H.HOLIDAY = ' only then end TIME_DATE to another null) «FIRST»,
  min (case when TIME_DATE between trunc (sysdate, 'MM') + 14 and last_day (sysdate) and)
  H.HOLIDAY = ' only then end TIME_DATE to another null) "FIRST > = 15.
  Holiday h.
  (select next_day (trunc(sysdate, 'MONTH')-1, 'Monday') + 7 *(level-1) double DD
  connect by level<= 5)="">
  where M.DD = h.TIME_DATE

• How many times the files are saved automatically and how to clear the backup?

  The properties of a folder in the Windows 7 system, you can retrieve files stored once even if they have been removed.

  How many times are the files saved in this way automatically?
  Files including files get saved in this way?
  How long they stay in the system?
  How can we make them disappear in order to reclaim space?

  Because I am doing a complete disk image automated nightly, I did not invoke the 'previous version' feature of Windows 7 and therefore do not know many details about it.

  These web pages are substantially the same as the help files for support &, but maybe add a little:
  http://Windows.Microsoft.com/en-us/Windows-Vista/previous-versions-of-files-frequently-asked-questions
  http://Windows.Microsoft.com/en-us/Windows7/recover-lost-or-deleted-files

  'Previous versions' applies to both files and folders.  I haven't experienced it, but likely restore a previous version of a file would restore files that have been deleted from this folder since the creation of the earlier version.

  Under Windows 7, restore points are created automatically each week (on XP, it was once / day) and just before significant system events, such as the installation of a program or device driver. You can also create a manually restore point.  In practice, you will find a lot more than one restore points / week.  For example, my Win 7 Pro box displays the restore points following last week:
  Automatic restore point 3/17
  Update of windows of 3/16
  Update of windows of 3/16
  Windows 3/12 update
  Installed software 3/11
  USB device driver installed 3/11
  Automatic restore point 3/10

  It is not clear to me how to change the frequency of the automatic system restore points in Windows 7. If seen sites which proposes to change the frequency of a scheduled task in the Task Scheduler - but the settings in my task scheduler to launch SR once / day and as seen above, which does NOT result in a daily automatic Restore Point. I saw references to editing a registry value, but it was not definite either.

  To remove "Previous Versions"-

  • Click on the start Orb, then right click on "Computer", then select Properties (Alternatively, control panel > system)
  • Click on the "System Protection" link in the left pane
  • Click on the tab 'System Protection '.
  • Click on the button "configure."
  • Select the option "Turn off system protection" or click on the button 'delete '.
  • OK your way out

  If I have not addressed your questions, it is because I do not know the answers.

• What happen to folios in the 2015 to indesing version, how do I create a new folio in the new version, what happens with the sheets that I create and how can I download the adobe Viewer? Thank you

  Folios indesing 2015 version, what happens?

  Transferred to DPS forum

  DPS and CC 2015 InDesign

• At what stage of the treatment we use a rule to update to apply logic to the way the data are updated in the database?

  Hello

  At what stage of treatment do you use a rule to update to apply logic to the way the data are updated in the database?

  Rahul

  Hello Rahul,

  Update the existing record or a data object

  Thank you

  edynamic expert Eloqua

• While turning on the laptop its gives me a message "your pc will restart in two days for the installation of updates.

  About a week ago I just bought windows mobile 8 is installed. Now for the last two days while turning on the laptop its gives me a message "your pc will restart in two days for the installation of updates.

  To stop, I get three option 1) sleep 2) arrested update 3) and close

  What should I do?

  Original title: windows update issue 8.

  Hi Parichay,

  The updates that are being invited to install are automatic updates.

  The message you get is offered by Windows 8 after that updates are downloaded and installed.

  If you do not restart your computer soon, Windows will force a restart of your computer two days after that it has installed new updates to complete their installation.

  You must restart your computer at a convenient time for you, rather than wait two days and have it suddenly reboot maybe at an inopportune time.

  Hope that solves your problem.

• First day of the month

  How to find the first day of the month if the month format is like TO_CHAR(SYSDATE,'YYYYMM')
  
  Sanjay

  Published by: user12957777 on May 23, 2012 21:12

  There is no 'day' in this date format.

  What you trying to do? What do you expect the result to look like?

  Are you wanting to set a date for the first day of the month and year of your example?

  SELECT TO_DATE(TO_CHAR(SYSDATE,'YYYYMM') || '01', 'YYYYMMDD') FROM DUAL;
  

• Day of the month Dimension or is there another way?

