Controls created as dependencies

Similar Questions

• Why can I not use my labview controls created dll in labwindow CVI?

  I created a DLL in LabVIEW for run of LabWindows/CVI.  The DLL is started very well but I have no control on the GUI.  Why and how can I use this GUI controls?

  I found the solution on the following thread.

  http://forums.NI.com/NI/board/message?board.ID=180&message.ID=36951&query.ID=314335#M36951

• [Bug] Controls created from primitives have the wrong default value

  I feel like the scene in South Park where MOM Kyles is in the Office of the Director and the Director asked "Hello, which seems to be"cheesing"you today?  Here's what's me cheesing today:

  When you create a control from a terminal to a primitive of the control's default value is not transmitted to the control is created as we are accustomed from subVIs.  Oh the label certainly will make you think that it is because it seems to be considered good style to write a small exhibition on the default inside the parentheses.

  For example, drop 'Get the tail' on a BD and a control of the size of the queue terminal max.  The control is created has value of-1 as you can imagine, and the label says "the maximum queue size (-1, the queue that is created in this case has an unlimited size.»  It seems as reasonable to do something)".  Okay, maybe my memory is not clear on the actual label, but something like that.  Now to the fact that the default value of the terminal is '-1' and the label contains (-1 blah blah blah), and the current value is '-1', you may suspect that the control's default value is '-1', but you'd be wrong.»»»  '0' is the default I32.

  This is not upward mostly because 1. most of the defaults tend to be default values by default (ie. false, 0, ") 2.  Usually, I first create constants and change the controls later that transfers by default.

  My recent encounter was in a VI that worked until I Inline it and then stopped working.  A man who was difficult to diagnose.  I thought WTF say you I can't create a queue of size 0, I have a control with a value '-1' sitting right here!  Finally, I realized that this feature fed to the default, then I tried "reset default" and to my surprise I saw the value of-1 to 0.  What? What? What?

  Darin.K,

  Thought you might like to know that I filed the request for Corrective Action - 441061 # in response to this post on the forum.  R & D is now aware of the issue.

• How can I remove a control created with NewCtrl?

  I create controls dynamically with NewCtrl(). Now, I need to remove them and create different controls.

  How delete/delete one control that I created with NewCtrl?

  DiscardCtrl (); See the "Programming with controls" section in the help

• Click management problem in the controls created dynamically events

  I'm creating the ObjectListField loop i-e (CustomObjectListField class is extended by the ObjectListField to customize its behavior) but the problem is that only by clicking the list no. 5 is managed other lists click handling is not manipulated thr id mylist2...

  CustomObjectListField mylist2;

  for (int i = 0; i)<>

  {

  mylist2 = new CustomObjectListField();

  }

  and click on manage using method...

  protected boolean navigationClick (int status, int time)
  {

  if(Field==mylist2)
  {/ / implementation of a feature}

  }

  }

  pls help

  Hello Shaina

  Your code is not so clear. I don't know why you're my differrrent creaing objects and passing them to the same reference. The last (the 5th list) one will be that which makes reference. In your method of navigation click you compare the rating with mylist2 that contains the reference to the list 5, it's why you have found the events for 5th list only.

  You must create an array of objectListfield, assign values to it and then use part of this comparison table.

  CustomObjectListField mylist2 [] = new CustomObjectListField [5];

  for (int i = 0; i)<>

  {

  mylist2 [i] = new CustomObjectListField();

  }

  and click on manage using method...

  protected boolean navigationClick (int status, int time)
  {

  if(Field==mylist2[0])
  {/ / implementation of a feature}

  }

  if(Field==mylist2[1])
  {/ / implementation of a feature}

  }

  if(Field==mylist2[2])
  {/ / implementation of a feature}

  }

  .

  .

  .

  .

  .

  }

  It may be useful

  Thanks Pierre

• A datagrid control creating reusable sortCompareFunction

  People,

  I was looking to write a re-usable sortCompareFunction for use with the DataGrids, but I think I'm missing something obvious.  A comparison function sorts has a signature that looks like:

  function mySort (obj1: object, obj2: Object): int

  Now suppose the data for the grid contains objects that have fields 'A', 'B' and 'C '.

  When the mySort() function is called to sort the data, it seems not that I know what column / field in the data of the kind should apply to.  It seems to me that I have to write three functions, one for 'A', a 'B' and one for 'C' and define each of them to the sortCompareFunction for the corresponding column.  But in my solution, I can't do that I have a variable/dynamic number of columns and don't know the name of the field in the object that I need to sort on advance.

  Neil

  I guess you could always take this approach

  http://www.Adobe.com/cfusion/CommunityEngine/index.cfm?event=ShowDetails&ProductID=2&postI d = 8047

  for example

  public void doSortForField(field:String):Function
  {
  return function(obj1:Object,_obj2:Object):int
  {
  Return mx.utils.ObjectUtil.stringCompare (obj1 [field],
  obj2 [Field], true);
  }
  }

  And extend the method (or establish a class) to support an array of fields rather than a single field.

