Analog trigger with time information

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  We have two PCIe analog LTC/VITC time Code Reader (Adrienne card) we would like to install on one of our virtual dedicated server

  My question is, how can make us it one of the Virtual hosts to recognized this card and use it or its automatically detects?

  Please advice

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  You can't do work at all - random PCI cards may not have sent resources to a virtual computer.

  -Matt

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• How to structure the DMA buffer for SMU 6341 DAQ card for analog output with different frequencies on each channel

  I use the outgoing/incoming analog DDK with the DAQ 6341 SMU map.

  The examples, for example aoex5, show a single timer (method outTimerHelper::loadUI), but the example shows the DMA loaded with same size of vector data.

  There is a comment in the outTimerHelper:call rogramUpdateCount, which implies that memory sizes different pad per channel can be used.

  (the comment is: switching between the sizes of the various buffers is not used)

  Nobody knows what should be the format the DMA buffer for data from multiple channels with different frequencies?

  For example, we want a0 with a sinusoid at 1 kHz and a1 with a sine wave of 1.5 Khz.  What looks like the DMA buffer?

  With the same frequency for each channel, the data are interleaved, for example (ao0 #0, ao1 #0; ao0 ao1 #1, #1,...), but when the frequencies for each channel is different, what the stamp looks like?

  Hello Kenstern,

  Data are always intertwined since each card has only a single timing for each subsystem engine.

  To AO, you must specify the number of samples that will be released to the AO. You also specify the number of channels. Because he didn't is that a single engine timing for AO, each AO will be channel will be updated at the same time to update clock tick. Data will be interlaced exactly as shown in the example because each channel AO needs output at each tick of the clock to update. The data itself can change depending on the frequency you want to copy.

  kenstern wrote:

  For example, we want a0 with a sinusoid at 1 kHz and a1 with a sine wave of 1.5 Khz.  What looks like the DMA buffer?

  With the same frequency for each channel, the data are interleaved, for example (ao0 #0, ao1 #0; ao0 ao1 #1, #1,...), but when the frequencies for each channel is different, what the stamp looks like?

  In your example, you must come with an update rate that works for the two waveforms (sine waves of 1 and 1.5 KHz). To get a good representation of a sine wave, you need to update more than 10 x faster than your fastest frequency... I would recommend x 100 if possible.

  Update frequency: 150 KHz

  Channels: 2

  Then create you stamps that include complete cycles of each wave you want to produce based on the frequency of update. These buffers must also be of the same size.

  Buffer 1: Contains data for the sine wave of 1 KHz, 300 points 2 cycles of sine wave

  Buffer 2: Contains data for the sine wave of 1.5 KHz, 300 points, 3 cycles of sine wave

  You can Interleave them as before. When the data are performed through the ADC, they are out different sine waves, even if the AO channels are updated at the same speed.

• Trigger with NOR-DAQmx in Ansi C/C++ and OR USB-6210

  Hello

  We need to read an analog signal each time a trigger signal it is does not know how to get the trigger to work. Here is the code that we have found so far:

  ////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

  ...
  DAQmxErrChk (DAQmxCreateAIVoltageChan (analogInputTaskHandle, "Dev1/ai0", "AI0', DAQmx_Val_Diff,-10, 10, DAQmx_Val_Volts, NULL));

  Int32 numSampsPerChan = 20;
  uInt64 sampsPerChan = numSampsPerChan;
  float64 timeout = 0; Time in seconds to wait for the function read String-> 0 try to read only once; -1 wait infinitely;
  bool32 fillMode = DAQmx_Val_GroupByChannel; Reading non-interlaced channel
  const uInt32 arraySizeInSamples = 20; Number of samples that are read
  float64 analogValuesFromDevice [arraySizeInSamples];
  sampsPerChanRead of Int32;
  bool32 * reserved = NULL;

  char startTrigger [256] = ' / PFI0/Dev1;
  int startEdge = DAQmx_Val_Rising; rising edge