  I was asked to create a cube that contains data at the granularity of a day. For example, the daily sales. However, Essbase does not allow duplicate member names. I built temporarily an additional dimension of day of the month to allow the loading of the data, but the presentation to users is a little awkward using Smart View in Excel as they expected data rollup by date. Anyone is attacked in a similar project? Thank you.

  I would not create a dimension of day. I did several cubes 'daily' in my career. A good question to ask yourself is "turning back is really important daily detail?" For each project every day that I did, this response is in the ballpark of two or three months... and no more. So what I did was to create a rolling cube of two months (or three) with separate daily details (put in the alias and refreshing dates by load rules then roll to a new month.) This cube balances with the same two months in the full year monthly retail only cubes. I did my first one before there was the partitioning or @XREF so now you have options to connect these cubes. Even if you load the monthly cube full year directly, it might be interesting to create a "related" partition so that users can jump from the current month or the month before, for example, in the year cube full in the daily details expanded in the daily cube.

  If it turns out a full year of daily detail is necessary (although I doubt it is the need in an OLAP model given the possibilities for extracting relational retail uses the EIA or Essbase Studio depending on your version), then ASO would be my choice to handle the extra volume. Otherwise, I'm talking about BSO. I hope you find it useful.

  Sincerely, Darrell Barr

  PS - don't forget that you can activate duplicate names if you are on the latest versions of the product (although I don't really recommend it).

• Last day of the month with the last minute of the day

  Hello
  I wonder about how to get the last day of the month with the last minute of this day(23:59). We can use the last_day function (DATE) to get the last date, but reminds me of the time of day when the function has been executed. But I want to have the last minute with my last date of the current month.
  
  Please inform.
  
  Thank you
  
  HP

  Hello

  Ora_bie wrote:
  Hello
  I wonder about how to get the last day of the month with the last minute of this day(23:59). We can use the last_day function (DATE) to get the last date, but reminds me of the time of day when the function has been executed. But I want to have the last minute with my last date of the current month.

  In fact, it returns at the same time as the argument you pass; But whatever it is, is not what you want.

  This will return the last day of the month that contains the DATE 23:59 (or 23:59) dt:

  SELECT  ADD_MONTHS ( TRUNC (dt, 'MONTH')
               , 1
               ) - (1 / (24 * 60))
  FROM    dual
  ;
  

  TRUNC (dt, 'MONTH') is 00:00 on the first day of the month that contains dt.
  ADD_MONTHS (TRUNC (dt, 'MONTH'), 1) is from 00:00 the first day of the month following the one containing dt.
  ADD_MONTHS (TRUNC (dt, 'MONTH'), 1)-(1 / (24 * 60)) is a minute earlier.
  (Since there are 24 hours, each with 60 minutes, every day, 1 / (24 * 60) days is identical to a minute.)

  Another (less clear, in my opinion) way to get the same results is:

  TRUNC (LAST_DAY (dt)) + (1439/1440)  -- 1440 minutes = 1 day
  

• Get the first and the last day of the month...

  Hi friends,
  
  I'm trying to get the first and last day of a month and wants to implement that in the following code:
  
  SELECT COALESCE (Date_A, Date_B, Date_C)
  OF the double
  
  Here Date A and B are in Format DD MM YYYY (March 14, 2008)
  and Date like MM YYYY (March 2008)
  
  How can I get the Date_C as of March 1, 2008, OR March 31, 2008 if Date A and B are NULL?
  
  Thank you!
  
  Published by: user11095386 on April 23, 2009 10:45

  Hello

  In my previous message, I thought that you were starting with strings like ' 03 12 2009"and you want to display in the form of" 12 March 2009'.» If what you have is just the opposite, then simply reverse strings format in my first message. Add a comma, if you want, in the format string.
  I think that's what you want:

  COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_C, 'fmMonth YYYY'),    'MM DD YYYY')
           )
  

  Notice how, on the 3rd line, TO_DATE is called without DD in the format string:

  TO_DATE ( Date_C, 'fmMonth YYYY')
  

  When you do so, by default the day the 1st of the month, so that's all you need to do to convert the VARCHAR2 'March 2009' at the DATE of March 1, 2009.