  Bonus points for also support different types.

  -Corey Lucier

• Time of design and of the dynamically created controls

  I have a project written in VC6 as a project of the MFC dialog box. In a particular area, I dynamically create several (the exact number depends on user input) CNiGraphs. There is also a two CNiButtons that were created at design time using the resource editor. The problem I have is that when this dialog box is open, a message appears saying it is an eval version and the control will go off after 5 minutes. After 5 minutes of waiting, the CNiButtons 2 go inactive (black tower), but the continuous CNiGraphs of work. I have a valid license of MStudio 8.1.6, version but it seems that these 2 buttons do not recognize the license. There are also other buttons from the moment of conception of the project, but these have no problem at all. When you create the dynamic creation of the CNiGraphs, give them a valid license string, and I was wondering if there is a problem with the time created and dynamically controls created in the same dialog box to design. Anyone know?

  I don't remember, but I can have created these 2 CNiButtons when I was with only an eval license. (All others were undoubtedly create when I got a full license) Could have an impact on them? I have a vague memory of reading somewhere that DTC create controls to check the license when they are created in the designer and store that info in them license. If this is the case does anyone know an easy way to update the license stored in control? I rather not just delete it and Add again because I would avoid having to redo the tab order (unless someone knows how to easily insert something in the middle of the order of tab instead of having to click through all the controls in the correct order)?

  In addition, I don't know if this would affect anything, but the project was originally built with ComponentWorks 1.0, we were forced to move to MStudio when we met a few bugs in CW, so all controls were originally CW controls which have been converted into control of CNi. I doubt that this is so like everywhere else, we changed during controls is not a problem, but I'm ready to try the suggestions.

  Hi JC,.

  I hope you had a good weekend!  I'm glad to hear that you're back running.  Add the extra button was, in fact, causing update the licensing information for the other buttons, as you can imagine.  After further research, I found that the license information are stored only the form of the control, and if this control doesn't change in any way (or in your case, adding a new project), he sees no reason when compiling to recreate a link to the license.  However, after the change of control and a new, it updates the link between the license information, which solved this problem in your case.

  I hope this helps, JC.  Have a great day!

• How do Control M to create an adjustment layer curves?

  M control creates a default curves adjustment.  However, there is a way to get control M to create a curves adjustment layer.  I forgot how to do this!

  Go to Edition > shortcuts keyboard and change the Ctrl + M to layer > new adjustment layer > curves.

• problem in the control file created by file LKM to Oracle (SQLLDR)

  I have a fixed file ABC.txt and it has three fields/columns of length, C1: = 4, C2: = 10 & C3: = 6 & I use LKM to Oracle (SQLLDR) file to load data into the target oracle table.
  
  I received the following error message in step CALL SQLLDR at km
  "org.apache.bsf.BSFException: exception of Jython: Traceback (innermost last):
  File "< string >", line 3, in? »
  
  Then I checked the registry of file control and found that the start value position & final value was not defined in the control file that is created automatically by LKM
  "
  SQL * Loader-350: error of syntax on line 14.
  Expects an integer positive, found ': '.
  C1_C1 POSITION (:) '
  
  
  The control created by ODI file & the position value is missing.
  
  OPTIONS)
  SKIP = 0,
  ERRORS = 0,
  DIRECT = FALSE
  )
  DOWNLOAD THE DATA
  INFILE 'C:/SNAPON/EOL.txt '.
  BADFILE "C:/SNAPON/ABC.bad."
  DISCARDFILE 'C:/SNAPON/ABC.dsc '.
  DISCARDMAX 1
  IN THE TABLE SNAPON_W.C$ _0ABC
  (
  C1_C1 POSITION (:),
  C2_C2 POSITION (:),
  C3_C3 POSITION (:)
  )
  
  '
  Anyone know why the position value is not created in the control file.
  
  Published by: neeraj_singh on March 3, 2011 01:25

  Hi Neeraj,

  It happens because you have not selected the area of mapping as STAGUING running.

  Open your interface, click each column of your data target store, make sure that "run them One" is marked on the "transit Zone".

  Then run your interface.

  Thank you
  Fati

• Class SoundMixer... cannot control the sounds created by the ACE?

  I'm doing a preso loading sounds in AS3 vs AS2.
  
  According to the AS3 SoundMixer class documentation "...". integrated controls of sounds continuously in a SWF file. it does not control created dynamically sound objects (that is, sound objects created in ActionScript). »
  
  Reference
  
  
  However, if I load a new AS3 document, type the following in the frame1 and then put "SoundMixer.stopAll ();" in the context of 20, he * will be * stop all sounds.
  