  DAQmxErrChk (DAQmxCfgSampClkTiming (analogInputTaskHandle, "", 10000.0, DAQmx_Val_Rising, DAQmx_Val_FiniteSamps, 10));

  DAQmxErrChk (DAQmxCfgDigEdgeStartTrig (analogInputTaskHandle, startTrigger, startEdge));

  DAQmxErrChk (DAQmxStartTask (analogInputTaskHandle));

  DAQmxErrChk (DAQmxReadAnalogF64 (analogInputTaskHandle, numSampsPerChan, timeout, fillMode, analogValuesFromDevice, arraySizeInSamples, & sampsPerChanRead, reserved));

  DAQmxErrChk (DAQmxStopTask (analogInputTaskHandle));

  Frees the memory of the task
  DAQmxErrChk (DAQmxClearTask (analogInputTaskHandle));

  ...

  ////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

  This is the error message we receive.

  DAQmx error: relation to the outbreak of the reference or the beginning reading
  position of pre-trigger samples before the acquisition is completed.

  Wait until the acquisition is complete before reading or increase your reading timeo
  UT. Additionally, make sure that the equipment is set up and wired correctly, the signal for
  the reference trigger is correct, and that the reference trigger occurs during th
  e device is data acquisition.
  Property: DAQmx_Read_RelativeTo
  Value: DAQmx_Val_FirstPretrigSamp

  Task name: ReadAnalogInput

  State code:-200281

  Can you tell us how to expect the acquisition supplement or increase our reading timeout? We think these are the problems we face.

  Thanks for all your help.

  Update:

  We use is no longer a trigger, so it's resolved.

  We believe that we receive at the origin of the mistake because we weren't using a TTL signal.

• Two tasks to trigger a simple analog trigger signal

  I use the 6351 and have two tasks:

  AnalogInputTask has 3 channels of I

  AnalogOutputTask has 1 channel AO

  When I created these two tasks to trigger a single digital channel, I have no problem. But when I want to use an analog trigger, I get error 50103 during the second task (no matter the order in which they are in) is engaged. Are there restrictions with the implementation of an analog trigger?

  The code looks like this:

  public AnalogInputChannel (config ConfigSettings, sweep of SweepSettings, SweepType sweepType)
  {

  AnalogInputTask = new Task();
  AnalogInputTask.AIChannels.CreateVoltageChannel (voltageChannelName, "detection of voltage", AITerminalConfiguration.Differential, -5, 5, AIVoltageUnits.Volts ");
  AnalogInputTask.AIChannels.CreateCurrentChannel (currentChannelName, "meaning current", AITerminalConfiguration.Differential, -15, 15, currentSense, AICurrentUnits.Amps ");
  AnalogInputTask.AIChannels.CreateVoltageChannel (irradianceChannelName, "Meaning the irradiance", AITerminalConfiguration.Differential, 0, 5, AIVoltageUnits.Volts);
   
  AnalogInputTask.Triggers.StartTrigger.ConfigureAnalogEdgeTrigger (sweepTriggerAIChannel, AnalogEdgeStartTriggerSlope.Rising, aiTriggerLevel);

  AnalogInputTask.Timing.ConfigureSampleClock (string. Empty, rate, SampleClockActiveEdge.Rising, SampleQuantityMode.FiniteSamples, length);
  AnalogInputTask.Stream.ReadAllAvailableSamples = true;
  AnalogInputTask.Stream.ReadWaitMode = ReadWaitMode.Poll;
  Reader = new AnalogMultiChannelReader (t.Stream);
  AnalogInputTask.Control (TaskAction.Commit);
  AnalogInputTask.Start ();
  }

  public AnalogOutputChannel (config ConfigSettings, sweep of SweepSettings, SweepType sweepType)
  {
  AnalogOutputTask = new Task();
  AnalogOutputTask.AOChannels.CreateVoltageChannel (vOutChannel, "voltage Source", -10, 10, AOVoltageUnits.Volts ");