  If you would like the last day of the month, not the first, when Date_C is selected, then use LAST_DAY:

  COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( LAST_DAY ( TO_DATE ( Date_C
                                            , 'fmMonth YYYY'
                              )
                       )
               , 'MM DD YYYY'
               )
           )
  

• How to calculate the first day of the month following in BI Publisher

  I need to be able to calculate the first day of the month of a date field in a BI Publisher model. The field name is COL_CLM_180 and contains a date in the format "YYYY-MM-DD". I have found so far any documentation that still gives me an idea of what to do.

  Any help or advice would be appreciated

  Hi - thank you very much for your help. Your last answer got me going in the right direction and I indeed was dense. I don't know why I don't think to the calculation in the original query. I put the statement: TRUNC (ADD_MONTHS(A.COL_CLM_180,1), 'MM') in a column in the query of conduct and it has worked flawlessly. Thank you - thank you - thank you.

• first day of the month and time

  Hello

  Using oracle 11.2.0.3

  A table with a column date

  sample opening time data 04/08/2014-08:30 one single column, another column start date 04/02/2014

  Want to have a sql that will go through an opening time table set on the first day of the month as well as existing time

  for example expect times to be

  04/01/2014 08:30

  Code below will give the first day of the month

  What is the best way to achieve this-date data type columns.

  {code}

  Select trunc(start_time,'MM))

  of customer_hours ch

  {code}

  Select

  SYSDATE - trunc (sysdate) + trunc (sysdate, 'MM')

  of the double

  resp.

  Select

  start_time - trunc (start_time) + trunc (start_time, 'MM')

  of the double

• Breaking a year in coming weeks of beginning and end Dates (parameters) and first and last day of the month

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  SELECT first_thursday + (7 * (LEVEL - 1))   AS week_start_date,
                   first_thursday + (7 * LEVEL) - 1    AS  week_end_date
  FROM
  (
    SELECT TRUNC(p_from_date + 4, 'IW') - 4   AS first_thursday, -- Week should start the pre ceeding THURSDAY based on the Start Date
                    TRUNC( p_to_date + 4,  'IW') - 5     AS last_wednesday
    FROM
    (
      SELECT to_date('01-JAN-2013') AS p_from_date,
                      NVL(to_date('31-DEC-2013'), SYSDATE) AS p_to_date
      FROM     dual
    ) parms
  ) end_points
  CONNECT BY LEVEL <= ( last_wednesday + 1 - first_thursday)/7;
  

  Currently, this is the result I get (I'm only including the months of January and December here).

  Week_Start_Date     Week_End_Date
  27-DEC-12                02-JAN-13
  03-JAN-13                 09-JAN-13
  10-JAN-13                 16-JAN-13
  17-JAN-13                 23-JAN-13
  24-JAN-13                 30-JAN-13
  31-JAN-13                 06-FEB-13
  

  December:

  28-NOV-13               04-DEC-13
  05-DEC-13              11-DEC-13
  12-DEC-13              18-DEC-13
  19-DEC-13              25-DEC-13
  

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  01-JAN-13              02-JAN-13
  03-JAN-13              09-JAN-13
  10-JAN-13             16-JAN-13
  17-JAN-13             23-JAN-13
  24-JAN-13             30-JAN-13
  31-JAN-13             31-JAN-13
  

  February:

  01-FEB-13    06-FEB-13
  07-FEB-13    13-FEB-13
  14-FEB-13    20-FEB-13
  21-FEB-13    27-FEB-13
  28-FEB-13    28-FEB-13
  

  November:

  31-OCT-13    06-NOV-13
  07-NOV-13    13-NOV-13
  14-NOV-13    20-NOV-13
  21-NOV-13    27-NOV-13
  28-NOV-13    04-DEC-13
  

  December:

  01-DEC-13           04-DEC-13
  05-DEC-13           11-DEC-13
  12-DEC-13          18-DEC-13
  19-DEC-13          25-DEC-13
  26-DEC-13          31-DEC-13
  

  Hello

  Roxyrollers wrote:

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  1. First_thursday SELECT + (7 * (LEVEL - 1)) AS week_start_date,
  2. first_thursday + (7 * LEVEL)-1 AS week_end_date
  3. Of
  4. (
  5. SELECT TRUNC (p_from_date + 4, 'IW') - 4 AS first_thursday,-week should start to perform the pre-mounted THURSDAY based on the Start Date
  6. TRUNC (p_to_date + 4, 'IW') - 5 AS last_wednesday
  7. Of
  8. (
  9. SELECT to_date('01-JAN-2013') AS p_from_date,
  10. NVL (to_date('31-Dec-2013'), SYSDATE) AS p_to_date
  11. OF the double
  12. ) parms
  13. ) end_points
  14. CONNECT BY LEVEL<= (="" last_wednesday="" +="" 1="" -="">

  Currently, this is the result I get (I'm only including the months of January and December here).