  I'm not exactly complaining, but are the docs wrong, or I'll just crazy here? I still have to find an instance where the class SoundMixer does not work operating docs.
  
  
  var mySound:Sound = new Sound();
  var mySoundRequest:URLRequest = new URLRequest ("someMusic.mp3");
  mySound.addEventListener (Event.COMPLETE, onSoundLoaded);
  mySound.load (mySoundRequest);
  
  function onSoundLoaded(event:Event):void
  {
  var localSound:Sound = event.target as Sound;
  localSound.play ();
  }

  midimidi,

  "> According to the AS3 SoundMixer class documentation"
  >.. .controls integrated streaming sounds in a SWF file. id is
  > not control Sound created dynamically (that is, objects
  (> Sound objects created in ActionScript). »

  Yes, I noticed that too.

  > However, if I load a new AS3 document, type the following command
  > in image1, then put 'SoundMixer.stopAll () '; in frame 20, it
  > * will * stop all sounds.

  This was also my experience. It is the same for the volume control
  on SoundMixer, and pan, through its soundTransform property, which
  provides a reference to a SoundTransform instance that is, without doubt,
  Global (in the sense of affecting all the sounds).

  > I'm not exactly complaining, but the docs are bad.

  My hunch is that the docs are simply wrong on this one.

  David Stiller
  Co-author, Foundation Flash CS3 for designers
  http://tinyurl.com/2k29mj
  "Luck is the residue of good design."

• Picture 2D controls Export in JPG format

  Hi guys,.

  I created a piece of radar using a 2D image control. However on the attempts to export by using "Get the Image" I find myself with a full white/black (depends on the background color) square box. So in short, the plot of radar created from 2 variables is not visible.

  Suggestions for the export of a .jpg of a parcel of a 2D image Control created radar file?

  Thanks a bunch!

  Have you tried the picture to Pixmap followed a JPEG Image function write?

  EDIT: The code snippet is a modification of the example of the expedition. Everything I had chosen for the snipper were the three screws and wires between them. Nothing else has been selected. The displayed snippet, that's what I got. (Don't have the tool to Capture of Code installed on the virtual machine.)

• customization of a gauge in a steering control control

  I would use sensor direction and to show leadership position on the façade, one of the ways would be to customize the gauge control. I've seen examples of control custom in to find examples where think gauge control could be customized in anything the user wants it to appear as. I would like to than the gauge control to be appeared as on the attachment, but I have no idea how to create image direction, replace with the needle of the gauge and so on.

  Ideas please!

  Best regards

  Dear Kwaris,

  I think you missed the point that Ben was. According to me, it suggests that you have numerious images (showing each position wheels different) and create code that runs through the positions. A very reasonable approach.

  Please take a look at my code attached. It was a bit rushed, effort but he illastrates that your original idea is possible. As I said, this method is far eligant. Resizing the control will fill the effect.

  There are plenty of articles and tutorials on custom controls created - including this awesome community page.

  http://decibel.NI.com/content/docs/doc-4819

  Hope this has been useful,

  Best wishes

• Cannot open vi dynamically when it contains tcp controls

  The idea is that if I had a framework for data collection. The thing is that I don't know beforehand how data are collected. That's why a vi opens dynamically to recover these data.

  When I use udp control in this vi recover data over a network, everything works fine. However, when I use tcp controls I get error 1003: "the VI is not executable. The error appears in the control of 'Reference VI open'.

  I don't see why this should be a problem.

  In this case, "Default path" returns the folder where is my program.

  In any case, I found a solution. The problem lies inside the Subvi 'Listen.vi TCP'. I went there for the controls 'Create listening TCP port' and "Wait for the TCP listening port" and now everything works fine.

• How to make the password in the tab control?

  Hello

  My version of Labview is 8.6.

  I use a "tab control" create a GUI of two tabs. I'm trying to protect one of the tab for only authorized operators. So, what is the best way to do it? I don't actually have a different GUI password, but just a simple pop-up will be great. Alternatively, what else I could use to achieve the protection?

  The structure of my program is a selection of cases in a while loop. The while loop is for the detection of key as well as the race continues while the structure of the deal is for the selection of modes.

  I will appreciate your advice very much.

  See you soon,.

  Nicholas

  Put a chain on the tab indicator, they can always do.  Use and structure of the event in a loop in order to detect the vale change event on this channel.  If the string is the secret password, select the other tab.  If not, disable the other tab.

  Initialization code for your program must clear the chain by writing an empty string for the node of this String Value property (signalling).

  

• Automatic control of the channel select

  I have a text input box that is displayed to the user for the information to be included - this will be done via a bar code reader, but it does not work because to enter in the text (bar code), a user must select the channel control unit where the text should be enter - so my question is how can I automatically select the text entery box , press the tab key also works so is it possible to send the command {tab} in VI?

  Thank you

  If your question is how to give attention to your control, the solution is a proprity (right-click on your control > create > property node > Keyfocus).

  CDT