  AnalogOutputTask.Triggers.StartTrigger.ConfigureAnalogEdgeTrigger (sweepTriggerAIChannel, AnalogEdgeStartTriggerSlope.Rising, aiTriggerLevel);
             
  AnalogOutputTask.Timing.ConfigureSampleClock ("", note, SampleClockActiveEdge.Rising, SampleQuantityMode.FiniteSamples, length);
  Writer = new AnalogSingleChannelWriter (t.Stream);
  Writer.WriteMultiSample (false, waveform);
  AnalogOutputTask.Control (TaskAction.Commit);  ERROR GETTING PAST HERE
  AnalogOutputTask.Start ();
  }

  Instead of I. StartTrigger, try to use the name of Terminal DAQmx "/ Dev1/AI/StartTrigger.

  Best regards

• before trigger with four cards PXI-6115

  Hello

  I have a PXI-1010 chassis with four cards PXI-6115, labeled boards 3, 4, 5, 6, installed in it.  Each of these cards has 4 analog inputs (BNC inputs).  In my current system, all four boards fire off the coast of the entrance on first 3 analog.  I'm using an analog trigger mounted on Board 3, which then triggers a trigger digital beginning on the boards, 4, 5 and 6.

  Now, I would be able to take samples before firing.  I worked on this for a while and that seems to happen is that 3rd Chess Board properly triggers and takes samples of relaxation before, but plates 4, 5 and 6 are somehow trigger too late or early or something - they never record my test signal input of.

  Can someone help me understand where I'm going wrong here?  I enclose my VI and also a picture of the important part of my block diagram.

  Thank you!

  It could be that you connect the number of samples per channel in the clocks of the sample for tables 4, 5 and 6. This will ensure that the task creates a buffer on your PC that is large enough to accommodate all the samples you want to read.

  Also, why did you remove the structure of sequence? You need to ensure that the advice of slaves were armed in front of the master bedroom.

  Here is a link to an example similar to what you're trying to do. This example acquires the data at different speeds on different boards, but it seems that everything is identical to what you are doing. I think it might be useful for you: https://decibel.ni.com/content/docs/DOC-11698

  Jeremy P.

• redeclenchables out initial varaible on each trigger with delay

  I'm trying to implement a redeclenchables generation digital pulses of the train on 6363 PCIe with LabVIEW with the additional feature of an initial delay variable.

  For example:

  -J' have a fixed pulse train

  -After the 1st trigger, it is generated without delay

  -2nd after trigger, there is a delay of 10µs

  -Each subsequent trigger increases the delay of 10µs

  I tried to do by writing new samples to the digital output, which include an initial delay. Since it merely controls how the buffering is managed this does not seem to work reliable with reboot and redeclenchables ouput.

  Is there another way to do this using a perhaps additional internal counter for the generation of delay?

  Thank you

  Christoph

  I would look at using an additional counter that your delay generator.  There is a counter property called

  Delay 'auto increment Count', which lets specify you such a regularly increasing.  Here is one

  DevZone article and example that should help get you started.

  The idea is that the extra meter comes between your initial trigger signal and the

  pulse train finish that you want to generate.  The additional counter made its own triggered impulse

  with time growing after the initial trigger and your finite pulse train gets triggered by

  This additional counter output.

  -Kevin P

• Problems with timer

  repTimer = new timer (650, pattern.length);

  repTimer.start ();
  repTimer.addEventListener (TimerEvent.TIMER, chooseColor);

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  private var: delay timer = new Timer (650, 1);

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  Essentially what this should do changes an image every 650 ms according to the values stored in the table model.

  However, it seems to make them all at once, can any1 point out what I'm doing wrong here?

  I don't quite understand what you're trying to do, but here's something that can help:

  You create a single instance of "delayed".  So whenever repTimer fires (and note that you asked so that he can produce a total of events "pattern.length"), you run through the loop times "pattern.length", and for each passage, you ask that the self-timer starts.

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  Hello

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  end;
  /

  At this point, function foo was built without debug and function foo2 was build debug.

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  Good luck

  Dean

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