  1. Week_Start_Date Week_End_Date
  2. DECEMBER 27, 12 2 JANUARY 13
  3. JANUARY 3, 13 JANUARY 9, 13
  4. 10 JANUARY 13 JANUARY 16, 13
  5. 17 JANUARY 13 23 JANUARY 13
  6. 24 JANUARY 13 30 JANUARY 13
  7. 31 JANUARY 13 FEBRUARY 6, 13

  December:

  1. NOVEMBER 28, 13 4 DECEMBER 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  1. JANUARY 1, 13 2 JANUARY 13
  2. JANUARY 3, 13 JANUARY 9, 13
  3. 10 JANUARY 13 JANUARY 16, 13
  4. 17 JANUARY 13 23 JANUARY 13
  5. 24 JANUARY 13 30 JANUARY 13
  6. 31 JANUARY 13 JANUARY 31, 13

  February:

  1. 1ST FEBRUARY 13 FEBRUARY 6, 13
  2. 7 FEBRUARY 13 FEBRUARY 13, 13
  3. 14 FEBRUARY 13 FEBRUARY 20, 13
  4. 21 FEBRUARY 13 FEBRUARY 27, 13
  5. 28 FEBRUARY 13 FEBRUARY 28, 13

  November:

  1. 31 OCTOBER 13 NOVEMBER 6, 13
  2. 7 NOVEMBER 13 NOVEMBER 13, 13
  3. 14 NOVEMBER 13 NOVEMBER 20, 13
  4. 21 NOVEMBER 13 NOVEMBER 27, 13
  5. NOVEMBER 28, 13 4 DECEMBER 13

  December:

  1. 1ST DECEMBER 13 DECEMBER 4, 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13
  5. 26 DECEMBER 13 DECEMBER 31, 13

  Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less?  (For example, February 28 is a 'week' alone.)

  The following works for the other months:

  WITH all_days AS

  (

  SELECT DATE "2013-01-01' + LEVEL - AS a_date 1

  OF the double

  CONNECT BY LEVEL<=>

  )

  SELECT DISTINCT

  More GRAND (TRUNC (a_date + 4, 'IW') - 4)

  , TRUNC (a_date, 'MONTH')

  ) AS week_begin

  , The LEAST (TRUNC (a_date + 4, 'IW') + 2

  TRUNC (LAST_DAY (a_date))

  ), Week_end

  Of all_days

  ORDER BY week_begin

  ;

  Output:

  WEEK_BEGIN WEEK_END

  ----------- -----------

  January 1, 2013 January 2, 2013

  January 3, 2013 January 9, 2013

  January 10, 2013 January 16, 2013

  January 17, 2013 January 23, 2013

  January 24, 2013 January 30, 2013

  January 31, 2013 January 31, 2013

  February 1, 2013 February 6, 2013

  February 7, 2013 February 13, 2013

  February 14, 2013 February 20, 2013

  February 21, 2013 February 27, 2013

  February 28, 2013 February 28, 2013

  ...

  November 1, 2013 November 6, 2013

  November 7, 2013 November 13, 2013

  November 14, 2013 November 20, 2013

  November 21, 2013 November 27, 2013

  November 28, 2013 November 30, 2013

  December 1, 2013 December 4, 2013

  December 5, 2013 December 11, 2013

  December 12, 2013 December 18, 2013

  December 19, 2013 December 25, 2013

  26 December 2013 31 December 2013

• I have purchased the monthly pack of LR and PS for my iMac but appear always as "evaluation period". I have another LR and PS pack installed on my MacBook Air ajd it works ok. What should I do to unlock the "trial period" message, when I start LR o PS?

  I have purchased the monthly pack of LR and PS for my iMac but appear always as "evaluation period". I have another LR and PS pack installed on my MacBook Air ajd it works ok. What should I do to unlock the "trial period" message, when I start LR o PS?

  Hello

  Please see the links below:

  Connect and disconnect activate Cloud Creative applications

  Applications creative Cloud back in test mode after an update until 2015 for CC

  Enable and disable Adobe products

  Creating cloud connection errors

  Creating cloud app request serial number

  Let us know if that helps.

  Kind regards

  BANI